Shell script to extract data from file between two date ranges - bash
I have a huge file, with each line starting with a timestamp as shown below. I need a way to grep lines between two dates. Is there any easy way to do this using sed or awk instead of extracting out date fields in each line and comparing day/month/year?
example, need to extract data between 2013-06-01 to 2013-06-15 by checking the timestamp in the first field
File contents:
2013-06-02T19:44:59;(3305,3308,2338,102116);aaaa;xxxx
2013-06-14T20:01:58;(2338);aaaa;xxxx
2013-06-12T20:01:58;(3305,3308,2338);bbbb;xxxx
2013-06-13T20:01:59;(3305,3308,2338,102116);bbbb;xxxx
2013-06-13T20:02:53;(2338);bbbb;xxxx
2013-06-13T20:02:53;(3305,3308,2338);aaaa2;xxxx
2013-06-13T20:02:54;(3305,3308,2338,102116);aaaa2;xxxx
2013-06-14T20:31:58;(2338);aaaa2;xxxx
2013-06-14T20:31:58;(3305,3308,2338);aaaa;xxxx
2013-06-15T20:31:59;(3305,3308,2338,102116);bbbb;xxxx
2013-06-16T20:32:53;(2338);aaaa;xxxx
2013-06-16T20:32:53;(3305,3308,2338);aaaa2;xxxx
2013-06-16T20:32:54;(3305,3308,2338,102116);bbbb;xxxx
It may not have been your first choice but Perl is great for this task.
perl -ne "print if ( m/2013-06-02/ .. m/2013-06-15/ )" myfile.txt
The way this works is that if the first trigger is matched (i.e. m/2013-06-02/) then the condition (print) will be executed on each line until the second trigger is matched (i.e. m/2013-06-15).
However this trick won't work if you specify m/2013-06-01/ as a trigger because this is never matched in your file.
A less exciting technique is to extract some text from each line and test that:
perl -ne 'if ( m/^([0-9-]+)/ ) { $date = $1; print if ( $date ge "2013-06-01" and $date le "2013-06-15" ) }' myfile.txt
(Tested both expressions and working).
You can try something like:
awk -F'-|T' '$1==2013 && $2==06 && $3>=01 && $3<=15' hugefile
You can use sed to print all lines between two patterns. In this case, you will have to sort the file first because the dates are interleaved:
$ sort file | sed -n '/2013-06-12/,/2013-06-15/p'
2013-06-12T20:01:58;(3305,3308,2338);bbbb;xxxx
2013-06-13T20:01:59;(3305,3308,2338,102116);bbbb;xxxx
2013-06-13T20:02:53;(2338);bbbb;xxxx
2013-06-13T20:02:53;(3305,3308,2338);aaaa2;xxxx
2013-06-13T20:02:54;(3305,3308,2338,102116);aaaa2;xxxx
2013-06-14T20:01:58;(2338);aaaa;xxxx
2013-06-14T20:31:58;(2338);aaaa2;xxxx
2013-06-14T20:31:58;(3305,3308,2338);aaaa;xxxx
2013-06-15T20:31:59;(3305,3308,2338,102116);bbbb;xxxx
Related
Test if a value is in a csv file in bash
I have a 3-4M lines csv file (my_csv.csv) with two columns as :
col1,col2
val11,val12
val21,val22
val31,val32
...
The csv contains only two columns with one comma per line. Col1 and Col2 values are only strings (nothing else). The result shown above is the result of the command head my_csv.cs..
I would like to check if a string test_str is into the col2 values. What I mean here is, if test_str = val12 I would like the test to return True because val12 is located in column 2 (as show in the example).
But if test_str = val1244 I want the code to return False.
In python it would be something as :
import pandas as pd
df = pd.read_csv('my_csv.csv')
test_str = 'val42'
if test_str in df['col2'].to_list():
# Expected to return true
# Do the job
But I have no clues how to do it in bash.
