Moving the second column to first column using awk - bash

I would like do the following using awk:
Example of my input data with four columns and a number of rows:
10 20 30 40
50 30 60 80
90 12 40 20
Desired output:
10 20
30 40
>
50 30
60 80
>
90 12
40 20


Try something like:
awk '{print $1 " " $2 "\n" $3 " " $4 "\n>"}'
output is:
10 20
30 40
>
50 30
60 80
>
90 12
40 20
>
Sorry about the trailing >


Try awk '{ print $1" "$2"\n" $3" "$4"\n>" }'


GNU sed
sed -r 's/(\S+\s+){2}/&\n/;$!a >' file
10 20
30 40
>
50 30
60 80
>
90 12
40 20
Notice the last line, no unwanted trailing >.


I add a pure bash solution (w/o calling any external utilities):
Script:
while read a b c d; do echo -e "$a $b\n$c $d\n>"; done <infile
Or without the explicit loop:
printf "%s %s\n%s %s\n>\n" $(<infile)
Input:
cat >infile <<XXX
10 20 30 40
50 30 60 80
90 12 40 20
XXX
Output:
10 20
30 40
>
50 30
60 80
>
90 12
40 20
>

Related

Delete repeated rows keeping one closer to another file using awk

I have two files
$cat file1.txt
0105 20 20 95 50
0106 20 20 95 50
0110 20 20 88 60
0110 20 20 88 65
0115 20 20 82 70
0115 20 20 82 70
0115 20 20 82 75
If you see the file1.txt, there are repeated values in column-1, which are 0110 and 0115.
So I would like to keep one row only based on the column-5 values, which are closer to corresponding values in a reference file (file2.txt). Here closer means the equal or the nearest value in file2.txt. I don't want to change any value in file1.txt, but just to select one row.
$cat file2.txt
0105 20 20 95 50
0106 20 20 95 50
0107 20 20 95 52
0110 20 20 88 65 34
0112 20 20 82 80 23
0113 20 20 82 85 32
0114 20 20 82 70 23
0115 20 20 82 72
0118 20 20 87 79
0120 20 20 83 79
So if we compare the two files, we must keep 0110 20 20 88 65, as the column-5 entry (i.e. 65) in file1.txt is closer that in reference file (i.e. 65 in file2.txt) and delete the other repeated rows. Similarly we must keep 0115 20 20 82 70 because 70 is closer to 72 and delete other two rows starting with 0115
Desire output:
0105 20 20 95 50
0106 20 20 95 50
0110 20 20 88 65
0115 20 20 82 70
I am trying with the following script, but not getting my desire result.
awk 'FNR==NR { a[$5]; next } $5 in a ' file1.txt file2.txt > test.txt
awk '{a[NR]=$1""$2} a[NR]!=a[NR-1]{print}' test.txt
My fortran program algorithm is:
# check each entries in column-1 in file1.txt with next rows if they are same or not
i.e. for i=1,i++ do # Here i is ith row
for j=1,j++ do
if a[i,j] != a[i+1,j]; then print the whole row as it is,
else
# find the row b[i,j] in file2.txt starting with a[i,j]
# and compare the 5th column i.e. b[i,j+5] with all a[i,j+5] starting with a[i,j] in file1.txt
# and take the differences to find closest one
e.g. if we have 3 rows starting with same entry, then
we select the a[i,j] in which diff(b[i,j+5],a[i,j+5]) is minumum i=1,2,3

awk 'BEGIN {
while ((getline line < "file2.txt")>0) {
split(line, f);
file2[f[1]] = line;
}
}
{
if (!($1 in result)) result[$1] = $0;
split(result[$1], a);
split(file2[$1], f);
if (abs(f[5]-$5) < abs(f[5]-a[5])) result[$1] = $0;
}
END {
for (i in result) print result[i];
}
function abs(n) {
return (n < 0 ? -n : n);
}' file1.txt | sort

in bash split a variable into an array with each array value containing n values from the list

So i'm issuing a query to mysql and it's returning say 1,000 rows,but each iteration of the program could return a different number of rows. I need to break up (without using a mysql limit) this result set into chunks of 100 rows that i can then programatically iterate through in these 100 row chunks.
So
MySQLOutPut='1 2 3 4 ... 10,000"
I need to turn that into an array that looks like
array[1]="1 2 3 ... 100"
array[2]="101 102 103 ... 200"
etc.
I have no clue how to accomplish this elegantly

