I am using ajax to go the function and check if the value already exist on the database or not. If the data already exist, I show the jQuery dialog which is working fine but if the value doesn't already exist I don't want to show the popup and refresh the entire page. Here's my AJAX function:
function copyFile(val) {
var choices = document.getElementsByName("choice_shard_with_me").value;
var file_owner = document.getElementById('username').value;
$.ajax({
type: "GET",
url: "/copy_file/",
data: {choices:choices, file_owner:file_owner},
success: function(data){
$('#dialog-confirm').html(data)
}
});
}
My Django view:
if request.GET:
choices = request.GET.getlist('choice_shard_with_me')
file_owner = request.GET.getlist('username')
#Test if the file already exist in the user share directory
x = [File.objects.filter(user_id=request.user.id, file_name=i, flag='A').values_list('file_name') for i in choices]
y = [y[0] for y in x[0]]
if len(y) > 1:
return render_to_response('copyexist.html', {'file':y}, context_instance=RequestContext(request))
//doesn't refresh the whole page show the popup.
else:
//refresh whole page and do something
My question is: when the popup is displayed it is shown using Ajax in a div. If it goes into the else statement file copied is done and the successful message is given in a little div itself(I want to do whole page refresh here).
You can make your answer for example json encoded, where you will return two parameters:
{
success: true/false,
data : YOUR_DATA_HERE
}
So success callback can look into success part, and decide whether to show popup with data, or make page reload
Sorry, I don't know python, so can't advise exact expression to make correct json encode.
Related
Haven't come across this before with ajax. On click of a button I am posting a form with ajax. In the successful return function I am opening up a modal window in bootstrap 3 with a single parameter attached from the previous form submission.
I am using the modal as a confirmation window to confirm a user deletion. I am using ajax again then in the modal to do the actual deletion of the user in the db and returning success or fail.
Since all the operations are being processed in the actual modal's ajax (confirm the username exists then perform the delete operations)... is there a way I can skip the initial form processing? In this example p_delete_user.php' really does absolutely nothing other than allow me to return and attach the username parameter to the modal I open.
Can I skip this step somehow and go straight to my success calls with the attached parameter value. I have no need to check if the param is valid or not in this step as the validation occurs in the ajax of the modal that is opened.
my ajax:
// delete user account
var deleteAccount = function() {
$('#delete-user').on('click', function () {
var $form = $(this).closest('form');
$.ajax({
type: 'post',
url: '/spc_admin/process/p_delete_user.php',
data: $form.serialize(),
dataType : 'json'
}).done(function (response) {
if (response.success) {
// user account exists so show confirmation modal
$('#modal-ajax').load('/spc_admin/modals/m_delete_user.php?username='+response.username+'');
$('#modal-ajax').modal('show');
}
else
{
// show error toast
toastr.error('An error has occurred. Please contact support.', 'Error');
}
});
});
}
Use Javascript to get the username from the form, and put that directly into the modal:
var deleteAccount = function() {
$('#delete-user').on('click', function () {
var username = $(this).closest('form').find("input[name=username]").val();
$('#modal-ajax').load('/spc_admin/modals/m_delete_user.php?username='+encodeURIComponent(username));
$('#modal-ajax').modal('show');
});
}
What i am trying to do is to get the value of the selected elements by jquery selection. After that, those value are post to php script via ajax and then retrieve the data from the database and display it on the same page (something called autocompete).
var marvalue=$("input[name=m_status]:checked").val();
var fromhvalue=$("#fromheight").val();
var tohvalue=$("#toheight").val();
var value = $("#edu_det1").val();
alert (value);
var regvalue = $("#religion").val();
alert (regvalue);
var occvalue = $("#occupation").val();
alert (occvalue);
var convalue = $("#country").val();
alert (convalue);
Alert is there to check the correct values. As you see the code above this will get the values from the different input elements.
Below is the code i used to post to php
/*
$.post("regsearch.php", {queryString: ""+value+"",queryString1: ""+marvalue+"",queryStringfage: ""+fage+"",queryStringtage: ""+tage+""+queryStringfromh: ""+fromhvalue+""+queryStringtoh: ""+tohvalue+""+}, function(data) { // Do an AJAX call
$('#suggestions').fadeIn(); // Show the suggestions box
$('#suggestions').html(data); // Fill the suggestions box
});
*/
The problem :
when the comment is removed nor the alert popup and neither the result displayed. Ok about the result as no query is posted.