(I know that df['col2'].to_list() is not a good idea, but I didn't want to use built-in pandas function for the code to be easier to understand)
awk is most suited amongst the bash utilities to handle csv data:
awk -F, -v val='val22' '$2 == val {print "found a match:", $0}' file
found a match: val21,val22
An equivalent bash loop would be like this:
while IFS=',' read -ra arr; do
if [[ ${arr[1]} == 'val22' ]]; then
echo "found a match: ${arr[#]}"
fi
done < file
But do keep in mind that Bash while read loop extremely slow compared to cat, why?
Parsing CSV is difficult... unless your fields do not contain commas, newlines... And you don't do what you want in bash, on a large file it will be extremely slow. You do it using utilities like awk or grep that would also be available with dash, zsh or another shell. So, if you have a very simple CSV format you can use, e.g., grep: if grep -q ',val42$' my_csv.csv; then <do that> fi We can also put the string to search for in a variable but remember that some characters have a special meaning in regular expressions and shall be escaped. Example if there are no special characters in the string to search for: test_str="val42" if grep -q ",$test_str$" my_csv.csv; then <do that> fi
3-4M rows is a small file to awk. might as well just do
{m,g}awk 'END { exit !index($_,","(__)"\n") }' RS='^$' FS='^$' __="${test_str}"
convert a file content using shell script
Hello everyone I'm a beginner in shell coding. In daily basis I need to convert a file's data to another format, I usually do it manually with Text Editor. But I often do mistakes. So I decided to code an easy script who can do the work for me.
The file's content like this
/release201209
a1,a2,"a3",a4,a5
b1,b2,"b3",b4,b5
c1,c2,"c3",c4,c5
to this:
a2>a3
b2>b3
c2>c3
The script should ignore the first line and print the second and third values separated by '>'
I'm half way there, and here is my code
#!/bin/bash
#while Loops
i=1
while IFS=\" read t1 t2 t3
do
test $i -eq 1 && ((i=i+1)) && continue
echo $t1|cut -d\, -f2 | { tr -d '\n'; echo \>$t2; }
done < $1
The problem in my code is that the last line isnt printed unless the file finishes with an empty line \n
And I want the echo to be printed inside a new CSV file(I tried to set the standard output to my new file but only the last echo is printed there).
Can someone please help me out? Thanks in advance.
Rather than treating the double quotes as a field separator, it seems cleaner to just delete them (assuming that is valid). Eg:
$ < input tr -d '"' | awk 'NR>1{print $2,$3}' FS=, OFS=\>
a2>a3
b2>b3
c2>c3
If you cannot just strip the quotes as in your sample input but those quotes are escaping commas, you could hack together a solution but you would be better off using a proper CSV parsing tool. (eg perl's Text::CSV)
Here's a simple pipeline that will do the trick: sed '1d' data.txt | cut -d, -f2-3 | tr -d '"' | tr ',' '>' Here, we're just removing the first line (as desired), selecting fields 2 & 3 (based on a comma field separator), removing the double quotes and mapping the remaining , to >.
Use this Perl one-liner:
perl -F',' -lane 'next if $. == 1; print join ">", map { tr/"//d; $_ } #F[1,2]' in_file
The Perl one-liner uses these command line flags:
-e : Tells Perl to look for code in-line, instead of in a file.
-n : Loop over the input one line at a time, assigning it to $_ by default.
-l : Strip the input line separator ("\n" on *NIX by default) before executing the code in-line, and append it when printing.
-a : Split $_ into array #F on whitespace or on the regex specified in -F option.
-F',' : Split into #F on comma, rather than on whitespace.