Using Charles' data generation:
MySQLOutput=$(seq 1 10000 | tr '\n' ' ')
# the sed command will add a newline after every 100 words
# and the mapfile command will read the lines into an array
mapfile -t MySQLOutSplit < <(
sed -r 's/([^[:blank:]]+ ){100}/&\n/g; $s/\n$//' <<< "$MySQLOutput"
)
echo "${#MySQLOutSplit[#]}"
# 100
echo "${MySQLOutSplit[0]}"
# 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
echo "${MySQLOutSplit[99]}"
# 9901 9902 9903 9904 9905 9906 9907 9908 9909 9910 9911 9912 9913 9914 9915 9916 9917 9918 9919 9920 9921 9922 9923 9924 9925 9926 9927 9928 9929 9930 9931 9932 9933 9934 9935 9936 9937 9938 9939 9940 9941 9942 9943 9944 9945 9946 9947 9948 9949 9950 9951 9952 9953 9954 9955 9956 9957 9958 9959 9960 9961 9962 9963 9964 9965 9966 9967 9968 9969 9970 9971 9972 9973 9974 9975 9976 9977 9978 9979 9980 9981 9982 9983 9984 9985 9986 9987 9988 9989 9990 9991 9992 9993 9994 9995 9996 9997 9998 9999 10000

Something like this:
# generate content
MySQLOutput=$(seq 1 10000 | tr '\n' ' ') # seq is awful, don't use in real life
# split into a large array, each item stored individually
read -r -a MySQLoutArr <<<"$MySQLOutput"
# add each batch of 100 items into a new array entry
batchSize=100
MySQLoutSplit=( )
for ((i=0; i<${#MySQLoutArr[#]}; i+=batchSize)); do
MySQLoutSplit+=( "${MySQLoutArr[*]:i:batchSize}" )
done
To explain some of the finer points:
read -r -a foo reads contents into an array named foo, split on IFS, up to the next character specified by read -d (none given here, thus reading only a single line). If you wanted each line to be a new array entry, consider IFS=$'\n' read -r -d '' -a foo, which will read each line into an array, terminated at the first NUL in the input stream.
"${foo[*]:i:batchSize}" expands to a list of items in array foo, starting at index i, and taking the next batchSize items, concatenated into a single string with the first character in $IFS used as a separator.

convert comma separated list in text file into columns in bash

I've managed to extract data (from an html page) that goes into a table, and I've isolated the columns of said table into a text file that contains the lines below:
[30,30,32,35,34,43,52,68,88,97,105,107,107,105,101,93,88,80,69,55],
[28,6,6,50,58,56,64,87,99,110,116,119,120,117,114,113,103,82,6,47],
[-7,,,43,71,30,23,28,13,13,10,11,12,11,13,22,17,3,,-15,-20,,38,71],
[0,,,3,5,1.5,1,1.5,0.5,0.5,0,0.5,0.5,0.5,0.5,1,0.5,0,-0.5,-0.5,2.5]
Each bracketed list of numbers represents a column. What I'd like to do is turn these lists into actual columns that I can work with in different data formats. I'd also like to be sure to include that blank parts of these lists too (i.e., "[,,,]")
This is basically what I'm trying to accomplish:
30 28 -7 0
30 6
32 6
35 50 43 3
34 58 71 5
43 56 30 1.5
52 64 23 1
. . . .
. . . .
. . . .
I'm parsing data from a web page, and ultimately planning to make the process as automated as possible so I can easily work with the data after I output it to a nice format.
Anyone know how to do this, have any suggestions, or thoughts on scripting this?

Since you have your lists in python, just do it in python:
l=[["30", "30", "32"], ["28","6","6"], ["-7", "", ""], ["0", "", ""]]
for i in zip(*l):
print "\t".join(i)
produces
30 28 -7 0
30 6
32 6

awk based solution:
awk -F, '{gsub(/\[|\]/, ""); for (i=1; i<=NF; i++) a[i]=a[i] ? a[i] OFS $i: $i}
END {for (i=1; i<=NF; i++) print a[i]}' file
30 28 -7 0
30 6
32 6
35 50 43 3
34 58 71 5
43 56 30 1.5
52 64 23 1
..........
..........

Another solution, but it works only for file with 4 lines:
$ paste \
<(sed -n '1{s,\[,,g;s,\],,g;s|,|\n|g;p}' t) \
<(sed -n '2{s,\[,,g;s,\],,g;s|,|\n|g;p}' t) \
<(sed -n '3{s,\[,,g;s,\],,g;s|,|\n|g;p}' t) \
<(sed -n '4{s,\[,,g;s,\],,g;s|,|\n|g;p}' t)
30 28 -7 0
30 6
32 6
35 50 43 3
34 58 71 5
43 56 30 1.5
52 64 23 1
68 87 28 1.5
88 99 13 0.5
97 110 13 0.5
105 116 10 0
107 119 11 0.5
107 120 12 0.5
105 117 11 0.5
101 114 13 0.5
93 113 22 1
88 103 17 0.5
80 82 3 0
69 6 -0.5
55 47 -15 -0.5
-20 2.5
38
71
Updated: or another version with preprocessing:
$ sed 's|\[||;s|\][,]\?||' t >t2
$ paste \
<(sed -n '1{s|,|\n|g;p}' t2) \
<(sed -n '2{s|,|\n|g;p}' t2) \
<(sed -n '3{s|,|\n|g;p}' t2) \
<(sed -n '4{s|,|\n|g;p}' t2)

