How can I get specific data from a file in ruby? I want to get some 10. ip addresses from a file set up like this...
Whatever: xathun
ip_address: 10.2.232.6
etc: aouoeu
more: snthuh
I want to push the ip addresses into an array.
I can pull 10. addresses out of text. I was hoping for a more accurate way to do it as in only the data after the 'ip_address:' label in case there is unwanted matching data.
s_text = File.open("test.txt",'r').read
ip_addresses = s_text.scan(/\d+.\d+.\d+.\d+/)
puts ip_addresses.inspect #=> ["10.2.232.6"]
Here's a simple enough solution.
open('<textfile path>') { |f| puts f.grep(/10\./) }
If the file is setup like that throughout you can do:
arr = []
File.open("text").each_line do |line|
parts = line.split(":")
arr << parts[1].strip if parts[0] == "ip_address"
end
adding to array as you go through once, one line at a time:
ip_data.txt
Whatever: xathun
ip_address: 10.2.232.6
etc: aouoeu
more: snthuh
Whatever: badone
ip_address: 66.8.103.3
etc: huh
more: noooo
Whatever: blah
ip_address: 10.9.244.13
etc: hello
more: goodbye
code
found_tens = []
File.open('ip_data.txt') {|f|
f.each {|line|
line = line.chomp
next if line.empty?
found_tens << $1 if line =~ /^ip_address:\s+(10\.\d+\.\d+\.\d+)/
}
}
p found_tens #["10.2.232.6", "10.9.244.13"]
Related
I want to create a facter that returns all users.
Facter.add("sysusers") do
setcode do
File.readlines('/etc/passwd').each do |line|
line.match(/^[^:]+/)[0]
end
end
end
Then in my .pp file I have this:
$users = inline_template("<%= scope.lookupvar('sysusers') %>")
$users.each |String $user| {
notify { "$user":}
}
This should work but the facter returns just one letter at a time.
So notify { "$user":} just prints:
Notify[r]
Notify[o]
And then it craches because the next letter is also "o" (two o`s in "root" and root is the first user stated in /etc/passwd).
So how can I print all the users?
EDIT
With the edit to:
Facter.add("sysusers") do
setcode do
File.readlines('/etc/passwd').each do |line|
line.match(/^[^:]+/).to_s
end
end
end
Then the output is:
root#mymachine]# facter sysusers
[
"root:x:0:0:root:/root:/bin/bash
",
"bin:x:1:1:bin:/bin:/usr/bin/nologin
",
"daemon:x:2:2:daemon:/:/usr/bin/nologin
...
...
So it still does not seem to work as expeced.
This is the match you want.
line.match(/^[^:]+/).to_s
When you add [0], it is taking the first character from the string that is the user name.
EDIT
File.readlines('/etc/passwd').collect do |line|
line.match(/^[^:]+/).to_s
end
That will collect an array which to be returned in your setcode.
Parsing /etc/passwd is a clunky approach to your problem.
It's cleaner to use the Etc module
require 'etc'
result = []
Etc.passwd { |user| result << user.name }
result
Use the following ruby code, which reads and prints the user names from /etc/passwd file.
IO.readlines("/etc/passwd").each do |val|
user = val.split(":").first
puts user
end
I've got a list of devices:
ipc-bei640-r-br-01
ipc-bei640-r-br-02
ipc-bei640-r-br-03
ipc-bei640-r-br-04
ipc-bei640-r-br-05
ipc-bem640-r-br-01
ipc-bem640-r-br-02
ipc-bem640-r-br-03
ipc-crg660-r-br-02
ipc-geb680-r-br-04
ipc-lgv630-r-br-01
This small little ruby script counts the lines of the file braslist.txt scans it with a regex and writes the results to a newfile called "strippedfile.txt"
lines = IO.readlines("/usr/local/bin/braslist.txt")
