Filling in gaps with awk or anything - bash

Question

I have a list such as below, where the 1 column is position and the other columns aren't important for this question.
1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
I want to fill in the gaps such that the list is continuous and it reads
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
I am familiar with awk and shell scripts, but whatever way it can be done is fine with me.
Thanks for any help..

Answer 1

this one-liner may work for you:
awk '$1>++p{for(;p<$1;p++)print p"  0 0 0 0 0"}1' file
with your example:
kent$ echo '1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5'|awk '$1>++p{for(;p<$1;p++)print p" 0 0 0 0 0"}1'
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5

Answer 2

You can use the following awk one-liner:
awk '{b=a;a=$1;while(a>(b++)+1){print(b+1)," 0 0 0 0 0"}}1' input.file
Tested with here-doc input:
awk '{b=a;a=$1;while(a>(b++)+1){print(b+1)," 0 0 0 0 0"}}1' <<EOF
1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
EOF
the output is as follows:
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
Explanation:
On every input line b is set to a where a is the value of the first column. Because of the order in which b and a are initialized, b can be used in a while loop that runs as long as b < a-1 and inserts the missing lines, filled up with zeros. The 1 at the end of the script will finally print the input line.

Answer 3

This is only for fun:
join -a2 FILE <(seq -f "%g 0 0 0 0 0" $(tail -1 FILE | cut -d' ' -f1)) | cut -d' ' -f -6
produces:
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5

Answer 4

Here is another way:
awk '{x=$1-b;while(x-->1){print ++b," 0 0 0 0 0"};b=$1}1' file
Test:
$ cat file
1 1 2 3 4 5
2 1 2 3 4 5
5 1 2 3 4 5
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5
$ awk '{x=$1-b;while(x-->1){print ++b," 0 0 0 0 0"};b=$1}1' file
1 1 2 3 4 5
2 1 2 3 4 5
3 0 0 0 0 0
4 0 0 0 0 0
5 1 2 3 4 5
6 0 0 0 0 0
7 0 0 0 0 0
8 1 2 3 4 5
9 1 2 3 4 5
10 1 2 3 4 5
11 1 2 3 4 5