Obtain sub-cv::Mat from a given image such that - algorithm

I have a processed an image that returns a Mat say:
[
[ 0, 0, 255, 255, 255, 0, 0, 0],
[ 0, 0, 0, 255, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 255, 255, 0],
[ 0, 0, 0, 0, 0, 255, 255, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0]
]
are there any segmentation functions that can help me isolate individually ?
if not so what would be the best approach ?
i.e. say if i do mysegment(Mat a,0) should return
[
[ 0, 0, 255, 255, 255, 0, 0, 0],
[ 0, 0, 0, 255, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0]
]
then mysegment(Mat a,1) will return
[
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 255, 255, 0],
[ 0, 0, 0, 0, 0, 255, 255, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0]
]
I consider continuous 255 pixels to be a block. Now I want to iterate over or process these blocks ... since more than one block can be formed in a matrix.

You can use contours
findContours( canny_output, contours, hierarchy, CV_RETR_TREE, CV_CHAIN_APPROX_SIMPLE, Point(0, 0) );
the link to the library

Related

Laravel sortBy multiple values and multiple keys

I'm trying to figure out the best way to sort by multiple values and multiple keys at once.
I have the following "sort sequence";
sort by "finished or not"
sort by "out of time or not"
sort by "points in total"
sort by "points for your time"
sort by "points for each 'secret time control', can be null, then you end up at the end of that sorting"
sort by "the distance driven"
I currently have something like this of response (sorted);
[
{
"team_number": 201,
"points_for_time": 0,
"detail_points_for_time": {
"tc_start": 0,
"tc_round_in": 0,
"tc_stop": 0
},
"points_for_gtc": 1,
"detail_points_for_gtc": [
0,
1
],
"points_for_distance": 0,
"missed_controls": 100,
"out_of_time": false,
"dnf": false,
"total": 101
},
{
"team_number": 202,
"points_for_time": 2,
"detail_points_for_time": {
"tc_start": 0,
"tc_round_in": 0,
"tc_stop": 2
},
"points_for_gtc": 0,
"detail_points_for_gtc": [],
"points_for_distance": 0,
"missed_controls": 100,
"out_of_time": false,
"dnf": false,
"total": 102
},
{
"team_number": 203,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
},
{
"team_number": 204,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
},
{
"team_number": 205,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
},
{
"team_number": 206,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
},
{
"team_number": 207,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
},
{
"team_number": 208,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
},
{
"team_number": 209,
"points_for_time": 0,
"detail_points_for_time": 0,
"points_for_gtc": 0,
"detail_points_for_gtc": 0,
"points_for_distance": 0,
"missed_controls": 0,
"out_of_time": false,
"dnf": true,
"total": 0
}
]
So the goal here is, that I get a full sorting based on the above "sequence".
I currentmy use this;
$results = $results->sortBy('total')
->sortBy('points_for_time')
->sortBy('points_for_gtc') // this is an issue, since it puts you below someone else when you have less points
->sortBy('points_for_distance')
->sortBy('out_of_time')
->sortBy('dnf');
There is another "field" I have, detail_points_for_gtc, which holds the points (in order) for each "time control".
The possibility exists that there is nothing filled in, if so, then you should be at the end of the list. it's also possible that the value is null. Then it should be sorted at the end.
I have no idea on how I can sort on the detail_points_for_gtc, and if this sorting is "the correct sorting"?
Anyone who understands the question and may be able to help?
I think you can try this;
// you can send column and direction from request or where you need
$results = $request->direction == 'asc' ? $results->sortBy($request->column) : $results->sortByDesc($request->column);

