How can I render a template in Go without any variables? - go

I've loaded a template file into memory with the following code:
t := template.New("master")
tpl, err := t.ParseFiles("templates/index.html")
Now I want to draw that template into a string, so my index.html is pretty empty:
{{define "master"}}
Hello World
{{end}}
I'm just starting out, so I don't have any data yet. Is there a way I can convert the Template object into a string without data?

If your template doesn't (yet) use any variables, you can just pass any value as data to render the template. So, to render the template to stdout, you could for example use:
tpl.Execute(os.Stdout, nil)
If you really want to render the template to a string, you can use a bytes.Buffer as an intermediary:
var buf bytes.Buffer
tpl.Execute(&buf, nil)
str := buf.String()

This is impossible in Go, by design - if you don't have data, the Template package is unnecessary overhead.
If you have no data, just read the file using the io package, instead of using templates.

Related

Embedding a static YAML file in a binary using Go 1.15 [duplicate]

I'm working on a small web application in Go that's meant to be used as a tool on a developer's machine to help debug their applications/web services. The interface to the program is a web page that includes not only the HTML but some JavaScript (for functionality), images, and CSS (for styling). I'm planning on open-sourcing this application, so users should be able to run a Makefile, and all the resources will go where they need to go. However, I'd also like to be able to simply distribute an executable with as few files/dependencies as possible. Is there a good way to bundle the HTML/CSS/JS with the executable, so users only have to download and worry about one file?
Right now, in my app, serving a static file looks a little like this:
// called via http.ListenAndServe
func switchboard(w http.ResponseWriter, r *http.Request) {
// snipped dynamic routing...
// look for static resource
uri := r.URL.RequestURI()
if fp, err := os.Open("static" + uri); err == nil {
defer fp.Close()
staticHandler(w, r, fp)
return
}
// snipped blackhole route
}
So it's pretty simple: if the requested file exists in my static directory, invoke the handler, which simply opens the file and tries to set a good Content-Type before serving. My thought was that there's no reason this needs to be based on the real filesystem: if there were compiled resources, I could simply index them by request URI and serve them as such.
Let me know if there's not a good way to do this or I'm barking up the wrong tree by trying to do this. I just figured the end-user would appreciate as few files as possible to manage.
If there are more appropriate tags than go, please feel free to add them or let me know.
Starting with Go 1.16 the go tool has support for embedding static files directly in the executable binary.
You have to import the embed package, and use the //go:embed directive to mark what files you want to embed and into which variable you want to store them.
3 ways to embed a hello.txt file into the executable:
import "embed"
//go:embed hello.txt
var s string
print(s)
//go:embed hello.txt
var b []byte
print(string(b))
//go:embed hello.txt
var f embed.FS
data, _ := f.ReadFile("hello.txt")
print(string(data))
Using the embed.FS type for the variable you can even include multiple files into a variable that will provide a simple file-system interface:
// content holds our static web server content.
//go:embed image/* template/*
//go:embed html/index.html
var content embed.FS
The net/http has support to serve files from a value of embed.FS using http.FS() like this:
http.Handle("/static/", http.StripPrefix("/static/", http.FileServer(http.FS(content))))
The template packages can also parse templates using text/template.ParseFS(), html/template.ParseFS() functions and text/template.Template.ParseFS(), html/template.Template.ParseFS() methods:
template.ParseFS(content, "*.tmpl")
The following of the answer lists your old options (prior to Go 1.16).
Embedding Text Files
If we're talking about text files, they can easily be embedded in the source code itself. Just use the back quotes to declare the string literal like this:
const html = `
<html>
<body>Example embedded HTML content.</body>
</html>
`
// Sending it:
w.Write([]byte(html)) // w is an io.Writer
Optimization tip:
Since most of the times you will only need to write the resource to an io.Writer, you can also store the result of a []byte conversion:
var html = []byte(`
<html><body>Example...</body></html>
`)
// Sending it:
w.Write(html) // w is an io.Writer
Only thing you have to be careful about is that raw string literals cannot contain the back quote character (`). Raw string literals cannot contain sequences (unlike the interpreted string literals), so if the text you want to embed does contain back quotes, you have to break the raw string literal and concatenate back quotes as interpreted string literals, like in this example:
