I'm using PL/SQL (Oracle) and this is the result I have from a simple select query at the moment (with an order by):
Name Hour Value
---------------------------------
Peter 1 10
Peter 2 12
Peter 3 22
Joe 1 8
Joe 2 8
Joe 3 12
Richard 1 9
Richard 2 7
Matt 1 11
In SSRS, I have a complex Matrix where I want to have alternating row colors*. Therefor, I need the rownumber, but it must be 'grouped' by the Name. So this is what I want:
Name Hour Value Row_Num
--------------------------------------------
Peter 1 10 1
Peter 2 12 1
Peter 3 22 1
Joe 1 8 2
Joe 2 8 2
Joe 3 12 2
Richard 1 9 3
Richard 2 7 3
Matt 1 11 4
Notice how the Row_Num (or whatever you want to call it) only changes when the Name changes. Is this possible in PL/SQL?
*I know of the techniques to get alternating row colors in SSRS, but I'm using a matrix and have the problem mentioned by Kyle Hale in the comments to ahmad's answer to this question.
This is easy to do with the dense_rank() function in the query used to fetch the results:
select name, hour, value,
dense_rank() over (order by name) as row_num
from t;
Note: this will not necessarily assign the values in the order you have given. But each group will get a different value. If you need them in the order given, then you will need to identify the order. SQL tables are inherently unordered, so a column is needed to specify the ordering.
select name
, value
, hour
, dense_rank() over (partition by 1 order by name) as row_num
from
(
select 'Peter' name, '1' hour , '10' value from dual union all
select 'Peter', '2', '12' from dual union all
select 'Peter', '3', '22' from dual union all
select 'Joe', '1', '8' from dual union all
select 'Joe', '2', '8' from dual union all
select 'Joe', '3', '12' from dual union all
select 'Richard','1', '9' from dual union all
select 'Richard','2', '7' from dual union all
select 'Matt', '1', '11' from dual
)
Joe 8 2 1
Joe 12 3 1
Joe 8 1 1
Matt 11 1 2
Peter 22 3 3
Peter 12 2 3
Peter 10 1 3
Richard 9 1 4
Richard 7 2 4
Related
I have a table like this:
Division
Region
Date of Last Visit
1
2
11/20/2021
1
2
11/18/2021
1
7
10/18/2021
1
7
11/19/2021
2
2
11/17/2021
2
3
09/20/2021
2
3
10/20/2021
I want to write a query that groups by the division and region columns and gives me the last 5 dates for each group separated by commas in a single column. Something like this:
Division
Region
Date of Last Visit
Today
Days since last visit
1
2
11/20/2021, 11/18/2021
sysdate
sysdate - max(date of last visit)
1
7
10/18/2021, 11/19/2021
sysdate
sysdate - max(date of last visit)
2
2
11/17/2021
sysdate
sysdate - max(date of last visit)
2
3
9/20/2021, 10/20/2021
sysdate
sysdate - max(date of last visit)
The last two columns are custom calculated columns that I also need for the final output table. Any help would be greatly appreciated as I have tried a lot of things but I keep getting errors about it not being grouped properly, possibly because of the two extra columns at the end. But even without that, I am not sure how to fetch only the last 5 dates per group in oracle.
Thanks!
You want to filter the greatest-n-per-group using the ROW_NUMBER analytic function and then aggregate:
SELECT division,
region,
LISTAGG(TO_CHAR(date_of_last_visit, 'DD/MM/YYYY'), ',')
WITHIN GROUP (ORDER BY date_of_last_visit DESC)
AS date_of_last_visit,
SYSDATE AS today,
TRUNC(SYSDATE - MAX(date_of_last_visit)) AS days_since_last_visit
FROM (
SELECT t.*,
ROW_NUMBER() OVER (PARTITION BY division, region
ORDER BY date_of_last_visit DESC) AS rn
FROM table_name t
)
WHERE rn <= 5
GROUP BY
division,
region
Which, for the sample data:
CREATE TABLE table_name (division, region, date_of_last_visit) as
select 1, 2, date '2021-11-20' from dual union all
select 1, 2, date '2021-11-18' from dual union all
select 1, 7, date '2021-10-18' from dual union all
select 1, 7, date '2021-11-19' from dual union all
select 2, 2, date '2021-11-17' from dual union all
select 2, 3, date '2021-09-20' from dual union all
select 2, 3, date '2021-10-20' from dual;
Outputs:
DIVISION
REGION
DATE_OF_LAST_VISIT
TODAY
DAYS_SINCE_LAST_VISIT
1
2
20/11/2021,18/11/2021
30-NOV-21
10
1
7
19/11/2021,18/10/2021
30-NOV-21
11
2
2
17/11/2021
30-NOV-21
13
2
3
20/10/2021,20/09/2021
30-NOV-21
41
db<>fiddle here
Here you go; read comments within code.
