cat Error00
4 0 375
4 2001 21
4 2002 20
cat Error01
4 0 465
4 2001 12
4 2002 40
4 2016 1
I want output as below
4 0 375 465
4 2001 21 12
4 2002 20 20
4 2016 - 1
i am using the below query. here problem is i m not able to handle grep for two field because space is coming.
please suggest how can to get rid of this.
keylist=$(awk '{print $1,$2'} Error0[0-1] | sort | uniq)
for key in ${keylist} ; do
echo ${key}
val_a=$(grep "^${key}" Error00 | awk '{print $3}') ;val_a=${val_a:---}
val_b=$(grep "^${key}" Error01 | awk '{print $1,$2}') ; val_b=${val_b:--- --}
echo $key ${val_a} >>testreport
done
i m geting the oputput as below
4 375 465
0
4 21 12
2001
4 20 20
2002
4 - 1
2016
A single awk one liner can handle this easily:
awk 'FNR==NR{a[$1,$2]=$3;next}{print $1,$2,(a[$1,$2]?a[$1,$2]:"-"),$3}' err0 err1
4 0 375 465
4 2001 21 12
4 2002 20 40
4 2016 - 1
For formatted output you can use printf instead of print. Like Jonathan Leffler suggest:
printf "%s %-6s %-6s %s\n",$1,$2,(a[$1,$2]?a[$1,$2]:"-"),$3
4 0 375 465
4 2001 21 12
4 2002 20 40
4 2016 - 1
However a general solution is to use column -t for a nice table output:
awk '{....}' err0 err1 | column -t
4 0 375 465
4 2001 21 12
4 2002 20 40
4 2016 - 1
grep is not really the right tool for this job. You can either play with awk or Perl (or Python, or …), or you can use join. However, join only joins on a single column at a time, and you appear to need to join on two columns. So, we're going to have to massage the data so that it will work with join. I'm about to assume you're using bash and so have process substitution available. You can do the job without, but it is fiddlier and involves temporary files (and traps to clean them up, etc).
The key to the join will be to replace the blank between the first two columns with a colon (or any other convenient character — control-A would work fine too), then join the files on column 1 with a replacement character. The inputs must be sorted; the output must have the colon replaced with a blank.
$ join -o 0,1.2,2.2 -a 1 -a 2 -e '-' \
> <(sed 's/ */:/' Error00 | sort) \
> <(sed 's/ */:/' Error01 | sort) |
> sed 's/:/ /'
4 0 375 465
4 2001 21 12
4 2002 20 40
4 2016 - 1
$
The 's/ */:/' operation replaces the first sequence of one or more blanks with a colon; the input data has two blanks between the 4 and the 0 in the first line of Error00. The input to join must be in sorted order of the joining field, here the first field. The output is the join field, the second column of Error00 and the second column of Error01 (remembering that means the second column after the first two have been fused by the colon). If there's an unmatched line in the first file, generate an output line (-a 1); ditto for the second file; and for the missing fields, insert a dash (-e '-'). The final sed removes the colon that was added.
If you want the data formatted, pipe it through awk.
$ join -o 0,1.2,2.2 -a 1 -a 2 -e '-' \
> <(sed 's/ */:/' Error00 | sort) \
> <(sed 's/ */:/' Error01 | sort) |
> sed 's/:/ /' |
> awk '{printf("%s %-6s %-6s %s\n", $1, $2, $3, $4)}'
4 0 375 465
4 2001 21 12
4 2002 20 40
4 2016 - 1
$
Related
For my file which looks like this:
AABBCC 10 5 CCAABB 100
BBCCAA 4 2 AABBCC 50
CCAABB 16 8 BBCCAA 20
... I am trying to sort columns 4 and 5, by matching column 4 to column 1.
Ideally this would return:
AABBCC 10 5 AABBCC 50
BBCCAA 4 2 BBCCAA 20
CCAABB 16 8 CCAABB 100
I have tried using sort, however as far as I'm aware it doesn't have a utility to sort within files.
Any help would be greatly appreciated!
awk solution:
awk 'NR==FNR{ a[$4]=$5; next }$1 in a{ print $1,$2,$3,$1,a[$1] }' file1 OFS="\t" file1
The output:
AABBCC 10 5 AABBCC 50
BBCCAA 4 2 BBCCAA 20
CCAABB 16 8 CCAABB 100
You may pipe to sort at the end: ... | sort
join -t $'\t' -o 1.1,1.2,1.3,2.1,2.2 <(cut -f1-3 file.tsv | sort -k 1,1) <(cut -f4- file.tsv | sort -k 1,1) | sort
Cut the original file, then join on the first field of both. We need to specify the full join fields in -o to preserve the first column, or join will eat it.
