I'm totally new to pyside and I'm having a problem with my little program (and pyside layouts in general).
What I have is an UI with some QlineEdits, comboboxes and a button. After I have filled out the Qlines and press the button I want to either to open a new window with a completely new layout or preferably clear out the open window and fill it with a new layout based on the input from the qlines. Perhaps this is super basic but I can't get it to work. The reason is that I can't grasp how I would be able to replace or add new stuff to my gui when it's already set and shown.
Let's say I have a script like this:
import sys
import os
from PySide import QtCore, QtGui
class BasicGui(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def initUI(self):
self.projectNameLbl1 = QtGui.QLabel('Label1')
self.projectNameLbl2 = QtGui.QLabel('Label2')
self.nextBtn = QtGui.QPushButton("Next")
self.projectNameEdit = QtGui.QLineEdit(self)
self.projectNameEdit2 = QtGui.QLineEdit(self)
grid = QtGui.QGridLayout()
grid.setSpacing(10)
grid.addWidget(self.projectNameLbl1, 2, 0)
grid.addWidget(self.projectNameEdit, 2, 1)
grid.addWidget(self.projectNameLbl2, 3, 0)
grid.addWidget(self.projectNameEdit2, 3, 1)
grid.addWidget(self.nextBtn, 4, 1)
self.setLayout(grid)
self.setGeometry(300, 300, 350, 300)
self.setWindowTitle('projectCreator')
self.show()
self.nextBtn.clicked.connect(self.nextPressed)
def nextPressed(self):
self.msgBox = QtGui.QMessageBox()
self.msgBox.setText("When this button is pressed I want to generate a new layout")
self.msgBox.exec_()
def main():
app = QtGui.QApplication(sys.argv)
ex = BasicGui()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
Say that I enter 10 in the line next to label1 and 2 in the other and press Next.Now I want to clear everything out and create 2 new columns with 10 qlines in each (or something like that).
Excuse me if I'm being either to vague or if I'm just repeating myself. I'm tired and irritated and English is not my first language.
I would deeply appreciate any help I could get or a push in the right direction.
Edit: If it's easier to accomplish this with some other widgetype with tabs or something that's fine. All i want to do is generate new widgets after i have recieved input from the user.
What you'll want to do is used a QStackedLayout[1].
Create a QWidget.
Create your layout.
Call setLayout() on the widget with your layout as the argument.
Push the new widget onto the QStackedLayout.
Use QStackedLayout's setCurrentIndex() or setCurrentWidget() functions to set the current layout.
I did something similar in a project of mine. See https://github.com/shanet/Cryptully/blob/master/cryptully/qt/qChatTab.py for a more complete example. Also see Pyside Changing Layouts for a similar problem.
[1] http://qt-project.org/doc/qt-4.8/qstackedlayout.html
Related
How could I add a check sign next to the currently selected item (or highlight it) in a OptionMenu in a tkinter GUI? The idea is that when I click again to select another item, I can see easily which one is selected (similar to the following picture)
I just added a new example:
from tkinter import *
OptionList = [
"Aries",
"Taurus",
"Gemini",
"Cancer"
]
app = Tk()
app.geometry('100x200')
variable = StringVar(app)
variable.set(OptionList[0])
opt = OptionMenu(app, variable, *OptionList)
opt.config(width=90, font=('Helvetica', 12))
opt.pack(side="top")
labelTest = Label(text="", font=('Helvetica', 12), fg='red')
labelTest.pack(side="top")
def callback(*args):
labelTest.configure(text="The selected item is {}".format(variable.get()))
variable.trace("w", callback)
app.mainloop()
Just use ttk widgets for this modern looking style, try saying something like:
from tkinter import ttk
....
#arguments - master variable default *values
opt = ttk.Optionmenu(app, variable, OptionList[0], *OptionList)
The effect given by this is pretty similar or maybe identical to what your trying to achieve.