Major part is that when i use the below code which hold only m_status and edu_det1 it works.
marvalue=$("input[name=m_status]:checked").val();
alert (marvalue);
var value = $("#edu_det1").val();
alert (value);
The post code for above is
$.post("regsearch.php", {
queryString: ""+value+"",
queryString1: ""+marvalue+"",
queryStringfage: ""+fage+"",queryStringtage: ""+tage+""
}, function(data) {
// Do an AJAX call
$('#suggestions').fadeIn(); // Show the suggestions box
$('#suggestions').html(data); // Fill the suggestions box
});
The code for age and it verification is not added here. What is the problem and how to sort this out?
It will be better if you use jquery serialize() function. This will make your life easier to work with forms.
var querstring = $(form).serialize();
above will help
I guess using ajax post jQuery.ajax() will do the same thing and you can even serialize the fields in your page.
http://api.jquery.com/jQuery.ajax/#jQuery-ajax-settings
I have done similar type of code
UserName is the field Which I am passing
var data = $('#Username').serialize();
$('#usernameCheck').empty();
if (!$("form").validate().element("#Username"))
return;
$.ajax({
url: '/SignUp/CheckUsername',
type: 'POST',
data: data,
async: true,
success: function (result) {
if (result == 1) {
$('#usernameCheck').html('<font color=green>Username available</font>');
usernameOK = true;
}
else if (result == 2) {
$('#usernameCheck').html('<font color=red>Username not available</font>');
usernameOK = false;
}
else {
$('#usernameCheck').empty();
usernameOK = false;
}
}
});
First of all you should use your console to see Javascript errors, as I'm sure this will generate some. For example that querystring is undefined.
I'd also console.log instead of alert, it is less annoying and more informative.
Then: you dont need to use f.e. ""+marvalue+"" - just use marvalue. On the other hand f.e. queryString should be quoted...
$.post("regsearch.php", {'queryString':value,'queryString1': marvalue,'queryStringfage':fage,'queryStringtage':tage,'queryStringfromh': fromhvalue,'queryStringtoh':tohvalue}, function(data) {
$('#suggestions').fadeIn();
$('#suggestions').html(data);
});
I have the following code that loads content when a user scrolls to the bottom of the page. The problem is that if one scrolls too fast it double loads the content. What ways can I change my code to prevent this?
$(window).scroll(function(){
if($(window).scrollTop() == $(document).height() - $(window).height()){
$('div#ajaxResults').show();
$.ajax({
url: "ajax/home.php?last_id=" + $(".postitem:last").attr("id"),
success: function(html){
if(html){
$("#messages").append(html);
$('#ajaxResults').hide();
}else{
$('#ajaxResults').html('<center>None.</center>');
}
}
});
}
});
I need for the solution to work multiple times. This script loads the next 5 messages, but there may be hundreds of messages that could be loaded. It is supposed to work in the same way that facebook or twitter loads updates.
SOLUTION:
$(window).scroll(function(){
if($(window).scrollTop() == $(document).height() - $(window).height()){
var lastid = $(".postitem:last").attr("id");
$('div#ajaxResults').show();
$.ajax({
url: "ajax/home.php?last_id=" + $(".postitem:last").attr("id"),
success: function(html){
if(html){
if(lastid == $(".postitem:last").attr("id")){
$("#messages").append(html);
$('#ajaxResults').hide();
}
}else{
$('#ajaxResults').html('<center>None.</center>');
}
}
});
}
});
Add a variable that checks the lastid before the ajax is loaded, then only append html if the variable == the document last id. This way if ajax has already loaded, the two will not be equal and the update won't be posted.
Try adding $(this).unbind('scroll'); inside the if block, assuming you do not want the ajax request to run more than once. Don't put it in the $.ajax success callback though, since it may fire more than 1 ajax request this way.
http://api.jquery.com/unbind/
Can you set a variable that stores the timestamp it was called and if it's within a few milli-seconds then doesn't call again? Kind of hack-ish but might do the trick.
Obviously this isn't really solving the problem as that seems to be with how the scroll event is being triggered.
I'm trying to do an ajax post after a button is clicked, and it works in firefox but not in IE the first time the page is loaded. It does work if I refresh the page and try again second time - but not first time and this is crucial.
I've scanned over various web pages - could it be anything to do with the listener? (I've just seen this mentioned mentiond somewhere) Is there something not set correctly to do with ajax and posting when page first loads?
$(document).ready(function() {
$('#btnCont').bind('click',function () {
var itm = $("#txtItm").val();
var qty = $("#txtQty").val();
var msg = $("#txtMessage").val();
var op_id = $("#txtOp_id").val();
//if i alert these values out they alert out no prob
alert(itm+'-'+qty+'-'+msg+'-'+op_id);
$.ajax({
type: "POST",
url: "do_request.php?msg="+msg+"&itm="+itm+"&qty="+qty+"&op_id="+op_id,
success: function (msg) {
document.getElementById('div_main').style.display='none';
document.getElementById('div_success').style.display='block';
var row_id = document.getElementById('txtRow').value;
document.getElementById('row'+row_id).style.backgroundColor='#b4e8aa';
},
error: function (XMLHttpRequest, textStatus, errorThrown) {
alert('Error submitting request.');
}
});
});
I would start debugging the click event. I.e. if you try to put .bind into a a href tag, the tag itself has a click event that may act on an unwanted way. There exist a command that are named something like event.preventDefaults() that avoids the standard feature of click. After All, you try to manipulate the DOM last of all actions (document.load).
