I have finally figured out how to perform a somewhat successful UNION query with left joins! Yeah (snaps for me)..
Now, the problem I'm running into is that I can get it to Group them so that I only have one entry for each code...
SELECT vg.*, lh.*
FROM tbl_vluchtgegevens vg
INNER JOIN tbl_luchthaven lh
ON lh.luchthavenID = vg.vertrekluchthaven
UNION
SELECT vg.*, lh.*
FROM tbl_vluchtgegevens vg
INNER JOIN tbl_luchthaven lh
ON lh.luchthavenID = vg.aankomstluchthaven
GROUP BY lh.luchthavencode;
I've tried grouping based on the luchthavencode, which is what i'm displaying. I've tired the luchthavenID...
Here is a sample of what I am trying to accomplish (note: I did not spend a lot of time reproducing the field names in my tables, I just used some shorthand, i will translate that later)
Here is an example of what I am trying to achieve. This board won't let me post until I have at least 10 reputation.
http://globe-trekking.com/union_query_example.jpg
kind of pulling my hairs out on this... though i'm sure it's simple?
Any help would be great!
Regards,
Try this and see if it fits for you
SELECT
Luchthaven.Luchthaven.luchthavencode as CODE,
Luchthaven.luchthavennaam as NAME
FROM
Luchthaven , Vluchtgegens
WHERE
Luchthaven.LID = Vluchtgegens.vertrek AND
Luchthaven.LID = Vluchtgegens.aankomst AND
ORDER BY Luchthaven.luchthavennaam DESC
GROUP BY Luchthaven.luchthavennaam
I was able to get it by using:
select *
from
(
SELECT vg.vertrekluchthaven AS code
FROM tbl_vluchtgegevens vg
WHERE vg.vertrekdatum <=NOW()
UNION
SELECT vg.aankomstluchthaven AS code
FROM tbl_vluchtgegevens vg
WHERE vg.vertrekdatum <=NOW()
) vg
INNER JOIN tbl_luchthaven lh
ON lh.luchthavenID = vg.code
Group by vg.code
Order by lh.luchthavencode;
Thanks for your help... sorry if my thought process was not very clear.
Related
I had an issue with the LEft outer join and my query was little bit wierd. Tried searching for it , but did not get any clues.
This is happening due to were clause has been added.
The query below is not working as expected.
SELECT count(*) from
BN_DATA_TEMP.EDS_DELIVERYITEM_GBQ_SAMPLE_DATA A
LEFT OUTER JOIN BN_DATA_TEMP.TBL_EDS_DELIVERYITEMS_DATES B
on (
to_Date(substr(A.LASTUPDATEDTIME,1,10)) = '2020-05-31'
and to_Date(substr(B.LASTUPDATEDTIME,1,10)) = '2020-05-31'
and A.deliveryid = B.deliveryid )
where B.deliveryid is null;
Trying to get Records in A but not in B. But the count is very different and it is wrong.
I need to consider only the dates with 2020-05-31 from both the tables.
Modified like the below and it gave the correct result.
select count(*) from
(SELECT * from
BN_DATA_TEMP.EDS_DELIVERYITEM_GBQ_SAMPLE_DATA where to_Date(substr(LASTUPDATEDTIME,1,10)) = '2020-05-31' ) A
LEFT OUTER JOIN
(select * from
BN_DATA_TEMP.TBL_EDS_DELIVERYITEMS_DATES where to_Date(substr(LASTUPDATEDTIME,1,10)) = '2020-05-31' ) B
on A.deliveryid = B.deliveryid
where B.deliveryid is null;
I have never use much of Left outer joins for Data validation. So thought of posting over here and learn the same.
Thanks in Advance.
I need to create a query that shows the "Legal Entity", "Application Name", "Close Date" and "Period" I'm working with Oracle R11, Right now I've found the query for
"Legal Entity"
SELECT name
FROM hr_organization_information HOI
INNER JOIN hr_all_organization_units HAOU
ON HOI.ORGANIZATION_ID = Haou.Organization_Id
WHERE HOI.org_information_context LIKE 'Legal Entity Accounting'
ORDER BY NAME ASC;
and for "Application Name, Close Date, Period"
SELECT A.APPLICATION_ID,
B.APPLICATION_NAME,
TO_CHAR(A.END_DATE,'HH24:MI DD-MON-YYYYI'),
A.PERIOD_NUM
FROM GL_PERIOD_STATUSES A
INNER JOIN FND_APPLICATION_TL B ON A.APPLICATION_ID = B.APPLICATION_ID
WHERE A.Application_Id=101
AND LANGUAGE='US'
OR A.APPLICATION_ID=200
AND LANGUAGE='US'
OR A.APPLICATION_ID=222
AND LANGUAGE='US';
Separately but I haven't found the way to join them in one query, can you help me with that?
Antonio, I think Brian has given you sound advice. Posting to an EBS forum (or whatever application this is) might also be worthwhile if his advice has not lead you to the answer. I will offer that sometimes the way to join table_A and table_B is through table_C. That is, if you do not find any directly related data in the queries of one se to one of the tables in the other set then look at the FK defined on and pointing to these tables to see if you can find a table not currently part of either query that relates the sets. You figure out how to join each of your current queries to it and that is how you join the two queries together.
Thank you all!
