I'm trying to open local xml file and output its content in terminal.
I've tried this;
puts File.new('file.xml', 'r')
and this;
puts File.open('file.xml', 'r')
output from both is, instead of printing xml file to the screen;
#<File:0x00000000....>
Try this
puts File.read('file.xml')
or
puts File.open('file.xml').read
Documentation: IO.read, IO#read
I would suggest you to use block with File#open method. As with block,you don't need to close the file explicitly.Perform all your task inside the block with the file. The file will be closed automatically,when block will be terminated.
File.open('doc.txt','r') do |file|
puts file.read
end
# >> ,"11: Agriculture, Forestry, Fishing and Hunting",,
# >> ,,"111: Crop Production",
# >> ,,,"111110: Soybean Farming"
# >> ,,,"111120: Oilseed (except Soybean) Farming"
Related
Let's say you have the following code:
from_file, to_file = ARGV
puts "Copying from #{from_file} to #{to_file}"
#in_file = open(from_file)
#indata = in_file.read
indata = open(from_file).read # Combined in_file and indata.
puts "The input file is #{indata.length} bytes long."
puts "Does the output file exist? #{File.exist?(to_file)}"
puts "Ready, hit RETURN to continue or CTRL-C to abort."
$stdin.gets
out_file = open(to_file, 'w')
out_file.write(indata)
puts "Alright, all done."
out_file.close
#in_file.close
How would you close the file descriptor invoked by indata? You will need to close File open, but indata is really a (File open).read.
P.S. Since it's a script, it will be closed automatically upon exit. Let's assume that we're running a general, consistently running backend service. And we don't know whether garbage collector will kick in, so we will need to explicitly close it. What would you do?
If you are just copying the file...
you could just use FileUtils#cp:
FileUtils.cp("from_file", "to_file")
or even shell-out to the operating system and do it with a system command.
Let's suppose you want to do something to the input file before writing it to the output file.
If from_file is not large,...
you could "gulp it" into a string using IO.read:
str = IO.read(from_file)
manipulate str as desired, to obtain new_str, then then blast it to the output file using IO#write:
IO.write("to_file", new_str)
Note that for the class File:
File < IO #=> true # File inherits IO's methods
which is why you often see this written File.read(...) and File.write(...).
If from_file is large, read a line, write a line...
provided the changes to be made are done for each line separately.
f = File.open("to_file", "w") # or File.new("to_file", "w")
IO.foreach("from_file") do |line|
# < modify line to produce new_line >
f.puts new_line
end
f.close
foreach closes "from_file" when it's finished. If f.close is not present, Ruby will close "to_file" when the method containing the code goes out of scope. Still, it's a good idea to close it in case other work is done before the code goes out of scope.
Passing File.open a block is generally a nice way to go about things, so I’ll offer it up as an alternative even if it doesn’t seem to be quite what you asked.
indata = File.open(from_file) do |f|
f.read
end
I am trying to log some state to a file using standard file i/o in ruby. The file will just have one line with a number in it. I want to read in the line and then on each iteration of a loop I want to update this number.
I know I can read in the file with
file = File.open('out.log', 'a+')
num = file.readline
The problem is, I don't know how to then overwrite the first line in a loop without just re-opening the file every iteration i.e.
file = File.open('out.log', 'w')
which will create an empty file
No need to open it each time:
file = File.open('out.log', File::RDWR)
10.times do |i|
file.seek(0) # rewind to the beginning of the file (line in your case)
file.write("iteration #{i}") # write what you want
# the following is just in order to show what was written
file.seek(0)
puts file.readline
end
file.close
You can use IO::open with block to close the file, when block exits automatically.
File.open("#{__dir__}/test.txt", File::RDWR) do |file|
10.times do |i|
file.rewind
file.puts("iteration #{i}")
end
end
puts File.read("#{__dir__}/test.txt")
# >> iteration 9
When I start printing lines from a file, I get this error
#<File:0x007ff65ee297b0>
Here is the code
require 'rubygems'
File.open("sample.txt", 'r') do |f|
puts f
end
You are printing the file object. To get the contents line by line, you can use File.foreach
File.foreach('sample.txt', 'r') do |line|
puts line # called for every line
end
To process the whole file at once, you can use the read method on the file object:
File.open('sample.txt', 'r') do |file|
puts file.read # called only once
end
This is not an error. It prints correctly one line which is your File object.
