So I have correctly setup a jetty (eclipse based) server listening on 8080. (i put a little hello world html to test). So if I go to
http://localhost:8080/index.html
my html is displayed.
Now I have followed this tutorial, to work with Websockets.
https://gist.github.com/manzke/1021982
the web.xml is configured as follow:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<display-name>tailor</display-name>
<servlet>
<servlet-name>WebSocket</servlet-name>
<servlet-class>org.sample.websocket.ChatWebSocketServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>WebSocket</servlet-name>
<url-pattern>/jetty-test/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
To connect to my Websocket I use the following url:
ws://localhost:8080/jetty-test/servlet/WebSocket
But when I click on "Connect" nothing happend ?, The connect doesn't seems to establish..
Am I missing something? Or is the url that is wrong?
Thanks !
Your web.xml is wrong, replace
<url-pattern>/jetty-test/*</url-pattern>
by
<url-pattern>/servlet/*</url-pattern>
Related
im new to using apache and spring framework and i've been using this tutorial for learning: http://docs.spring.io/docs/Spring-MVC-step-by-step/part1.html
i made an .jsp file however my browser tells me "The requested resource is not available."
the .jsp file is pretty simple
<html>
<head><title>Hello :: Spring Application</title></head>
<body>
<h1>Hello - Spring Application</h1>
<p>Greetings.</p>
</body>
</html>
entering http://localhost:8080/project/hello.htm gives me a 404.
my web.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" >
<servlet>
<servlet-name>project</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>project</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>
index.jsp
</welcome-file>
</welcome-file-list>
</web-app>
any idea how to fix this?
404 error means the requested resource is not in the server.
Your problem can be either
1. Not properly matching hello.htm to any controller
bean id="/hello.htm" class="foo.controller" or
2. You have to put your hello.jsp in webcontent folder, along with index.jsp. Not in WEB-INF folder. Refer tutorial.
I´m using spring mvc, I have got a project (Apliconta2Web) and your url is //Apliconta2Web/, but if i copy this project and change your name by (Apliconta3WebPrimefaces) when i push button run as i want url //Apliconta3WebPrimefaces/ but always i have got //Apliconta2Web/.
I have changed servlet-name. and add server the name is Apliconta3WebPrimefaces(Apliconta2Web)
How i can change it? Very thank. sorry by my english. i´m learning.
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:web="http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd">
<display-name>Aplicacion Web Apliconta3WebPrimefaces</display-name>
<servlet>
<servlet-name>apliconta3webPrimeFaces</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/app-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>apliconta3webPrimefaces</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.htm</welcome-file>
</welcome-file-list>
</web-app>
I'm trying to integrate GWT and Spring using the library spring4gwt-0.0.1.jar, but get the following error:
Caused by: java.lang.IllegalArgumentException: Servlet mapping specifies an unknown servlet name springGwtRemoteServiceServlet
at org.apache.catalina.core.StandardContext.addServletMapping(StandardContext.java:3275)
at org.apache.catalina.core.StandardContext.addServletMapping(StandardContext.java:3254)
at org.apache.catalina.deploy.WebXml.configureContext(WebXml.java:1430)
at org.apache.catalina.startup.ContextConfig.webConfig(ContextConfig.java:1344)
at org.apache.catalina.startup.ContextConfig.configureStart(ContextConfig.java:876)
at org.apache.catalina.startup.ContextConfig.lifecycleEvent(ContextConfig.java:374)
at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:117)
at org.apache.catalina.util.LifecycleBase.fireLifecycleEvent(LifecycleBase.java:90)
at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5355)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
... 6 more
My web.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>TelephoneBook</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/application-config.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>springGwtRemoteServiceServlet</servlet-name>
<servlet-class>org.spring4gwt.server.SpringGwtRemoteServiceServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>>springGwtRemoteServiceServlet</servlet-name>
<url-pattern>/TelephoneBook/springGwtServices/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>TelephoneBook.html</welcome-file>
</welcome-file-list>
</web-app>
What's the matter? Thanks in advance!
Here <servlet-name>>springGwtRemoteServiceServlet</servlet-name> you have an >to much. Is it a copy pase error? (after beginning servlet-name tag
I use jboss6.1. When I try to deploy a web app, it say class not found when try to load spring.
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
the error is
Caused by: java.lang.ClassNotFoundException: org.springframework.context.ApplicationListener
I put the spring in WEB/lib. Is that wrong? Or should be something else?
