Put print result in a variable or concat text variable - macos

Question

I have this
var1='hello'
var2='world'
I need helloworld in a variable. If I write
print $var1$var2 # prints "helloworld"
But when I write
var3=$var1$var2 # var3 is not "helloworld"
I tried
var3=$(print $var1$var2)
var3='$var1$var2'
Sure the only one I did not try is the good one but which one?
Edit after discovery curious thing:
If I do exactly as I wrote
var3=$var1$var2
print $var3 # prints "helloworld"
But in fact I wrote this to resume my problem with others variables, my own variables. The difference is that $var1 is the result of a awk command to extract this text from a file.
I try to explain:
myvar1 the variable I realy use is definite like this:
myvar1=awk -F"/" '${print $1}' $dir_path
And not like this
myvar1=world
That is only to ask you the question. I don't know why, but this seems to be important.
If I do the same thing with my variables that with var3=$var1$var2, it doe snot work. To get the right result with my variables, I have just found I must use:
myvar3=echo$myvar1$myvar2
print $myvar3 # gives the right result.
On the other hand, if I do
var3=echo$var1$var2
print $var3 # prints "echohelloworld"
How to explain that?
I am using Mac OS X, the command-line terminal and Zsh.

Answer 1

If you have
var1='hello'
var2='world'
Any of these will result in print $var3 # prints "helloworld"
var3="$var1$var2"
var4=$var1$var2
var5=$(print $var1$var2)
You should use the first one. You can verify either by printing the variables or by calling set:
$ print var3 # prints "helloworld"
$ set|grep var
var1=hello
var2=world
var3=helloworld
var4=helloworld
var5=helloworld
Your edit says, that you use: myvar1=awk -F"/" '{print $1} $dir_path. This line is missing a $():
myvar1=$(awk 'BEGIN { print "hello" }')
echo $myvar1 # prints hello