Parameter in routes - laravel

I have the following route
Route::get('compare/{user_id}/{compare_id}', 'CompareController#index');
Since only the owner or members of the working group should have access to this site, I need to filter it. But how can I add the user_id and the compare_id in to the filter?

There's a couple of ways you could do this. Firstly you could just use Request::segment() to fetch each of the required segments of the URI.
A second and better solution is to get the current route with Route::getCurrentRoute().
Route::filter('example', function()
{
$route = Route::getCurrentRoute();
$user_id = $route->getParameter('user_id');
$compare_id = $route->getParameter('compare_id');
});

Related

How do I pass a value in my Route to the Controller to be used in the View in Laravel?

I have 2 entities called Match and Roster.
My Match routes are like this
http://localhost:8888/app/public/matches (index)
http://localhost:8888/app/public/matches/14 (show)
In order to view/create the teams for each specific match I added the routes for the match roster like this:
Route::get('/matches/'.'{id}'.'/roster/', [App\Http\Controllers\RosterController::class, 'index']);
Now I need that {id} i have in my URL to pass it to the Controller here:
public function index()
{
return view('roster.index');
}
I need that for a couple of things. First I need to do a search on the Roster table filtering by a column with that value, so I can display only the players that belong to that match.
Second, I need to pass it on to the view so I can use it on my store and update forms. I want to add or remove players from the roster from that same index view.
How can I do that?
#1 You can get the route parameter defined on ur routes via request()->route('parameter_name').
public function index()
{
// get {id} from the route (/matches/{id}/roster)
$id = request()->route('id');
}
#2 You can pass the data object via using return view(file_name, object)
public function index()
{
// get {id} from the route (/matches/{id}/roster)
$id = request()->route('id');
// query what u want to show
// dunno ur models specific things, so just simple example.
$rosters = Roster::where('match_id', '=', $id);
// return view & data
return view('roster.index', $rosters);
}
#3 It can be done not only index but also others (create, store, edit, update)
In addition, STRONGLY RECOMMEND learn Official Tutorial with simple example first.
Like a Blog, Board, etc..
You need to know essentials to build Laravel App.
Most of the time, I prefer named routes.
Route::get('{bundle}/edit', [BundleController::class, 'edit'])->name('bundle.edit');
In controller
public function edit(Bundle $bundle): Response
{
// do your magic here
}
You can call the route by,
route('bundle.edit', $bundle);

Laravel 8 - friendly url that call multiple controllers depending on match (products, categories, pages) - How to design it?

i would like to build a route that catch clean seo friendly url and call correct controller to display page. Examples:
https://mypage.com/some-friendly-url-separated-with-dashes [PageController]
https://mypage.com/some-cool-eletronic-ipod [ProductController]
https://mypage.com/some-furniture-drawers [CategoryController]
So I have in app route:
Route::get('/{friendlyUrl}', 'RouteController#index');
Each friendly url is a unique url(string) so there is no duplicate between pages/products/categories. There is also no pattern between urls - they could be any string used in seo(only text plus dashes/ sometimes params).
Is it wise to build one db table that keeps all urls in on place with info what to call ( url | controller_name | action_name) - as an example.
Another question is - how to call different controllers depending on url used? (for above example -> RouteController catch friendly urls -finds match in db table -> then calls correct controller)
Many thanks for any help.
Have a nice day
Mark
There's two approaches you can take to this.
Proactive:
In web.php
$slugs = Product::pluck('slug');
foreach ($slugs as $slug) {
Route::get($slug, 'ProductController#index');
}
$slugs = Category::pluck('slug');
foreach ($slugs as $slug) {
Route::get($slug, 'CategoryController#index');
}
$slugs = Page::pluck('slug');
foreach ($slugs as $slug) {
Route::get($slug, 'PagesController#index');
}
Then you can determine the product in the appropriate controler via e.g.
$actualItem = Product::where('slug', request()->path())->first();
The downside to this approach is that all routes are registered on every request even if they are not used meaning you hit the database on every request to populate them. Also, routes can't be cached when using this approach.
Reactive:
In this approach you use the fallback route:
In web.php:
Route::fallback(function (Request $request) {
if (Page::where('slug', $request->path())->exists()) {
return app()->call([ PageController::class, 'index' ]);
}
if (Category::where('slug', $request->path())->exists()) {
return app()->call([ CategoryController::class, 'index' ]);
}
if (Product::where('slug', $request->path())->exists()) {
return app()->call([ ProductController::class, 'index' ]);
}
abort(404);
});
You need create a table call slugs.
Then create a unique slug (can be auto generated or specified) for each page, product, category.
slug records also have columns to get Controller and params, ex: type and id
It'd be better if you just use a prefix for each type like this:
https://mypage.com/pages/some-friendly-url-separated-with-dashes [PageController]
https://mypage.com/products/some-cool-eletronic-ipod [ProductController]
https://mypage.com/category/some-furniture-drawers [CategoryController]
Then for achieving this, create three routes like this
Route::get('pages/{friendlyUrl}', 'PageController#index');
Route::get('products/{friendlyUrl}', 'ProductController#index');
Route::get('category/{friendlyUrl}', 'CategoryController#index');
These URLs would be SEO friendly