With bash and GNU paste:
With temporary files for illustration:
cut -f 1-3 file | sort > file_1to3
cut -f 4-5 file | sort > file_4to5
paste -d '\t' file_1to3 file_4to5
Without temporary files:
paste -d '\t' <(cut -f 1-3 file | sort) <(cut -f 4-5 file | sort)
Output:
AABBCC 10 5 AABBCC 50
BBCCAA 4 2 BBCCAA 20
CCAABB 16 8 CCAABB 100
Im stuck on some homework. The requirements of the assignment are to accept an input file and perform some statistics on the values. The user may specify whether to calculate the statistics by row or by value. The shell script must be pure bash script so I can't use awk, sed, perl, python etc.
sample input:
1 1 1 1 1 1 1
39 43 4 3225 5 2 2
6 57 8 9 7 3 4
3 36 8 9 14 4 3
3 4 2 1 4 5 5
6 4 4814 7 7 6 6
I can't figure out how to sort and process the data by column. My code for processing the rows works fine.
# CODE FOR ROWS
while read -r line
echo $(printf "%d\n" $line | sort -n) | tr ' ' \\t > sorted.txt
....
#I perform the stats calculations
# for row line by working with the temp file sorted.txt
done
How could I process this data by column? I've never worked with shell script so I've been staring at this for hours.
If you wanted to analyze by columns you'll need the cols value first (number of columns). head -n 1 gives you the first row, and NF counts the number of fields, giving us the number of columns.
cols=$(head -n 1 test.txt | awk '{print NF}');
Then you can use cut with the '\t' delimiter to grab every column from input.txt, and run it through sort -n, as you did in your original post.
$ for i in `seq 2 $((cols+1))`; do cut -f$i -d$'\t' input.txt; done | sort -n > output.txt
For rows, you can use the shell built-in printf with the format modifier %dfor integers. The sort command works on lines of input, so we replace spaces ' ' with newlines \n using the tr command:
$ cat input.txt | while read line; do echo $(printf "%d\n" $line); done | tr ' ' '\n' | sort -n > output.txt
Now take the output file to gather our statistics:
Min: cat output.txt | head -n 1
Max: cat output.txt | tail -n 1
Sum: (courtesy of Dimitre Radoulov): cat output.txt | paste -sd+ - | bc
Mean: (courtesy of porges): cat output.txt | awk '{ $total += $2 } END { print $total/NR }'
Median: (courtesy of maxschlepzig): cat output.txt | awk ' { a[i++]=$1; } END { print a[int(i/2)]; }'
Histogram: cat output.txt | uniq -c
8 1
3 2
4 3
6 4
3 5
4 6
3 7
2 8
2 9
1 14
1 36
1 39
1 43
1 57
1 3225
1 4814
I have the following test file:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
I want to separate it in a way that each file contains the last line of the previous file as the first line. The example would be:
file 1:
1
2
3
4
5
file2:
5
6
7
8
9
file3:
9
10
11
12
13
file4:
13
14
15
16
17
file5:
17
18
19
20
That would make 4 files with 5 lines and 1 file with 4 lines.
As a first step, I tried to test the following commands I wrote to get only the first file which contains the first 5 lines. I can't figure out why the awk command in the if statement, instead of printing the first 5 lines, it prints the whole 20?
d=$(wc test)
a=$(echo $d | cut -f1 -d " ")
lines=$(echo $a/5 | bc -l)
integer=$(echo $lines | cut -f1 -d ".")
for i in $(seq 1 $integer); do
start=$(echo $i*5 | bc -l)
var=$((var+=1))
echo start $start
echo $var
if [[ $var = 1 ]]; then
awk 'NR<=$start' test
fi
done
Thanks!
Why not just use the split util available from your POSIX toolkit. It has an option to split on number of lines which you can give it as 5
split -l 5 input-file
From the man split page,
-l, --lines=NUMBER
put NUMBER lines/records per output file
Note that, -l is POSIX compliant also.
$ ls
$
$ seq 20 | awk 'NR%4==1{ if (out) { print > out; close(out) } out="file"++c } {print > out}'
$
$ ls
file1 file2 file3 file4 file5
.
