After checking this post, I know that Joomla use task=X.Y to call the controller to handle the request.
But if I click NEW button on com_categories component, it will access the URL of /administrator/index.php?option=com_categories&view=items and containing the POST data as below:
Then the URL get redirected to /administrator/index.php?option=com_categories&view=item&layout=edit.
My question is why the URL /administrator/index.php?option=com_categories&view=items don't have the task=X.Y and it can redirect to /administrator/index.php?option=com_categories&view=item&layout=edit?
I know that it contains the POST data with task=item.add, but which controller convert this POST data to the destination URL and get redirected to that?
Thanks.
Actually (on 2.5.14), when you click on the "New" button in the Category Manger view, the first request generates a POST:
POST /administrator/index.php?option=com_categories&view=categories HTTP/1.1
POST requests usually send query strings in the HTTP message body not just in the URL, in this case the POST request has the following form data in the body:
filter_search
filter_level
filter_published
filter_access
filter_language
limit 5
limitstart 0
order[] 1
order[] 1
order[] 1
order[] 1
order[] 2
batch[assetgroup_id]
batch[language_id]
batch[category_id]
batch[move_copy] m
extension com_content
task category.add
boxchecked 0
filter_order a.lft
filter_order_Dir asc
original_order_values 1,1,1,1,2
796194955f38a0d8db484c92d92ca5ce 1
You will notice this has a task parameter that has the value category.add (not item.add), this is taken into account by the JController class when getInstance($prefix, $config) is called in the com_categories entry point file:
$controller = JControllerLegacy::getInstance('Categories');
The JController class converts category.add into a $type of category and a $task of add. The $type value is used to assemble the path to the controller in conjunction with the components base path ( in this case /pathto/site/administrator/components/com_categories ).
So, when the instantiated JController class receives the ->execute($task) message in com_categories/categories.php entry point file:
$controller->execute(JRequest::getVar('task'));
it's actually already a controller of type CategoriesControllerCategory which is the what you would expect to handle the New button request.
Related
Im using Laravel v7 and i have a question about pagination.
So far im using 2 routes, 1rst to return a view with all rows from database, and 2nd receives an input and returns that view with the rows filtered by that input value.
But im using pagination, and on the 2nd route, when i try to go to 2nd page it gives me an error:
Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException
The GET method is not supported for this route. Supported methods: POST.
I've tried to change my form method to GET but i need that the token doesn't appear on the page URL and beside that, when i go to 2nd page, it returns all the rows again.
Thats my code so far:
Routes:
Route::get('concessions', 'ConcessionController#index')->name('concessions.index');
Route::post('concessions/search', 'ConcessionController#search')->name('concessions.search');
Controller
class ConcessionController extends Controller
{
public function index()
{
$concessions = DB::table('concessions')->paginate(12);
return view('admin.concessions.index', compact('concessions'));
}
public function search(Request $request)
{
$name = $request->name;
$concessions = Concession::where('name', 'like', '%' . $name . '%')->paginate(12);
return view('admin.concessions.index', compact('concessions', 'name'));
}
}
Any way to do that?
Laravel pagination only works with get parameters.
You should use GET method for your search page. POST requests aren't meant for the purpose of displaying data. Why? There are many reasons, but to be short I will give you three examples :
1. When you access the first page, you get the data by GET request,
not POST request. So if you want to use POST request, you
need to access the page as POST request by sending data with
POST method.
2. With GET parameters, let's say you are on 5th page - you can
copy the link and paste it to friend and he will be able to view
the same content as you. With POST this is impossible.
3. You can not use back button with POST requests, if you manage to
get pagination to work.
POST requests are useful when you need to submit data to the server, in order to create new record, for example.
So I suggest you to change your route type to GET.
From my perspective, if you change your route code similar to below code, it will work properly with both methods of GET and POST.
