I have a problem replacing default password hash in config file:
sed -i 's/default_password_crypted: "[^"]*"/default_password_crypted: "\$1\$mF86/UHC\$WvcIcXred6crBz2onWxyac."/' input.txt
i get following error:
sed: -e expression #1, char 74: unknown option to `s'
works:
search pattern: default_password_crypted: "$1$mF86/UHC$WvcIcX2t6crBz2onWxyac."
sed -i 's/default_password_crypted: "[^"]*"/default_password_crypted: "1234567890"/' input.txt
how do i need to write replace pattern for hash ?
thx
You need to escape the literal / inside your replacement as it’s the delimiter:
sed -i 's/default_password_crypted: "[^"]*"/default_password_crypted: "\$1\$mF86\/UHC\$WvcIcXred6crBz2onWxyac."/' input.txt
Or simply use a different character, for example a ,:
sed -i 's,default_password_crypted: "[^"]*",default_password_crypted: "\$1\$mF86,UHC\$WvcIcXred6crBz2onWxyac.",' input.txt
You also don’t need to escape the $ inside the replacement.
Related
Following is the xml file in which STORAGE_ACCOUNT_KEY should be replaced with EoKpaH0W/kqTv9awgIpQX5s+qQwGzXUSxMxhRjfSWG7SIUTWhut1OYQkNxhb3/9UKGf+g4tc3UaC0zKMTSrTNg==
<property>
<name>fs.azure.account.key.storageaccountname.blob.core.windows.net</name>
<value>STORAGE_ACCOUNT_KEY</value>
</property>
I have tried the following. But nothing helps me solve it.
Using / after s and before g
sed -i "s/STORAGE_ACCOUNT_KEY/EoKpaH0W/kqTv9awgIpQX5s+qQwGzXUSxMxhRjfSWG7SIUTWhut1OYQkNxhb3/9UKGf+g4tc3UaC0zKMTSrTNg==/g" test.xml
Error:-
sed: -e expression #1, char 32: unknown option to `s'
Using | after s and before g
sed -i "s|STORAGE_ACCOUNT_KEY/EoKpaH0W/kqTv9awgIpQX5s+qQwGzXUSxMxhRjfSWG7SIUTWhut1OYQkNxhb3/9UKGf+g4tc3UaC0zKMTSrTNg==|g" test.xml
Error:-
sed: -e expression #1, char 112: unterminated `s' command
Note:- $STORAGE_ACCOUNT_KEY is a dynamic variable as below
sed -i "s|STORAGE_ACCOUNT_KEY/$STORAGE_ACCOUNT_KEY|g"
To replace XML, I would adivse to use an XML parser (for example xmllint) instead of sed.
That said, your sed expression is wrong.
sed s command uses 3 delimiters (any printable character you want), but these 3 must be the same and is defined by the one right after the s command.
s/foo/bar/g # right
s|foo|bar|g # right
s|foo/bar|g # wrong
Since you replace a string with a base64 string, you should not use any of the base64 character, so don't use / as a sed delimiter in that case.
Your expression should be like this:
sed -i "s|STORAGE_ACCOUNT_KEY|EoKpaH0W/kqTv9awgIpQX5s+qQwGzXUSxMxhRjfSWG7SIUTWhut1OYQkNxhb3/9UKGf+g4tc3UaC0zKMTSrTNg==|g" test.xml
Note that the g modifier at the end of the command might not be necessary if you only have 1 string to replace per line.
How to remove all occurences of string "???" of a file and save it?
My approach so far:
cat file.txt | sed -ie '/s/???//' file.txt
However I get the following error:
sed: -e expression #1, char 4: unknown command: `?'
You can use this sed command:
sed -i 's/???//g' file.txt
There is no reason to use cat here as sed can directly operate on a file and save it in-line.
Also note that unlike other regex flavors BRE (Basic Regular Expressions) which is default regex engine of sed doesn't treat ? as a special regex meta character hence there is no need to escape ? here.
I have to find a specific text in the file and then replace that text with some new text.