You might notice an additional third positional argument here, it is actually default=OptionList[0] argument specified here(specific to just ttk.Optionmenu), it is just the default value that the optionmenu will display, ignoring this might lead to some bugs in the looks of optionmenu, like this.
And also keep in mind, it does not have a font option too. To overcome this, check this out
Hope this was of some help to you, do let me know if any errors or doubts.
Cheers
You can get similar effect using tk.OptionMenu:
from tkinter import *
OptionList = [
"Aries",
"Taurus",
"Gemini",
"Cancer"
]
app = Tk()
app.geometry('300x200')
variable = StringVar(app)
variable.set(OptionList[0])
opt = OptionMenu(app, variable, None) # need to supply at least one menu item
opt.config(width=90, font=('Helvetica', 12))
opt.pack(side="top")
# populate the menu items
menu = opt['menu']
menu.delete(0) # remove the None item
for item in OptionList:
menu.add_radiobutton(label=item, variable=variable)
labelTest = Label(text="", font=('Helvetica', 12), fg='red')
labelTest.pack(side="top")
def callback(*args):
labelTest.configure(text="The selected item is {}".format(variable.get()))
variable.trace("w", callback)
app.mainloop()
When using a QComboBox in PySide2 the popup menu seems to initially start about 10 pixels or so to the left until its finished animating down at which point it pops (about) 10 pixels to the right into the correct position.
How can I fix this? Or am I able to disable the animation so the menu just opens without animating? And am I able to control the animation time for the popup?
Here are two screenshots, the top one is while the combobox dropdown is animating down and the bottom one is after the dropdown is open:
Here's the simple example code use to produce the combobox above:
from PySide2 import QtCore, QtWidgets
import sys
class MyDialog(QtWidgets.QDialog):
def __init__(self, parent=None):
super(MyDialog, self).__init__(parent)
self.setWindowTitle('Modal Dialogs')
self.setMinimumSize(300,80)
# remove help icon (question mark) from window
self.setWindowFlags(self.windowFlags() ^ QtCore.Qt.WindowContextHelpButtonHint)
# create widgets, layouts and connections (signals and slots)
self.create_widgets()
self.create_layouts()
self.create_connections()
def create_widgets(self):
self.combo = QtWidgets.QComboBox()
self.combo.addItems(['one','two','three'])
def create_layouts(self):
# self must be passed to the main_layout so it is parented to the dialog instance
main_layout = QtWidgets.QVBoxLayout(self)
main_layout.addWidget(self.combo)
def create_connections(self):
pass
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
my_dialog = MyDialog()
my_dialog.show() # Show the UI
sys.exit(app.exec_())
My computer doesn't have any way of letting me know if my NumLk is on or off, so I am trying to add an icon in my systray that will changed depending on the state of my NumLk. This .py will always be running when my computer is on.
So far I was able to mix 3 codes and I am able to display the icon in the systray but it doesn't get updated when the state of NumLk change. Actually if I press NumLk twice, I still get the same icon (the on one) and I get this error:
QCoreApplication::exec: The event loop is already running
File "\systray_icon_NumLk_on_off.py", line 21, in on_key_press
main(on)
File "\systray_icon_NumLk_on_off.py", line 46, in main
sys.exit(app.exec_())
SystemExit: -1
My code may not be the best way to do it, so any alternative is welcome! Here is what I came up so far:
#####get the state of NumLk key
from win32api import GetKeyState
from win32con import VK_NUMLOCK
#how to use: print(GetKeyState(VK_NUMLOCK))
#source: http://stackoverflow.com/questions/21160100/python-3-x-getting-the-state-of-caps-lock-num-lock-scroll-lock-on-windows
#####Detect if NumLk is pressed
import pyglet
from pyglet.window import key
window = pyglet.window.Window()