Route::any('concessions/search', 'ConcessionController#search')->name('concessions.search');
411 Length Required
The request did not specify the length of its content, which is required by the requested resource.
I have the following code:
[HttpPost]
[Route("UploadFileAsync/{RequestID}")]
public async Task<HttpResponseMessage> UploadFileAsync(int RequestID)
{
SetUser();
long maxAllowedFileSize = 9999999;
long? contentLenght = Request.Content.Headers.ContentLength;
if (!contentLenght.HasValue || contentLenght.Value > maxAllowedFileSize)
{
return Request.CreateErrorResponse(HttpStatusCode.LengthRequired, "Please set content lenght and file size should be less than 10 Mb");
}
It works and return 411 status code when size of request is more than 9999999.
But I would like to validate it before uploading the whole request to server (as I understand, sense of this 411 status code to prevent uploading big files if server can't process it). How can I reject request and send 411 status code before sending the whole request to server?
If you want to to validate the size before sending the request to Web API, then you need to do it at Web API client level.
However if you want to perform the validation before the Action in your web api controller is executed, you can use Action Filters. Typically, following steps are involved.
Create custom action filter for the Web API by inherting ActionFilterAttribute class.
Override OnActionExecuting method and write the code to check the content length and return appropriate error code within the method definition.
Register the custom filter in WebApiConfig file.
Decorate the action for which you want to apply this filter with your custom attribute
Refer to this link for step by step implementation.
So, say I have an existing, working page Display Cashier, which displays information about a cashier in a shop. Now, I add a button to this page that looks like:
Manager
The request-mapping for this URL maps it (successfully) to a controller: HandleGetManager
the HandleGetManager controller looks like this:
#Controller
public class HandleGetManager{
private employeeBO employeeBO; //BO handles all business logic
//spring hooks
public HandleGetManager(){}
public void setemployeeBo(employeeBO employeeBO){
this.employeeBO = employeeBO;
}
//get controller
#RequestMapping(method=RequestMethod.GET)
public String getManager(#RequestParam String cashierId){
Long managerId = employeeBO.getManagerByCashierId(cashierId);
String redirectUrl = "/displayManager.ctl?managerId=" + managerId.toString();
return redirectUrl;
}
}
Here's what happens when I try it:
I hit the new button on the Display Cashier page, I expect the following to happen:
The browser sends a get request to the indicated URL
The spring request-mapping ensures that the flow of control is passed to this class.
the #RequestMapping(method=RequestMethod.GET) piece ensures that this method is evoked
The #RequestParam String cashierId instructs Spring to parse the URL and pass the cashierId value into this method as a parameter.
The EmployeeBo has been injected into the controller via spring.
The Business logic takes place, envoking the BO and the managerId var is populated with the correct value.
The method returns the name of a different view, with a new managerId URL arg appended
Now, up until this point, everything goes to plan. What I expect to happen next is:
the browsers is directed to that URL
whereupon it will send a get request to that url,
the whole process will start again in another controller, with a different URL and a different URL arg.
instead what happens is:
this controller returns the name of a different view
The browser is redirected to a half-right, half wrong URL: handleGetManager.ctl?managerId=12345
The URL argument changes, but the name of the controller does not, despite my explicitly returning it
I get an error
What am I doing wrong? Have I missed something?
Assuming you have a UrlBasedViewResolver in your MVC configuration, the String value you return is a View name. The ViewResolver will take that name and try to resolve a View for it.
What you seem to want to do is to have a 301 response with a redirect. With view names, you do that by specifying a redirect: prefix in your view name. It's described in the documentation, here.
Here's a question/answer explaining all the (default) ways you can perform a redirect:
How can I prevent Spring MVC from doing a redirect?
I have my site like http://mysite.com/ and on the index page i have search box and for the result i am using jqgrid. When user click row in the jqgrid row I am taking data from cells and do ajax call to server and fetch json data and once data arrived I hide the search box and jqgrid and show another div which is I kept for result. In short, user will be on the same page just div's hide/show.
