I have the following code:
set DATE=%date%
echo %DATE%
set DAY=%DATE:~0,2%
echo %DAY%
rename file09.txt file%DAY%09.txt
pause
It is supposed to rename a text file and put the day of the month in the file name. I am however getting a syntax error on the rename command.
I think the problem is in inserting the variable into the file name. Any help would be appreciated. The echos are just in the program for my own reference.
As has already been stated - your code as pasted had trailing spaces on many lines and the spaces often matter. I posted this because you had reused the system DATE variable name and that causes issues, and to show you that quotes are often helpful - and needed with long filenames.
set "D=%date%"
echo "%D%"
set "DAY=%D:~0,2%"
echo "%DAY%"
rename "file09.txt" "file%DAY%09.txt"
pause
you might have trailing spaces in the set command. Just try this:
set "DAY=%DATE:~0,2%"
btw. with set DATE=%date% you doesn't create a new variable. Variables must have case insensitive unique Names.
The problem was the date configuration, because of that the content of the variables is wrong.
Really use quotation marks worked as it ensures full name if the variables have spaces or unusual characters.
Review my post for view the Endoro answer..it works right for me
Renaming file with Batch variable doesnt work with another user profile
"Renaming file with Batch variable doesnt work with another user profile"
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I have filenames that come with the date at the beginning of their names, e.g. 20171015….txt.
I currently use a batch file to strip off the first 8 characters and this has worked well. However I'd like to now keep the date but move it to the end of the file name.
With the file name without extension set as a variable, %Variable%:
Ren "%Variable%.ext" "%Variable:~8%%Variable:~,8%.ext"
Or if performed within some sort of loop and delayed expansion enabled, i.e.SetLocal EnableDelayedExpansion:
Ren "!Variable!.ext" "!Variable:~8!!Variable:~,8!.ext"
I have a variable from a text file.
set /p namz=<"playersname.txt"
Right now if I echoed this, it would echo the entire contents of the file.
The Contents of playersname.txt include the following,
theplayernameis:Player One
I need a code that I can use in .bat to help me to extract everything after the ":" from the .txt file while ignoring everything else before it, "Player One" then it needs to store it in another variable which I can call upon anytime I want it.
I've been racking my brain on this, trying to come up with a solution, been forum hopping for a long time, haven't quite found what I needed yet. Please help..
You have a single-line textfile, you need the second token after a delimiter that might be : or /:
for /f "tokens=2 delims=:/" %%a in (playersname.txt) do set namz=%%a
add every possible delimter to delims=
SOLVED!
Update: It figures moments after posting for help which is something I never do I'd figure it out...I tend to over think things, and that was the case here, it was just so simple! >.<
Solution:
(This worked under Windows 7 Ultimate 64 Bit)
Set var=
Set var=SomeText %var1% %var2% %var3%
Echo %var% > output.txt
See an explanation in my answer below.
I've been searching and trying several posts here similar to my question for hours with no success. I'm not new to Programming in BATCH but I have memory problems and thus can't always remember things. It also doesn't help that I program in other languages on other platforms which usually means I'm trying to use *nix shell commands in my Windows Batch scripts >.<
I've gotten quite close with some examples but nothing that works as needed.
Ideally, I'd like this work to work on Windows 7, 8, 8.1, Vista and 10 as that is the intended target.
This is what I need to accomplish:
The user will answer a series of questions, each question is stored into a .txt file (or variable if you prefer. I just used text files because of a past project where I ran into issues with variables that couldn't be solved and text files worked). The lines in each text file will need to be output into a single text file, on a single line which will then be read back in as a variable and run. Again, you could just use and combine the variables in your example if that's easier for you or both of us ;P
This is a snippet example of how I was doing it
SET file1=
SET /P file1=file1:%=%
ECHO %file1% > file1.txt
Then
copy /b file1.txt + file2.txt + file3.txt + file4.txt output.txt
Here is how I'd like the result to look
toolkit /S "C:\ToolKit Bravo\Data\etc" "D:\ToolKit Bravo\Data\Ops"
The "" quotation marks are necessary. The output MUST be EXACTLY as shown above for the example I've given. The "/S" & paths are variable NOT fixed!
Here is the best I've been able to come up with using variables..
"toolkit /S "C:\ToolKit Bravo\Data\etc" "D:\ToolKit Bravo\Data\Ops""
Update 2 - An explanation as requested:
The paths in the above example directly above this are not fixed! This was an Example Only. "toolkit" is fixed, this doesn't change. "/S" is an option selected by the user to pass on to the "toolkit". Both the source and destination paths are again input by the user in "quotation" marks. They're not fixed paths.
As you can see the result is surrounded by quotations which is NOT acceptable. And Please remember, I NEED the quotations around the paths in the end result, so removing them all is NOT an option!
Any help is greatly appreciated! Thank you for your time.
Just take all of the characters between the quotes.
SET X="toolkit /S "C:\ToolKit Bravo\Data\etc" "D:\ToolKit Bravo\Data\Ops""
ECHO %X%
SET Y=%x:~1,-1%
ECHO %Y%
Solution:
This solved my problem under Windows 7 Ultimate 64 Bit
Set var=
Set var=SomeText %var1% %var2% %var3%
Echo %var% > textfile.txt
Using the SET command I first made sure the variable or var for short was empty. Using this command:
Set var=
I then proceeded to create my variable using all of the other variables I had created and wanted to combine using this line of code:
Set var=SomeText %var1% %var2% %var3%
Note that I have preceded the variables with "SomeText". This is where I'll place the name of the .exe I'm passing the arguments to, but it can be anything you want included. I also need spaces between each variable so I've left spaces between them in the example code. If you don't want the spaces simply remove them, and you'll have 1234, instead of 1 2 3 4.