The advices that all of you gave to me were useful, I've found the table HR_LEGAL_ENTITIES (Table C) that have two columns that allow me to join Table A with Table B, the final query was:
SELECT HAOU.NAME,
FAT.APPLICATION_NAME,
TO_CHAR(GPS.END_DATE,'HH24:MI DD-MON-YYYY'),
GPS.PERIOD_NUM
FROM HR_ALL_ORGANIZATION_UNITS HAOU
INNER JOIN HR_LEGAL_ENTITIES HLE
ON HLE.ORGANIZATION_ID = HAOU.ORGANIZATION_ID
INNER JOIN GL_PERIOD_STATUSES GPS
ON HLE.SET_OF_BOOKS_ID = GPS.SET_OF_BOOKS_ID
INNER JOIN FND_APPLICATION_TL FAT
ON GPS.APPLICATION_ID = FAT.APPLICATION_ID
WHERE GPS.Application_Id IN (101,200,222) AND LANGUAGE='US'
ORDER BY NAME ASC;
Regards!
I am very new at using Oracle (in the class now). I have a problem with the query I am trying to run. I have researched a lot of other answers on this site and none of them seem to apply directly to my problem so the solutions aren't working.
I need to find the total amount spent on lunches by each employee.
Show first_name, last_name, credit_limit, and total_price_spent in your results.
Order the answer by total_price_spent in descending order. Only show the employees who spent more than their credit limit.
I figured out how to do everything but the part about showing only the employees who spent more than their credit limit. I tried to use a select statement at the end but discovered that I can't use an alias in a select statement so I don't really know where to go from here. Any help would be appreciated. This is what I have so far.
select a.first_name, a.last_name, credit_limit, sum(c.quantity * d.price) as total_price_spent
from l_employees a join l_lunches b on a.employee_id = b.employee_id join l_lunch_items c on b.lunch_id = c.lunch_id join l_foods d on c.supplier_id = d.supplier_id and c.product_code = d.product_code
group by a.first_name, a.last_name, a.credit_limit
order by total_price_spent desc;
As Mike said : Add HAVING
select a.first_name, a.last_name, credit_limit, sum(c.quantity * d.price) as total_price_spent
from l_employees a join l_lunches b on a.employee_id = b.employee_id join l_lunch_items c on b.lunch_id = c.lunch_id join l_foods d on c.supplier_id = d.supplier_id and c.product_code = d.product_code
group by a.first_name, a.last_name, a.credit_limit
having sum(c.quantity * d.price) > credit_limit
order by total_price_spent desc;
I think what you're looking for is a HAVING clause. It's like a WHERE, but is used when you're using group by. You want to drop it in between the group by and order by. Something like 'HAVING total > a.credit_limit' should work. If using the alias 'total' doesn't work (haven't tested this), you might have to do 'sum(c.quantity * d.price)' again in the HAVING clause instead of using total, so HAVING sum(c.quantity * d.price) > a.credit_limit.
I have this HQL where I need a subquery. I know it's not legal to make a subquery in order by, but I can't figure out how to do it
SELECT OBJECT(l) FROM InboundNotification l
INNER JOIN l.item item
WHERE l.job = ? ORDER BY (SELECT SUM(itemInst.qty)
FROM ItemInst itemInst
WHERE itemInst.receivedFromNotification_id = l.id) DESC, item.localId DESC
The above fails since I have the subquery in order by. How can I reconfigure it so this will work?
A sort in the Java code is not a option here even though it's almost as efficient.
ok, i haven't a notion of hql, but I'm gonna assume it's something like other query languages dive in here given that this question has remained unanswered for so long.
could you rewrite the query so it's something like this:
SELECT OBJECT(l), SUM(itemInst.qty) theSum
FROM InboundNotification l
INNER JOIN l.item item WHERE l.job = ?
INNER JOIN ItemInst on ItemInst.KEY = l.KEY
WHERE itemInst.receivedFromNotification_id = l.id)
GROUP BY OBJECT(l)
ORDER BY theSum
where ItemInst.KEY = l.KEY shows the appropriate relationship for your situation (if such a relationship exists)
The RIGHT JOIN on this query causes a TABLE ACCESS FULL on lims.operator. A regular join runs quickly, but of course, the samples 'WHERE authorised_by IS NULL' do not show up.
Is there a more efficient alternative to a RIGHT JOIN in this case?
SELECT full_name
FROM (SELECT operator_id AS authorised_by, full_name
FROM lims.operator)
RIGHT JOIN (SELECT sample_id, authorised_by
FROM lims.sample
WHERE sample_template_id = 200)
USING (authorised_by)
NOTE: All columns shown (except full_name) are indexed and the primary key of some table.
Since you're doing an outer join, it could easily be that it actually is more efficient to do a full table scan rather than use the index.
If you are convinced the index should be used, force it with a hint:
SELECT /*+ INDEX (lims.operator operator_index_name)*/ ...
then see what happens...
No need to nest queries. Try this:
select s.full_name
from lims.operator o, lims.sample s
where o.operator_id = s.authorised_by(+)
and s.sample_template_id = 200
I didn't write sql for oracle since a while, but i would write the query like this:
SELECT lims.operator.full_name
FROM lims.operator
RIGHT JOIN lims.sample
on lims.operator.operator_id = lims.sample.authorized_by
and sample_template_id = 200
Does this still perform that bad?