SQL> with test (division, region, datum) as
2 -- sample data
3 (select 1, 2, date '2021-11-20' from dual union all
4 select 1, 2, date '2021-11-18' from dual union all
5 select 1, 7, date '2021-10-18' from dual union all
6 select 1, 7, date '2021-11-19' from dual union all
7 select 2, 2, date '2021-11-17' from dual union all
8 select 2, 3, date '2021-09-20' from dual union all
9 select 2, 3, date '2021-10-20' from dual
10 ),
11 temp as
12 -- rank rows per division/region, sorted by date column in descending order
13 (select t.*,
14 rank() over (partition by division, region order by datum desc) rnk
15 from test t
16 )
17 -- select up to 5 last rows per division/region
18 select division, region,
19 listagg(datum, ', ') within group (order by datum) dates,
20 trunc(sysdate) today,
21 --
22 (select trunc(sysdate) - a.datum
23 from temp a
24 where a.division = t.division
25 and a.region = t.region
26 and a.rnk = 1) days_since
27 from temp t
28 where rnk <= 5
29 group by division, region
30 order by division, region;
DIVISION REGION DATES TODAY DAYS_SINCE
---------- ---------- ------------------------------ ---------- ----------
1 2 11/18/2021, 11/20/2021 11/30/2021 10
1 7 10/18/2021, 11/19/2021 11/30/2021 11
2 2 11/17/2021 11/30/2021 13
2 3 09/20/2021, 10/20/2021 11/30/2021 41
SQL>
I believe there is probably an easy way to solve these problems with pivots or partitions but I can't seem to find the proper solutions. I have a round about solution for problem 1 by using a long list of select sum()s and a long solution for problem 2 where I just select the count(*) from table B where id = id from table A multiple times in a (select) blocks but if I have a large number of IDs both of those solution equal very long SQL that gets very tedious and I'm sure there is a better way it is just eluding me.
I would really like solutions that would allow me to include a large set of multiple IDs or supply the solution with a table of IDs to evaluate.
Problem 1:
Table:
------------------
ID DESC YEAR
1 A 2021
1 B 2021
1 C 2021
2 A 2021
2 B 2021
2 C 2021
3 A 2019
3 B 2019
I would like to have the count of the ID's for each DESC by year.
Expected Result:
------------------
Year CountA CountB CountC
2019 1 1 0
2021 2 2 2
Problem 2:
Table A:
------------------
ID DESC
1 A
2 B
3 C
Table B:
------------------
SET ID
10 1
10 1
12 1
13 2
14 3
I would like to see (1) how many of each ID from Table A can be found in each SET in Table B and (2) how many of each ID from Table A can be found in each SET in Table B and not in any other SET of Table B (unique matches).
Expected Result 1:
------------------
ID Count10 Count12 Count13 Count14
1 2 1 0 0
2 0 0 1 0
3 0 0 0 1
Expected Result 2:
------------------
ID UniqueCount10 UniqueCount12 UniqueCount13 UniqueCount14
1 0 0 0 0
2 0 0 1 0
3 0 0 0 1
Thank you for any and all assistance.
All three problems can be solved with pivoting (calling Problem 2 "two different problems"), although it is not clear what purpose Result 2 would serve (in the second problem; see my comments to you).
Note that desc and set are reserved keywords, and year is a keyword, so they shouldn't be used as column names. I changed to descr, set_ (with an underscore) and yr. Also, I do not use double-quotes for column names in the output; all-caps column names are just fine.
In the second problem it is not clear why you need Table A. Could you have some id values that don't appear at all in Table B, but you still want them in the final output? If so, you will need to change my semi-joins to outer joins; left as an exercise, since it's a different (and much more basic) type of question.
