I have a text_field :birthday_line in my user form, that I need to parse into the user's birthday attribute.
So I'm doing something like this in my User class.
attr_accessor :birthday_line
before_save :set_birthday
def set_birthday
self.birthday = Date.strptime(birthday_line, I18n.translate("date.formats.default")
end
But the problem is that for some reason it gives me an error saying Invalid date when I try to pass in a string 27 января 1987 г. wich should be parsed to 1987-01-27.
The format and month names in my config/locales/ru.yml
ru:
date:
formats:
default: "%d %B %Y г."
month_names: [~, января, февраля, марта, апреля, мая, июня, июля, августа, сентября, октября, ноября, декабря]
seem to be correct.
Date.parse also doesn't help, it just parses the day number (27) and puts the month and year to todays date (so it'll be September 27 2013 instead of January 27 1987).
I had the same problem and what I can suggest:
string_with_cyrillic_date = '27 Января 1987'
1)create array of arrays like this
months = [["января", "Jan"], ["февраля", "Feb"], ["марта", "Mar"], ["апреля", "Apr"], ["мая", "May"], ["июня", "Jun"], ["июля", "Jul"], ["августа", "Aug"], ["сентября", "Sep"], ["октября", "Oct"], ["ноября", "Nov"], ["декабря", "Dec"]]
2) Now you can iterate this and find your cyrillic month:
months.each do |cyrillic_month, latin_month|
if string_with_cyrillic_date.match cyrillic_month
DateTime.parse string_with_cyrillic_date.gsub!(/#{cyrillic_month}/, latin_month)
end
end
And now you will receive the date that you expect
27 Jan 1987
Related
I have been trying to use Date/DateTime to validate that a given date is in the correct format.
str = "January 17, 2017 10:30 AM"
temp = DateTime.strptime(str, '%B %-d, %y %l:%M %p')
but am getting the error
`strptime': invalid date (ArgumentError)
I have been able to split the string into ""January 17," "2017 10:30 AM" and validate it without issue, but I would really like to know why I can't just use strptime on the whole string, or what I am doing wrong if it can be done.
This error is happening because according to the docs of DateTime#strptime:
Parses the given representation of date and time with the given template, and creates a date object. strptime does not support specification of flags and width unlike strftime.
And your format includes a value of %-d which is a width parameter, hence the exception. If you try a basic invocation like:
DateTime.strptime(str, '%B %d, %Y')
you'll see it works. Also, you'll want uppercase-Y for the full 4-digit year.
In a nutshell: you'll need to adjust your format string
This format works fine :
temp = DateTime.strptime(str, '%B %d, %Y %l:%M %p')
#<DateTime: 2017-01-17T10:30:00+00:00 ((2457771j,37800s,0n),+0s,2299161j)>
I've got a bunch of user-inputted dates and times like so:
date = "01:00pm 06/03/2015"
I'm trying to submit them to a datetime column in a database, and I'm trying to systemize them like this:
DateTime.strptime(date, '%m/%d/%Y %H:%M')
But I consistently get an invalid date error. What am I doing wrong? If I submit the string without strptime the record will save but it sometimes gets the date wrong.
Also, how can I append a timezone to a DateTime object?
Edit:
So .to_datetime and DateTime.parse(date) work for the date string and fail for date2. What's going on?
date2 = "03:30pm 05/28/2015"
Try using to_datetime:
date.to_datetime
# => Fri, 06 Mar 2015 13:00:00 +0000
Also if you read the documentation for DateTime#strptime, here. It states:
Parses the given representation of date and time with the given
template, and creates a date object.
Its important to note that the template sequence must match to that of input string sequence, which don't in your case - leading to error.
Update
Using to_datetime over second example will generate
ArgumentError: invalid date
This is because it expects the date to be in dd-mm-yy format. Same error will be raised for DateTime.parse as to_datetime is nothing but an api for the later. You should use strptime in-case of non-standard custom date formats. Here:
date2 = "03:30pm 05/28/2015"
DateTime.strptime(date2, "%I:%M%p %m/%d/%Y")
# => Thu, 28 May 2015 15:30:00 +0000
date = "01:00pm 06/03/2015"
DateTime.parse(date)
=> Fri, 06 Mar 2015 13:00:00 +0000
You haven't got your parameters in the correct order.
DateTime.strptime(date, '%H:%M%p %m/%d/%Y')
You'll also need to add %p for the am/pm suffix
controller action:
#days = (#date_start - Date.today)
rendering <%= #days %> returns
2/1
The first digit is correct. How is the rest being generated and what does it mean?
According to docs:
d - other → date or rational
Returns the difference between the two dates if the other is a date object. If the other is a numeric value, returns a date object pointing other days before self. If the other is flonum, assumes its precision is at most nanosecond.
So your (2/1) is a Rational number. You can check it with #days.class.
If your #date_start is also Date object - you can convert #days to Integer to get difference in days with #days.to_i without information loss since difference between Dates will always be (n/1)
But in general, method returns Rational, because you can also subtract DateTime objects(specifying not only date, but also time), like this:
DateTime.new(2001,2,3) - DateTime.new(2001,2,2,12)
# 03 Feb 2001 00:00:00 - 02 Feb 2001 12:00:00
# => (1/2)
And in this case only half of the day is between 03 Feb 2001 00:00:00 and 02 Feb 2001 12:00:00, thus it returns (1/2).
I want to check if a day is the last day of the month and if it is, for a function to return true, otherwise return false.
For example, if I pass in an argument of "Sun, 30 Jun 2013", the function is to return true, because it is the last day of the month, however if I pass in the argument "Mon, 03 Jun 2013" the function is to return false.
How can this be accomplished using Ruby.
If you're using Rails, you can always do this as well:
date == date.end_of_month
or to check the end of this month:
date == Date.today.end_of_month
I would do something like this
def is_last_day(mydate)
mydate.month != mydate.next_day.month
end
Parse the date with DateTime.parse. DateTime.parse has built-in support for many date formats (including those in your example), but you can always use DateTime.strptime for more complex formats.
See if the next day is 1 (first day of next month) by using Date#+.
require 'date'
def last_day?(date_string)
date = DateTime.parse(date_string)
(date + 1).day == 1
end
puts last_day?('Sun, 30 Jun 2013') # true
puts last_day?('Mon, 03 Jun 2013') # false
I'm trying to figure out how to extract dates from unstructured text using Ruby.
For example, I'd like to parse the date out of this string "Applications started after 12:00 A.M. Midnight (EST) February 1, 2010 will not be considered."
Any suggestions?
Try Chronic (http://chronic.rubyforge.org/) it might be able to parse that otherwise you're going to have to use Date.strptime.
Assuming you just want dates and not datetimes:
require 'date'
string = "Applications started after 12:00 A.M. Midnight (EST) February 1, 2010 will not be considered."
r = /(January|February|March|April|May|June|July|August|September|October|November|December) (\d+{1,2}), (\d{4})/
if string[r]
date =Date.parse(string[r])
puts date
end
Also you can try a gem that can help find date in string.
Exapmle:
input = 'circa 1960 and full date 07 Jun 1941'
dates_from_string = DatesFromString.new
dates_from_string.get_structure(input)
#=> return
# [{:type=>:year, :value=>"1960", :distance=>4, :key_words=>[]},
# {:type=>:day, :value=>"07", :distance=>1, :key_words=>[]},
# {:type=>:month, :value=>"06", :distance=>1, :key_words=>[]},
# {:type=>:year, :value=>"1941", :distance=>0, :key_words=>[]}]