Go printing date to console - go

Question

I'm trying to pint the month, day, and year, separately to the console.
I need to be able to access each section of the date individually. I can get the whole thing using time.now() from the "time" package but I'm stuck after that.
Can anyone show me where I am going wrong please?

Answer 1

You're actually pretty close :) Then return value from time.Now() is a Time type, and looking at the package docs here will show you some of the methods you can call (for a quicker overview, go here and look under type Time). To get each of the attributes you mention above, you can do this:
package main
import (
"fmt"
"time"
)
func main() {
t := time.Now()
fmt.Println(t.Month())
fmt.Println(t.Day())
fmt.Println(t.Year())
}
If you are interested in printing the Month as an integer, you can use the Printf function:
package main
import (
"fmt"
"time"
)
func main() {
t := time.Now()
fmt.Printf("%d\n", t.Month())
}

Answer 2

Day, Month and Year can be extracted from a time.Time type with the Date() method. It will return ints for both day and year, and a time.Month for the month. You can also extract the Hour, Minute and Second values with the Clock() method, which returns ints for all results.
For example:
package main
import (
"fmt"
"time"
)
func main() {
t := time.Now()
y, mon, d := t.Date()
h, m, s := t.Clock()
fmt.Println("Year: ", y)
fmt.Println("Month: ", mon)
fmt.Println("Day: ", d)
fmt.Println("Hour: ", h)
fmt.Println("Minute: ", m)
fmt.Println("Second: ", s)
}
Please remember that the Month variable (mon) is returned as a time.Month, and not as a string, or an int. You can still print it with fmt.Print() as it has a String() method.
Playground

Answer 3

You can just parse the string to get year, month, & day.
package main
import (
"fmt"
"strings"
)
func main() {
currTime := time.Now()
date := strings.Split(currTime.String(), " ")[0]
splits := strings.Split(date, "-")
year := splits[0]
month := splits[1]
day := splits[2]
fmt.Printf("%s-%s-%s\n", year, month, day)
}