I need to write something that will read and execute all the files(Mainly executable scripts) inside one or more folders; in other words, a continuous chain with a break when finished. I'm new to shell and need syntax help. I'm on Ubuntu 12.10-Gnome btw.
Here are some main highlights I think should be included;
-The program should ask for one or more directories. Should process all the files given in these directories,
-Should create a .txt file on which files and folders are read and executed(for correction and informational purposes),
-Could contain a break option like control+shift+c maybe but thats clearly not of utmost importance.
The code, or the guidance to the code would be very much appreciated. Thx alot.
Related
I got a folder with a lot of images in it, and I'd like to move everything to the main folder so basically I would like to turn this:
L:\Pixiv\Tags\44324\Image1.jpg
L:\Pixiv\Tags\4564356\Image2.jpg
L:\Pixiv\Tags\325423\Image3.jpg
L:\Pixiv\Tags\16324\Image4.jpg
...into this
L:\Pixiv\Tags\Image1.jpg
L:\Pixiv\Tags\Image2.jpg
L:\Pixiv\Tags\Image3.jpg
L:\Pixiv\Tags\Image4.jpg
I did some looking, and I discovered a move function for CMD, and while most of it I can understand, some of it I can't, and frankly, I'm just that smart enough to know what happens when you start playing around with stuff you don't fully understand, so I don't do it. Point is your basic move function is basically something like "move c:\Whatever C:\Whocares," but as you can tell from below, this is a little more complicated.
for /r %d in (*) do move "%d" "d:\all snaps\"
/r I think goes through all the folders at the current target directory. So if I'm in L:\Pixiv\Artists and I type in this code for L:\Pixiv\Artists as a destination folder every file in Artists is going to be dumped into Tags. Is this correct?
%d I couldn't make sense out of, so I've no idea what it does. Also, for ease of use, I would like to put this in a batch script, because boy howdy, do I got a lot of folders that needs to be fixed. From what little I was able to read I should write the same as above, but change %d to %dd, correct? Also where at would I add a target directory, so I could just write a batch script, and be done with it? Also, apologies in advance for my lack of knowledge, usually I use Batchrun when it comes to automating stuff.
I am wondering if it is possible to accomplish the following, given some context and example.
I have files in "Server\Share\Folder\File##.ext"
Sometimes the "File##.ext" can be "File01.ext" through "File20.ext", and other times it may be "File01.ext" through "File40.ext"
Sometimes there are less of these files, sometimes there are more.
I want a batch file to take the files from "Server\Share\Folder\File##.ext" and move them to "Server\Share\OtherFolder\File##.ext". I know I can accomplish this easily with:
copy /y "Server\Share\Folder\File01.ext" "Server\Share\OtherFolder\File01.ext"
Then just add another line for each extra "File02.ext, File03.ext, etc., but I am wondering if it is possible to make it so that any file that resembles "File##.ext" can be included, so that no matter how many ## I have, it always works without issue.
Thanks in advance for any and all advice!
EDIT
Someone mentioned using Wildcards, but my question with that is - lets say those files are File01.ext through File05.ext, will it match what it finds to the newly moved file? Like will it find File01 from File?? on the source and Make it File01 from File?? at the destination?
You can accomplish this task with a FORloop program in batch-file.
You can also loop through the Commands using : and variable name.
Combining these two would help you get what you want.
We can help you with Ideas and little bit of the coding. But the Efforts must be done by you. So U can learn programming better
I am a novice Go lang programmer,trying to learn Go lang features.I wanted to split a large csv file into multiple files in GO lang, each file containing the header.How do i do this? I have searched everywhere but couldnt get the right solution.Any help in this regard will be greatly appreciated.
Also please suggest me a good book for reference.
Thanking You
Depending on your shell fu this problem might be better suited for common shell utilities but you specifically mentioned go.
Let's think through the problem.
How big is this csv file? Are we talking 100 lines or is it 5G ?
If it's smallish I typically use this:
http://golang.org/pkg/io/ioutil/#ReadFile
However, this package also exists:
http://golang.org/pkg/encoding/csv/
Regardless - let's return to the abstraction of the problem. You have a header (which is the first line) and then the rest of the document.
