Printing a specific line of a file in windows cmd - cmd

I am trying to print specific lines of a text file stored on my computer by using the Windows cmd.
For instance if I want to output line 17 of the textfile in the cmd, how is this possible? I have been using quite some time on this and I am running out of ideas.
Could you please help?
Regards
Magnus

#echo off
for /f "tokens=1,* delims=]" %%a in ('find /n /v "" ^< "myfile.txt" ^| findstr "^\[17\]" ') do set "variable=%%b"
echo "%variable%"

Related

FOR command won't run in .cmd file, but runs at command prompt

When I try to run file.cmd containing the following:
for /l %m in (1,1,1) do #for /f "tokens=1,2* delims=:" %a in ('findstr /n /r "^" csv\data.csv ^| findstr /r "^%m:"') do #echo %b >csv\header.csv
I get this error:
" m:")'. Unexpected at this time
But when I run that same command at a command prompt (no .cmd file), it works.
You realize there is a much much much simpler way to get the first line of a file into a variable.
set /p header=<data.csv
echo %header%>header.csv

Batch scripting, mutlple finds and multple do sets

At the moment I am running the following to get some information from 'systeminfo', however it needs to run systeminfo twice which takes some time. How would I be able to do multple 'Find"XXX" do sets'?
For /f "delims=" %%A IN ('systeminfo ^| Find "OS Name"') DO Set "VarA=%%A"
For /f "delims=" %%A IN ('systeminfo ^| Find "BIOS Version"') DO Set "VarB=%%A"
Any help is greatly appreciated.
Next code snippet could work (note set commands are merely ECHOed for debugging purposes; remove capitalized ECHO no sooner than debugged):
For /f "delims=" %%A IN ('systeminfo') DO (
For /F "delims=" %%G IN ('echo %%A ^| Find /I "OS Name"') Do ECHO Set "VarA=%%A"
For /F "delims=" %%G IN ('echo %%A ^| Find /I "BIOS Version"') DO ECHO Set "VarB=%%A"
)
However, follow Stephan's advice and parse wmic output rather (do not forget /value option). To do that correctly, note great Dave Benham's article WMIC and FOR /F: A fix for the trailing <CR> problem
I too would use WMIC, but there is a simple solution if you want to use SYSTEMINFO - use FINDSTR with two /C:"search strings"
for /f "tokens=1,2*" %A in ('systeminfo ^| findstr /c:"OS Name" /c:"BIOS Version"') do set "%A=%C"
The above will define two variables on an English machine: OS and BIOS.
Thanks for the replies guys.
I wanted to set the bit version windows the batch file would run on, I figured it out ages ago but thought I would post it here for those that came across it:
echo %PROCESSOR_ARCHITECTURE% | find "64" > NUL
If %ERRORLEVEL% equ 0 (Set bit=64) else (Set bit=32)
Thanks!

windows 7 not generating txt report

I want to generate a txt file with my dns history. Although the batch script executes just fine on windows 8, when i run it on windows 7 it simply creates a blank txt file. Does anyone knows why this is happening?
Here's the batch script
#echo off
setlocal enableextensions
set "baseName=dnshistory"
set "count=0"
for /f "delims=%baseName%." %%a in (
'dir /b /o-d "%baseName%*.txt" 2^>nul'
) do ( set /a "count=%%a+1" & goto saveData )
:saveData
ipconfig /displaydns | find "Record Name" > "%baseName%%count%.txt"
Is you Windows 7 version in English too ?
Open a CMD windows and test just the command :
ipconfig /displaydns | find /i "Record Name"
and look if something is displayed.
If not, try just the command :
ipconfig /displaydns
and look the language used Then correct your code with the correct words.
IE in Portuguese it will be :
ipconfig /displaydns | find /i "Nome do Registro"
try this for a language independent solution:
:saveData
(for /f "tokens=2 delims=:" %%a in ('ipconfig /displaydns') do (
echo %%a| find "." |findstr /v /r "[0-9]$"
))>file.txt
(take every line, filter those, that have a . after a : (second token) and filter out all lines that end with a number)
EDIT another approach (because the above gives some unwanted lines):
find the first line after every ----------------- line:
#echo off
setlocal enabledelayedexpansion
ipconfig /displaydns |findstr /n "^" >a.txt
for /f "tokens=1 delims=:" %%a in ('findstr /c:" --------------" a.txt') do (
set /a line=%%a+1
for /f "tokens=1,2,* delims=:" %%i in ('findstr /B "!line!:" a.txt') do echo(%%k
)