If a file named data contains the data given in the problem (exactly as defined above), then the following bash command line will produce the output requested:
$ sed -e 's/\[//' -e 's/\]//' -e 's/,/ /g' <data | rs -T
Example:
cat data
[30,30,32,35,34,43,52,68,88,97,105,107,107,105,101,93,88,80,69,55],
[28,6,6,50,58,56,64,87,99,110,116,119,120,117,114,113,103,82,6,47],
[-7,,,43,71,30,23,28,13,13,10,11,12,11,13,22,17,3,,-15,-20,,38,71],
[0,,,3,5,1.5,1,1.5,0.5,0.5,0,0.5,0.5,0.5,0.5,1,0.5,0,-0.5,-0.5,2.5]
$ sed -e 's/[//' -e 's/]//' -e 's/,/ /g' <data | rs -T
30 28 -7 0
30 6 43 3
32 6 71 5
35 50 30 1.5
34 58 23 1
43 56 28 1.5
52 64 13 0.5
68 87 13 0.5
88 99 10 0
97 110 11 0.5
105 116 12 0.5
107 119 11 0.5
107 120 13 0.5
105 117 22 1
101 114 17 0.5
93 113 3 0
88 103 -15 -0.5
80 82 -20 -0.5
69 6 38 2.5
55 47 71

Extract Maximum and minimum value using awk

How to find maximum and minimum value from the below table using awk command.
20 90 60 30
55 75 80 85
10 15 99 95
55 95 70 20
9 35 85 75
I want the output like max value=99 and min=9

with gnu awk:
awk '{for(x=1;x<=NF;x++)a[++y]=$x}END{c=asort(a);print "min:",a[1];print "max:",a[c]}'
output:
min: 9
max: 99
without awk:
xargs -n1|sort -n|head or tail -1
e.g.
min:
kent$ echo "20 90 60 30
55 75 80 85
10 15 99 95
55 95 70 20
9 35 85 75"|xargs -n1|sort -n|head -1
9
max:
kent$ echo "20 90 60 30
55 75 80 85
10 15 99 95
55 95 70 20
9 35 85 75"|xargs -n1|sort -n|tail -1
99
you can of course xargs -n1|sort -n then pipe to awk to pick first and last and print in one shot.

If you have GNU awk:
# using array
awk '{x[NR]=$1}END{asort(x);print "max="x[NR],"min="x[1]}' RS=' +|\n' file
max=99 min=9
# No array
awk 'NR==1{m=n=$1}{$1>m?m=$1:m;$1<n?n=$1:n}END{print "max="m,"min="n}' RS=' +|\n' file
max=99 min=9

awk '
NR == 1 { min=max=$1 }
{
for (i=1;i<=NF;i++) {
min = (min < $i ? min : $i)
max = (max > $i ? max : $i)
}
}
END {
printf "min value = %s\n", (min == "" ? "NaN" : min)
printf "max value = %s\n", (max == "" ? "NaN" : max)
}
' file
The test resulting in "NaN" is to accommodate empty input files.

Using bash to read elements on a diagonal on a matrix and redirecting it to another file

So, currently i have created a code to do this as shown below. This code works and does what it is supposed to do after I echo the variables:
a=`awk 'NR==2 {print $1}' $coor`
b=`awk 'NR==3 {print $2}' $coor`
c=`awK 'NR==4 {print $3}' $coor`
....but i have to do this for many more lines and i want a more general expression. So I have attempted to create a loop shown below. Syntax wise i don't think anything is wrong with the code, but it is not outputting anything to the file "Cmain".
I was wondering if anyone could help me, I'm kinda new at scripting.
If it helps any, I can also post what i am trying to read.
for (( i=1; i <= 4 ; i++ )); do
for (( j=0; j <= 3 ; j++ )); do
B="`grep -n "cell" "$coor" | awk 'NR=="$i" {print $j}'`"
done
done
echo "$B" >> Cmain

You can replace your lines of awk with this one:
awk '{ for (i=1; i<=NF; i++) if (NR >= 2 && NR == i) print $(i - 1) }' file.txt
Tested input:
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
51 52 53 54 55 56 57 58 59 60
61 62 63 64 65 66 67 68 69 70
71 72 73 74 75 76 77 78 79 80
Output:
11
22
33
44
55
66
77

awk 'BEGIN {f=1} {print $f; f=f+1}' infile > outfile

An alternative using sed and coreutils, assuming space separated input is in infile:
n=$(wc -l infile | cut -d' ' -f1)
for i in $(seq 1 $n); do
sed -n "${i} {p; q}" infile | cut -d' ' -f$i
done

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