I am not able to get the input text field data with id city_name from the form via jQuery-Ajax method.
The error that I keeps getting is "NetworkError: 403 FORBIDDEN - http://127.0.0.1:8000/dashboard".
I know how to get the data using hidden field type, but that option cannot be used here and moreover, getting data from hidden field is now an outdated method. So, how can I get data using Django-AjaxJquery method.
HTML
<form type = "POST">
{% csrf_token %}
<input type="text" placeholder = "Enter City Name" id = "city_name">
<input type="button" value = "On" id="on">
<input type="button" value = "Off" id="off">
</form>
JS File
$(function(){
$("#on").click(function (event) {
event.preventDefault();
$.ajax({
type: "POST",
url: "dashboard",
data : {
'city_name' : $("#city_name").val(),
},
});
});
});
View.py
#login_required
def dashboard(request):
ctx = {}
if request.is_ajax():
city_name = request.POST['city_name']
print city_name
return render_to_response('dashboard/dashboard.html',ctx, context_instance = RequestContext(request))
urls.py
urlpatterns = patterns('',
url(r'^dashboard$','apps.dashboard.views.dashboard', name = 'llumpps_dashboard'),
)
It is missing the CSRF token in the request.
You can either use #csrf_exempt decorator for your view like:
#login_required
#csrf_exempt
def dashboard(request):
...
Or send the token along with the request:
$.ajax({
type: "POST",
url: "dashboard",
data : {
'csrfmiddlewaretoken': $('input[name="csrfmiddlewaretoken"]').val();
'city_name' : $("#city_name").val(),
},
complete: function () {
// do whatever here
}
});
Read more about CSRF and AJAX in Django here: https://docs.djangoproject.com/en/dev/ref/contrib/csrf/#ajax
Hope it helps.
Related
I have simple form
class TimeForm(forms.Form):
time = forms.TimeField()
date = forms.DateField()
def clean_date(self):
time = self.cleaned_data['time']
date = self.cleaned_data['date']
date_time = datetime.combine(date, time)
if datetime.now() > date_time:
raise ValidationError("datetime error")
return start_date
with class based view
class TimeView(View):
#staticmethod
def post(request):
form = TimeForm(request.POST)
if form.is_valid():
# do something
json_data = json.dumps({'some_record': value})
else:
json_data = json.dumps({'errors': form.errors})
return HttpResponse(json_data, content_type='application/json')
In html I have standard form with submit connected do ajax
<form action="/time_url/" method="POST" id="time_form">
{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Submit">
</form>
<script>
$('#time_form').submit(function(event) {
event.preventDefault();
$.ajax({
type: "POST",
url: '/time_url/',
dataType: 'json',
data: $(this).serialize(),
success: function(data, textStatus, jqXHR){
alert('yay');
}
})
});
</script>
and I'd like to be able to submit this form without page reload. Everything seems to work perfectly but success function of ajax is not triggered, instead page is redirected to /time_url/ with json data. It doesn't matter wheter form is valid nor not, it's always redirected.
I've tried also with
return JsonResponse(form.errors.get_json_data())
instead of
return HttpResponse(json_data, ...)
as suggested here Django form submit with ajax but without success.
I'm new to javascript but for me it looks like problem with ajax, since proper data is served by server.
Thanks for any tips.
I'm trying to use Django Ajax to Modify user's avatar, but it doesn't work.There is no any error information, just doesn't work.
Here is my form in template:
<form class="clearfix" id="jsAvatarForm" enctype="multipart/form-data" autocomplete="off" method="post" action="{% url 'users:image_upload' %}" target='frameFile'>
<img id="avatarShow" src="{{ MEDIA_URL }}{{ request.user.image }}"/>
<input type="file" name="image" id="avatarUp" class=""/>
<button type="submit">Modify Avatar</button>
{% csrf_token %}
</form>
Here is my Ajax:
$("#jsAvatarForm").submit(function(){
var image = $("#avatarShow").val()
$.ajax({
cache: false,
type: "POST",
url:"{% url 'users:image_upload' %}",
data:{'user_pk':{{ user.pk }}, 'image':image},
async: true,
beforeSend:function(xhr, settings){
xhr.setRequestHeader("X-CSRFToken", "{{ csrf_token }}");
},
success: function(data) {
if(data.status == 'fail'){
if(data.msg == '用户未登录'){
window.location.href="login";
}else{
alert(data.msg)
}
}else if(data.status == 'success'){
window.location.reload();//refresh current page.