Printing tchar array as unicode string rust winapi

I'm using the winapi to grab a list of the current processes running on the system, here's my code:
use winapi::um::tlhelp32::{Process32Next, Process32First, CreateToolhelp32Snapshot, TH32CS_SNAPPROCESS, PROCESSENTRY32};
use winapi::um::winnt::HANDLE;
use winapi::um::handleapi::CloseHandle;
use std::mem::size_of;
...
fn get_processes() {
let h_process_snap: HANDLE;
// really, rust?
let mut pe32 = &mut PROCESSENTRY32{
dwSize: 0,
cntUsage: 0,
th32ProcessID: 0,
th32DefaultHeapID: 0,
th32ModuleID: 0,
cntThreads: 0,
th32ParentProcessID: 0,
pcPriClassBase: 0,
dwFlags: 0,
szExeFile: [0; 260],
};
unsafe {
h_process_snap = CreateToolhelp32Snapshot(TH32CS_SNAPPROCESS, 0);
}
pe32.dwSize = size_of::<PROCESSENTRY32>() as u32;
unsafe {
if Process32First(h_process_snap, pe32) == 0 {
CloseHandle(h_process_snap);
println!("can't get a process snapshot");
// TODO: return
}
while Process32Next(h_process_snap, pe32) != 0 {
println!("{:?}", pe32.szExeFile);
}
}
}
...
Now I'm trying to print the actual name of the process, in C++, this can be done using cout or wcout.
When I use println!("{:?}", pe32.szExeFile);, this is what I get:
[115, 117, 112, 101, 114, 102, 52, 45, 114, 117, 115, 116, 46, 101, 120, 101, 0, 116, 46, 101, 120, 101, 0, 98, 108, 101, 83, 104, 101, 108, 108, 46, 69, 120, 112, 101, 114, 105, 101, 110, 99, 101, 115, 46, 84, 101, 120, 116, 73, 110, 112, 117, 116, 46, 73, 110, 112, 117, 116, 65, 112, 112, 46, 101, 120, 101, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
I don't really understand how to work with this, how can I print the pe32.szExeFile as a Unicode string in rust?
see also: https://docs.rs/winapi/0.3.6/winapi/um/tlhelp32/struct.PROCESSENTRY32.html
Thanks to #IInspectable, I used the explicit Unicode versions, e.g. Process32FirstW, and from_wide to print the values in readable format:
let os_string = OsString::from_wide(&pe32.szExeFile[..]);
// ExeFile names have a lot of trailing 0's, remove them...
let exe_files: String = os_string.into_string().unwrap().replace("\u{0}", "");
println!("{:?}", exe_files);