$ cat file1
1
2
3
4
5
$ cat file2
5
6
7
8
9
$ cat file3
9
10
11
12
13
$ cat file4
13
14
15
16
17
$ cat file5
17
18
19
20
If you're ever tempted to use a shell loop to manipulate text again, make sure to read https://unix.stackexchange.com/questions/169716/why-is-using-a-shell-loop-to-process-text-considered-bad-practice first to understand at least some of the reasons to use awk instead. To learn awk, get the book Effective Awk Programming, 4th Edition, by Arnold Robbins.
oh. and wrt why your awk command awk 'NR<=$start' test didn't work - awk is not shell, it has no more access to shell variables (or vice-versa) than a C program does. To init an awk variable named awkstart with the value of a shell variable named start and then use that awk variable in your script you'd do awk -v awkstart="$start" 'NR<=awkstart' test. The awk variable can also be named start or anything else sensible - it is completely unrelated to the name of the shell variable.
You could improve your code by removing the unneccesary echo cut and bc and do it like this
#!/bin/bash
for i in $(seq $(wc -l < test) ); do
(( i % 4 != 1 )) && continue
tail +$i test | head -5 > "file$(( 1+i/4 ))"
done
But still the awk solution is much better. Reading the file only once and taking actions based on readily available information (like the linenumber) is the way to go. In shell you have to count the lines, there is no way around it. awk will give you that (and a lot of other things) for free.
Use split:
$ seq 20 | split -l 5
$ for fn in x*; do echo "$fn"; cat "$fn"; done
xaa
1
2
3
4
5
xab
6
7
8
9
10
xac
11
12
13
14
15
xad
16
17
18
19
20
Or, if you have a file:
$ split -l test_file
How can I merge three text files into three columns on screen?
1 A 1
2 B 2
3 C 3
D
E
I tried...
paste file1.txt file2.txt file3.txt | column -s $'\t' -t
...but I always get
1 A 1
2 B 2
3 C 3
D
E
Thanks in advance for your help!
line 1-2 of file1.txt
USB Device Class ID:
CdRom&Ven_ZALMAN&Prod__Virtual_CD-Rom&Rev_
line 1-2 of file2.txt
USB Instance ID:
______XX00000001&1
line 1-2 of file3.txt
Last updated (Subkey):
2015-01-12 15:08:45 UTC+0000
I don't know your input files, but paste works as intended.
$ paste <(seq 1 4) <(seq 10 17) <(seq 5 9)
1 10 5
2 11 6
3 12 7
4 13 8
14 9
15
16
17
:|paste -d ' ' file1 - file2 - file3 | column -ts "| " combine many files as a table column -t and -s as a separator "| " .
the output will be like that
1 A 1
2 B 2
3 C 3
D
E
If you only have 3 files or a few to deal with you can do this:
$ paste foo[12].txt | expand -t 45 | paste - foo3.txt | expand -t 12
USB Device Class ID: USB Instance ID: Last updated (Subkey):
CdRom&Ven_ZALMAN&Prod__Virtual_CD-Rom&Rev_ ______XX00000001&1 2015-01-12 15:08:45 UTC+0000
______XY0000000182
$
You need to choose the tab expansions 45 and 12 depending upon maximum line widths in foo1.txt and foo2.txt.
I have file like this
1814 1
2076 2
2076 1
3958 1
2076 2
2498 3
2858 2
2858 1
1818 2
1814 1
2423 1
3588 12
2026 2
2076 1
1814 1
3576 1
2005 2
1814 1
2107 1
2810 1
I would like to generate report like this
1814 3
2076 6
3958 1
2858 3
Basically calculate the total for each unique value in column 1
Using awk:
awk '{s[$1] += $2} END{ for (x in s) print x, s[x] }' input
Pure Bash:
declare -a sum
while read key val ; do
((sum[key]+=val))
done < "$infile"
for key in ${!sum[#]}; do
printf "%4d %4d\n" $key ${sum[$key]}
done
The output is sorted:
1814 4
1818 2
2005 2
2026 2
2076 6
2107 1
2423 1
2498 3
2810 1
2858 3
3576 1
3588 12
3958 1
Perl solution:
perl -lane '$s{$F[0]} += $F[1] }{ print "$_ $s{$_}" for keys %s' INPUT
Note that the output is different from the one you gave.
sum totals for each primary key (integers only)
for key in $(cut -d\ -f1 test.txt | sort -u)
do
echo $key $(echo $(grep $key test.txt | cut -d\ -f2 | tr \\n +)0 | bc)
done
simply sum a column of integers
echo $(cut -d\ -f2 test.txt | tr \\n +)0 | bc