var html = `<p>This is a back quote followed by a dot: ` + "`" + `.</p>`
Performance is not affected, as these concatenations will be executed by the compiler.
Embedding Binary Files
Storing as a byte slice
For binary files (e.g. images) most compact (regarding the resulting native binary) and most efficient would be to have the content of the file as a []byte in your source code. This can be generated by 3rd party toos/libraries like go-bindata.
If you don't want to use a 3rd party library for this, here's a simple code snippet that reads a binary file, and outputs Go source code that declares a variable of type []byte that will be initialized with the exact content of the file:
imgdata, err := ioutil.ReadFile("someimage.png")
if err != nil {
panic(err)
}
fmt.Print("var imgdata = []byte{")
for i, v := range imgdata {
if i > 0 {
fmt.Print(", ")
}
fmt.Print(v)
}
fmt.Println("}")
Example output if the file would contain bytes from 0 to 16 (try it on the Go Playground):
var imgdata = []byte{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}
Storing as base64 string
If the file is not "too large" (most images/icons qualify), there are other viable options too. You can convert the content of the file to a Base64 string and store that in your source code. On application startup (func init()) or when needed, you can decode it to the original []byte content. Go has nice support for Base64 encoding in the encoding/base64 package.
Converting a (binary) file to base64 string is as simple as:
data, err := ioutil.ReadFile("someimage.png")
if err != nil {
panic(err)
}
fmt.Println(base64.StdEncoding.EncodeToString(data))
Store the result base64 string in your source code, e.g. as a const.
Decoding it is just one function call:
const imgBase64 = "<insert base64 string here>"
data, err := base64.StdEncoding.DecodeString(imgBase64) // data is of type []byte
Storing as quoted string
More efficient than storing as base64, but may be longer in source code is storing the quoted string literal of the binary data. We can obtain the quoted form of any string using the strconv.Quote() function:
data, err := ioutil.ReadFile("someimage.png")
if err != nil {
panic(err)
}
fmt.Println(strconv.Quote(string(data))
For binary data containing values from 0 up to 64 this is how the output would look like (try it on the Go Playground):
"\x00\x01\x02\x03\x04\x05\x06\a\b\t\n\v\f\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !\"#$%&'()*+,-./0123456789:;<=>?"
(Note that strconv.Quote() appends and prepends a quotation mark to it.)
You can directly use this quoted string in your source code, for example:
const imgdata = "\x00\x01\x02\x03\x04\x05\x06\a\b\t\n\v\f\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !\"#$%&'()*+,-./0123456789:;<=>?"
It is ready to use, no need to decode it; the unquoting is done by the Go compiler, at compile time.
You may also store it as a byte slice should you need it like that:
var imgdata = []byte("\x00\x01\x02\x03\x04\x05\x06\a\b\t\n\v\f\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !\"#$%&'()*+,-./0123456789:;<=>?")
The go-bindata package looks like it might be what you're interested in.
https://github.com/go-bindata/go-bindata
It will allow you to convert any static file into a function call that can be embedded in your code and will return a byte slice of the file content when called.
Bundle React application
For example, you have a build output from react like the following:
build/favicon.ico
build/index.html
build/asset-manifest.json
build/static/css/**
build/static/js/**
build/manifest.json
When you use go:embed like this, it will serve the contents as http://localhost:port/build/index.html which is not what we want (unexpected /build).
//go:embed build/*
var static embed.FS
// ...
http.Handle("/", http.FileServer(http.FS(static)))
In fact, we will need to take one more step to make it works as expected by using fs.Sub:
package main
import (
"embed"
"io/fs"
"log"
"net/http"
)
//go:embed build/*
var static embed.FS
func main() {
contentStatic, _ := fs.Sub(static, "build")
http.Handle("/", http.FileServer(http.FS(contentStatic)))
log.Fatal(http.ListenAndServe("localhost:8080", nil))
}
Now, http://localhost:8080 should serve your web application as expected.
Credit to Amit Mittal.
Note: go:embed requires go 1.16 or higher.
also there is some exotic way - I use maven plugin to build GoLang projects and it allows to use JCP preprocessor to embed binary blocks and text files into sources. In the case code just look like line below (and some example can be found here)
var imageArray = []uint8{/*$binfile("./image.png","uint8[]")$*/}
As a popular alternative to go-bindata mentioned in another answer, mjibson/esc also embeds arbitrary files, but handles directory trees particularly conveniently.