}
},
});
return false;
});
Here is views.py:
class UploadImageView(LoginRequiredMixin, View):
def post(self, request):
user_pk = request.POST.get("user_pk", 0)
image = request.FILES.get('image')
user_change = UserProfile()
user_change.id = user_pk
user_change.image = image
user_change.save
return HttpResponse('ok')
Actually I also have a forms.py but I don't know how to use it with ajax:
class UploadImageForm(forms.ModelForm):
class Meta:
model = UserProfile
fields = ['image']
Here is my user model, note:I have rewrote my own USER:
class UserProfile(AbstractUser):
image = models.ImageField(upload_to="image/%Y/%m", default="image/default.png", max_length=100,verbose_name='头像')
class Meta:
verbose_name = "用户信息"
verbose_name_plural = verbose_name
def __str__(self):
return self.username
Any friend can help?Thank you so much!
Obviously You can send file such as image to django via js, depending of what you have posted in your question, I am showing you a way that you can proceed, there are lots of other ways to accomplish this fairly.
Feel free to comment, if anything is not working.
$("#jsAvatarForm").submit(function(){
var form = this;
// var image = $("#avatarShow").val() You can not retrieve the image like this
var formData = new FormData($(form)[0]);
// Everything inside the html form is serialized in the formData
// No need to add X-CSRFToken, {% csrf_token %} is inside the form
formData.append("NEW_KEY","NEW_VALUE"); # In case of further values
$.ajax({
url:$(form).attr('action'),
type:$(form).attr('method'),
data:formData,
processData: false,
contentType: false, //Don't set any content type header
success: function(){
// all your stuffs here
$('#avatarShow').attr('src',data.avatar_url)
},
error:function(){
alert("error");
}
});
return false;
});
Django
from django.http import JsonResponse
# codes here
user_change.image = image
user_change.save()
return JsonResponse({'avatar_url':user_change.image.url})
Note: Show the post view that rendering this template.
When I use ajax to submit a comment form in Django,the page will redirect to a blank page shows me the success data:
{"status":"success", "msg":"添加成功"}
,but not stay in current page.I want the page stay in current page and show me the new comment.
Here is my update_comment view:
def update_comment(request, news_pk):
news = get_object_or_404(News, id=news_pk)
comment_form = CommentForm(request.POST or None)
if request.method == 'POST' and comment_form.is_valid():
if not request.user.is_authenticated:
return render(request, 'login.html', {})
comments = comment_form.cleaned_data.get("comment")
news_comment = NewsComments(user=request.user, comments=comments, news=news)
news_comment.save()
# return redirect(reverse('news:news_detail', kwargs={'news_pk': news.id}))
return HttpResponse('{"status":"success", "msg":"添加成功"}', content_type='application/json')
else:
return HttpResponse('{"status":"fail", "msg":"添加失败"}', content_type='application/json')
Here is my ajax:
$(document).on('submit', 'comment_form', function(e){
e.preventDefault();
$.ajax({
cache: false,
type: "POST",
url:"{% url 'operation:update_comment' news.id %}",
data:{'news_pk':{{ news.id }}, 'comments':comments},
async: true,
beforeSend:function(xhr, settings){
xhr.setRequestHeader("X-CSRFToken", "{{ csrf_token }}");
},
success: function(data) {
if(data.status == 'fail'){
if(data.msg == '用户未登录'){
window.location.href="login";
}else{
alert(data.msg)
}
}else if(data.status == 'success'){
window.location.reload();//refresh current page.
}
},
});
});
Here is my form:
<form id="comment_form" action="{% url 'operation:update_comment' news.id %}" method="POST" >
{% csrf_token %}
<textarea id="comment_textarea"name="comment"></textarea>
<input type="submit" value="Submit"> </input>
</form>
Finally I made it!Thanks Lord!Very excited!
I have Three major issues in my previous code.
First:Since the ajax will post the news_pk to the view update_comment,so I don't need add news_pk in this view's url and template(in the url of <form> tag and the url in the ajax),so I removed them,or the data will still pass through Form but not ajax.
Second:My binding is incorrect,I have the click handler on the form it should be a submit handler. If I was binding it to a button then I'd use click a handler.Ajax not work in Django post
But for this part I'm still a some confused,between the button summit way and form submit way.