$('#btnCont').bind('click',function () { .. }
I would also try to debug the same functionality with adding onClientClick to the tag instead of adding bind to the document load.
I hope that bring some light.
Given so much different options to submit sth to the server, I feel a little confused.
Can someone help me to clear the idea when I should use which and why?
1> $.ajax()
2> $('#myForm').ajaxForm
3> ajaxSubmit
4> $('#myForm').submit
Thank you
I personally prefer creating a function such as submitForm(url,data) that way it can be reused.
Javascript:
function submitForm(t_url,t_data) {
$.ajax({
type: 'POST',
url: t_url,
data: t_data,
success: function(data) {
$('#responseArea').html(data);
}
});
}
HTML:
<form action='javascript: submitForm("whatever.php",$("#whatevervalue").val());' method='POST'> etc etc
edit try this then:
$('#yourForm').submit(function() {
var yourValues = {};
$.each($('#yourForm').serializeArray(), function(i, field) {
yourValues[field.name] = field.value;
});
submitForm('whatever.php',yourvalues);
});
Here is my understanding
$.ajax does the nice ajax way to send data to server without whole page reload and refresh. epically you want to refresh the segment on the page. But it has it's own limitation, it doesn't support file upload. so if you don't have any fileupload, this works OK.
$("#form").submit is the javascript way to submit the form and has same behaviour as the input with "submit" type, but you can do some nice js validation check before you submit, which means you can prevent the submit if client validation failed.
ajaxForm and ajaxSubmit basically are same and does the normal way form submit behaviour with some ajax response. The different between these two has been specified on their website, under FAQ section. I just quote it for some lazy people
What is the difference between ajaxForm and ajaxSubmit?
There are two main differences between these methods:
ajaxSubmit submits the form, ajaxForm does not. When you invoke ajaxSubmit it immediately serializes the form data and sends it to the server. When you invoke ajaxForm it adds the necessary event listeners to the form so that it can detect when the form is submitted by the user. When this occurs ajaxSubmit is called for you.
When using ajaxForm the submitted data will include the name and value of the submitting element (or its click coordinates if the submitting element is an image).
A bit late, but here's my contribution. In my experience, $.ajax is the preferred way to send an AJAX call, including forms, to the server. It has a plethora more options. In order to perform the validation which #vincent mentioned, I add a normal submit button to the form, then bind to $(document).on("submit", "#myForm", .... In that, I prevent the default submit action (e.preventDefault() assuming your event is e), do my validation, and then submit.
A simplified version of this would be as follows:
$(document).on("submit", "#login-form", function(e) {
e.preventDefault(); // don't actually submit
// show applicable progress indicators
$("#login-submit-wrapper").addClass("hide");
$("#login-progress-wrapper").removeClass("hide");
// simple validation of username to avoid extra server calls
if (!new RegExp(/^([A-Za-z0-9._-]){2,64}$/).test($("#login-username").val())) {
// if it is invalid, mark the input and revert submit progress bar
markInputInvalid($("#login-username"), "Invalid Username");
$("#login-submit-wrapper").removeClass("hide");
$("#login-progress-wrapper").addClass("hide");
return false;
}
// additional check could go here
// i like FormData as I can submit files using it. However, a standard {} Object would work
var data = new FormData();
data.append("username", $("#login-username").val());
data.append("password", $("#login-password").val()); // just some examples
data.append("captcha", grecaptcha.getResponse());
$.ajax("handler.php", {
data: data,
processData: false, // prevent weird bugs when submitting files with FormData, optional for normal forms
contentType: false,
method: "POST"
}).done(function(response) {
// do something like redirect, display success, etc
}).fail(function(response) {
var data = JSON.parse(response.responseText); // parse server error
switch (data.error_code) { // do something based on that
case 1:
markInputInvalid($("#login-username"), data.message);
return;
break;
case 2:
markInputInvalid($("#login-password"), data.message);
return;
break;
default:
alert(data.message);
return;
break;
}
}).always(function() { // ALWAYS revert the form to old state, fail or success. .always has the benefit of running, even if .fail throws an error itself (bad JSON parse?)
$("#login-submit-wrapper").removeClass("hide");
$("#login-progress-wrapper").addClass("hide");
});
});