escape template in range

I want to print user list like: <#user1> <#user2>, this is an internal format in my company internal, but the golang template always escape the < to <. My code:
tpl, _ := template.New("text").Parse(`{{range .Users}} <#{{.}}> {{end}}`)
var buffer bytes.Buffer
tpl.Execute(&buffer, struct {
Users []string
}{
Users: []string{"user1", "user2"},
})
fmt.Println(buffer.String())
expect:
<#user1> <#user2>
output:
<#user1> <#user2>
How to fix this?
If you want to do so, use text/template. Here's a part of documentation for better understanding each:
Godoc: html/template:
This package wraps package text/template so you can share its template API to parse and execute HTML templates safely.
tmpl, err := template.New("name").Parse(...)
// Error checking elided
err = tmpl.Execute(out, data)
If successful, tmpl will now be injection-safe. Otherwise, err is an error defined in the docs for ErrorCode.
HTML templates treat data values as plain text which should be encoded so they can be safely embedded in an HTML document. The escaping is contextual, so actions can appear within JavaScript, CSS, and URI contexts.
The security model used by this package assumes that template authors are trusted, while Execute's data parameter is not. More details are provided below.
Example
import "text/template"
...
t, err := template.New("foo").Parse(`{{define "T"}}Hello, {{.}}!{{end}}`)
err = t.ExecuteTemplate(out, "T", "<script>alert('you have been pwned')</script>")
produces
Hello, <script>alert('you have been pwned')</script>!
but the contextual autoescaping in html/template
import "html/template"
...
t, err := template.New("foo").Parse(`{{define "T"}}Hello, {{.}}!{{end}}`)
err = t.ExecuteTemplate(out, "T", "<script>alert('you have been pwned')</script>")
produces safe, escaped HTML output
Hello, <script>alert('you have been pwned')</script>!

How can I override a template block with an empty template?

Using text/html I define a block in my base template, containing default content. In some situations I would like this block to be empty, so I thought I could just re-define its name and make it contain nothing like:
{{ block "something" . }}
<h1>Default content</h1>
{{ end }}
// later in a place that does not want "something" ...
{{ define "something" }}{{ end }}
Somehow Go seems to think that this definition is "Zero" and will still render the default content unless I put any non-whitespace content into the definition.
I found this issue on the Golang repo which describes the very same thing nicely in a Playground example:
package main
import (
"fmt"
"os"
"runtime"
"text/template"
)
func main() {
fmt.Printf("Version: %q\n", runtime.Version())
t, err := template.New("master").Parse(`{{block "area51" .}}Original Content{{end}}`)
if err != nil {
panic(err)
}
t, err = t.New("other_template").Parse(`{{define "area51"}}{{end}}`)
if err != nil {
panic(err)
}
fmt.Printf("Output:\n")
if err := t.ExecuteTemplate(os.Stdout, "master", nil); err != nil {
panic(err)
}
fmt.Printf("\n")
}
Weirdly, the issue mention it is fixed (and landed in 1.8.1 if I understand it correctly), but it does not work for me, neither with 1.8.1+ nor 1.9.
Is this a bug in Golang or is the approach flawed? Do I need to do anything differently in order to re-define the block so that it renders empty?
This is the expected behavior. This is documented at Template.Parse():
Templates can be redefined in successive calls to Parse, before the first use of Execute on t or any associated template. A template definition with a body containing only white space and comments is considered empty and will not replace an existing template's body. This allows using Parse to add new named template definitions without overwriting the main template body.
So you can't "erase" an already defined template (you can't replace its content to be empty).
If you "conditionally" need it, then use an {{if}} action to decide if the template is to be called. Alternatively you may put an {{if}} inside the template, and the template itself may choose not to render anything. In this case you have to make sure to pass the proper argument that controls what the template will render.
P.S. If you're working with HTML templates, you should always use html/template instead of text/template, as the former provides the same interface as package text/template but also provides contextual escaping to generate HTML output safe against code injection.

