In CMD the following variable will give you the name of the computer: %COMPUTERNAME%
I need a variable that takes a part of the computername.
I need a if statement that checks if the computername contains "KM" at the start and 00 at the end. It should not look at the number between KM and -00
KM100-00
KM200-00
This works here:
echo %computername%| findstr "^KM.*00$" >nul && echo found the right format
You can do this with substring commands, as per the following transcript:
pax> set xyzzy=KM100-00 KM200-00
pax> echo %xyzzy%
KM100-00 KM200-00
pax> echo %xyzzy:~0,2%
KM
pax> echo %xyzzy:~-2,2%
00
pax> if %xyzzy:~0,2%==KM if %xyzzy:~-2,2%==00 echo yes
yes
That final (chained) if statement is the one you're looking for to see if your variable starts with KM and ends with 00.
The expression %X:~Y,Z% will give you the Z characters starting at position Y (zero-based) of the variable X. You can provide a negative value of Y to make it relative to the end of the string.
echo %computername%| findstr /I /b "KM" | findstr /i /e "00" && echo computer name is like KM-XX-00
You can try also with hostname instead of echo %computername%
I recommend you to read this page, which is about substring usage in command prompt.
And why dont you try this;
set str=KM2000-00
echo.%str%
set pre=%str:~0,2%
echo.%pre%
set pst=%str:~-2%
echo.%pst%
IF %pre% == KM( IF %pst% == 00( echo.true ) )
pause
Related
First of all I'm trying to obtain a certain property from a KML file. For now, I tried
ogrinfo C:/test.kml -so -al | findstr "Extent"
which was recommended to me and outputs
Extent: (-100.054053, 33.702234) - (-94.647180, 37.125712)
I would require this in the form
-100.054053,-94.647180,33.702234,37.125712 for which I thought to use regex.
I tried the following just to see what it outputted:
ogrinfo C:/test.kml -so -al | findstr "Extent" | findstr /r /c:"-*[0-9]*\.[0-9]*"
but this still outputs
Extent: (-100.054053, 33.702234) - (-94.647180, 37.125712)
I read somewhere that Windows' FINDSTR only outputs the line where it matched and not the regex matches themselves. Is there some other way of doing it?
If I get that working I would save the matches in different variables somehow in a shell script. I'm no expert in shell scripting but I've been looking around and was thinking of doing something like this
#!/bin/bash
for /f "tokens=*" %%a in ('ogrinfo C:/test.kml -so -al ^| findstr "Extent" ^| findstr /r /c:"-*[0-9]*\.[0-9]*"') do (
echo %%a
#do something
)
done >output
but running this causes the shell to immediately disappears and can't even see the error.
Assumptions
You have a kml file with raw data.
You can extract a single line which starts with "Extent: " to get the values you want
Single line => there is only 1 line with that format in the kml file
The format of that line is:
Extent: (NUMBER1, NUMBER2) - (NUMBER3, NUMBER4)
A number can have the following characters: 0 1 2 3 4 5 6 7 8 9 . -
The output you want is:
NUMBER1,NUMBER3,NUMBER2,NUMBER4
Using Linux tools only, you can do this:
#!/bin/bash
#
datafile="data.kml"
# Ensure the data file exists
if [[ ! -f "$datafile" ]]
then
echo "ERROR: the data file does not exist."
exit 1
fi
# Extract the "Extent:" line
dataline=$(grep "Extent: " "$datafile")
# Make sure the line is of a valid format, and assign the number variables
if [[ $dataline =~ "Extent: ("([0-9.-]+)", "([0-9.-]+)") - ("([0-9.-]+)", "([0-9.-]+)")" ]] && number1="${BASH_REMATCH[1]}" && number2="${BASH_REMATCH[2]}" && number3="${BASH_REMATCH[3]}" && number4="${BASH_REMATCH[4]}"
then
echo "-----DEBUG-----"
echo "line==$dataline"
echo "1==$number1"
echo "2==$number2"
echo "3==$number3"
echo "4==$number4"
echo "-- END DEBUG --"
echo ""
echo "$number1,$number3,$number2,$number4"
else
echo "ERROR: there is no \"Extent: \" line in the data file ($datafile)"
fi
Details:
Everything is done in the if line.
