Counting the number of files in a directory in bash - bash

Question

I have a bash script where I'm trying to find out the number of files in a directory and perform an addition operation on it as well.
But while doing the same I'm getting the error as follows:
admin> ./fileCount.sh
1
./fileCount.sh: line 6: 22 + : syntax error: operand expected (error token is " ")
My script is as shown:
#!/usr/bin/bash
Var1=22
Var2= ls /stud_data/Input_Data/test3 | grep ".txt" | wc -l
Var3= $(($Var1 + $Var2))
echo $Var3
Can anyone point out where is the error.

Answer 1

A little away
As #devnull already answered to the question point out where is the error,
Just some more ideas:
General unix
To make this kind of browsing, there is a very powerfull command find that let you find recursively, exactly what you're serching for:
Var2=`find /stud_data/Input_Data/test3 -name '*.txt' | wc -l`
If you won't this to be recursive:
Var2=`find /stud_data/Input_Data/test3 -maxdepth 1 -name '*.txt' | wc -l`
If you want files only (meaning no symlink, nor directories)
Var2=`find /stud_data/Input_Data/test3 -maxdepth 1 -type f -name '*.txt' | wc -l`
And so on... Please read the man page: man find.
Particular bash solutions
As your question stand for bash, there is some bashism you could use to make this a lot quicker:
#!/bin/bash
Var1=22
VarLs=(/stud_data/Input_Data/test3/*.txt)
[ -e $VarLs ] && Var2=${#VarLs[#]} || Var2=0
Var3=$(( Var1 + Var2 ))
echo $Var3
# Uncomment next line to see more about current environment
# set | grep ^Var
Where bash expansion will translate /path/*.txt in an array containing all filenames matching the jocker form.
If there is no file matching the form, VarLs will only contain the jocker form himself.
So the test -e will correct this: If the first file of the returned list exist, then assing the number of elements in the list (${#VarLs[#]}) to Var2 else, assign 0 to Var2.

Answer 2

Can anyone point out where is the error.
You shouldn't have spaces around =.
You probably wanted to use command substitution to capture the result in Var2.
Try:
Var1=22
Var2=$(ls /stud_data/Input_Data/test3 | grep ".txt" | wc -l)
Var3=$(($Var1 + $Var2))
echo $Var3
Moreover, you could also say
Var3=$((Var1 + Var2))