SEE ALSO:
perldoc perlrun: how to execute the Perl interpreter: command line switches
Convert multi-line csv to single line using Linux tools
I have a .csv file that contains double quoted multi-line fields. I need to convert the multi-line cell to a single line. It doesn't show in the sample data but I do not know which fields might be multi-line so any solution will need to check every field. I do know how many columns I'll have. The first line will also need to be skipped. I don't how much data so performance isn't a consideration. I need something that I can run from a bash script on Linux. Preferably using tools such as awk or sed and not actual programming languages. The data will be processed further with Logstash but it doesn't handle double quoted multi-line fields hence the need to do some pre-processing. I tried something like this and it kind of works on one row but fails on multiple rows. sed -e :0 -e '/,.*,.*,.*,.*,/b' -e N -e '1n;N;N;N;s/\n/ /g' -e b0 file.csv CSV example First name,Last name,Address,ZIP John,Doe,"Country City Street",12345 The output I want is First name,Last name,Address,ZIP John,Doe,Country City Street,12345 Jane,Doe,Country City Street,67890 etc. etc.
First my apologies for getting here 7 months late... I came across a problem similar to yours today, with multiple fields with multi-line types. I was glad to find your question but at least for my case I have the complexity that, as more than one field is conflicting, quotes might open, close and open again on the same line... anyway, reading a lot and combining answers from different posts I came up with something like this: First I count the quotes in a line, to do that, I take out everything but quotes and then use wc: quotes=`echo $line | tr -cd '"' | wc -c` # Counts the quotes If you think of a single multi-line field, knowing if the quotes are 1 or 2 is enough. In a more generic scenario like mine I have to know if the number of quotes is odd or even to know if the line completes the record or expects more information. To check for even or odd you can use the mod operand (%), in general: even % 2 = 0 odd % 2 = 1 For the first line: Odd means that the line expects more information on the next line. Even means the line is complete. For the subsequent lines, I have to know the status of the previous one. for instance in your sample text: First name,Last name,Address,ZIP John,Doe,"Country City Street",12345 You can say line 1 (John,Doe,"Country) has 1 quote (odd) what means the status of the record is incomplete or open. When you go to line 2, there is no quote (even). Nevertheless this does not mean the record is complete, you have to consider the previous status... so for the lines following the first one it will be: Odd means that record status toggles (incomplete to complete). Even means that record status remains as the previous line. What I did was looping line by line while carrying the status of the last line to the next one: incomplete=0 cat file.csv | while read line; do quotes=`echo $line | tr -cd '"' | wc -c` # Counts the quotes incomplete=$((($quotes+$incomplete)%2)) # Check if Odd or Even to decide status if [ $incomplete -eq 1 ]; then echo -n "$line " >> new.csv # If line is incomplete join with next else echo "$line" >> new.csv # If line completes the record finish fi done Once this was executed, a file in your format generates a new.csv like this: First name,Last name,Address,ZIP John,Doe,"Country City Street",12345 I like one-liners as much as everyone, I wrote that script just for the sake of clarity, you can - arguably - write it in one line like: i=0;cat file.csv|while read l;do i=$((($(echo $l|tr -cd '"'|wc -c)+$i)%2));[[ $i = 1 ]] && echo -n "$l " || echo "$l";done >new.csv I would appreciate it if you could go back to your example and see if this works for your case (which you most likely already solved). Hopefully this can still help someone else down the road... Recovering the multi-line fields Every need is different, in my case I wanted the records in one line to further process the csv to add some bash-extracted data, but I would like to keep the csv as it was. To accomplish that, instead of joining the lines with a space I used a code - likely unique - that I could then search and replace: i=0;cat file.csv|while read l;do i=$((($(echo $l|tr -cd '"'|wc -c)+$i)%2));[[ $i = 1 ]] && echo -n "$l ~newline~ " || echo "$l";done >new.csv the code is ~newline~, this is totally arbitrary of course. Then, after doing my processing, I took the csv text file and replaced the coded newlines with real newlines: sed -i 's/ ~newline~ /\n/g' new.csv References: Ternary operator: https://stackoverflow.com/a/3953666/6316852 Count char occurrences: https://stackoverflow.com/a/41119233/6316852 Other peculiar cases: https://www.linuxquestions.org/questions/programming-9/complex-bash-string-substitution-of-csv-file-with-multiline-data-937179/ TL;DR Run this: i=0;cat file.csv|while read l;do i=$((($(echo $l|tr -cd '"'|wc -c)+$i)%2));[[ $i = 1 ]] && echo -n "$l " || echo "$l";done >new.csv ... and collect results in new.csv I hope it helps!