=~ matches the left side with the pattern on the right side.
In the regular expression, you can define sections you want to reuse with ( ).
Ex: abcd(1)efgh(2)ijkl. The sections you can reuse are 1 and 2.
So in the if, each number is surrounded by parentheses.
When the =~ is processed, the BASH_REMATCH array is defined with each section.
The "DEBUG" echo statements can be removed or commented out.
If you have more than one "Extent: ..." in the KML file, you can loop on the lines and process each one at a time.
echo %time:~-5% returns a 5-character string, such as
18.09
However, i cannot seem to set that string to a variable:
set start = %time:~-5%
echo %start%
returns
10:07:18.09
what's simple way to get those last 5 chars into a variable?
thx
Windows doesn't like space next to =. So try this ...
set start=%time:~-5%
echo %start%
My text file contains one line comments that all being with "// ". Two forward slashes and a space. These may either take up the whole line or just the last part of a line. Each comment does not extend beyond the line that it's on. So no /* */ type comments crossing multiple lines.
In simple terms, all comments start with "//space" anywhere on the line. Anything starting with "//space" should be removed and trailing spaces on that line should also be removed. Leading spaces should stay. Any blank lines should be removed.
Sample file:
// This is a comment
x = 1 // This is also a comment after the double slash
x = 2
x = 3 // The above is a blank line
// Comment on this record but nothing precedes it, so should be deleted.
y = 4 // A line with leading spaces that should be kept.
z = "//path"; // The first double slashes are not a comment since the space is missing after the "//"
// Last comment line.
Result file (no trailing spaces, but keep leading spaces.:
x = 1
x = 2
x = 3
y = 4
z = "//path";
I can remove the blank lines using gc file.txt | Where-Object { $_ -ne ''} > result.txt. However I'm having trouble with reading just the beginning part of a line up to the "//" comment part.
I also tried findstr but haven't found how to read each line up to the "//" and then trim spaces out.
I could write a script program to loop throught the file and do this, but it seems like there should be a way to accomplish it using a simple one or two line powershell or bat file command.
What is the easiest way (shortest amount of code) to remove these comments while keeping the uncommented contents of the file?
Since you seem to equate "easy" with "short", here's a fairly simple solution:
gc .\samplefile.txt|%{$_-replace"(.*)(// .*)",'$1'}|?{$_}
if it's really that important to you :-)
A bit more verbose version (still using regex):
Get-Content .\samplefile.txt | Where-Object {
-not ([String]::IsNullOrEmpty($_.Trim()) -or $_-match"^\s*// ")
} |ForEach-Object { $_ -replace "(.*)(// .*)",'$1' }
That being said, I would (personally) go for a more verbose and easier-to-read/maintain solution:
To remove everything after //, the easiest way is to find the first occurrence of // with String.IndexOf() and then grab the first part with String.Substring():
PS C:\> $CommentedString = "Content // this is a comment"
PS C:\> $CommentIndex = $CommentedString.IndexOf('// ')
PS C:\> $CommentedString.Substring(0,$CommentIndex)
Content
For the indented comments you can also use String.Trim() to remove whitespace from the beginning and end of the string:
PS C:\> " // Indented comment" -match '^//'
True
You can use the ForEach-Object cmdlet to go through every line and apply the above:
function Remove-Comments {
param(
[string]$Path,
[string]$OutFile
)
# Read file, remove comments and blank lines
$CleanLines = Get-Content $Path |ForEach-Object {
$Line = $_
# Trim() removes whitespace from both ends of string
$TrimmedLine = $Line.Trim()
# Check if what's left is either nothing or a comment
if([string]::IsNullOrEmpty($TrimmedLine) -or $TrimmedLine -match "^// ") {
# if so, return nothing (inside foreach-object "return" acts like "coninue")
return
}
# See if non-empty line contains comment
$CommentIndex = $Line.IndexOf("// ")
if($CommentIndex -ge 0) {
# if so, remove the comment
$Line = $Line.Substring(0,$CommentIndex)
}
# return $Line to $CleanLines
return $Line
}
if($OutFile -and (Test-Path $OutFile)){
[System.IO.File]::WriteAllLines($OutFile, $CleanLines)
} else {
# No OutFile was specified, write lines to pipeline
Write-Output $CleanLines
}
}
Applied to your sample:
PS C:\> Remove-Comments D:\samplefile.txt
x = 1
x = 2
x = 3
Like a great many text processing problems, there is a simple solution using JREPL.BAT - a powerful regex text processing utility for the Windows command line. It is pure script (hybrid JScript/batch) that runs natively on any Windows machine from XP onward. Full documentation is embedded within the script.
