What must be the problem with this code:
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title><?php echo $title; ?></title>
<?php
echo link_tag('assets/css/jquery.mobile-1.3.2.min.css', 'stylesheet');
echo script_tag('assets/js/jquery-1.10.2.min.js');
echo script_tag('assets/js/jquery.mobile-1.3.2.min.js');
?>
</head>
<body>
<div data-role="page">
<header data-role="header">
Show
<h3><?php echo $title; ?></h3>
<div data-role="controlgroup" data-type="horizontal" class="ui-btn-right">
My Account
Logout
</div>
</header>
I'am using jquery mobile for my client-side script and PHP(codeigniter) for server-side script.
When I refresh the page after including the in anchor the page now doesn't display the page anymore.
Can anyone tell what's wrong with the code or I'am just missing something.
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Event_management_c extends CI_Controller {
public function __construct() {
parent::__construct();
$this->load->helper('html', 'url', 'form');
}
public function index() {
$data['title'] = 'Events';
$data['reply_title'] = 'Reply Message';
$this->load->view('fragments/header', $data);
$this->load->view('fragments/nav', $data);
$this->load->view('events/index', $data);
$this->load->view('fragments/footer', $data);
}
}
?>
Problem here
Logout
to
Logout
you can use template library for codeigniter like TEMPLATE LIBRARY
and reload the script and style files.
Based on your extra answers from the comments; the problem is most likely that the function site_url() isn't defined. The result of this is a fatal error, which isn't shown to you due to settings in php concerning error_report.
To solve this, run $this->load->helper('url') in relevant controller, or simply add url to the helper array in application/config/autoload.php. Since this function is so common, I recommend to autoload it.
Related
I'm learning Laravel, and I've been trying to pass data between a controller and a view, but I'm still getting the same error on the page. Does anyone know how to fix this? Even with this small code, it doesn't seem to work. Do I need to make a configuration or something?
I've tried
->with('message', 'Hi Victoria')
view
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<title>App title</title>
<html>
<body>
<h1>Hello, {{ $message }}</h1>
</body>
</html>
</html>
controller
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Models\Hello;
class HelloWorld extends Controller
{
public function sayHello()
{
return view('hello', ['message' => 'Hi Victoria']);
}
}
web.php
Route::get('/', function(){
return view('hello');
});
The problem is that you have written a controller, but you are not using it. In your route ( web.php ), you have returned the view.
You should take a look at Laravel's documentation regarding how to make a route point to a controller method
So, you would need to change your route in web.php to
use App\Http\Controllers\HelloWorld;
Route::get('/', [HelloWorld::class, 'sayHello']);
In web.php, you should write the following code to use the HelloWorld controller:
use App\Http\Controllers\HelloWorld;
Route::get('/', [HelloWorld::class, 'sayHello']);
you can try this in web.php
Route::get('/', function(){
return view('hello',['message' => 'Hi Victoria']);
});
i'm try to get news_id from database but when go to view say : error -> Trying to get property of non-object / Message: Undefined variable: data
this model - >
class Model1 extends CI_Model {
public function get_art()
{
$query = $this->db->get('entries');
return $query->result();
}
}
here controller Code - >
class Home extends CI_Controller
{
public function members()
{
$this->load->model('model1');
$data=$this->model1->get_art();
$this->load->view('members', $data);
}
}
and this Full View - >
<html>
<head>
<meta charset="utf-8">
<title>Welcome to CodeIgniter</title>
</head>
<body>
<h1>
<? echo $data->body; ?>
</h1>
</body>
</html>
This is because of you invalid pass data to view. At controller replace line
$data=$this->model1->get_art();
with
$data["query"] = $this->model1->get_art();
Then at view you will have var $query with results of your database query.
You can use it like this:
<h1>
<? foreach($query as $row) {
echo $row->body;
}
?>
</h1>
I'm a new to CodeIgniter and I have a problem when I display a list of items, I want each items to be a link, so when the user clicks that particular item, it will show the details of that item. Or perhaps give some suggestion on what I should google for. I have literally no idea whats terms or keywords that should I search about.
controller:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Site extends CI_Controller
{
public function index()
{
$this->getListOfAgent();
}
function getListOfAgent()
{
$this->load->model("agentDB_model");
$data['results'] = $this->agentDB_model->getAllAgentInfo();
$this->load->view("viewAgent_view", $data);
}
function userInformation()
{
//how to i get the selected item which the user clicked and show the details accordingly?
}
}
model
<?php
class agentDB_model extends CI_Model
{
function getAllAgentInfo()
{
$query = $this->db->query("SELECT * FROM user");
return $query->result();
}
function addAgent($newAgent)
{
$this->db->insert("user", $newAgent);
}
}
view
<!DOCTYPE html>
<html lang="en">
<head>
<title>Welcome</title>
</head>
<body>
<div id="content">
<h1>Home Page</h1>
<p>List Of Agent in database</p>
</div>
<?php
foreach($results as $row)
{
echo "<a href = 'Site/userInformation'>$row->userName</a>";
echo "</br>";
echo "</br>";
}
//$this->load->controller(Site/userInformation);
?>
<div id="footer">
<p>Copyright (c) 2012 basicsite.com</p>
</div>
</body>
</html>
You need to tell the Site/userInformation method for what record you want the information. You use URI segments for this.