# Linecount is forwarded to StdOut.
puts lines.length
str = File.read('braslist.txt')
file_name = ['strippedfile.txt']
file_name.each do |file_name|
text = File.read(file_name)
new_contents = str.scan(/^ipc-(?<bng>[a-z]{3}\d{3})-r-br(?<nr>-\d{2})$/)
# open and write to a file with ruby
open('strippedfile.txt', 'w') { |f|
f.print new_contents
}
end
Now what i cant seem to fix, is in the new file "strippedfile" the results are always ["bei640", "-01"] ["bei640", "-02"] ["bei640", "-03"]
And i am trying to get all results in this format:
bei640-01
bei640-02
bei640-03
bei640-04
scan returns an array of matches, you probably want to join them:
- new_contents = str.scan(/^ipc-(?<bng>[a-z]{3}\d{3})-r-br(?<nr>-\d{2})$/)
+ new_contents = str.scan(/^ipc-(?<bng>[a-z]{3}\d{3})-r-br(?<nr>-\d{2})$/).map(&:join)
To print everything without quotes and brackets line by line:
- f.print new_contents
+ f.puts new_contents
Assuming your resultant array is
a = [["bei640", "-02"], ["bei640", "-03"]]
You can use join to get your desired result
a.map{|i| i.join } #=> ["bei640-02", "bei640-03"]
or use shortcut as mudasobwa answered
a.map(&:join) #=> ["bei640-02", "bei640-03"]
I have a question about Ruby. What I want to do is first to sort my items ascending and then write them out to a CSV-file. Now, the problem is further complicated by the fact that I want to iterate over a lot of CSV-files. I found this thread and the answer looks fine, but I am not able to get more than the last line written to my output file.
How can I get the whole data sorted and written to different CSV-files?
My code:
require 'date'
require 'csv'
class Daily <
# Daily has a open
Struct.new(:open)
# a method to print out a csv record for the current Daily.
def print_csv_record
printf("%s,", open)
printf("\n")
end
end
#------#
# MAIN #
#------#
# This is where I iterate over my csv-files:
foobar = ['foo', 'bar']
foobar.each do |foobar|
# get the input filename from the command line
input_file = "#{foobar}.csv"
# define an array to hold the Daily records
arr = Array.new
# loop through each record in the csv file, adding
# each record to my array while overlooking the header.
f = File.open(input_file, "r")
f.each_with_index { |row, i|
next if i == 0
words = row.split(',')
p = Daily.new
# do a little work here to convert my numbers
p.open = words[1].to_f
arr.push(p)
}
# sort the data by ascending opens
arr.sort! { |a,b| a.open <=> b.open }
# print out all the sorted records (just print to stdout)
arr.each { |p|
CSV.open("#{foobar}_new.csv", "w") do |csv|
csv << p.print_csv_record
end
}
end
My input CSV-file:
Open
52.23
52.45
52.36
52.07
52.69
52.38
51.2
50.99
51.41
51.89
51.38
50.94
49.55
50.21
50.13
50.14
49.49
48.5
47.92
My output CSV-file:
47.92
You need to put the iteration inside the open CSV file:
CSV.open("#{foobar}_new.csv", "w") do |csv|
arr.each { |p|
csv << p.print_csv_record
}
end
I'm trying to open a CSV file, look up a string, and then return the 2nd column of the csv file, but only the the first instance of it. I've gotten as far as the following, but unfortunately, it returns every instance. I'm a bit flummoxed.
Can the gods of Ruby help? Thanks much in advance.
M
for the purpose of this example, let's say names.csv is a file with the following:
foo, happy
foo, sad
bar, tired
foo, hungry
foo, bad
#!/usr/local/bin/ruby -w
require 'rubygems'
require 'fastercsv'
require 'pp'
FasterCSV.open('newfile.csv', 'w') do |output|
FasterCSV.foreach('names.csv') do |lookup|
index_PL = lookup.index('foo')
if index_PL
output << lookup[2]
end
end
end
ok, so, if I want to return all instances of foo, but in a csv, then how does that work?
so what I'd like as an outcome is happy, sad, hungry, bad. I thought it would be:
FasterCSV.open('newfile.csv', 'w') do |output|
FasterCSV.foreach('names.csv') do |lookup|
index_PL = lookup.index('foo')
if index_PL
build_str << "," << lookup[2]
end
output << build_str
end
end
but it does not seem to work
Replace foreach with open (to get an Enumerable) and find:
FasterCSV.open('newfile.csv', 'w') do |output|
output << FasterCSV.open('names.csv').find { |r| r.index('foo') }[2]
end
The index call will return nil if it doesn't find anything; that means that the find will give you the first row that has 'foo' and you can pull out the column at index 2 from the result.
