In the following script (saved as script.sh):
#!/bin/sh
cd $MY_PYTHON_WORKING_DIRECTORY
python script1.py
python script2.py
Then, when I try to run the command script.sh in my bash shell, I got the error bash: script.sh: command not found. Why does this not work as expected? If the first line of any scripts start by #! prefix, then the following path on the line is interpreted as a command, right? For your information, even if I changed my first line to #!/bin/bash, the same error still occurred. If I run the script as either sh script.sh or bash script.sh, then the script ran as expected.
Is there any way to run the script by just hitting script.sh?
One more question, between sh and bash, which should I use? I'm on OS X 10.8 and my default shell is currently set bash, but I wonder which one to use going forward.
Thanks.
First, make the script executable:
chmod u+x script.sh
Second, your current directory is not in your $PATH. Therefore, you have to run the script with a path (relative is enough):
./script.sh
Related
I am trying to use git bash to run my .sh file that was generated using Makefile.
When running the command ./run.sh I get this message ./run.sh: line 1: /home/user/run: No such file or directory
To run a script file (using Git Bash), you do the following:
Add a "sh-bang" line on the first line (e.g. #!/bin/bash OR #!/usr/bin/env sh) this is how git bash knows a file is executable.
Use ./ (or any valid dir spec): ./script.sh
Note : any "sh-bang" will work
You are using git bash so I suppose you are using Windows.
As for me I always use shebang on my scripts. Depending on the content of your script, you may add one of the following lines at the first line of your script.
#!/bin/sh
#!/bin/bash
#!/usr/bin/perl
#!/usr/bin/tcl
#!/bin/sed
#!/usr/awk
#!/usr/bin/python
If you still have problems running the script with ./run.sh command, you may try to use sh run.sh (on Git bash) and it should execute the script just as ./run.sh does it on linux.
This error message says that the first line of the script tries to execute an executable program named run in your home directory, and this does not exist.
I don't know what run.sh is supposed to do, but if you want to execute it a program, you need to make sure that the program exists, for instance by creating it.
I'm working on an Ubuntu 18.04 and I'm trying to run a very simple bash script named print_test:
#!/bin/bash
echo 123
I have the $PATH variable set correctly (it includes the /bin directory) and I have tested that
I'm using the correct line ending (wc -l print_test results in 2). I have changed the permissions using
chmod +x print_test. When I try to run the script I get:
print_test: command not found
Any idea what I might be doing wrong?
Note: when I simply run echo 123 in the terminal it does prints 123 .
Thanks!
If the path is set properly it must work
Easier way , to invoke a shell script
chmod +x script.sh
./script.sh
Here replace script with the name of your script
Use this at the first line of your script
#!<path/to/bash>
I am trying to learn the basics of shell. I used vim editro for creating my own list of commands to be executed. Here is the way I created the code
vi mycommands
then inside this file I wrote
cd Documents
I am using macOS Catalina which has zsh by default but switched to bash
So when I write the following command in the terminal:
$ sh +x mycommands
It shows
+cd Documents
The Documents has some files and directories but it is not changing directory.Where am I going wrong?
Any help will be greatly appreciated.
Scripts run like sh myscript execute in a separate sub-shell, not the current shell. Changing directory inside a script will not cause your shell to change directory. If you want to change directory in your shell, you need to run the commands in your shell.
To do that, run:
. ./myscript (sh, bash) or source ./myscript (bash).
See this question.
I have a shell script with some functionalities. I want to convert it to an executable file. Any idea if this is possible?
Thanks
Add the following line at the very top of your script:
#!/bin/sh
This is known as a shebang. It indicates which program to invoke the shell script with when you execute it. You could change it to anything. Eg, to run a zsh script you would use #!/bin/zsh, which is the path to the zsh interpreter on my machine.
Then you need to mark the file as executable using chmod. You can do this as follows:
chmod +x myscript
You can now run the script like this:
/full/path/to/myscript
Or, if you're in the directory the script is in:
./myscript
The '.' expands to the path of your current working directory.
If you want to be able to run the script from anywhere, stick it somewhere in your path. Eg.
mv myscript /usr/bin
You can now run the script from anywhere by typing in just the name.
i have a script that reads a file line by line
the code is
FILE=commands.txt
while read CMD; do
echo "$CMD"
done < "$FILE"
This code is stored in a script file vxm_alarm.sh
In Korn shell, this loop works perfectly, when i run the command vxm_alarm.sh. In bash however i get the following error
vxm_alarm.sh: syntax error at line 4: `done' unexpected
In Bash I'm executing the script using the command sh vxm_alarm.sh. what am i doing wrong? And why can't we execute a script simply by doing this in bash
chmod +x filename.sh
filename.sh
Your code works on my machine using GNU bash 4.1.5
Try adding a shebang to the top:
#!/bin/sh
FILE=commands.txt
while read CMD; do
echo "$CMD"
done < "$FILE"
If you run sh vxm_alarm.sh you are most likely not running Bash. Try sh --version - If you get anything other than a version string, it's not Bash. Try running bash vxm_alarm.sh instead.
To be able to run a script without a path before it it has to be in one of the directories listed in the PATH variable. For example, if
echo "$PATH"
prints
/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
you can put filename.sh in /usr/local/sbin, /usr/local/bin, /usr/sbin, /usr/bin, /sbin or /bin and run it as simply filename.sh. If you want your script to be run from a directory not in the path, you have three choices:
Modify $PATH to include the directory where the script resides.
Run it with a relative or absolute path.
Create an alias or function pointing to the relative or absolute path.
I'd like to answer this part of your question:
why can't we execute a script simply by doing this in bash
chmod +x filename.sh
filename.sh
As others already pointed out in part, there are several things required for that to work:
execution rights (You ensured that with your chmod command)
the shebang, so the system knows what shell/interpreter to use
#!/bin/bash
(it is important to say bash if you want bash and not sh)
make sure the command is found. This is the case when its directory is found in PATH. However what you'd rather do in this case is specify the directory. For the current directory you can do it like this
./name-of-the-script
In contrast to DOS and (IIRC) the various Windows Command line interfaces, Unix systems usually don't have the current directory on the PATH. It is possible to add it, but discouraged due to severe implications on security.