So, in your view, change the following line:
echo "<a href = 'Site/userInformation'>$row->userName</a>";
to:
echo "<a href = 'Site/userInformation/$row->userID'>$row->userName</a>";
Then, in your controller method, add the parameter to the method declaration:
function userInformation($userID)
{
// now, you use the model to get the correct record from the db based on
// the $userID and display the information
}
I am more efficient at setting up my view logic with straight up php. Blade is cool but it's not for me. I am trying to translate all the Blade specific examples and docs to just php. I don't like the fact that I need to assign all the variables for my views in an array of View::make(). I did found all of this so far.
controllers/home.php:
class Home_Controller extends Base_Controller {
public $layout = 'layouts.default';
public function action_index()
{
$this->layout->name = 'James';
$this->layout->nest('content', 'home.index');
}
}
views/layouts/default.php:
// head code
<?php echo Section::yield('content') ?>
// footer code
views/home/index.php
<?php Section::start('content'); ?>
<?php echo $name ?>
<?php Section::stop(); ?>
I am greeted with this error: Error rendering view: [home.index] Undefined variable: name. I know that $this->layout->nest('content', 'home.index', array('name' => 'James')); works but that negates my point about having to send all my variables to an array. This can't be the only way.
The view templating docs doesn't seem to touch on doing variables with nested views from controllers.
you can pass variables this way;
class Home_Controller extends Base_Controller {
public $layout = 'layouts.default';
public function action_index()
{
$this->layout->nest('content', 'home.index')
->with('name', 'James');
}
}
Here's an example of how I'm templating with laravel.
Class Products_Controller extends Whatever_Controller {
public $layout = 'layouts.main';
public function get_index()
{
// .. snip ..
$view = View::make('home.product')
->with('product', $product); // passing all of my variable to the view
$this->layout->page_title = $cat_title . $product->title;
$this->layout->meta_desc = $product->description;
$this->layout->content = $view->render(); // notice the render()
}
}
my main layout looks like
<html>
<head>
<title> {{ $page_title }} </title>
<meta name="description" content="{{ $meta_desc }}" />
</head>
<body>
{{ $content }}
</body>
</html>
and the home/product page looks like
<div class="whatev">
<h1> {{ $product->title }} </h1>
<p> {{ $product->description }} </p>
</div>
Hope that helps you clear some things up
I know it has been a while on this question, but since it was asked, Laravel 4 has come out and there are newer ways to do things.
If you are reading this these days you should consider using View Composers to prepare the data for your views.
Example:
class MyViewComposer {
public function compose($view){
$view->title = 'this is my title';
$view->name = 'joe';
...
$view->propertyX = ...;
}
}
After setting up your view composer register it with the app:
View::composer('home.index', 'MyViewComposer');
For more information check out the laravel docs on view composers:
http://laravel.com/docs/responses
I am following the guide here to play around with the facebook php sdk, but my little app doesn't work. It keeps staying on the login page.
Here is the controller:
<?php if (!defined('BASEPATH')) exit('No direct script access allowed');
class Facebook_connect extends CI_Controller
{
function __construct()
{
parent::__construct();
$this->load->helper(array('form','url'));
$this->load->library('fb_connect');
}
function index()
{
}
function test()
{
$data['title'] = 'Facebook API Testing';
$data['user_id'] = $this->fb_connect->user_id;
if($data['user_id'])
{
$data['user_profile'] = $this->fb_connect->user;
}
if($data['user_id'])
{
$data['logout_url'] = $this->fb_connect->getLogoutUrl();;
}
else
{
$data['login_url'] = $this->fb_connect->getLoginUrl();
}
$this->template->load('template', 'facebook_connect/test', $data);
}
}
?>
Here is the view:
<h1>php-sdk</h1>
<?php if($user_id): ?>
Logout
<?php else: ?>
<div>
Login using OAuth 2.0 handled by the PHP SDK:
Login with Facebook
</div>
<?php endif ?>
<h3>PHP Session</h3>
<pre><?php print_r($_SESSION); ?></pre>
<?php if($user_id): ?>
<h3>Your Avata</h3>
<img src="https://graph.facebook.com/<?php echo $user_id; ?>/picture">
<h3>Your User Object (/me)</h3>
<pre><?php print_r($user_profile); ?></pre>
<?php else: ?>
<strong><em>You are not Connected.</em></strong>
<?php endif ?>
I get stuck at it and couldn't figure out why.
Use this example provided by facebook:
https://github.com/facebook/php-sdk/blob/master/examples/example.php
But keep your $this->load->library('fb_connect'); and make sure to add $this->fb_connect to any facebook library calls in that example.
It works 100%. Try to just put all the code in the controller to make sure it works, then distribute as needed. Not sure what your problem is, perhaps faulty return url.