So what we probably want to do (if ignoring csv for the moment) is to read in our file.
Then we want to split the file body by all the newlines in it.
You can use this to do so:
http://golang.org/pkg/strings/#Split
You didn't mention but do you know how many files you want to split by or would you rather split by the line count or byte count? What's the actual limitation here?
Generally it's not going to be file count but if we pretend it is we simply want to divide our line count by our expected file count to give lines/file.
Now we can take slices of the appropriate size and write the file back out via:
http://golang.org/pkg/io/ioutil/#WriteFile
A trick I use sometime to help think me threw these things is to write down our mission statement.
"I want to split a large csv file into multiple files in go"
Then I start breaking that up into pieces but take the divide/conquer approach - don't try to solve the entire problem in one go - just break it up to where you can think about it.
Also - make gratiutious use of pseudo-code until you can comfortably write the real code itself. Sometimes it helps to just write a short comment inline with how you think the code should flow and then get it down to the smallest portion that you can code and work from there.
By the way - many of the golang.org packages have example links where you can literally run in your browser the example code and cut/paste that to your own local environment.
Also, I know I'll catch some haters with this - but as for books - imo - you are going to learn a lot faster just by trying to get things working rather than reading. Action trumps passivity always. Don't be afraid to fail.
Here is a package that might help. You can set a necessary chunk size in bytes and a file will be split on an appropriate amount of chunks.
So, is there a possible way to move Test.txt to C:\ProgramData\CsD2\Tools\("Unknown Folder Name")\data\per Using command prompt?
using foxidrives solution for your previous question for detecting the correct directory, then just
move test.txt "%folder%\"
Short answer: yes. Not quite sure what the situation is that has left only the middle part of your path unknown, and the need to use the comnand line, but I have encountered similar cases on Linux and expect the algoirthm can be adapted to Windows commands. It's possible to do this by hand rather than writing a shell script, but it's up to you and your skills.
Permissions matter. Make sure you elevate yours enough to read and write in Tools before continuing.
First, change directory to C:\ProgramData\CsD2\Tools\
Presumably there are many items here. Some may be "hidden," so list the contents of this directory and be sure to include an option to show hidden files and folders. If you can, restrict the search to directories only.
It's tempting to display contents recursively in the above step. It's up to you, but I find it makes the output cluttered without a script to do the rest of the work.
Now it's time to search for the subfolder set that theoretically only exists in your target folder. Suppose Tools contains the directories fldr1, fldr2, and fldr3. Use your command to list a directory's contents with the path "fldr1\data\per", then use "fldr2\data\per", and so on until it doesn't return an error. Per may be empty, but that should look different from the path not found error.
Now you've found the name of your mystery folder. Write it down for future reference.
At thus point, you know the path to Test.txt, and the full path to the destination directory. Do a move command to relocate Test.txt, and you're done. I like to relist the contents of the target directory after to be comfortable that it arrived.
It looks like all EXE files begin with MZ when they are opened in ASCII mode, is there an ASCII identified for vbs, com and bat files as well? i can't seem to find a pattern...
Or maybe there's another way to identify them? aside from just the extension...
No, not really (Windows executables can have PE or PK at the beginning instead of MZ - see this for other possible formats).
For other types of files, there are certain heuristics you can use (e.g. GIF files start with "GIF89", Bash shell scripts usually start with #!/bin/bash, BAT files often execute #echo off at the beginning, VBS scripts use apostrophe at the start of line as a comment marker), but they aren't always 100% reliable (a file can be both a BAT script and a Bash shell script; or a file that's both a valid ZIP archive and a valid GIF image (like that stegosaurus image), for example).
See e.g. this article for further reading.
TrID seems to have a "standalone" application you could probably use and pass the file in and read the contents out and see what file it is. It prides itself on the ability to pass it a generic file (extension or without) and it uses the headers of the file to discover what file type it actually is.
See if this tutorial is helpful (How to detect the types of executable files 3 part series). He has even presented a step by step algorithm on how to do this.
Also see this post: How to determine if a file is executable?