FOR statement to parse datetime stamp in file names [closed] - windows

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How will I accomplish the following in a FOR statement?
I have files in a windows PC directory that I want to identify by all or part of a datetime stamp that is part of the files name, ie-
CLIENT CODE / ID DATETIME STAMP
0000090000010009.CLIENTNAME.20121212140022.txt
0001090000010009.CLIENTNAME.20130916110025.txt
0001090000010009.CLIENTNAME.20130908150022.txt
I do not have to open/read the file. I just need to identify files in a particular date time range to either MOVE, DELETE or COPY them.

for /f "tokens=1-4delims=." %%a in ('dir /b /a-d "*.clientname.*.*"') do (
set "dts=%%c"
setlocal enabledelayedexpansion
set "yyyy=!dts:~0,4!"
set "mm=!dts:~4,2!"
set "dd=!dts:~6,2!"
set "hh=!dts:~8,2!"
set "min=!dts:~10,2!"
set "sec=!dts:~12,2!"
echo File: %%a.%%b.%%c.%%d date/time: !dd!/!mm!/!yyyy! -- !hh!:!min!:!sec!
endlocal
)

You can use the dir command with wildcard. So say you want the file 0000090000010009.CLIENTNAME.20121212140022.txt you can do:
dir *20121212140022*
If you want to put it in a loop then for /F will do the trick:
for /F %x in ('dir *20121212140022* /b /a-d ') do del %x

Related

Script to list extensions [closed]

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I want to write a windows batch script that lists all extensions in a directory, recursively.
The desired behaviour is this:
You start the bat file in directory "a" which contains the following files: b.txt, c.png, d.txt, e.jpeg, f.jpg.
The script should output the following:
txt
png
jpeg
jpg
I would like the each extension to be in a new line, alphabetic ordering is not necessary.
The method you linked to is probably overkill for what you want.
Do a for /r loop to get all files recursively and set a variable named the same as the extension (the value isn't important, we need only the variable to be defined)
Then do a for /f loop to list the variables (with set . - all of them start with a dot conveniently because the %%~x modifier gets the extension with the dot (.txt)). Then just sort them alphabetically, if needed:
#echo off & setlocal
for /r %%a in (*) do set "%%~xa=X" 2>nul
for /f "delims==" %%a in ('set .') do echo %%a
(edit: removed the sort, because set . already sorts alphabetically - thank you #LotPings for the hint)

Creating year,month,date folder structure based on filename [closed]

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I have some files in a some unix server. When i copy to windows, based on filename , the file has to be copied into corresponding year,corresponding month and corresponding date folders. Sample filename : 20120201.117_visual_sciences_web_feed.out.gz.
Folder structure to be created based on first part of filename, in this case : 20120201(YYYY,MM,DD) . In above example ,filename should be copied into 2012 -> 02-> 01 folder.Folders should be created if not created Honestly i am not getting how this can be implemented, please suggest.
This should do the trick for you -
#echo off
set filename=20120201.117_visual_sciences_web_feed.out.gz
set filepath=PATH\TO\%filename%
REM get the date from the file name
for /f "delims=." %%A in ("%filename%") do set fdate=%%A
REM Y=YEAR; M=MONTH; D=DAY
set Y=%fdate:~0,4%
set M=%fdate:~4,2%
set D=%fdate:~6,2%
REM echo %Y% %M% %D%
REM check to see if directories exist
if not exist \%Y% mkdir %Y%
if not exist \%Y%\%M% mkdir %Y%\%M%
if not exist \%Y%\%M%\%D% mkdir %Y%\%M%\%D%
REM copy the file to the newly created destination folder
copy %filepath% %Y%\%M%\%D%\%filename%
pause
I hope you're able to implement this into your script easily enough. As pointed out; if you added some examples from your script - I would be able to help more.

How do you find the last modified folder in a directory with command prompt? [closed]

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In the end, I want to copy the last modified folder in a directory. In order to do this, I need to pass in the name of the last modified folder to xcopy.
How do you find the last modified folder, not file, in a directory with command prompt? I have found many scripts that will find the last modified file, but I cannot seem to find a command that will find the last modified folder.
Any help would be appreciated.
#echo off
for /f "delims=" %%a in (' dir /ad /od /b ') do set "folder=%%a"

Findstr -- exclude a file type -- search only ascii [closed]

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I want to run a FINDSTR dos command in a way beyond what it is easily found in "findstr /?". How would I run findstr so that it only searches ascii files. (I am not sure if that is possible. My gut feeling is that it is not possible) Additionally, how would I run this command line so that it would exclude some file times. For example, what if I wanted to exclude .psd files
What is wrong with the /P option that is described in the help?
/P Skip files with non-printable characters.
It worked for me.
To take further control of which files are searched, simply iterate the files with a for loop and add whatever logic you need. To skip .psd files and also skip binary files:
for /f "eol=: delims=" %%F in ('dir /a-d /b^|findstr /live ".psd"') do findstr /p "search" "%%F"
Use a single percent instead of double percents if run from the command line.

Windows command prompt (Dos) copies all the files that start with the specified file name [closed]

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In Dos if you type
copy c:\a.txt
it will copy a.txt* (a.txt1, a.txtb, etc)
how can I just copy a.txt?
Your question is not correct - copy c:\a.txt will only copy the single file to the current directory. It will ignore the other files like a.txt1 and a.txtb.
You must have tried copy c:\*.txt - that will copy all forms because the pattern matching searches both long and short (8.3) names.
You can eliminate the problem by using FINDSTR:
for /f "eol=: delims=" %F in ('dir /b /a-d c:\*.txt^|findstr /eli ".txt"') do #copy "c:\%F"

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