using "AND" operator in rails - ruby

Question

I have something like this:
#photos = Photo.where(:user_id => #user.id)
I want something like:
#photos = Photo.where(:user_id => #user.id, :public => 1)
However this does not work. I cannot find how to use the "AND" operator

Answer 1

Your solution should work:
Photo.where(user_id: #user.id, public: 1)
Generates a query like this (assuming MySQL and a #user.id of 5):
SELECT `photos`.* FROM `photos` WHERE ((`photos`.`user_id` = 5 AND `photos`.`public` = 1))
I suspect that public is a boolean field and depending on your database adapter, true and false can either be stored as 1 and 0 or as t and f.
Try to pass a boolean value instead and let Rails handle the conversion:
Photo.where(user_id: #user.id, public: true)
It's even easier if you set up associations and some scopes:
class User < ActiveRecord::Base
has_many :photos
end
class Photo < ActiveRecord::Base
belongs_to :user
scope :public, -> { where(public: true) }
scope :private, -> { where(public: false) }
end
Now you can fetch a user's photos with:
#user.photos.public # user's public photos
#user.photos.private # user's private photos

Answer 2

Databases do not always store boolean values as 1 or 0.
So ActiveRecord normalizes that and only recognizes true and false (or nil) when using hash conditions.
All these queries are equivalent:
#photos = Photo.where("user_id = ? AND public = ?", #user.id, 1)
#photos = Photo.where(user_id: #user.id, public: true)
#photos = Photo.where(user: #user, public: true)
But it is generally preferred to write it like that:
#photos = #user.photos.where(public: true)

Answer 3

Try
#photos = Photo.where("user_id = ? AND public = ?", #user_id, 1)
Active record documentation will help you.