If Perl is your option, please try the following:
perl -e '
while (<>) {
$str .= $_;
}
while ($str =~ /("(("")|[^"])*")|((^|(?<=,))[^,]*((?=,)|$))/g) {
if (($el = $&) =~ /^".*"$/s) {
$el =~ s/^"//s; $el =~ s/"$//s;
$el =~ s/""/"/g;
$el =~ s/\s+(?!$)/ /g;
}
push(#ary, $el);
}
foreach (#ary) {
print /\n$/ ? "$_" : "$_,";
}' sample.csv
sample.csv:
First name,Last name,Address,ZIP
John,Doe,"Country
City
Street",12345
John,Doe,"Country
City
Street",67890
Result:
First name,Last name,Address,ZIP
John,Doe,Country City Street,12345
John,Doe,Country City Street,67890
This might work for you (GNU sed): sed ':a;s/[^,]\+/&/4;tb;N;ba;:b;s/\n\+/ /g;s/"//g' file Test each line to see that it contains the correct number of fields (in the example that was 4). If there are not enough fields, append the next line and repeat the test. Otherwise, replace the newline(s) by spaces and finally remove the "'s. N.B. This may be fraught with problems such as ,'s between "'s and quoted "'s.
Try cat -v file.csv. When the file was made with Excel, you might have some luck: When the newlines in a field are a simple \n and the newline at the end is a \r\n (which will look like ^M), parsing is simple. # delete all newlines and replace the ^M with a new newline. tr -d "\n" < file.csv| tr "\r" "\n" # Above two steps with one command tr "\n\r" " \n" < file.csv When you want a space between the joined line, you need an additional step. tr "\n\r" " \n" < file.csv | sed '2,$ s/^ //' EDIT: #sjaak commented this didn't work is his case. When your broken lines also have ^M you still can be a lucky (wo-)man. When your broken field is always the first field in double quotes and you have GNU sed 4.2.2, you can join 2 lines when the first line has exactly one double quote. sed -rz ':a;s/(\n|^)([^"]*)"([^"]*)\n/\1\2"\3 /;ta' file.csv Explanation: -z don't use \n as line endings :a label for repeating the step after successful replacement (\n|^) Search after a newline or the very first line ([^"]*) Substring without a " ta Go back to label a and repeat
awk pattern matching is working.
answer in one line :
awk '/,"/{ORS=" "};/",/{ORS="\n"}{print $0}' YourFile
if you'd like to drop quotes, you could use:
awk '/,"/{ORS=" "};/",/{ORS="\n"}{print $0}' YourFile | sed 's/"//gw NewFile'
but I prefer to keep it.
to explain the code:
/Pattern/ : find pattern in current line.
ORS : indicates the output line record.
$0 : indicates the whole of the current line.
's/OldPattern/NewPattern/': substitude first OldPattern with NewPattern
/g : does the previous action for all OldPattern
/w : write the result to Newfile
How to convert HHMMSS to HH:MM:SS Unix?
