How to put a SELECT from Oracle into a bash variable? - oracle

Question

I try to save the output of an Oracle SELECT command into a bash variable.
I tried the following lines but it didn't work really well...
ACCESS_SQL=`{
sqlplus << EOF
${USER}/${PASSWORD}#DB
set head off;
set feedback off;
set pagesize 5000;
set linesize 30000;
set serveroutput on;
DECLARE
data varchar(5000);
BEGIN
select ACCESS_ID, PROFILE_ID, START_DATE, END_DATE, PLATFORM, ACCESS_TYPE, PERM_FLAG, ACTIVE_FLAG into data from uam.access_list where USER_ID='${USER_ID}';
dbms_output.put_line(data);
END;
/
exit;
EOF
}`
The error statement I get is :
SQL> SQL> SQL> SQL> SQL> SQL> 2 3 4 5 6 7 select ACCESS_ID, PROFILE_ID, START_DATE, END_DATE, PLATFORM, ACCESS_TYPE, PERM_FLAG, ACTIVE_FLAG into data from uam.access_list where USER_ID='PZ230';
*
ERROR at line 4:
ORA-06550: line 4, column 110:
PL/SQL: ORA-00947: not enough values
ORA-06550: line 4, column 2:
PL/SQL: SQL Statement ignored
I was wondering if using a varchar is the right thing to do...

Answer 1

You don't need to select into a variable and then use dbms_output.put_line to print it out. (Your select into statement won't work anyway, because you can't select multiple columns into a single data variable.)
Instead, do it like this:
data=$(sqlplus -S ${USER}/${PASSWORD} << EOF
set head off
set feedback off
set pagesize 5000
set linesize 30000
select ACCESS_ID, PROFILE_ID, START_DATE, END_DATE, PLATFORM, ACCESS_TYPE, PERM_FLAG, ACTIVE_FLAG from uam.access_list where USER_ID='${USER_ID}';
exit
EOF)
echo "$data"