#source: http://stackoverflow.com/questions/28324372/detecting-a-numlock-capslock-scrlock-keypress-keyup-in-python
on=r'on.png'
off=r'off.png'
#window.event
def on_key_press(symbol, modifiers):
if symbol == key.NUMLOCK:
if GetKeyState(VK_NUMLOCK):
#print(GetKeyState(VK_NUMLOCK))#should be 0 and 1 but
main(on)
else:
main(off)
#window.event
def on_draw():
window.clear()
### display icon in systray
import sys
from PyQt5 import QtCore, QtGui, QtWidgets
#source: http://stackoverflow.com/questions/893984/pyqt-show-menu-in-a-system-tray-application - add answer PyQt5
class SystemTrayIcon(QtWidgets.QSystemTrayIcon):
def __init__(self, icon, parent=None):
QtWidgets.QSystemTrayIcon.__init__(self, icon, parent)
menu = QtWidgets.QMenu(parent)
exitAction = menu.addAction("Exit")
self.setContextMenu(menu)
def main(image):
app = QtWidgets.QApplication(sys.argv)
w = QtWidgets.QWidget()
trayIcon = SystemTrayIcon(QtGui.QIcon(image), w)
trayIcon.show()
sys.exit(app.exec_())
if __name__ == '__main__':
pyglet.app.run()
The reason for QCoreApplication::exec: The event loop is already running is actually because you're trying to start app.run() twice. Qt will notice there's already an instance running and throw this exception. When instead, what you want to do is just swap the icon in the already running instance.
Your main problem here is actually the mix of libraries to solve one task if you ask me.
Rather two tasks, but using Qt5 for the graphical part is fine tho.
The way you use Pyglet is wrong from the get go.
Pyglet is intended to be a highly powerful and effective graphics library where you build a graphics engine ontop of it. For instance if you're making a game or a video-player or something.
The way you use win32api is also wrong because you're using it in a graphical window that only checks the value when a key is pressed inside that window.
Now, if you move your win32api code into a Thread (a QtThread to be precise) you can check the state no matter if you pressed your key inside your graphical window or not.
import sys
import win32api
import win32con
from PyQt5 import QtCore, QtGui, QtWidgets
from threading import Thread, enumerate
from time import sleep
class SystemTrayIcon(QtWidgets.QSystemTrayIcon):
def __init__(self, icon, parent=None):
QtWidgets.QSystemTrayIcon.__init__(self, icon, parent)
menu = QtWidgets.QMenu(parent)
exitAction = menu.addAction("Exit")
exitAction.setShortcut('Ctrl+Q')
exitAction.setStatusTip('Exit application')
exitAction.triggered.connect(QtWidgets.qApp.quit)
self.setContextMenu(menu)
class KeyCheck(QtCore.QThread):
def __init__(self, mainWindow):
QtCore.QThread.__init__(self)
self.mainWindow = mainWindow
def run(self):
main = None
for t in enumerate():
if t.name == 'MainThread':
main = t
break
while main and main.isAlive():
x = win32api.GetAsyncKeyState(win32con.VK_NUMLOCK)
## Now, GetAsyncKeyState returns three values,
## 0 == No change since last time
## -3000 / 1 == State changed
##
## Either you use the positive and negative values to figure out which state you're at.
## Or you just swap it, but if you just swap it you need to get the startup-state correct.
if x == 1:
self.mainWindow.swap()
elif x < 0:
self.mainWindow.swap()
sleep(0.25)
class GUI():
def __init__(self):
self.app = QtWidgets.QApplication(sys.argv)
self.state = True
w = QtWidgets.QWidget()
self.modes = {
True : SystemTrayIcon(QtGui.QIcon('on.png'), w),
False : SystemTrayIcon(QtGui.QIcon('off.png'), w)
}
self.refresh()
keyChecker = KeyCheck(self)
keyChecker.start()
sys.exit(self.app.exec_())
def swap(self, state=None):
if state is not None:
self.state = state
else:
if self.state:
self.state = False
else:
self.state = True
self.refresh()
def refresh(self):
for mode in self.modes:
if self.state == mode:
self.modes[mode].show()
else:
self.modes[mode].hide()
GUI()
Note that I don't do Qt programming often (every 4 years or so).