I tried to convert the HHMMSS to HH:MM:SS and I am able to convert it successfully but my script takes 2 hours to complete because of the file size. Is there any better way (fastest way) to complete this task
Data File
data.txt
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,,,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,,071600,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,072200,072200,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TAB,072600,072600,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,073200,073200,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,073500,073500,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,MRO,073700,073700,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,CPT,073900,073900,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,074400,,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,,,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,,090200,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,090900,090900,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,091500,091500,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TAB,091900,091900,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,092500,092500,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,092900,092900,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,MRO,093200,093200,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,CPT,093500,093500,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,094500,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,CPT,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,MRO,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TAB,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,,170100,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,CPT,170400,170400,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,MRO,170700,170700,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,171000,171000,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,171500,171500,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TAB,171900,171900,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,172500,172500,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,172900,172900,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,173500,173500,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,174100,,
My code : script.sh
#!/bin/bash
awk -F"," '{print $5}' Data.txt > tmp.txt # print first line first string before , to tmp.txt i.e. all Numbers will be placed into tmp.txt
sort tmp.txt | uniq -d > Uniqe_number.txt # unique values be stored to Uniqe_number.txt
rm tmp.txt # removes tmp file
while read line; do
echo $line
cat Data.txt | grep ",$line," > Numbers/All/$line.txt # grep Number and creats files induvidtually
awk -F"," '{print $5","$4","$7","$8","$9","$10","$11}' Numbers/All/$line.txt > Numbers/All/tmp_$line.txt
mv Numbers/All/tmp_$line.txt Numbers/Final/Final_$line.txt
done < Uniqe_number.txt
ls Numbers/Final > files.txt
dos2unix files.txt
bash time_replace.sh
when you execute above script it will call time_replace.sh script
My Code for time_replace.sh
#!/bin/bash
for i in `cat files.txt`
do
while read aline
do
TimeDep=`echo $aline | awk -F"," '{print $6}'`
#echo $TimeDep
finalTimeDep=`echo $TimeDep | awk '{for(i=1;i<=length($0);i+=2){printf("%s:",substr($0,i,2))}}'|awk '{sub(/:$/,"")};1'`
#echo $finalTimeDep
##########
TimeAri=`echo $aline | awk -F"," '{print $7}'`
#echo $TimeAri
finalTimeAri=`echo $TimeAri | awk '{for(i=1;i<=length($0);i+=2){printf("%s:",substr($0,i,2))}}'|awk '{sub(/:$/,"")};1'`
#echo $finalTimeAri
sed -i 's/',$TimeDep'/',$finalTimeDep'/g' Numbers/Final/$i
sed -i 's/',$TimeAri'/',$finalTimeAri'/g' Numbers/Final/$i
############################
done < Numbers/Final/$i
done
Any better solution?
Appreciate any help.
Thanks
Sri
If there's a large quantity of files, then the pipelines are probably what are going to impact performance more than anything else - although processes can be cheap, if you're doing a huge amount of processing then cutting down the amount of time you do pass data through a pipeline can reap dividends.
So you're probably going to be better off writing the entire script in awk (or perl). For example, awk can send output to an arbitary file, so the while lop in your first file could be replaced with an awk script that does this. You also don't need to use a temporary file.
I assume the sorting is just for tracking progress easily as you know how many numbers there are. But if you don't care for the sorting, you can simply do this:
#!/bin/sh
awk -F ',' '
{
print $5","$4","$7","$8","$9","$10","$11 > Numbers/Final/Final_$line.txt
}' datafile.txt
ls Numbers/Final > files.txt
Alternatively, if you need to sort you can do sort -t, -k5,4,10 (or whichever field your sort keys actually need to be).
As for formatting the datetime, awk also does functions, so you could actually have an awk script that looks like this. This would replace both of your scripts above whilst retaining the same functionality (at least, as far as I can make out with a quick analysis) ... (Note! Untested, so may contain vauge syntax errors):
#!/usr/bin/awk
BEGIN {
FS=","
}
function formattime (t)
{
return substr(t,1,2)":"substr(t,3,2)":"substr(t,5,2)
}
{
print $5","$4","$7","$8","$9","formattime($10)","formattime($11) > Numbers/Final/Final_$line.txt
}
which you can save, chmod 700, and call directly as:
dostuff.awk filename
Other awk options include changing fields in-situ, so if you want to maintain the entire original file but with formatted datetimes, you can do a modification of the above. Change the print block to:
{
$10=formattime($10)
$11=formattime($11)
print $0
}
If this doesn't do everything you need it to, hopefully it gives some ideas that will help the code.
