Loading Content Via Ajax - ajax

Question

Ok, so I'm pretty new to ajax and loading content externally and would appreciate any insight to my problem.
I currently have a hidden div that is empty where the ajax content should load in after a link is clicked.
<div id="#ajax-wrap"></div>
I currently have a list of links that all have the same class and I'd like to have, when clicked, the blank div do a slide toggle and then load in the content from the page that the link was to.
Link:
Current jQuery:
$("a.home-right").click(function () {
$('#ajax-wrap').slideToggle();
});
Being as I'm new to Ajax and loading the external content, I'd like to know how to load content from the linked page that's house in the #content tag. So essentially, I'd like a .home-right link, #ajax-wrap would slide toggle, and then Ajax would pull content from the linked page (which is always going to be a different random link) and it's #content div, placing that content in #ajax-wrap.
Thanks in advance for any help folks!

Answer 1

You want to set the ajax for the links. Requirements:
Writing a handler for links.
We must cancel the default behaviour of browser when somebody click on a link (that redirect to the page).
Removing old data ajax recieved from server and make the #ajax-wrap fresh.
Load the remote page via ajax and set it to #ajax-wrap.
Now slide it down.
// Document Ready
$(function () {
// attaching click handler to links
$("a.home-right").click(function (e) {
// cancel the default behaviour
e.preventDefault();
// get the address of the link
var href = $(this).attr('href');
// getting the desired element for working with it later
var $wrap = $('#ajax-wrap');
$wrap
// removing old data
.html('')
// slide it up
.slideUp()
// load the remote page
.load(href + ' #content', function () {
// now slide it down
$wrap.slideDown();
});
});
});

Answer 2

You can simply use the ajax like this:
$("a.home-right").click(function () {
$.ajax({
type: "get",
url: "YOUR URL HERE",
success: function(data){
$('#ajax-wrap').html(data);
$('#ajax-wrap').slideToggle();
},
error: function(){
alert("An error occured");
}
});
});

Answer 3

try this:
$(function(){
$("a.home-right").click(function () {
$('#ajax-wrap').slideUp();
var url = $(this).attr("href")
$.ajax({
type: "get",
url: url,
success: function(msg){
$('#ajax-wrap').html(msg)
$('#ajax-wrap').slideDown();
},
error: function(){
alert("An error occured");
}
});
})
})

Answer 4

Use get:
// Inside click handler
$.get('url_that_returns_data')
.done(function(response){
var $response = $(response);
$('#ajax-wrap').html($response.find('#content')).slideToggle();
});