Now I have seen history api and used pushState and popstate so my url becomes in the addressbar like http://mysite.com/controller/action/para1/para2 (here para1 and para2 are the parameters i am passing to action). Everything is ok so far.
Now the problem is if I copy this URL "http://mysite.com/controller/action/para1/para2" and if I open this with let's say different browser and hit enter it display just json data. So, I am confused that how to handle when user directly use that url in controller.
I was thinking to check in the controller action if the request is AJAX then return json data otherwise full page, is that right approach? OR something on the client side we have so that it load the same way as earlier.
Thanks
if I copy this URL "http://mysite.com/controller/action/para1/para2" and if I open this with let's say different browser and hit enter it display just json data.
it only display json data because its ajax call only so how to deal with that so that it also display the same page even user directly access the url.
I think what you're looking for is Request.IsAjaxRequest():
public class FooController : Controller {
public ActionResult GetFoo(int id) {
var model = _fooService.Get(id);
if (Request.IsAjaxRequest())
return PartialView("_Foo", model);
return View("Foo", model);
}
}
Note: It's recommended to use WebAPI controllers to handle only json data. So if the user got there by typing the url the mvc controller will handle it and if you need to get the json data for that view you could call the webapi controller.
Use a separate controller or action method for AJAX and for Views. The View controller should match the URL. The Ajax controller should be the less "pretty" URL since it's behind the scenes.
You need to set up a routing definition in global.asax (MVC 3) or App_Start/RouteConfig.cs (MVC 4) to handle the parameters if you haven't already done that.
routes.MapRoute(
"MyRoute",
"MyUrlController/{action}/{para1}/{para2}",
new
{
action = "Index",
para1 = UrlParameter.Optional,
para2 = UrlParameter.Optional
}
);
Then in the View controller:
public ActionResult Index(string para1 = "Default Value", string para2 = "Default Value")
{
// ...Handle parameters...
return View("_MyView", viewModel);
}
Returning a View object type is the key. The History API URL doesn't get it's data from the same AJAX source controller which returns a PartialViewResult.
I need to get the quantity of items from a form and pass that to CI's paypal_lib auto_form:
This is my controller:
function auto_form()
{
$this->paypal_lib->add_field('business', 'admin_1261513315_biz#pixelcraftwebdesign.com');
$this->paypal_lib->add_field('return', site_url('home/success'));
$this->paypal_lib->add_field('cancel_return', site_url('home/cancel'));
$this->paypal_lib->add_field('notify_url', site_url('home/ipn')); // <-- IPN url
$this->paypal_lib->add_field('custom', '1234567890'); // <-- Verify return
$this->paypal_lib->add_field('item_name', 'Paypal Test Transaction');
$this->paypal_lib->add_field('item_number', '001');
$this->paypal_lib->add_field('quantity', $quant);
$this->paypal_lib->add_field('amount', '1');
$this->paypal_lib->paypal_auto_form();
}
I have a library of my own that validates the input and redirects to auto_form on validation. I just need to pass the var $quant to the controller.
How can I achieve this?!
If you're redirecting directly to the auto_form controller method you can setup an argument there to pass your data in:
auto_form($quant)
Then, depending assuming you have no routes, rewriting, or querystrings 'on' (basically a stock CI setup) to interfere, and you are using the URL helper to redirect, you would do your redirect something like this:
redirect('/index.php/your_controller/auto_form/'. $quantity_from_form);
More on passing URI segments to your functions here.
Or if you're already using CI sessions in your application you can add the quantity value to a session variable for later retrieval inside of the auto_form controller method:
// Set After Your Form Passed Validation
$this->session->set_userdata('quant', $quantity_from_form);
// Retrieve Later in Controller Method After Redirect
$this->paypal_lib->add_field('quantity', $this->session->userdata('item'));
More on CI sessions here.