Go template name

In the html/template (and text/template) packages, template.New has the following signature:
func New(name string) *Template
What exactly is the name used for? I've scanned the docs (and a bit of source), but to no avail. I just instantiate all of my templates with an empty string and it doesn't seem to make a difference. Why should I bother with a name?
Even for naming templates, the two seem equivalent:
template.Must(template.New("").Parse(`{{ define "body" }}Body{{ end }}`))
template.Must(template.New("body").Parse(`Body`))
https://play.golang.org/p/wKzCHdLf2S
The name of the template–unsurprisingly–is to name the template.
What is it good for? As long as you don't want to refer to the template, it doesn't really matter. But if you want to refer to it, then yes, you refer to it by its name.
When would you want to refer to it? When you want to include a template in another e.g. using the {{template}} action, or when you want to execute a specific template using Template.ExecuteTemplate().
So far so good, but there's still a missing key point. This is not unambiguous / trivial: a template.Template value is "the representation of a parsed template". But the wording here is a little "imperfect". A template.Template value may be (and usually is) a collection of multiple, associated templates. template.Template has an unexported field:
tmpl map[string]*Template // Map from name to defined templates.
This tmpl field holds all other associated templates, templates that are visible to the template, and which can be referred to–yes–by their names.
When you parse multiple templates at once, using Template.ParseFiles() or Template.ParseGlob(), then the templates will be named by the file names, and they will be associated automatically (the above mentioned functions return a single template.Template value, which holds all the parsed templates, associated). Doc of Template.ParseFiles() is clear on this:
ParseFiles creates a new Template and parses the template definitions from the named files. The returned template's name will have the base name and parsed contents of the first file. [...]
When parsing multiple files with the same name in different directories, the last one mentioned will be the one that results. For instance, ParseFiles("a/foo", "b/foo") stores "b/foo" as the template named "foo", while "a/foo" is unavailable.
The template name can come from multiple places:
it can come from the file name (as seen above)
it can be specified explicitly (if defined using the {{define "somename"}} or {{block "somename"}} actions),
or it may be defined as an argument passed to template.New() (function) or Template.New() (method).
Let's see some examples:
func main() {
t := template.Must(template.New("one").Parse(t1src))
template.Must(t.New("other").Parse(t2src))
// error checks omitted for brevity
// Executes default, "one":
t.Execute(os.Stdout, nil)
// Executes explicit, "one":
t.ExecuteTemplate(os.Stdout, "one", nil)
// Executes explicit, "other":
t.ExecuteTemplate(os.Stdout, "other", nil)
}
const t1src = `I'm some template.
`
const t2src = `I'm some OTHER template.
`
Output (try it on the Go Playground):
I'm some template.
I'm some template.
I'm some OTHER template.
If you now go ahead, and change the first 2 lines to this:
t := template.Must(template.New("one").Parse(t1src))
t = template.Must(t.New("other").Parse(t2src))
Then what happens here is that we assigned a new template.Template value to t, which was the result of parsing t2src, so that will be the default, but still both templates can be "reached" from it as they are associated. The output changes to this (try it on the Go Playground):
I'm some OTHER template.
I'm some template.
I'm some OTHER template.
Calling template.New() (function) creates a new template, associated to none. When calling Template.New() (method), the returned template will be associated with (all) the template(s) the method is called on.
Now let's see some examples regarding "embedded" templates.
func main() {
t := template.Must(template.New("one").Parse(t1src))
template.Must(t.New("other").Parse(t2src))
template.Must(t.New("third").Parse(t3src))
t.Execute(os.Stdout, nil)
t.ExecuteTemplate(os.Stdout, "one", nil)
t.ExecuteTemplate(os.Stdout, "other", nil)
t.ExecuteTemplate(os.Stdout, "embedded", nil)
t.ExecuteTemplate(os.Stdout, "third", nil)
}
const t1src = `I'm some template. {{block "embedded" .}}I'm embedded in "one".
{{end}}`
const t2src = `I'm some OTHER template.
`
const t3src = `I'm the 3rd, including everything from "one": {{template "one"}}
`
Output (try it on the Go Playground):
I'm some template. I'm embedded in "one".
I'm some template. I'm embedded in "one".
I'm some OTHER template.
I'm embedded in "one".
I'm the 3rd, including everything from "one": I'm some template. I'm embedded in "one".
It should be obvious now what the role of the template name is, and where it comes from.
It is used to render associated templates.
For instance:
tmpl := template.Must(template.New("body").Parse(`
{{ define "body" }}
Body
{{ end }}
`))
tmpl = template.Must(tmpl.New("base").Parse(`
Start of base template
{{ template "body" }}
End of base template
`))
tmpl = template.Must(tmpl.New("baz").Parse(`
Start of baz template
{{ template "body" }}
End of baz template
`))
tmpl.ExecuteTemplate(os.Stdout, "base", nil)
tmpl.ExecuteTemplate(os.Stdout, "baz", nil)
Play Example
Output:
Start of base template
Body
End of base template
Start of baz template
Body
End of baz template
tmpl.ExecuteTemplate(os.Stdout, "base", nil) will render the template using the "base" template
tmpl.ExecuteTemplate(os.Stdout, "baz", nil) will render the template using the "baz" template
If you don't need the name, you can just use the new builtin with
template.Template:
package main
import (
"os"
"text/template"
)
func main() {
t, err := new(template.Template).Parse("hello {{.}}\n")
if err != nil {
panic(err)
}
t.Execute(os.Stdout, "world")
}