How to get part of string in Windows CMD

I am trying to get part of string from a file and write it into a variable using win CMD, but the file have a few strings, and I need only part of the third string. For example, file "myfile.txt" contain next strings:
package:com.test0.android
package:com.test1.android
package:com.test2.android
package:com.test3.android
And I need to write only "com.test2.android" in to a variable, but I can't find solution how to do this. Can anybody help me please?
Try this:
#echo off
for /f "tokens=1,* delims=]" %%a in ('find /n /v "" ^< "myfile.txt" ^| findstr "^\[3\]" ') do set "variable=%%b"
echo "%variable%"
Not sure if this is what you are looking for. But give it a try
set str=package:com.test0.android
set str=%str:package:=%

How to count no of lines in text file and store the value into a variable using batch script?

I want to count the no of lines in a text file and then the value has to be stored into a environment variable. The command to count the no of lines is
findstr /R /N "^" file.txt | find /C ":"
I refered the question How to store the result of a command expression in a variable using bat scripts?
Then I tried,
set cmd="findstr /R /N "^" file.txt | find /C ":" "
I am getting the error message,
FIND: Parameter format not correct
How could i get rid of this error.
There is a much simpler way than all of these other methods.
find /v /c "" filename.ext
Holdover from the legacy MS-DOS days, apparently. More info here: https://devblogs.microsoft.com/oldnewthing/20110825-00/?p=9803
Example use:
adb shell pm list packages | find /v /c ""
If your android device is connected to your PC and you have the android SDK on your path, this prints out the number of apps installed on your device.
You could use the FOR /F loop, to assign the output to a variable.
I use the cmd-variable, so it's not neccessary to escape the pipe or other characters in the cmd-string, as the delayed expansion passes the string "unchanged" to the FOR-Loop.
#echo off
cls
setlocal EnableDelayedExpansion
set "cmd=findstr /R /N "^^" file.txt | find /C ":""
for /f %%a in ('!cmd!') do set number=%%a
echo %number%
Inspired by the previous posts,
a shorter way of doing so:
CMD.exe
C:\>FINDSTR /R /N "^.*$" file.txt | FIND /C ":"
The number of lines
Try it. It works in my console.
EDITED:
(the "$" sign removed)
FINDSTR /R /N "^.*" file.txt | FIND /C ":"
$ reduces the number by 1 because it is accepting the first row as Field name and then counting the number of rows.
Try this:
#Echo off
Set _File=file.txt
Set /a _Lines=0
For /f %%j in ('Find "" /v /c ^< %_File%') Do Set /a _Lines=%%j
Echo %_File% has %_Lines% lines.
It eliminates the extra FindStr and doesn't need expansion.
- edited to use ChrisJJ's redirect suggestion. Removal of the TYPE command makes it three times faster.
#Tony: You can even get rid of the type %file% command.
for /f "tokens=2 delims=:" %%a in ('find /c /v "" %_file%') do set /a _Lines=%%a
For long files this should be even quicker.
I usually use something more like this
for /f %%a in (%_file%) do (set /a Lines+=1)
for /f "usebackq" %A in (`TYPE c:\temp\file.txt ^| find /v /c "" `) do set numlines=%A
in a batch file, use %%A instead of %A
The perfect solution is:
FOR /F %%i IN ('TYPE "Text file.txt" ^| FIND /C /V ""') DO SET Lines=%%i
I found this solution to work best for creating a log file that maintains itself:
setlocal enabledelayedexpansion
SET /A maxlines= 10
set "cmd=findstr /R /N "^^" "filename.txt" | find /C ":""
for /f %%a in ('!cmd!') do set linecount=%%a
GOTO NEXT
:NEXT
FOR /F %%A IN ("filename.txt") DO (
IF %linecount% GEQ %maxlines% GOTO ExitLoop
echo %clientname% %Date% %Time% >> "filename.txt")
EXIT
:ExitLoop
echo %clientname% %Date% %Time% > "filename.txt"
EXIT
Environmental variables included are %clientname% the computername of the remote client %Date% is the current date and %Time% the current time. :NEXT is called after getting the number of lines in the file. If the file line count is greater than the %maxlines% variable it goes to the :EXITLOOP where it overwrites the file, creating a new one with the first line of information. if it is less than the %maxlines% variable it simply adds the line to the current file.
You don't need to use find.
#echo off
set /a counter=0
for /f %%a in (filename) do set /a counter+=1
echo Number of lines: %counter%