Thanks for the kind replies. What confuses me is I put the spring jars in my webapp's WEB/lib folder. Isn't that enough?
Following are the web.xml and the jars. ( I put all I grabbed in the dist folder of spring3.1)
But I wonder maybe is because I use jboss and there's something special in it? I google some post class loader but don't understand.
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:jsp="http://java.sun.com/xml/ns/javaee/jsp"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="CMDB_WS_HOST" version="3.0">
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<session-config>
<session-timeout>99999999</session-timeout>
</session-config>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/beans.xml</param-value>
</context-param>
<servlet>
<servlet-name>CXFServlet</servlet-name>
<servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXFServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>com.inspur.cmdb.system.StartupListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
spring jars in web/lib
org.springframework.aop-3.1.0.M2.jar
org.springframework.asm-3.1.0.M2.jar
org.springframework.aspects-3.1.0.M2.jar
org.springframework.beans-3.1.0.M2.jar
org.springframework.context.support-3.1.0.M2.jar
org.springframework.context-3.1.0.M2.jar
org.springframework.core-3.1.0.M2.jar
org.springframework.expression-3.1.0.M2.jar
org.springframework.instrument.tomcat-3.1.0.M2.jar
org.springframework.instrument-3.1.0.M2.jar
org.springframework.jdbc-3.1.0.M2.jar
org.springframework.jms-3.1.0.M2.jar
org.springframework.orm-3.1.0.M2.jar
org.springframework.oxm-3.1.0.M2.jar
org.springframework.test-3.1.0.M2.jar
org.springframework.transaction-3.1.0.M2.jar
org.springframework.web.portlet-3.1.0.M2.jar
org.springframework.web.servlet-3.1.0.M2.jar
org.springframework.web.struts-3.1.0.M2.jar
org.springframework.web-3.1.0.M2.jar
Make sure your server classpath has included the Spring jar library. In Spring 3 its, spring-web.jar
check whether you have these jars in WEB/lib
commons-logging-1.1.1.jar
jstl-1.2.jar
spring-asm-3.0.3.RELEASE.jar
spring-beans-3.0.3.RELEASE.jar
spring-context-3.0.3.RELEASE.jar
spring-core-3.0.3.RELEASE.jar
spring-expression-3.0.3.RELEASE.jar
spring-web-3.0.3.RELEASE.jar
spring-webmvc-3.0.3.RELEASE.jar
It is ok with JBoss 7.It is classloading effect.
Config : /WEB-INF/jboss-web.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE jboss-web PUBLIC
"-//JBoss//DTD Web Application 4.2//EN"
"http://www.jboss.org/j2ee/dtd/jboss-web_4_2.dtd">
<jboss-web>
<class-loading java2ClassLoadingCompliance="false">
<loader-repository>
myapp:loader=anyUniqueName
<loader-repository-config>java2ParentDelegation=false</loader-repository-config>
</loader-repository>
</class-loading>
</jboss-web>
Otherwise
I reference here.
I have not tried with JBoss 6 yet. But, I hope, the following configuration will be helpful for JBoss 6.
NOTE:
On JBoss 6.0, to avoid the container loading the classes before the application actually starts, one needs to add a WEB-INF/jboss-scanning.xml file to the application archive - with the following content:
Config : /WEB-INF/jboss-scanning.xml
<scanning xmlns="urn:jboss:scanning:1.0"/>
Written in Liferay Documentation 6.1 on using Message Bus,
Configuration of Message Bus is done using the following files:
WEB-INF/src/META-INF/messaging-spring.xml - Specifies your destinations, listeners, and their mappings to each other
WEB-INF/web.xml - Holds a listing of deployment descriptors for your plugin. Be sure to add messaging-spring.xml to your list of Spring configurations in this file.
How does messaging-spring.xml listed in web.xml?
I tried this
<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener>
<context-param><param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/META-INF/messaging-spring.xml</param-value> </context-param>
</web-app>
but tomcat logged
org.apache.catalina.core.standardcontext start severe error listenerstart
And when i removed
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
tomcat logged
Container org.apache.catalina.core.ContainerBase.[Catalina].[localhost]. has not been started
just want to try the Message Bus, and i cant invoke the listener when a send a message using
Message message = new Message();
message.put("slogan", "Procurement");
MessageBusUtil.sendMessage("inkwell/slogan", message);
I'm developing in Liferay 6.0.5 Thanks for the help