In the first problem, you must pivot the result of a subquery, which selects only the relevant columns from the base table. There is no such need for the second problem (unless your tables have other columns that should not be considered - left for you to figure out).
Problem 1
Data:
create table tbl (id, descr, yr) as
select 1, 'A', 2021 from dual union all
select 1, 'B', 2021 from dual union all
select 1, 'C', 2021 from dual union all
select 2, 'A', 2021 from dual union all
select 2, 'B', 2021 from dual union all
select 2, 'C', 2021 from dual union all
select 3, 'A', 2019 from dual union all
select 3, 'B', 2019 from dual
;
Query and output:
select *
from (select descr, yr from tbl)
pivot (count(*) for descr in ('A' as count_a, 'B' as count_b, 'C' as count_c))
order by yr
;
YR COUNT_A COUNT_B COUNT_C
---- ------- ------- -------
2019 1 1 0
2021 2 2 2
Problem 2
Data:
create table table_a (id, descr) as
select 1, 'A' from dual union all
select 2, 'B' from dual union all
select 3, 'C' from dual
;
create table table_b (set_, id) as
select 10, 1 from dual union all
select 10, 1 from dual union all
select 12, 1 from dual union all
select 13, 2 from dual union all
select 14, 3 from dual
;
Part 1 - Query and result:
select *
from table_b
pivot (count(*) for set_ in (10 as count_10, 12 as count_12,
13 as count_13, 14 as count_14))
where id in (select id from table_a) -- is this needed?
order by id -- if needed
;
ID COUNT_10 COUNT_12 COUNT_13 COUNT_14
-- -------- -------- -------- --------
1 2 1 0 0
2 0 0 1 0
3 0 0 0 1
Part 2 - Query and result:
select *
from (
select id, case count(distinct set_) when 1 then max(set_) end as set_
from table_b
where id in (select id from table_a) -- is this needed?
group by id
)
pivot (count(*) for set_ in (10 as unique_ct_10, 12 as unique_ct_12,
13 as unique_ct_13, 14 as unique_ct_14))
order by id -- if needed
;
ID UNIQUE_CT_10 UNIQUE_CT_12 UNIQUE_CT_13 UNIQUE_CT_14
-- ------------ ------------ ------------ ------------
1 0 0 0 0
2 0 0 1 0
3 0 0 0 1
In this last part of the second problem, you might as well just take the subquery and run it separately - what's the purpose of pivoting its output?
I have a dataset in which one column is Branch-ID and other one is Branch Manager and it looks as follows in the given url.
dataset
I want to combine the branch managers into one single column based on the branch-id. For example if Bob and Sandra are two different branch-managers but have the same branch id which is branch-id=1, then we should concatenate them together as Bob-Sandra and place them in a separately created column.
I have attached the expected output for the above dataset. expected_output_dataset
I am currently using Oracle Analytics Cloud Professional Version.
I don't know Oracle Analytics, but - if it has anything to do with an Oracle database and its capabilities, then listagg helps.
Sample data in lines #1 - 10; query you might be interested in begins at line #11.
SQL> with test (account_id, branch_id, branch_manager) as
2 (select 1, 123, 'Sandra' from dual union all
3 select 3, 124, 'Martha' from dual union all
4 select 4, 125, 'John' from dual union all
5 select 6, 126, 'Andrew' from dual union all
6 select 7, 126, 'Mathew' from dual union all
7 select 2, 123, 'Michael' from dual union all
8 select 5, 125, 'David' from dual union all
9 select 8, 126, 'Mark' from dual
10 )
11 select a.account_id, a.branch_id, a.branch_manager,
12 b.concatenated_column
13 from test a join (select branch_id,
14 listagg(branch_manager, '-') within group (order by null) concatenated_column
15 from test
16 group by branch_id
17 ) b on b.branch_id = a.branch_id;
ACCOUNT_ID BRANCH_ID BRANCH_ CONCATENATED_COLUMN
---------- ---------- ------- -------------------------
1 123 Sandra Michael-Sandra
3 124 Martha Martha
4 125 John David-John
6 126 Andrew Andrew-Mark-Mathew
7 126 Mathew Andrew-Mark-Mathew
2 123 Michael Michael-Sandra
5 125 David David-John
8 126 Mark Andrew-Mark-Mathew
8 rows selected.