laravel dynamic route groups using year

I have a site that pulls a lot of data and it is all tied to a specific year. I was trying to think of the best way to add a dynamic route group that included the year so that it would always be showing for the user and that I could use in my models.
Something like www.site.com/2015/dashboard
I can do this using a standard route group, but it requires me to add the route perameters to every method I use.
Is there a better way to use something like this and have the year available to the controller at all times and not have to send it with each route?
Type this in routes.php
$year= Request::segment(1);
Route::group(['prefix'=>$year], function() {
Route::get('dashboard', ['uses' => 'SomeController#someMethod']);
});
And in your controller pick year:
$year = Request::segment(1)

Laravel routing - shorten the urls upto only one URI segment.

It is said that shorter the URL, better the seo (atleast my client believes on it).
Now am creating website similar to watchtown.co.uk in laravel. I need to generate in such a way that the uri should not be more than one segment.
Requirement
I have following urls:
1.Need to change From:
localhost/laravelproj/public/brands/brandname/watches
to
localhost/laravelproj/public/brandname-watches.html
2.Need to change From:
localhost/laravelproj/public/brands/brandname/jewellery
to
localhost/laravelproj/public/brandname-jewellery.html
3.Need to change From:
localhost/laravelproj/public/categories/categoryname/watches
to
localhost/laravelproj/public/categoryname-watches.html
4.Need to change From:
localhost/laravelproj/public/categories/categoryname/jewellery
to
localhost/laravelproj/public/categoryname-jewellery.html
5.Need to change From:
localhost/laravelproj/public/products/productname
to
localhost/laravelproj/public/productname-watches.html
I hope you understood the pattern .
I can see watchtown.co.uk has done exactly the same (or is it any other way ?)
I created this function in controller for brands:
public function showProductListingByBrands($brandSlug) {
$brand = Brand::findBySlug($brandSlug)->first();
$products = "";
if($brand){
$products = $brand->products()->paginate(Misc::getSetting('paginate'));
}
$products = Product::findBySlug($brandSlug);
return View::make('store');
}
Now how do i manipulate it as my requirement? Im really new in laravel.
Thanks in advance.
Just to give you a brief idea.
On your route page
Route::get('/{product_name}/', array(
'as' => 'product_page',
'uses' => 'ProductPage#getProduct'
));
As you see when the user goes to the page like
Example: www.website.com/watch
it will go to the controller ProductPage with the method of getProduct, so the variable {product_name} will be passed on the controller.
Controller
public function getProduct($product_name = false) {
$product = Products::where('product_name', '=', $product_name);
// Do check product existing record
if ($product->count() == 0) {
return Redirect::route('some-page-error')
->with('failure', 'The hell are you doing?');
} else {
$product = $product->first();
return View::make('product_page')
->with('product_name', $product);
}
}
So on method getProduct, the parameter $product_name is watch
So, the method will check if the product exists or not, if not the user will be redirected to 404 page.
If not, it will be redirected to the template that you've made then pass all the product data and display it all there.
But it would be nice if you put the Route into /product/{product_name}, also it would be also good if it's product id instead of product name since product name can get redundant.
So yea.
edits
I don't know what you're trying to do and why it must be .html, but mmm.. Just wanna give you an idea. Well I don't know if my answer is a good way, someone might give better answer than me.

Laravel how to route old urls

I am using Laravel 4.
I have an old url that needs to be routable. It doesn't really matter what it's purpose is but it exists within the paypal systems and will be called regularly but cannot be changed (which is ridiculous I know).
I realise that this isn't the format url's are supposed to take in Laravel, but this is the url that will be called and I need to find a way to route it:
http://domain.com/forum/index.php?app=subscriptions&r_f_g=xxx-paypal
(xxx will be different on every request)
I can't figure out how to route this with laravel, i'd like to route it to the method PaypalController#ipbIpn so i've tried something like this:
Route::post('forum/index.php?app=subscriptions&r_f_g={id}-paypal', 'PaypalController#ipbIpn');
But this doesn't work, infact I can't even get this to work:
Route::post('forum/index.php', 'PaypalController#ipbIpn');
But this will:
Route::post('forum/index', 'PaypalController#ipbIpn');
So the question is how can I route the url, as it is at the top of this question, using Laravel?
For completeness I should say that this will always be a post not a get, but that shouldn't really make any difference to the solution.
Use this:
Route::post('forum/{file}', 'PaypalController#ipbIpn');
And then in the controller, use
public function forum($file) {
$request = Route::getRequest();
$q = (array) $request->query; // GET
$parameters = array();
foreach($q as $key => $pararr) {
$parameters = array_merge($parameters, $pararr);
}
}
You can then access the get parameters via e.g.
echo $parameters['app'];
you can use route redirection to mask and ending .php route ex:
Route::get('forum/index', ['uses'=> 'PaypalController#ipbIpn']);
Route::redirect('forum/index.php', 'forum/index');

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