Cythonizing function containing too many arrays

Running setup.py on the code below takes some seconds to finish; however, by increasing number of arrays to 20k, .pyd is not generated after 2 hours of running the setup on windows XP 32 bit. Should I use a specific definition for the arrays?
import numpy
import scipy.interpolate
from scipy.interpolate import interp2d
x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
y = [0.1, 0.2, .3, 0.4, 0.5, 0.6, .7, 0.8, .9, 1, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9]
def interpolate(DATA,x_new,y_new):
var1 = DATA[0]
var2 = DATA[1]
f = interp2d(y,x,var1,kind='linear')
k1 = f(y_new,x_new)
f = interp2d(y,x,var2,kind='linear')
k2 = f(y_new,x_new)
return (k1[0],k2[0])
def function(condition1,condition2,param1,param2):
Data1_var1=[[6L, 5L, 8L, 8L, 9L, 3L, 2L, 1L, 1L, .7, 5.7, 4.8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [5L, 1L, 9L, 5L, 4L, 8L, 9L, 3L, 9.5, 7.2, 5.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 9L, 8L, 4L, 2L, 6L, 2L, 8, 7, 5.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [8L, 3L, 8L, 4L, 2L, 2L, 4L, 1L, .8, .1, 4.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 5L, 4L, 2L, 1L, 6L, 1L, 8, .8, 5.4, 4.2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [5L, 4L, 3L, 2L, 7L, 3L, 1L, 8L, 6.3, 5.2, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [4L, 3L, 2L, 2L, 1L, 3L, 1L, 8.4, 6.8, 5.6, 4.4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 1L, 6L, 2L, 1L, 4L, 1L, 9.2, 6, 6.3, 5L, 4.2, 3.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [3L, 7L, 4L, 1L, 6L, 4L, 2L, .8, 8.3, 7L, .6, 4.8, 4.1, 3.7, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 4L, 1L, 8L, 6L, 1L, 2L, 10L, 8.9, 7.7, 6.5, 5.6, 5L, 4.6, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 2L, 7L, 5L, 3L, 2L, 10L, 9.2, 8.1, 6.9, .1, .6, 5.1, 4.6, .2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
Data1_var2=[[6L, 5L, 8L, 8L, 9L, 3L, 2L, 1L, 1L, .7, 5.7, 4.8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [5L, 1L, 9L, 5L, 4L, 8L, 9L, 3L, 9.5, 7.2, 5.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 9L, 8L, 4L, 2L, 6L, 2L, 8, 7, 5.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [8L, 3L, 8L, 4L, 2L, 2L, 4L, 1L, .8, .1, 4.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 5L, 4L, 2L, 1L, 6L, 1L, 8, .8, 5.4, 4.2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [5L, 4L, 3L, 2L, 7L, 3L, 1L, 8L, 6.3, 5.2, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [4L, 3L, 2L, 2L, 1L, 3L, 1L, 8.4, 6.8, 5.6, 4.4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 1L, 6L, 2L, 1L, 4L, 1L, 9.2, 6, 6.3, 5L, 4.2, 3.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [3L, 7L, 4L, 1L, 6L, 4L, 2L, .8, 8.3, 7L, .6, 4.8, 4.1, 3.7, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 4L, 1L, 8L, 6L, 1L, 2L, 10L, 8.9, 7.7, 6.5, 5.6, 5L, 4.6, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 2L, 7L, 5L, 3L, 2L, 10L, 9.2, 8.1, 6.9, .1, .6, 5.1, 4.6, .2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
Data2_var1=[[9L, 4L, 8L, 8L, 9L, 3L, 2L, 1L, 1L, .7, 5.7, 4.8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [3L, 1L, 9L, 5L, 4L, 8L, 9L, 3L, 9.5, 7.2, 5.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 9L, 8L, 4L, 2L, 6L, 2L, 8, 7, 5.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [8L, 3L, 8L, 4L, 2L, 2L, 4L, 1L, .8, .1, 4.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 5L, 4L, 2L, 1L, 6L, 1L, 8, .8, 5.4, 4.2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [5L, 4L, 3L, 2L, 7L, 3L, 1L, 8L, 6.3, 5.2, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [4L, 3L, 2L, 2L, 1L, 3L, 1L, 8.4, 6.8, 5.6, 4.4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 1L, 6L, 2L, 1L, 4L, 1L, 9.2, 6, 6.3, 5L, 4.2, 3.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [3L, 7L, 4L, 1L, 6L, 4L, 2L, .8, 8.3, 7L, .6, 4.8, 4.1, 3.7, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 4L, 1L, 8L, 6L, 1L, 2L, 10L, 8.9, 7.7, 6.5, 5.6, 5L, 4.6, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 2L, 7L, 5L, 3L, 2L, 10L, 9.2, 8.1, 6.9, .1, .6, 5.1, 4.6, .2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
Data2_var2=[[4L, 5L, 8L, 8L, 9L, 3L, 2L, 1L, 1L, .7, 5.7, 4.8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 1L, 9L, 5L, 4L, 8L, 9L, 3L, 9.5, 7.2, 5.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [1L, 5L, 9L, 8L, 4L, 2L, 6L, 2L, 8, 7, 5.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [8L, 3L, 8L, 4L, 2L, 2L, 4L, 1L, .8, .1, 4.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 5L, 4L, 2L, 1L, 6L, 1L, 8, .8, 5.4, 4.2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [5L, 4L, 3L, 2L, 7L, 3L, 1L, 8L, 6.3, 5.2, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [4L, 3L, 2L, 2L, 1L, 3L, 1L, 8.4, 6.8, 5.6, 4.4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [6L, 1L, 6L, 2L, 1L, 4L, 1L, 9.2, 6, 6.3, 5L, 4.2, 3.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [3L, 7L, 4L, 1L, 6L, 4L, 2L, .8, 8.3, 7L, .6, 4.8, 4.1, 3.7, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 4L, 1L, 8L, 6L, 1L, 2L, 10L, 8.9, 7.7, 6.5, 5.6, 5L, 4.6, 4.1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [2L, 3L, 2L, 7L, 5L, 3L, 2L, 10L, 9.2, 8.1, 6.9, .1, .6, 5.1, 4.6, .2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
if condition1:
if condition2:
out = interpolate(Data1,param1,param2)
else:
out = interpolate(Data2,param1,param2)