What's the best way to bundle static resources in a Go program?

I'm working on a small web application in Go that's meant to be used as a tool on a developer's machine to help debug their applications/web services. The interface to the program is a web page that includes not only the HTML but some JavaScript (for functionality), images, and CSS (for styling). I'm planning on open-sourcing this application, so users should be able to run a Makefile, and all the resources will go where they need to go. However, I'd also like to be able to simply distribute an executable with as few files/dependencies as possible. Is there a good way to bundle the HTML/CSS/JS with the executable, so users only have to download and worry about one file?
Right now, in my app, serving a static file looks a little like this:
// called via http.ListenAndServe
func switchboard(w http.ResponseWriter, r *http.Request) {
// snipped dynamic routing...
// look for static resource
uri := r.URL.RequestURI()
if fp, err := os.Open("static" + uri); err == nil {
defer fp.Close()
staticHandler(w, r, fp)
return
}
// snipped blackhole route
}
So it's pretty simple: if the requested file exists in my static directory, invoke the handler, which simply opens the file and tries to set a good Content-Type before serving. My thought was that there's no reason this needs to be based on the real filesystem: if there were compiled resources, I could simply index them by request URI and serve them as such.
Let me know if there's not a good way to do this or I'm barking up the wrong tree by trying to do this. I just figured the end-user would appreciate as few files as possible to manage.
If there are more appropriate tags than go, please feel free to add them or let me know.
Starting with Go 1.16 the go tool has support for embedding static files directly in the executable binary.
You have to import the embed package, and use the //go:embed directive to mark what files you want to embed and into which variable you want to store them.
3 ways to embed a hello.txt file into the executable:
import "embed"
//go:embed hello.txt
var s string
print(s)
//go:embed hello.txt
var b []byte
print(string(b))
//go:embed hello.txt
var f embed.FS
data, _ := f.ReadFile("hello.txt")
print(string(data))
Using the embed.FS type for the variable you can even include multiple files into a variable that will provide a simple file-system interface:
// content holds our static web server content.
//go:embed image/* template/*
//go:embed html/index.html
var content embed.FS
The net/http has support to serve files from a value of embed.FS using http.FS() like this:
http.Handle("/static/", http.StripPrefix("/static/", http.FileServer(http.FS(content))))
The template packages can also parse templates using text/template.ParseFS(), html/template.ParseFS() functions and text/template.Template.ParseFS(), html/template.Template.ParseFS() methods:
template.ParseFS(content, "*.tmpl")
The following of the answer lists your old options (prior to Go 1.16).
Embedding Text Files
If we're talking about text files, they can easily be embedded in the source code itself. Just use the back quotes to declare the string literal like this:
const html = `
<html>
<body>Example embedded HTML content.</body>
</html>
`
// Sending it:
w.Write([]byte(html)) // w is an io.Writer
Optimization tip:
Since most of the times you will only need to write the resource to an io.Writer, you can also store the result of a []byte conversion:
var html = []byte(`
<html><body>Example...</body></html>
`)
// Sending it:
w.Write(html) // w is an io.Writer
Only thing you have to be careful about is that raw string literals cannot contain the back quote character (`). Raw string literals cannot contain sequences (unlike the interpreted string literals), so if the text you want to embed does contain back quotes, you have to break the raw string literal and concatenate back quotes as interpreted string literals, like in this example:
var html = `<p>This is a back quote followed by a dot: ` + "`" + `.</p>`
Performance is not affected, as these concatenations will be executed by the compiler.
Embedding Binary Files
Storing as a byte slice
For binary files (e.g. images) most compact (regarding the resulting native binary) and most efficient would be to have the content of the file as a []byte in your source code. This can be generated by 3rd party toos/libraries like go-bindata.