Finally I send the combined variable out to a .txt file.
Echo %var% > textfile.txt
However, you could also simply call the new variable now like this:
%var%
CMD does not appear to be recognizing any variable I store using SET. If I run this batch file:
#ECHO off
SET /P name = What is your name?
ECHO %name%
PAUSE
ECHO on
I get the following output:
What is your name? steven
ECHO is off.
Press any key to continue . . .
When I run line 2 and then line 3 from the command prompt, it just prints:
%name%
Do I have something configured incorrectly? Am I correct in thinking that line 2 should create a session variable that should be recognized in line 3?
I searched, but I could only find answers related to variable expansion within IF blocks. This is happening to me outside any IF/FOR/etc blocks.
This is Windows 7, by the way. I'm not sure how much cmd changes from one version of Windows to another.
There must not be any spaces around the equal sign in the set instruction. Change this
SET /P name = What is your name?
into this
SET /P name=What is your name?
and your problem will disappear.
since I can not add any comments yet I have to post a new answer. The information:
"There must not be any spaces around the equal sign in the set instruction."
is only partly correct. To be exact it should say: the equal sign must follow directly after the variable name (in sricks3's case without a space). Whatever comes after the equal sign will be used as input-prompt for the variable including any spaces, so the following code will work as well:
SET /P name= What is your name?
I'm working on a Windows batch file that will bcp three text files into SQL Server. If something goes wrong in production, I want to be able to override the file names. So I'm thinking of doing something like this.
bcp.exe MyDB..MyTable1 in %1 -SMyServer -T -c -m0
bcp.exe MyDB..MyTable2 in %2 -SMyServer -T -c -m0
bcp.exe MyDB..MyTable3 in %3 -SMyServer -T -c -m0
I would like to be able to enter default names for all three files, to be used if the positional parameters are not supplied. The idea would be either to execute
myjob.bat
with no parameters, and have it use the defaults, or execute
myjob.bat "c:\myfile1" "c:\myfile2" "c:\myfile3"
and have it use those files. I haven't been able to figure out how to tell if %1, %2 and %3 exist and/or are null. I also don't know how to set those values conditionally. Is this possible? Any suggestions would be appreciated.
To test for the existence of a command line paramater, use empty brackets:
IF [%1]==[] echo Value Missing
or
IF [%1] EQU [] echo Value Missing
The SS64 page on IF will help you here. Under "Does %1 exist?".
You can't set a positional parameter, so what you should do is do something like
SET MYVAR=%1
You can then re-set MYVAR based on its contents.
The right thing would be to use a "if defined" statement, which is used to test for the existence of a variable. For example:
IF DEFINED somevariable echo Value exists
In this particular case, the negative form should be used:
IF NOT DEFINED somevariable echo Value missing
PS: the variable name should be used without "%" caracters.
Both answers given are correct, but I do mine a little different. You might want to consider a couple things...
Start the batch with:
SetLocal
and end it with
EndLocal
This will keep all your 'SETs" to be only valid during the current session, and will not leave vars left around named like "FileName1" or any other variables you set during the run, that could interfere with the next run of the batch file. So, you can do something like:
IF "%1"=="" SET FileName1=c:\file1.txt
The other trick is if you only provide 1, or 2 parameters, use the SHIFT command to move them, so the one you are looking for is ALWAYS at %1...
For example, process the first parameter, shift them, and then do it again. This way, you are not hard-coding %1, %2, %3, etc...
The Windows batch processor is much more powerful than people give it credit for.. I've done some crazy stuff with it, including calculating yesterday's date, even across month and year boundaries including Leap Year, and localization, etc.
If you really want to get creative, you can call functions in the batch processor... But that's really for a different discussion... :)
Oh, and don't name your batch files .bat either.. They are .cmd's now.. heh..
Hope this helps.
rem set defaults:
set filename1="c:\file1.txt"
set filename2="c:\file2.txt"
set filename3="c:\file3.txt"
rem set parameters:
IF NOT "a%1"=="a" (set filename1="%1")
IF NOT "a%2"=="a" (set filename2="%2")
IF NOT "a%3"=="a" (set filename1="%3")
echo %filename1%, %filename2%, %filename3%
Be careful with quotation characters though, you may or may not need them in your variables.
Late answer, but currently the accepted one is at least suboptimal.
Using quotes is ALWAYS better than using any other characters to enclose %1.
Because when %1 contains spaces or special characters like &, the IF [%1] == simply stops with a syntax error.
But for the case that %1 contains quotes, like in myBatch.bat "my file.txt", a simple IF "%1" == "" would fail.
But as you can't know if quotes are used or not, there is the syntax %~1, this removes enclosing quotes when necessary.
Therefore, the code should look like
set "file1=%~1"
IF "%~1"=="" set "file1=default file"
type "%file1%" --- always enclose your variables in quotes
If you have to handle stranger and nastier arguments like myBatch.bat "This & will "^&crash
Then take a look at SO:How to receive even the strangest command line parameters?