JQPlot Grouped Stacked graph with different colours

I am trying to produce the following graph with JQPlot
I have attempted this as best I can however the script causes an excsessive runtime and eventually firefox comes up with the stop script notice.
Any suggestions?
$(document).ready(function () {
var assigned1 = [5, 12, 2, 0, 0, 4, 8];
var assigned2 = [4, 0, 2, 0, 0, 2, 4];
var assigned3 = [1, 0, 2, 0, 0, 2, 0];
var assigned4 = [0, 0, 5, 0, 0, 3, 0];
var assigned5 = [0, 0, 1, 0, 0, 0, 0];
var assigned = [assigned1, assigned2, assigned3, assigned4, assigned5];
var numCompleted = [assigned1, assigned2, assigned3, assigned4, assigned5]; //[4,3,6,5,5,4,0,0,5,4,0,0,0,0];
//[1,1,0,0,2,2,8,7,4,4,11,10,1,1];
//var test3 = [4,6,3,8,6,3,1,9,1,5,3,6,7,4];
var dates = ['Assigned', 'Employee', 'Machine', 'Assigned', 'Employee', 'Machine', 'Assigned', 'Employee', 'Machine', 'Assigned', 'Employee', 'Machine', 'Assigned', 'Employee', 'Machine', 'Assigned', 'Employee', 'Machine', 'Assigned', 'Employee', 'Machine'];
plot3 = $.jqplot('chart3', [assigned, numCompleted], {
// Tell the plot to stack the bars.
seriesColors: ["#81a7d4", "#d0d0d0", "#fac"],
stackSeries: true,
shadow: false,
title: 'Cell Name',
animate: false,
captureRightClick: false,
grid: {
drawGridLines: false,
shadow: false
},
legend: {
show: false,
},
seriesDefaults: {
renderer: $.jqplot.BarRenderer,
rendererOptions: {
barMargin: 10,
barPadding: 0,
shadowOffset: 0,
groups: 7,
highlightMouseDown: true
},
pointLabels: {
show: true,
hideZeros: true,
edgeTolerance: 10
}
},
grid: {
gridLineColor: '#fff',
borderWidth: 0,
shadow: false,
background: "white"
},
axes: {
xaxis: {
renderer: $.jqplot.CategoryAxisRenderer,
ticks: dates,
showTickMarks: false
},
yaxis: {
showTicks: false
}
}
});
});
http://jsfiddle.net/K5cjj/1/
I have managed to do this by drawing multiple graphs to the same element. This has other issue but appears to work, can anyone expand on this to enable the click function to work on all bars
However this works in Firefox, chrome and IE11 only, IE 10 and below is all messed up (as usual)
http://jsfiddle.net/LADzf/1
$(document).ready(function(){
/* graph config */
var maxVal = 13;
/* graph vals */
var assigned1 = [5, 0, 0, 0, 12, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 4, 0, 0, 0, 8, 0, 0];
var assigned2 = [3, 0, 0, 0, 0, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 8, 0, 0, 0, 2, 0, 0];
var assigned3 = [2, 0, 0, 0, 0, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0];
var assigned4 = [0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
var employee1 = [0, 5, 0, 0, 0, 10, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 12, 0, 0, 0, 12, 0];
var employee2 = [0, 5, 0, 0, 0, 2, 0, 0, 0, 8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
var machine = [0, 0, 12, 0, 0, 0, 12, 0, 0, 0, 12, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 12, 0, 0, 0, 12];
var basevals = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
/* graph ticks */
var ticks = ['Assigned', 'Employee', 'Machine', ' ', 'Assigned', 'Employee', 'Machine', ' ', 'Assigned', 'Employee', 'Machine', ' ', 'Assigned', 'Employee', 'Machine', ' ', 'Assigned', 'Employee', 'Machine', ' ', 'Assigned', 'Employee', 'Machine', ' ', 'Assigned', 'Employee', 'Machine'];
var blankticks = [' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '];
