What's wrong with this xpath line added below:
/holiday[starts-with(#code,'A')/holidaytype[1]/duration[#period=(15)]
I'm trying to filter by holiday code and then by the number of day(period).
You are missing a / and a ]. Look:
/holiday[starts-with(#code,'A')/holidaytype[1]/duration[#period=(15)]
^ ^
^-- missing here ^-- and "]" here
In the first case, it can be a // or //*/. So, try:
//holiday[starts-with(#code,'A')]/holidaytype[1]/duration[#period=(15)]
Related
I need to allow only set of characters i.e.,
a to z A to Z 0 to 9 . !##$% *()_=+|[]{}"'';:?/.,-
but When I add dash(-) character to below query it is not working please help me at earliest.
SELECT :p_string FROM dual
WHERE NOT REGEXP_LIKE (translate(:p_string,chr(10)||chr(11)||chr(13), ' '),'[^]^A-Z^a-z^0-9^[^.^{^}^!^#^#^$^%^*^(^)^_^=^+^|^\^{^}^"^''^;^:^?^/^,^-^ ]' );
[.-.] will work fine on this query .
The extra ^ symbols inside the bracket expression in your pattern are not, as I think you expect, negations; only the first ^ inside the brackets does that.
The main issue that is causing, apart from allowing that actual circumflex symbol to be matched when you didn't seem to want it, is that you end up with ^-^ being treated as a range.
To include a literal - it has to be the first or last thing in the brackets; from the docs:
To specify a right bracket (]) in the bracket expression, place it first in the list (after the initial circumflex (^), if any).
To specify a hyphen in the bracket expression, place it first in the list (after the initial circumflex (^), if any), last in the list, or as an ending range point in a range expression.
So as you need to do both, make the hyphen last; you can change your pattern to:
'[^]A-Za-z0-9[.{}!##$%*()_=+|\{}"'';:?/, -]'
You could also skip the tralsnate step by including those special characters in the pattern too:
'[^]A-Za-z0-9[.{}!##$%*()_=+|\{}"'';:?/, '||chr(10)||chr(11)||chr(13)||'-]'
Looks like you need to permit only (7-bit) ASCII characters with exception of ~ and ^
In this case I would try it like this:
WHERE CONVERT(p_string, 'US7ASCII') = p_string
AND NOT REGEXP_LIKE(p_string, '~|\^')
Instead of CONVERT(p_string, 'US7ASCII') = p_string you can also use ASCIISTR(REPLACE(p_string, '\', '/')) = REPLACE(p_string, '\', '/')
I have a file like:
Fruit.Store={
#blabla
"customer-id:12345,item:store/apple" = (1,2); #blabla
"customer-id:23456,item:store/banana" = (1,3); #blabla
"customer-id:23456,item:store/watermelon" = (1,4);
#blabla
"customer-id:67890,item:store/watermelon" = (1,6);
#The following two are unique
"customer-id:0000,item:store/" = (100, 100);
#
"" = (0,0)
};
Except the comments, each line has the same format: customer-id and item:store/ are fixed, and customer-id is a 5-digit number. The last two records are unique. How could I make sure the file is in the right format elegantly? I am thinking about using the flag for the first special line Fruit.Store={ and than for the following lines split each line by "," and "=", and if the splitted line is not correct, match them with the last two records. I want to use Ruby for it. Any advice? Thank you.
I am also thinking about using regular expression for the format, and wrote:
^"customer:\d{5},item:store\/\D*"=\(\d*,\d*\);
but I want to combine these two situations (with comment and without comment):
^"customer:\d{5},item:store\/\D*"=\(\d*,\d*\);$
^"customer:\d{5},item:store\/\D*"=\(\d*,\d*\);#.*$
how could I do it? Thanks
Using regular expressions could be a good option since each line has a fixed format; and you almost got it, your regex just needed a few tweaks:
(?:#.*|^"customer-id:\d{5},item:store\/\D*" *= *\(\d*, *\d*\); *(?:#.*)?)$
This is what was added to your current regex:
Option to be a comment line (#.*) or (|) a regular line (everything after |).