SQL>
I would like to pivot a select statement.
Columns "Country", "Store" and "Sales" are given.
Now I would like to have an output like:
Store1 Store2 Store3
Country1 2342 2342 5675
Country2 5753 3274 7326
Country3 1543 4367 3367
So basically I need the salescount for every Store, for every Country.
The Input comes from (example):
Country: StoreNr: ProductSold:
Belgium 23 Car
Belgium 23 House
Netherland 23 Car
Output would be:
Store23
Belgium 2
Netherlands 1
If the number of stores is finite, you could use one of these approaches:
Using count() aggregate function combined with case expression:
-- sample of data. just for the sake of demonstration
SQL> with t1(Country, StoreNr, ProductSold) as(
2 select 'Belgium' , 23, 'Car' from dual union all
3 select 'Belgium' , 23, 'House' from dual union all
4 select 'Netherland', 23, 'Car' from dual union all
5 select 'Belgium' , 25, 'House' from dual
6 )
7 select country
8 , count(case
9 when StoreNr = 23
10 then 1
11 end) as storeNr_23
12 , count(case
13 when StoreNr = 25
14 then 1
15 end) as storeNr_25
16 from t1
17 group by country
18 ;
Result:
COUNTRY STORENR_23 STORENR_25
---------- ---------- ----------
Belgium 2 1
Netherland 1 0
Starting from Oracle 11g and up, the pivot operator as follows:
select *
from (Select country as country
, country as country_cnt
, StoreNr
from t1)
pivot( -- list all store numbers here
count(country_cnt) for storenr in ( 23 as StoreNr_23
, 25 as StoreNr_25)
)
Result:
COUNTRY STORENR_23 STORENR_25
---------- ---------- ----------
Belgium 2 1
Netherland 1 0
I am working on a time attendance system. I have the employees' transactions stored in the following table:
I want to get the earliest and the latest transactions for each employee including their date and type.
I am able to get the dates using grouping and aggregation. However, I am not able to figure out how to get types with them.
Would you please help me in it.
Thank you.
That's what the FIRST and LAST aggregate functions are designed for.
Here is a link to the documentation:
FIRST: http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions065.htm#SQLRF00641
LAST: http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions083.htm#sthref1206
And here is an example:
SQL> create table my_transactions (id,employee_id,action_date,type)
2 as
3 select 1, 1, sysdate, 'A' from dual union all
4 select 2, 1, sysdate-1, 'B' from dual union all
5 select 3, 1, sysdate-2, 'C' from dual union all
6 select 4, 1, sysdate-3, 'D' from dual union all
7 select 5, 2, sysdate-11, 'E' from dual union all
8 select 6, 2, sysdate-12, 'F' from dual union all
9 select 7, 2, sysdate-13, 'G' from dual
10 /
Table created.
SQL> select *
2 from my_transactions
3 order by id
4 /
ID EMPLOYEE_ID ACTION_DATE T
---------- ----------- ------------------- -
1 1 04-07-2011 10:15:07 A
2 1 03-07-2011 10:15:07 B
3 1 02-07-2011 10:15:07 C
4 1 01-07-2011 10:15:07 D
5 2 23-06-2011 10:15:07 E
6 2 22-06-2011 10:15:07 F
7 2 21-06-2011 10:15:07 G
7 rows selected.
SQL> select employee_id
2 , min(action_date) min_date
3 , max(type) keep (dense_rank first order by action_date) min_date_type
4 , max(action_date) max_date
5 , max(type) keep (dense_rank last order by action_date) max_date_type
6 from my_transactions
7 group by employee_id
8 /
EMPLOYEE_ID MIN_DATE M MAX_DATE M
----------- ------------------- - ------------------- -
1 01-07-2011 10:15:07 D 04-07-2011 10:15:07 A
2 21-06-2011 10:15:07 G 23-06-2011 10:15:07 E
2 rows selected.
Regards,
Rob.
You could try to use analytical(or windowing functions)
select *
from
(select id, employee_id, action_date,type,
max(action_date) over (partition by employee_id) max_action_date,
min(action_date) over (partition by employee_id) min_action_date
from transaction)
where action_date in (max_action_date, min_action_date)