jrepl "^(.*?)\s*// " "$1!=''?$1:false" /jmatch /f test.txt /o out.txt
You can overwrite the original file by specifying - as the output file:
jrepl "^(.*?)\s*// " "$1!=''?$1:false" /jmatch /f test.txt /o -
I've tested, and it gives the exact output you are looking for.
If you put the command within a batch script, then you must use call jrepl
Tha Batch file below do what you want. Sorry, but there is not an "easy short code" way to do this...
#echo off
setlocal EnableDelayedExpansion
rem Set the maximum number of trailing spaces as a power_of_2-1 value. For example, for 15 spaces:
set spcPow2=4
set "spaces= "
for /L %%i in (1,1,%spcPow2%) do set "spaces=!spaces!!spaces!"
set /A spcPow2-=1
rem Process all lines, excepting empty ones and lines that start with "/"
setlocal DisableDelayedExpansion
for /F "eol=/ delims=" %%a in (test.txt) do (
set "line=%%a"
rem Split line at "// " and get the first part
setlocal EnableDelayedExpansion
for /F "delims=¡" %%b in ("!line:// =¡!") do (
endlocal
set "line=%%b"
)
rem Eliminate trailing spaces
setlocal EnableDelayedExpansion
set spc=0
for /L %%b in (%spcPow2%,-1,0) do (
set /A "newSpc=spc+(1<<%%b)"
for %%n in (!newSpc!) do if "!line:~-%%n!" equ "!spaces:~-%%n!" set "spc=%%n"
)
if !spc! gtr 0 for %%n in (!spc!) do set "line=!line:~0,-%%n!"
rem Show resulting line
if defined line echo !line!
endlocal
)
EDIT: New solution added
#set #x=1 // & CScript //nologo //E:JScript "%~F0" < samplefile.txt & goto :EOF
WScript.Stdout.Write(WScript.Stdin.ReadAll().replace(/(.*)\/\/ .*/g,"$1"))
Copy previous code into a file with .BAT extension, that is, it is a Batch file!
I want to assign the alpha numeric value to one variable in Batch scripting.
I tried following one but getting error.
setlocal
set test = \765514e2aad02ca658cc56cdb7884947 *E:\\test1
echo %test%
endlocal
Error:
C:\Users\bgannu>setlocal
C:\Users\bgannu>set test = \765514e2aad02ca658cc56cdb7884947 *E:\\test1
C:\Users\bgannu>echo 0
0
C:\Users\bgannu>endlocal
The syntax for set is set [[/a [expression]] [/p [variable=]] string]
The = has to be directly after your variable so you need to change:
set test = \765514e2aad02ca658cc56cdb7884947 *E:\\test1
to:
set test=\765514e2aad02ca658cc56cdb7884947 *E:\\test1
Otherwise your variable name would have a space at the end. You can easily try this out:
> set bar = foo
> echo %bar%
%bar%
> echo %bar %
foo
Note that both the variable name and its content got a space.
Lose the /A. the /A is used for arithmetic.
C:\test>set var=\765514e2aad02ca658cc56cdb7884947 *E:\\test1
C:\test>echo %var%
\765514e2aad02ca658cc56cdb7884947 *E:\\test1
In the windows shell:
echo "foo bar" | find "foo"
succeeds (i.e. errorlevel = 0). However, I want a script that fails (i.e. errorlevel <> 0) when it finds a particular word in some input text. Any ideas?
A lttle trickery can emulate what you desire. Only the first three lines are required, the rest are just a test.
c:> echo "foo bar" | find "foo"
c:> if x%errorlevel%==x0 echo 1 | find "2"
c:> if not x%errorlevel%==x0 echo 1 | find "1" >nul 2>nul
c:> echo %errorlevel%
1