Check for possible spaces before and after =, after the comma (,) that separates the digits in parenthesis, and at the end of the line.
Option to include another comment at the end of the line ((?:#.*)?).
So just compare each line against this regex to check for the right format.
Apparently I still don't understand exactly how it works ...
Here is my problem: I'm trying to match numbers in strings such as:
910 -6.258000 6.290
That string should gives me an array like this:
[910, -6.2580000, 6.290]
while the string
blabla9999 some more text 1.1
should not be matched.
The regex I'm trying to use is
/([-]?\d+[.]?\d+)/
but it doesn't do exactly that. Could someone help me ?
It would be great if the answer could clarify the use of the parenthesis in the matching.
Here's a pattern that works:
/^[^\d]+?\d+[^\d]+?\d+[\.]?\d+$/
Note that [^\d]+ means at least one non digit character.
On second thought, here's a more generic solution that doesn't need to deal with regular expressions:
str.gsub(/[^\d.-]+/, " ").split.collect{|d| d.to_f}
Example:
str = "blabla9999 some more text -1.1"
Parsed:
[9999.0, -1.1]
The parenthesis have different meanings.
[] defines a character class, that means one character is matched that is part of this class
() is defining a capturing group, the string that is matched by this part in brackets is put into a variable.
You did not define any anchors so your pattern will match your second string
blabla9999 some more text 1.1
^^^^ here ^^^ and here
Maybe this is more what you wanted
^(\s*-?\d+(?:\.\d+)?\s*)+$
See it here on Regexr
^ anchors the pattern to the start of the string and $ to the end.
it allows Whitespace \s before and after the number and an optional fraction part (?:\.\d+)? This kind of pattern will be matched at least once.
maybe /(-?\d+(.\d+)?)+/
irb(main):010:0> "910 -6.258000 6.290".scan(/(\-?\d+(\.\d+)?)+/).map{|x| x[0]}
=> ["910", "-6.258000", "6.290"]
str = " 910 -6.258000 6.290"
str.scan(/-?\d+\.?\d+/).map(&:to_f)
# => [910.0, -6.258, 6.29]
If you don't want integers to be converted to floats, try this:
str = " 910 -6.258000 6.290"
str.scan(/-?\d+\.?\d+/).map do |ns|
ns[/\./] ? ns.to_f : ns.to_i
end
# => [910, -6.258, 6.29]
I have a string:
string = %q{<span class="no">2503</span>read_attribute_before_type_cast(<span class="pc">self</span>.class.primary_key)}
In this example I want to match the words 'class' which are not in the tag. Regexp for this:
/\bclass[^=]/
But the problem is that it matches the last letter
/\bclass[^=]/.match(string) => 'class.'
I don't want have a last dot in a result. I've tried this regexp:
/\bclass(?:[^=])/
but still got the same result. How to limit the result to 'class'? Thanks
You are almost correct, but you have an error in your look ahead. Try this:
/\bclass(?!=)/
The regex term (?!=) means the input to the right must not match the character '='
You can take your variable string and extract a subsection using groups:
substring = string[/\b(class)[^=]/, 1]
The brackets around class will set that as the first "group", which is referred to by the 1 as the second parameter in the square brackets.
Assuming your only issue is keeping it from matching span.class.blah, just ignore . as well, so [^=.].
I have the following lines I have to match
A
Ab
A#
F#7+9d
G3+9d
Gm
Basically I need to match the first letter and the # or the b following. I also need to match anything else (such as the 7+9d or the m).
Here is my code so far but it's not picking up the second part
preg_match('/A-G([A-Z0-9+]?)/i', $start_key, $matches)
Any ideas?
Try this
/^A-G(#|b)?([A-Z0-9+]*)$/i
Try adding a-z and # to the body of the character set, converting your statement into:
preg_match('/A-G([A-Za-z0-9+#]?)/i', $start_key, $matches)