The third issue is I mistaked 'comments' and 'comment'.'comment' is the name attribute of <textarea> ,through which forms.py gets the data.
comments is defined by ajax through var comments = $("#js-pl-textarea").val(), so in the view I need use comments = request.POST.get("comments", "") but not comment,that's the reason why 'post failed'.
Following is my code.
Here is the ajax:
$("#comment_form").submit(function(){
var comments = $("#js-pl-textarea").val()
$.ajax({
cache: false,
type: "POST",
url:"{% url 'operation:update_comment' %}",
data:{'news_pk':{{ news.pk }}, 'comments':comments},
async: true,
beforeSend:function(xhr, settings){
xhr.setRequestHeader("X-CSRFToken", "{{ csrf_token }}");
},
success: function(data) {
if(data.status == 'fail'){
if(data.msg == '用户未登录'){
window.location.href="login";
}else{
alert(data.msg)
}
}else if(data.status == 'success'){
window.location.reload();//refresh current page.
}
},
});
return false;
});
Here is my udate_comment view:
#login_required
def update_comment(request):
news_pk = request.POST.get("news_pk", 0)
comments = request.POST.get("comments", "")
if int(news_pk) > 0 and comments:
news_comments = NewsComments()
news = News.objects.get(id=int(news_pk))
news_comments.news = news
news_comments.comments = comments
news_comments.user = request.user
news_comments.save()
return HttpResponse('{"status":"success", "msg":"添加成功"}', content_type='application/json')
else:
return HttpResponse('{"status":"fail", "msg":"添加失败"}', content_type='application/json')
Here is my form in template:
<form id="comment_form" action="{% url 'operation:update_comment'%}" method="POST" >
{% csrf_token %}
<textarea id="js-pl-textarea"name="comment"></textarea>
<input type="submit" value="Submit"> </input>
</form>
I really appreciate everyone's reply!With your reply I figured out these issue step by step!
I have something similar in my project. Its a script to like a song. I'm just gonna put the relevant codes here.
The ajax script. I put this script in a separate file named like_script.html. I call it in a template using django template include
<script>
$('#like').click(function(){
$.ajax({
type: "POST",
url: "{% url 'song:like_song' %}",
data: {'pk': $(this).attr('pk'), 'csrfmiddlewaretoken': '{{ csrf_token }}'},
dataType: "json",
success: function(response) {
alert(response.message);
},
error: function(rs, e) {
alert(rs.responseText);
}
});
})
</script>
The django view
import json
from django.http import HttpResponse
from django.contrib.auth.decorators import login_required
from django.views.decorators.http import require_POST
#login_required
#require_POST
def song_like_view(request):
if request.method == 'POST':
user = SiteUser.objects.get(user=request.user)
pk = request.POST.get('pk', None)
song = get_object_or_404(Song, pk=pk)
if song.likes.filter(pk=user.pk).exists():
song.likes.remove(user)
song.like_count = song.likes.count()
song.save(update_fields=['like_count'])
message = "You unstarred this song.\n {} now has {} stars".format(song.title, song.like_count)
else:
song.likes.add(user)
song.like_count = song.likes.count()
song.save(update_fields=['like_count'])
message = "You starred this song.\n {} now has {} stars".format(song.title, song.like_count)
context = {'message' : message}
return HttpResponse(json.dumps(context), content_type='application/json')
The url
urlpatterns = path("like/", views.song_like_view, name='like_song'),
The template where the script is called
<a class="btn btn-sm btn-primary" href="" id="like" name="{{ song.pk }}" value="Like"></i> Unstar</a>
{% include 'like_script.html' %}
Same button for like and unlike. I hope you can follow the logic to make yours right. Notice that in your view you don't need to include the pk. Just get it from the POST data pk = request.POST.get('pk', None)
I am trying to create a simple todo list app that uses POST to post data into the data base and a 'x' (\u00D7) to delete the todo. The code is as following:
Views.py
def delete(self, request, id):
print(request.DELETE)
self.model.objects.get(pk=request.delete['pk']).delete()
return render(request, self.template_name, {'object_list':self.model.objects.all()})
Models.py
class TodoDB(models.Model):
todos = models.CharField(max_length=1000)
day = models.CharField(max_length=10)
def __str__(self):
return str(self.todos)
HTML and JS
<ul class="list-group list-group-flush" id="list-group">
{%for item in object_list%}
<li class="list-group-item">{{item.todos}}</li>
{%endfor%}
</ul>
for (var i = 0; i < close.length; i++) {
close[i].onclick = function() {
var li = this.parentElement;
li.style.display = "none";
$.ajax({
type: 'DELETE',
url: "{%url 'todo_list'%}",
data:{'pk':pk},
success: function(data){
alert("Success!");
},
error: function(){
alert("Error! Couldn't send delete request")
}
});
}
Any help would be great. Thanks!
