How to locate path of generated wsdl in Spring-ws - spring

Question

I have generated webservice using spring-ws. I have deployed my application in tomcat and deployed without any error. I am not able to find the path for WSDL. Please help me how to form path for wsdl.
My web.xml:
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>listener><servlet><servlet-name>spring-ws</servlet-name><servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class></servlet><servlet-mapping><servlet-name>sprig-ws</servlet-name><url-pattern>/</url-pattern></servlet-mapping> <context-param><param-name>contextConfigLocation</param-name><param-value>/WEB-INF/spring-ws--servlet.xml</param-value></context-param>
spring-ws-servlet.xml
<bean class="org.springframework.ws.server.endpoint.adapter.GenericMarshallingMethodEndpointAdapter">
<constructor-arg ref="marshaller" />
</bean>
<bean id="marshaller"
class="org.springframework.oxm.xmlbeans.XmlBeansMarshaller">
</bean>
<bean id="loginEndpoint" class="com.cloudexult.endpoint.LoginEndpoint">
</bean>
<sws:dynamic-wsdl id="loginmanager" portTypeName="LoginService" locationUri="/loginService/"
targetNamespace="http://www.example.org/Login/definitions">
<sws:xsd location="/WEB-INF/schema/Login.xsd"/>
</sws:dynamic-wsdl>

Answer 1

Your wsdl should be accessible through:
http://<servername>:<port>/<context-path>/loginService.wsdl
Can you try this and tell us if it doesn't work?

Answer 2

If you are really stuck, enabling log4j to print spring debug logs will help you.
Enable debug logging of spring by following in log4j.properties :
log4j.category.org.springframework=DEBUG
Once that is done, restart your container, look for following in the DEBUG log :
20:51:16,718 DEBUG main http.MessageDispatcherServlet:469 - Published [org.springframework.ws.wsdl.wsdl11.DefaultWsdl11Definition#61bf8785] as wsdl11Definition.wsdl
Above is just an example, however the last component of the log, will give you the URI of your WSDL.