So this code is buggy at it's best. You have to press Ctrl+C + Press "Exit" in your menu for this to stop.
I honestly don't want to put more time and effort in learning how to manage threads in Qt or how to exit the application properly, it's not my area of expertis. But this will give you a crude working example of how you can swap the icon in the lower corner instead of trying to re-instanciate the main() loop that you did.
from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys, os, time
class SetName(QWidget):
def __init__(self):
QWidget.__init__(self)
self.show()
toplayout = QVBoxLayout()
self.setWindowTitle('Personal Info')
self.form_layout = QFormLayout()
self.setLayout(self.form_layout)
self.line_edit_param = QLineEdit(self)
self.line_edit_param.setPlaceholderText("Write Here")
self.form_layout.addRow('Write Name', self.line_edit_param)
toplayout.addLayout(self.form_layout)
self.setFocus()
class LearnApp(QDialog):
def __init__(self):
super(QDialog, self).__init__()
self.setWindowTitle("LearnApp")
self.active = False
close_button = QPushButton("Close")
close_button.clicked.connect(self.close)
self.check_button = QPushButton("Check")
self.check_button.clicked.connect(self.set_data)
self.tr = QTextEdit()
self.tr.setReadOnly(True)
# layout
layout = QHBoxLayout()
#layout.addWidget(self.button3)
sub_layout = QVBoxLayout()
sub_layout.addWidget(self.check_button)
sub_layout.addWidget(close_button)
layout.addLayout(sub_layout)
layout.addWidget(self.tr)
self.setLayout(layout)
self.setFocus()
def set_data(self):
print "in set_data"
SetName()
app = QApplication(sys.argv)
dialog = LearnApp()
dialog.show()
app.exec_()
This is the code I'm trying. If edit it with toplayout = QGridLayout(), program works fine but with toplayout = QVBoxLayout(), it gives message QLayout::addChildLayout: layout "" already has a parentand just flashes the new window. What could be the problem? How should I tackle this? I wanna use QVBoxLayout instead of QGridLayout
Firstly, the new window disappears straight away because you don't store a reference to it. You need to store a reference to the instance in your LearnApp class, or parent it to another Qt object outside of set_data() if you want it to stick around.
The error message regarding the layouts is not occurring because of your choice of layouts, but because you are calling
self.setLayout(self.form_layout)
and then
toplayout.addLayout(self.form_layout)
The first call assigns the layout to the instance of SetName, but in doing so also makes the instance the parent of self.form_layout. The second call is trying to add the same layout to toplayout and set it as the parent, but Qt sees that self.form_layout already has a parent (i.e. is being used elsewhere). This is what the error message is trying to tell you.
I suspect that instead of self.setLayout(self.form_layout), you intended to write something like
self.setLayout(toplayout)
I am using Python 3.1 by the way.
I am trying to build a simple GUI using Tkinter - label, text entry field, button on the first row and editable text area with scrollbar to the right and on the bottom of it - on the second row. Please help me fix up the layout. What I have below does not quite work. If I have to use a grid, I will. I wish to keep the code very simple - I want to "sell" Python to some of my coworkers. So, I want to get a somewhat decent look and feel. Suggest better padding if you do not mind. Also, if my variable names, etc. seem weird, then please make a note.
At the same time I want to pretend that this is a throw-away script which I have not spent much time on. Since I am asking for your help, it ain't so, but they do not need to know ;). So, I do not want to introduce fancy code to create nice borders, etc. I just want something that is visually appealing, clean and simple. If I do not, then my presentation will not achieve its goal.