var dateticks = ['<br><br><br><br>01/01/2014', '<br><br><br><br>02/01/2014', '<br><br><br><br>03/01/2014', '<br><br><br><br>04/01/2014', '<br><br><br><br>05/01/2014', '<br><br><br><br>06/01/2014', '<br><br><br><br>07/01/2014'];
/* plot the base graph */
plotbase = $.jqplot('chart3', [basevals], {
seriesDefaults:{
renderer:$.jqplot.BarRenderer,
rendererOptions: {barMargin: 10},
pointLabels: {show: false}
},
axesDefaults: {show: false},
tickOptions: {showMark: false, angle: 90},
axes: {
showLabel: false,
xaxis: {
renderer: $.jqplot.CategoryAxisRenderer,
ticks: dateticks,
tickOptions: {markSize: 0}
},
yaxis: {
padMin: 0,
min: 0,
max: maxVal,
showLabel: false,
show: false
}
}
});
plot3 = $.jqplot('chart3', [machine], {
seriesColors: ["#a62525"],
stackSeries: true,
captureRightClick: true,
seriesDefaults:{
renderer:$.jqplot.BarRenderer,
rendererOptions: {
barMargin: 10,
highlightMouseOver: true
},
pointLabels: {show: false}
},
axesDefaults: {show: false},
tickOptions: {showMark: false, angle: 90},
axes: {
showLabel: false,
xaxis: {
renderer: $.jqplot.CategoryAxisRenderer,
ticks: blankticks,
tickOptions: {markSize: 0}
},
yaxis: {
padMin: 0,
min: 0,
max: maxVal,
showLabel: false,
show: false
}
}
});
plot2 = $.jqplot('chart3', [employee1, employee2], {
seriesColors: ["#67ce64", "#da9831"],
stackSeries: true,
captureRightClick: true,
seriesDefaults:{
renderer:$.jqplot.BarRenderer,
rendererOptions: {barMargin: 10, highlightMouseOver: true},
pointLabels: {show: false}
},
axesDefaults: {show: false},
tickOptions: {showMark: false},
axes: {
showLabel: false,
xaxis: {
renderer: $.jqplot.CategoryAxisRenderer,
ticks: blankticks
},
yaxis: {
padMin: 0,
min: 0,
max: maxVal,
showLabel: false,
show: false
}
},
grid: {background: 'transparent', drawGridLines: false, gridLineColor: 'transparent', borderColor: 'transparent'}
});
plot1 = $.jqplot('chart3', [assigned1, assigned2, assigned3, assigned4], {
stackSeries: true,
captureRightClick: true,
seriesColors: ["#effa38", "#37d1f8", "#5129b6"],
seriesDefaults:{
renderer:$.jqplot.BarRenderer,
rendererOptions: {barMargin: 10, highlightMouseOver: true },
pointLabels: {show: false}
},
axes: {
xaxis: {
renderer: $.jqplot.CategoryAxisRenderer,
tickRenderer:$.jqplot.CanvasAxisTickRenderer,
ticks: ticks,
tickOptions: {
angle: -90,
}
},
yaxis: {
padMin: 0,
min: 0,
max: maxVal
}
}, grid: {background: 'transparent', drawGridLines: false, gridLineColor: 'transparent', borderColor: 'transparent'}
});
$('#chart3').bind('jqplotDataClick', function (ev, seriesIndex, pointIndex, data) {
$('#info3').html('series: '+seriesIndex+', point: '+pointIndex+', data: '+data);
});
});

3D skew transformation matrix along one coordinate axis

Is there a way to calculate the skew transformation matrix along one coordinate axis, given the skew angle, as follows
This should work for the most part for skewing an object with a transformation matrix, in particular using glMultMatrix(matrix)
matrix1[] = {
1, 0, 0, 0,
tan(a), 1, 0, 0,
0, 0, 1, 0,
0, 0, 0, 1
};
matrix2[] = {
1, 0, 0, 0,
0, 1, 0, 0,
tan(a), 0, 1, 0,
0, 0, 0, 1
};
matrix3[] = {
1, tan(a), 0, 0,
0, 1, 0, 0,
0, 0, 1, 0,
0, 0, 0, 1
};
matrix4[] = {
1, 0, 0, 0,
0, 1, 0, 0,
0, tan(a), 1, 0,
0, 0, 0, 1
};
matrix5[] = {
1, 0, tan(a), 0,
0, 1, 0, 0,
0, 0, 1, 0,
0, 0, 0, 1
};
matrix6[] = {
1, 0, 0, 0,
0, 1, tan(a), 0,
0, 0, 1, 0,
0, 0, 0, 1
};

Resources