If you're not certain that names.csv will have what you're looking for then a bit of error checking would be advisable:
FasterCSV.open('newfile.csv', 'w') do |output|
foos_row = FasterCSV.open('names.csv').find { |r| r.index('foo') }
if(foos_row)
output << foos_row[2]
else
# complain or something
end
end
Or, if you want to silently ignore the lack of 'foo' and use an empty string instead, you could do something like this:
FasterCSV.open('newfile.csv', 'w') do |output|
output << (FasterCSV.open('names.csv').find { |r| r.index('foo') } || ['','',''])[2]
end
I'd probably go with the "complain if it isn't found" version though.
I have the following code, which works fine. The problem is that I get the following output:
Device ID: SEP1C17D3415659
IP address: 10.2.3.101
I would like to get:
SEP1C17D3415659 10.2.3.101
Thanks for your help
require 'net/telnet'
require '/apps/dateformat'
#tdate = Formatdate.new.mydate
hosts = %w"SW3"
hosts.each do |hostname|
tn = Net::Telnet::new("Host" => "#{hostname}",
"Timeout" => 10000,
"Prompt" => /[$%#>] \z/n)
tn.cmd('String' =>'user' , 'Match'=>/Password:/) { |c| puts c }
tn.cmd('String' =>'password', 'Match'=>/#/) { |c| puts c }
tn.cmd('String' =>'terminal length 0', 'Match'=>/#/) { |c| puts c }
File.open("/agents/#{hostname}-#{#tdate}-agents.txt",'w') do |o|
run=tn.cmd('String' =>'sh cd ne de | inc Device ID: | IP address:', 'Match'=>/#/) { |c| puts c }
run.each_line do |re|
mac = re.match /Device ID: ([\S]+)/
#ip = re.match /([\S]+) address/
ip = re.match /IP address: ([\S]+)/
o.puts mac
o.puts ip
end
end
end
puts automatically prints a new line after each output. Simply put both on the same line.
outputString = mac + " " + ip
o.puts outputString
If you have other output functions available such as print, it will function without putting a newline between the two statements.
You're correctly specify the grouping you want for your regular expression, but you're not using it when printing it out.
Your regular expression is:
mac = re.match /Device ID: ([\S]+)/
and this matches the whole line Device ID: SEP1C17D3415659, putting the part you want (SEP1C17D3415659) into a group so you can get at it later. However you then print it out using
o.puts mac
This gives the whole match, not just the group. What you want is this instead:
o.puts mac[1]
which specifies just the group.
Also, as Cody says, puts adds a newline on each call. If you want both matches to print on the same line try something like:
o.print "#{mac[1]} #{ip[1]}\n"
instead.
Edit:
I'm not familiar with net/telnet or the command you're running, but it looks like you're running a certain command, then filtering for certain lines and then printing some info from those lines. If this is the case, then any lines that don't match will give you nil for mac and ip so you'll get "undefind method []" on those lines.
If this is the case you can simply use:
o.print "#{mac[1]} #{ip[1]}\n" unless mac.nil?
You might find it worth while to restructure your code slightly to better express what you're doing, by combining the two regular expressions into one. Without knowing the structure of the actual lines I can't create the real expression you'll need, but it would look something like this:
run.each_line do |line|
match = line.match /^Device ID: ([\S]+), IP address: ([\S]+)$/ #these are the lines we want
next unless match #skip lines we don't want
o.print "#{match[1]} #{match[2]}\n" #print the details we're interested in
end