Thank you, my code is below:
class App:
def __init__(self, parent):
frame = Frame(parent)
self.__setup_gui(frame) # Call Helper
frame.pack(padx=15, pady=15)
parent.title('To be changed')
def __setup_gui(self, frame):
# First Row
self.cs_label = Label(frame, text='Change Set: ')
self.cs_label.pack(side=LEFT, padx=10, pady=10)
self.cs_val = Entry(frame, width=10)
self.cs_val.pack(side=LEFT, padx=10, pady=10)
self.get_button = Button(frame, text='Get', command=self.get_content)
self.get_button.pack(side=LEFT, padx=10, pady=10)
# Text area and scrollbar
self.text_area = Text(frame, height=10, width=50, background='white')
# Put a scroll bar in the frame
scroll = Scrollbar(frame)
self.text_area.configure(yscrollcommand=scroll.set)
self.text_area.pack(side=TOP)
scroll.pack(side=RIGHT,fill=Y)
self.clipboard_var = IntVar()
self.notepad_var = IntVar()
def get_content(self):
print(self.clipboard_var.get())
print(self.notepad_var.get())
###################################################################################################
if __name__ == '__main__':
root = Tk()
app = App(root)
root.mainloop()
You definitely want the grid manager -- Pack only works for a vertical or horizontal stackup by itself. You can use multiple frames to work around it, but I find it's easier to expand a GUI if you just do it with Grid to start.
Here's what I've worked up real quick based what you said and the code. I reduced/removed the padding -- it looked huge for me -- and I set up two scrollbars, in a subframe to make the padding work out more easily. Note that to make the horizontal scrollbar useful your Text area needs to have wrap=NONE; otherwise you might as well use the easy 'ScrolledText' widget from tkinter.scrolledtext and skip the horizontal scroll bar.
I've now reframed things a bit to allow for resize, with a minimum size that shows the top buttons -- see the uses of minsize and row/columnconfigure.
BTW, it looks like your variables aren't being pulled from anywhere -- is that intentional?
from tkinter import *
class App:
def __init__(self, parent):
self.__setup_gui(parent) # Call Helper
parent.title('To be changed')
def __setup_gui(self, parent):
# First Row
self.rowframe = Frame(parent)
self.rowframe.grid()
self.cs_label = Label(self.rowframe, text='Change Set: ')
self.cs_label.grid(row=0, column=0, padx=2, pady=2)
self.cs_val = Entry(self.rowframe, width=10)
self.cs_val.grid(row=0, column=1, padx=2, pady=2)
self.get_button = Button(self.rowframe, text='Get', command=self.get_content)
self.get_button.grid(row=0, column=2, padx=2, pady=2)
parent.update_idletasks()
parent.minsize(width=self.rowframe.winfo_width(), height=self.rowframe.winfo_height())
# Text area and scrollbars
self.textframe = Frame(parent)
self.textframe.grid(row=1, columnspan=2, padx=2, pady=2, sticky=N+S+E+W)
self.hscroll = Scrollbar(self.textframe, orient=HORIZONTAL)
self.vscroll = Scrollbar(self.textframe)
self.text_area = Text(self.textframe, height=10, width=50, wrap=NONE, background='white', yscrollcommand=self.vscroll.set, xscrollcommand=self.hscroll.set)
self.text_area.grid(row=0, column=0, sticky=N+S+E+W)
self.hscroll.config(command=self.text_area.xview)
self.hscroll.grid(row=1, column=0, sticky=E+W)
self.vscroll.config(command=self.text_area.yview)
self.vscroll.grid(row=0, column=1, sticky=N+S)
# Row 0 defaults to 0
parent.rowconfigure(1, weight=1)
parent.columnconfigure(1, weight=1)
# Textarea setup
self.textframe.rowconfigure(0, weight=1)
self.textframe.columnconfigure(0, weight=1)
self.clipboard_var = IntVar()
self.notepad_var = IntVar()
def get_content(self):
print(self.clipboard_var.get())
print(self.notepad_var.get())
###################################################################################################
if __name__ == '__main__':
root = Tk()
app = App(root)
root.mainloop()
Now, all that said...you might get more visual appeal with PyGTK, PyQt, or wxPython, though tkinter coming "standard" is a nice feature.