If you don't want to use a 3rd party library for this, here's a simple code snippet that reads a binary file, and outputs Go source code that declares a variable of type []byte that will be initialized with the exact content of the file:
imgdata, err := ioutil.ReadFile("someimage.png")
if err != nil {
panic(err)
}
fmt.Print("var imgdata = []byte{")
for i, v := range imgdata {
if i > 0 {
fmt.Print(", ")
}
fmt.Print(v)
}
fmt.Println("}")
Example output if the file would contain bytes from 0 to 16 (try it on the Go Playground):
var imgdata = []byte{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}
Storing as base64 string
If the file is not "too large" (most images/icons qualify), there are other viable options too. You can convert the content of the file to a Base64 string and store that in your source code. On application startup (func init()) or when needed, you can decode it to the original []byte content. Go has nice support for Base64 encoding in the encoding/base64 package.
Converting a (binary) file to base64 string is as simple as:
data, err := ioutil.ReadFile("someimage.png")
if err != nil {
panic(err)
}
fmt.Println(base64.StdEncoding.EncodeToString(data))
Store the result base64 string in your source code, e.g. as a const.
Decoding it is just one function call:
const imgBase64 = "<insert base64 string here>"
data, err := base64.StdEncoding.DecodeString(imgBase64) // data is of type []byte
Storing as quoted string
More efficient than storing as base64, but may be longer in source code is storing the quoted string literal of the binary data. We can obtain the quoted form of any string using the strconv.Quote() function:
data, err := ioutil.ReadFile("someimage.png")
if err != nil {
panic(err)
}
fmt.Println(strconv.Quote(string(data))
For binary data containing values from 0 up to 64 this is how the output would look like (try it on the Go Playground):
"\x00\x01\x02\x03\x04\x05\x06\a\b\t\n\v\f\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !\"#$%&'()*+,-./0123456789:;<=>?"
(Note that strconv.Quote() appends and prepends a quotation mark to it.)
You can directly use this quoted string in your source code, for example:
const imgdata = "\x00\x01\x02\x03\x04\x05\x06\a\b\t\n\v\f\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !\"#$%&'()*+,-./0123456789:;<=>?"
It is ready to use, no need to decode it; the unquoting is done by the Go compiler, at compile time.
You may also store it as a byte slice should you need it like that:
var imgdata = []byte("\x00\x01\x02\x03\x04\x05\x06\a\b\t\n\v\f\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !\"#$%&'()*+,-./0123456789:;<=>?")
The go-bindata package looks like it might be what you're interested in.
https://github.com/go-bindata/go-bindata
It will allow you to convert any static file into a function call that can be embedded in your code and will return a byte slice of the file content when called.
Bundle React application
For example, you have a build output from react like the following:
build/favicon.ico
build/index.html
build/asset-manifest.json
build/static/css/**
build/static/js/**
build/manifest.json
When you use go:embed like this, it will serve the contents as http://localhost:port/build/index.html which is not what we want (unexpected /build).
//go:embed build/*
var static embed.FS
// ...
http.Handle("/", http.FileServer(http.FS(static)))
In fact, we will need to take one more step to make it works as expected by using fs.Sub:
package main
import (
"embed"
"io/fs"
"log"
"net/http"
)
//go:embed build/*
var static embed.FS
func main() {
contentStatic, _ := fs.Sub(static, "build")
http.Handle("/", http.FileServer(http.FS(contentStatic)))
log.Fatal(http.ListenAndServe("localhost:8080", nil))
}
Now, http://localhost:8080 should serve your web application as expected.
Credit to Amit Mittal.
Note: go:embed requires go 1.16 or higher.
also there is some exotic way - I use maven plugin to build GoLang projects and it allows to use JCP preprocessor to embed binary blocks and text files into sources. In the case code just look like line below (and some example can be found here)
var imageArray = []uint8{/*$binfile("./image.png","uint8[]")$*/}
As a popular alternative to go-bindata mentioned in another answer, mjibson/esc also embeds arbitrary files, but handles directory trees particularly conveniently.

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