This iterates all lines in the file and increases the counter variable by 1 for each line.
The :countLines subroutine below accepts two parameters: a variable name; and a filename. The number of lines in the file are counted, the result is stored in the variable, and the result is passed back to the main program.
The code has the following features:
Reads files with Windows or Unix line endings.
Handles Unicode as well as ANSI/ASCII text files.
Copes with extremely long lines.
Isn’t fazed by the null character.
Raises an error on reading an empty file.
Counts beyond the Batch max int limit of (31^2)-1.
#echo off & setLocal enableExtensions disableDelayedExpansion
call :countLines noOfLines "%~1" || (
>&2 echo(file "%~nx1" is empty & goto end
) %= cond exec =%
echo(file "%~nx1" has %noOfLines% line(s)
:end - exit program with appropriate errorLevel
endLocal & goto :EOF
:countLines result= "%file%"
:: counts the number of lines in a file
setLocal disableDelayedExpansion
(set "lc=0" & call)
for /f "delims=:" %%N in ('
cmd /d /a /c type "%~2" ^^^& ^<nul set /p "=#" ^| (^
2^>nul findStr /n "^" ^&^& echo(^) ^| ^
findStr /blv 1: ^| 2^>nul findStr /lnxc:" "
') do (set "lc=%%N" & call;) %= for /f =%
endlocal & set "%1=%lc%"
exit /b %errorLevel% %= countLines =%
I know it looks hideous, but it covers most edge-cases and is surprisingly fast.
Just:
c:\>(for /r %f in (*.java) do #type %f ) | find /c /v ""
Font: https://superuser.com/questions/959036/what-is-the-windows-equivalent-of-wc-l
One nice surprise is for one who has git bash on his windows: just plain old linux wc -l <filename> will works for you there
In the below code, the variable name are SalaryCount and TaxCount
#ECHO OFF
echo Process started, please wait...
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Salary.txt"') do set SalaryCount=%%C
echo Salary,%SalaryCount%
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Tax.txt"') do set TaxCount=%%C
echo Tax,%TaxCount%
Now if you need to output these values to a csv file, you could use the below code.
#ECHO OFF
cd "D:\CSVOutputPath\"
echo Process started, please wait...
echo FILENAME,FILECOUNT> SUMMARY.csv
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Salary.txt"') do set Count=%%C
echo Salary,%Count%>> SUMMARY.csv
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Tax.txt"') do set Count=%%C
echo Tax,%Count%>> SUMMARY.csv
The > will overwrite the existing content of the file and the >> will append the new data to existing data. The CSV will be generated in D:\CSVOutputPath
You can pipe the output of type into find inside the in(…) clause of a for /f loop:
for /f %%A in ('
type "%~dpf1" ^| find /c /v ""
') do set "lineCount=%%A"
But the pipe starts a subshell, which slows things down.
Or, you could redirect input from the file into find like so:
for /f %%A in ('
find /c /v "" ^< "%~dpf1"
') do set "lineCount=%%A"
But this approach will give you an answer 1 less than the actual number of lines if the file ends with one or more blank lines, as teased out by the late foxidrive in counting lines in a file.
And then again, you could always try:
find /c /v "" example.txt
The trouble is, the output from the above command looks like this:
---------- EXAMPLE.TXT: 511
You could split the string on the colon to get the count, but there might be more than one colon if the filename had a full path.
Here’s my take on that problem:
for /f "delims=" %%A in ('
find /c /v "" "%~1"
') do for %%B in (%%A) do set "lineCount=%%B"
This will always store the count in the variable.
Just one last little problem… find treats null characters as newlines. So if sneaky nulls crept into your text file, or if you want to count the lines in a Unicode file, this answer isn’t for you.
You can also try
set n=0 & for /f "tokens=*" %a in (text.txt) do set/a n=!n!+1
echo !n!
You can also mark with a wildcard symbol * to facilitate group files to count.
Z:\SQLData>find /c /v "" FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_*.txt
Result
---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIFRS01_V1.TXT: 2041
---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIOST00_V1.TXT: 315938
---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIFRS00_V1.TXT: 0
---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_CNTPTF00_V1.TXT: 277

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