EDIT: I forgot to add the error: The error was csrf_token not found. I put the entire list under a new form tag and inserted a {%csrf_token%} in there, but it still doesn't accept the token.
Please consider reading
https://docs.djangoproject.com/en/2.0/ref/csrf/
on how it is made up in Django.
In brief you would need to render csrf token in your form and post it with AJAX during your request.
Your error is just about that.
data:{'pk':pk},
In your JS part should look something like:
data:{
'pk':pk,
'csrf_token': [your rendered token here...]
},
I want to make an ajax request in a Django framework. However, I don't pass to get data from the client in json. It works when I don't use Json.
If I use dataType:'json' with a {'a': 'value'} in the ajax, I can't get it in the view.py, the result is nothing...
However if I use data:$(this).serializeArray() in the ajax I can get result with request.POST. However, I really need to customize my data and send to my view.py other data than the data from the form. I would like to send a {'a', 'mydata', 'form': myformdata}...
Is there a way to do it?
template:
<form id="ajax2" action="/seghca/test-post/" method="post">{% csrf_token %}
Nom : <input type="text" name="nom" value="" id="nom"/><br/>
prenom : <input type="text" name="prenom" value=""/><br/>
<input type="submit" value="Envoyer"/>
</form>
<div id="result"></div>
javascript:
$(document).ready(function(){
// POST AJAX
$("#ajax2").submit( function() {
var urlSubmit = $(this).attr('action');
var data = $(this).serializeArray();
data.push({
key: "keyName",
value: "the value"
});
$.ajax({
type: "POST",
url: urlSubmit,
dataType: "json",
data : data,//$(this).serializeArray(),
success: function(response){
var json_response = JSON.parse(response);
// now get the variables from the json_response
$('#result').html(json_response.html);
}
});
return false;
});
});
view.py (the ajax launch the test_post view, home2 is the view of the formular):
from datetime import datetime
from django.http import HttpResponse, Http404
from django.shortcuts import redirect, render
from seghca.models import Article
from django.shortcuts import render_to_response
from django.http import HttpResponse
from django.template import RequestContext
from django.views.decorators.csrf import csrf_exempt
import json
def home2(request):
return render_to_response('seghca/form.html', context_instance=RequestContext(request))
#csrf_exempt
def test_post(request):
data = {'html': request.POST['key']}
return HttpResponse(json.dumps(data), mimetype="application/json")
When you are using ajax view you should return the data back from your view in the json form:
data = {'html': request.POST['input']}
return HttpResponse(json.dumps(data), mimetype="application/json")
Second it is necessary to parse the response first on client side:
success: function(response){
var json_response = JSON.parse(response);
// now get the variables from the json_response
$('#result').html(json_response.html);
}
Third if you need to pass the form data along with some more info you can do:
var data = $(this).serializeArray();
data.push({
key: "keyName",
value: "the value"
});
Fourth you are missing csrf token.
change data: data, to data: {'data': JSON.stringify(data)},
and you'll be able to access the serialized version of your data via POST['data'] in django. Keep in mind that if you want to use this in django you have to deserialize it, for instance json.loads(POST['data'])
I have your same needs. My solution was:
The AJAX request:
var posturl = $('#'+formid).prop('action');
$.ajax({
async:false,
type: "POST",
dataType: "json",
contentType: "application/x-www-form-urlencoded",
url : posturl,
data : $('#'+formid).serialize() + '&mode=ajax', //&mode=ajax is my custom data
success:function(response){
console.log(response);
alert(response.message);
},
timeout:10000
});
In the views.py:
data = {'error': '0', 'message': 'all was ok'}
return HttpResponse(json.dumps(data), mimetype="application/json")
The above should work for you. My test was with Django 1.6 and Python 2.7.5