The contents of the file are:
host=100
servers=4
clients=70
I have tried this:
var=$(grep "servers=" /path/to/file)
sed -i "s/${var}/servers=5/g" /path/to/file
But it gives me the error:
sed: -e expression #1, char 2: unterminated `s' command
Note: All I want is to update the value of each of the variable i.e. servers=4 should be replaced by servers=5.
Please help me figure out the solution.
Thanks.
The output of grep ends with a newline character. sed expects the whole command on one line or escaping line breaks.
However, you can easily achieve the complete task with sed only:
sed -i 's/^servers=[0-9]*$/servers=5/' /path/to/file
sed -i.bak "s/servers=[0-9]*/servers=5/" /path/to/file
I am using shell script. My requirement is to find and replace the string. The string contains "/" char as well. I am getting error sed: -e expression #1, char 18: unterminated `s' command. Can someone tell how should i replace the string which has "/"?
#!/bin/bash
...
search_string="../conf/TestSystem/Inst1.xml"
rep="Inst1/Instrument.xml"
sed -i 's|${line}|${rep}/g' MasterConfiguration.xml
I tried using another sed command but that one also gave error sed: -e expression #1, char 13: unknown option to `s'
sed -e "s/${line}/${rep}/g" MasterConfiguration.xml > tempfile
Whenever you deal with shell-variables you have to get them out of the "sed-string":
For example:
sed -e "s/"${line}"/"${rep}"/g" MasterConfiguration.xml > tempfile
Otherwise sed will treat the chars as-is and search for ${line} literally:
As you see, nothing happens here.
Furthermore, if your variables contain / you need to use another delimiter for sed. I tend to use ~ in such a case, but you're free to use other chars - just be consequent and don't mix them like in your first example-sed-command:
sed 's~'${line}'~'${rep}'/g' //WRONG
sed 's~'${line}'~'${rep}'~g' //RIGHT
Combine both and it will work:
You can try this sed,
sed -i "s#${line}#${rep}#g" MasterConfiguration.xml
Problem:
Instead you have,
sed -i "s|${line}|${rep}/g" MasterConfiguration.xml
It should be,
sed -i "s|${line}|${rep}|g" MasterConfiguration.xml
Syntax:
sed "s|pattern|replacement|g"
I need to remove escape character from the string in bash. I get a data structure, which contains url paths with / escaped so I receive the regular link:
http://stackoverflow.com/questions/ask
as one with escaped /:
http:\/\/stackoverflow.com\/questions\/ask
Now I need to remove \ from the second link. For this purpose I tried using sed
`echo '"'${paths[$index]}'"' | sed "s#\\##g"`
But I get an error:
sed: -e expression #1, char 6: unterminated `s' command
If I replace \\ with ie. _ it works like a charm and removes all occurrences of _ in a string. How do I get rid of escape characters in a string using sed?
try this:
.......|sed 's#\\##g'
or:
.......|sed "s#\\\\##g"
EDIT add a test output:
kent$ echo "http:\/\/stackoverflow.com\/questions\/ask"|sed "s#\\\\##g"
http://stackoverflow.com/questions/ask
kent$ echo "http:\/\/stackoverflow.com\/questions\/ask"|sed 's#\\##g'
http://stackoverflow.com/questions/ask
Your question isn't clear about which way round you want so here is both ways:
$ sed 's#/#\\/#g' <<< "http://stackoverflow.com/questions/ask"
http:\/\/stackoverflow.com\/questions\/ask
$ sed 's#\\/#/#g' <<< "http:\/\/stackoverflow.com\/questions\/ask"
http://stackoverflow.com/questions/ask
You don't need to use sed.
paths[index]=${paths[index]//\\/}
or simply
echo ${paths[index]//\\/}
to see the result without modifying the value in-place.
You can use this :
sed 's#\\##g'
But the problem is when you encounter a backslash that you actually want in the string, but is escaped. In that case :
sed 's/\\\\/\x1/' |sed 's/[\]//g' | sed 's/\x1/\\/g'
Replaces the double backslash with with a temp character[SOH], replaces all other backslashes and then restores the backslash that is needed.