It's not clear what all your sorting and uniq-ing is for. I'm assuming your data file has only one entry per line, and you need to change the 10th and 11th comma-separated fields from HHMMSS to HH:MM:SS.
while IFS=, read -a line ; do
echo -n ${line[0]},${line[1]},${line[2]},${line[3]},
echo -n ${line[4]},${line[5]},${line[6]},${line[7]},
echo -n ${line[8]},${line[9]},
if [ -n "${line[10]}" ]; then
echo -n ${line[10]:0:2}:${line[10]:2:2}:${line[10]:4:2}
fi
echo -n ,
if [ -n "${line[11]}" ]; then
echo -n ${line[11]:0:2}:${line[11]:2:2}:${line[11]:4:2}
fi
echo ""
done < data.txt
The operative part is the ${variable:offset:length} construct that lets you extract substrings out of a variable.
In Perl, that's close to child's play:
#!/usr/bin/env perl
use strict;
use warnings;
use English( -no_match_vars );
local($OFS) = ",";
while (<>)
{
my(#F) = split /,/;
$F[9] =~ s/(\d\d)(\d\d)(\d\d)/$1:$2:$3/ if defined $F[9];
$F[10] =~ s/(\d\d)(\d\d)(\d\d)/$1:$2:$3/ if defined $F[10];
print #F;
}
If you don't want to use English, you can write local($,) = ","; instead; it controls the output field separator, choosing to use comma. The code reads each line in the file, splits it up on the commas, takes the last two fields, counting from zero, and (if they're not empty) inserts colons in between the pairs of digits. I'm sure a 'Code Golf' solution would be made a lot shorter, but this is semi-legible if you know any Perl.
This will be quicker by far than the script, not least because it doesn't have to sort anything, but also because all the processing is done in a single process in a single pass through the file. Running multiple processes per line of input, as in your code, is a performance disaster when the files are big.
The output on the sample data you gave is:
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,,,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,,07:16:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,07:22:00,07:22:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TAB,07:26:00,07:26:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,07:32:00,07:32:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,07:35:00,07:35:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,MRO,07:37:00,07:37:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,CPT,07:39:00,07:39:00,
10,SRI,AA,20091210,8503,ABCXYZ,D,N,TMP,07:44:00,,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,,,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,,09:02:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,09:09:00,09:09:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,09:15:00,09:15:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TAB,09:19:00,09:19:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,09:25:00,09:25:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,09:29:00,09:29:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,MRO,09:32:00,09:32:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,CPT,09:35:00,09:35:00,
10,SRI,AA,20091210,8505,ABCXYZ,D,N,TMP,09:45:00,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,CPT,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,MRO,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TAB,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8506,ABCXYZ,U,N,TMP,,,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,,17:01:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,CPT,17:04:00,17:04:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,MRO,17:07:00,17:07:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,17:10:00,17:10:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,17:15:00,17:15:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TAB,17:19:00,17:19:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,17:25:00,17:25:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,17:29:00,17:29:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,17:35:00,17:35:00,
10,SRI,AA,20091210,8510,ABCXYZ,U,N,TMP,17:41:00,,
search a pattern in file and output each pattern result in its own file using awk, sed
I have a file of numbers in each new line: $cat test 700320947 700509217 701113187 701435748 701435889 701667717 701668467 702119126 702306577 702914910 that I want to search details of from another larger file with several comma separated fields and out put results in 700320947.csv 700509217.csv 701113187.csv 701435748.csv 701435889.csv 701667717.csv 701668467.csv 702119126.csv 702306577.csv 702914910.csv Logic: ls test | while read file; do zgrep $line *large*file*gz >> $line.csv ; done Please assist. Thanks
Since nothing said about the structure of the large file, I'll just assume that the numbers in test are to be found in the second column of the large file; generalize as needed.
This can be done in a single pass through each of the files by using output redirection in awk:
awk -F"," 'FILENAME == "test" { num[$1]=1; next }
num[$2] { print > $2".csv" }' test bigfile
Unzip the large file first; using zgrep means unzipping on-the-fly for every line of the number file... very inefficient. After unzipping the big file, this will do it: for number in `cat test`; do grep $number bigfile > $number.csv; done Edited: To limit hits to whole words only (eg 702119126 won't match 1702119126), add word boundaries to the regex: for number in `cat test`; do grep \\b$number\\b bigfile > $number.csv; done