Execute a read command - bash

Question

I have a little script that I use to send bash commands to several web servers under a load balancer. I'm able to send the command successfully, but I also want to execute it locally.
#!/bin/bash
echo "Type commands to be sent to web servers 1-8. Use ctrl+c to exit."
function getCommand() {
read thisCmd
echo "Sending '$thisCmd'..."
if [ ! -z "$thisCmd" ]; then
# Run command locally
echo "From web1"
cd ~
command $thisCmd
# Send to remotes
for i in {2..8}
do
echo "From web$i..."
ssh "web$i" "$thisCmd"
done
fi
echo Done
getCommand
}
getCommand
But this is resulting in
user#web1:~$ ./sshAll.sh
Type commands to be sent to web servers 1-8. Use ctrl+c to exit.
cd html; pwd
Sending 'cd html; pwd'...
From web1
./sshAll.sh: line 11: cd: html;: No such file or directory
From web2...
/home/user/html
How do I get this working?

Answer 1

When expanding a variable as a command like this:
$thisCmd
Or this
command $thisCmd
Bash would only parse it as a single command so ; and the likes would be just considered as an argument or part of it e.g. html;
So one basic solution to that is to use eval:
eval "$thisCmd"
But it's a little dangerous. Still it's just the same as those you send to the remote servers. You still execute them like how eval does it.