Diagonal Output of Assembly program - windows

Question

I have this assembly program and I want diagonal output of this program but I dont know how to put tabspace in assembly.
section .text
global _start ;must be declared for using gcc
_start: ;tell linker entry point
mov edx, len ;message length
mov ecx, msg ;message to write
mov ebx, 1 ;file descriptor (stdout)
mov eax, 4 ;system call number (sys_write)
int 0x80 ;call kernel
mov eax, 1 ;system call number (sys_exit)
int 0x80 ;call kernel
section .data
msg db 'Y',10,'O',10,'U',10,'S',10,'U',10,'F' ;our dear string
len equ $ - msg ;length of our dear string
Output of my program is:
Y
O
U
S
U
F
Output should like this:
Y
O
U
S
U
F
Is there any other way to write this program and get this output?

Answer 1

is there an other way to do this
Of course there is! You can do it anyway that you want! Since you say you are using Windows, but are using Linux Interrupts, this code is OS Neutral (meaning it will work on Windows or Linux)
extern exit, printf, malloc, free
global main
section .data
szText db "Gunner Diagonally!!"
Text_Len equ $ - szText
fmtstr db "%s", 10, 0
section .text
main:
push Text_Len
push szText
call PrintDiagonal
call exit
;~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
;~ PrintDiagonal - Prints text to terminal diagonally
;~ In: esp + 4 = address of text to print
;~ esp + 8 = length of string to print
;~ Returns - Nothing
;~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PrintDiagonal:
%define Text_ dword [ebp + 8]
%define TextLen_ dword [ebp + 12]
%define _Buffer dword [ebp - 4]
%define _SpaceCount dword [ebp - 8]
%define _CurLine dword [ebp - 12]
push ebp
mov ebp, esp
sub esp, 4 * 3
mov eax, TextLen_
add eax, eax
push eax
call malloc
add esp, 4 * 1
mov _Buffer, eax
mov _SpaceCount, 1
mov _CurLine, 1
mov esi, Text_
.NextLine:
mov edi, _Buffer
mov edx, _SpaceCount
dec edx
jz .SpaceDone
.SpaceStart:
mov ecx, _SpaceCount
dec ecx
.FillSpaces:
mov byte [edi], 32
inc edi
dec ecx
jnz .FillSpaces
.SpaceDone:
mov al, byte [esi]
mov byte [edi], al
mov byte [edi + 1], 0
push _Buffer
push fmtstr
call printf
add esp, 4 * 2
inc esi
add _SpaceCount, 2
mov edx, TextLen_
inc _CurLine
cmp _CurLine, edx
jng .NextLine
push _Buffer
call free
add esp, 4 * 1
leave
ret 4 * 2
There is no error checking, of course you would add your own.
We take the string and add the correct spaces in a loop then print.

Answer 2

You could put in your msg
msg db 'Y',10,9,'O',10,9,9,'U',10,9,9,9,'S',10,9,9,9,9,'U',10,9,9,9,9,9,'F' ;our dear string
9 is ascii for tab.

Answer 3

Only Windows (because of DOS legacy) has separated CR (carriage return) that moves the carriage at X position 0, and LF (line feed) that moves one line down without changing the carriage X position.
In Linux LF only is used and it do both: moves the carriage down and left to 0.
In order to have the same diagonal output in Linux, you should cheat a little:
; replace dots with spaces.
msg db 'Y',10,'.O',10,'..U',10,'...S',10,'....U',10,'.....F'