Here your create a file object and you did not ask it to fetch lines or anything else for that matter.
Several good answers already. But here is another way to do it with minimal change to your code:
File.open("sample.txt", 'r').each_line do |f|
puts f
end
Another way :
IO.foreach("sample.txt") {|line| line }
Or
File.foreach('sample.txt') {|line| line }
File::open returns file handle (which apparently is being printed out as #<File:0x007ff65ee297b0>.) If you need the file content line by line you might want to use IO::readlines:
IO.readlines("sample.txt").each do |line|
puts line
end
I am trying to create a Tempfile and write some text into it. But I get this strange behavior in console
t = Tempfile.new("test_temp") # => #<File:/tmp/test_temp20130805-28300-1u5g9dv-0>
t << "Test data" # => #<File:/tmp/test_temp20130805-28300-1u5g9dv-0>
t.write("test data") # => 9
IO.read t.path # => ""
I also tried cat /tmp/test_temp20130805-28300-1u5g9dv-0 but the file is empty.
Am I missing anything? Or what's the proper way to write to Tempfile?
FYI I'm using ruby 1.8.7
You're going to want to close the temp file after writing to it. Just add a t.close to the end. I bet the file has buffered output.
Try this
run t.rewind before read
require 'tempfile'
t = Tempfile.new("test_temp")
t << "Test data"
t.write("test data") # => 9
IO.read t.path # => ""
t.rewind
IO.read t.path # => "Test datatest data"
close or rewind will actually write out content to file. And you may want to delete it after using:
file = Tempfile.new('test_temp')
begin
file.write <<~FILE
Test data
test data
FILE
file.close
puts IO.read(file.path) #=> Test data\ntestdata\n
ensure
file.delete
end
It's worth mentioning, calling .rewind is a must otherwise any subsequent .read call will just return empty value
I want to copy the contents of one file to another using Ruby's file methods.
How can I do it using a simple Ruby program using file methods?
There is a very handy method for this - the IO#copy_stream method - see the output of ri copy_stream
Example usage:
File.open('src.txt') do |f|
f.puts 'Some text'
end
IO.copy_stream('src.txt', 'dest.txt')
For those that are interested, here's a variation of the IO#copy_stream, File#open + block answer(s) (written against ruby 2.2.x, 3 years too late).
copy = Tempfile.new
File.open(file, 'rb') do |input_stream|
File.open(copy, 'wb') do |output_stream|
IO.copy_stream(input_stream, output_stream)
end
end
As a precaution I would recommend using buffer unless you can guarantee whole file always fits into memory:
File.open("source", "rb") do |input|
File.open("target", "wb") do |output|
while buff = input.read(4096)
output.write(buff)
end
end
end
Here my implementation
class File
def self.copy(source, target)
File.open(source, 'rb') do |infile|
File.open(target, 'wb') do |outfile2|
while buffer = infile.read(4096)
outfile2 << buffer
end
end
end
end
end
Usage:
File.copy sourcepath, targetpath
Here is a simple way of doing that using ruby file operation methods :
source_file, destination_file = ARGV
script = $0
input = File.open(source_file)
data_to_copy = input.read() # gather the data using read() method
puts "The source file is #{data_to_copy.length} bytes long"
output = File.open(destination_file, 'w')
output.write(data_to_copy) # write up the data using write() method
puts "File has been copied"
output.close()
input.close()
You can also use File.exists? to check if the file exists or not. This would return a boolean true if it does!!
Here's a fast and concise way to do it.
# Open first file, read it, store it, then close it
input = File.open(ARGV[0]) {|f| f.read() }
# Open second file, write to it, then close it
output = File.open(ARGV[1], 'w') {|f| f.write(input) }
An example for running this would be.
$ ruby this_script.rb from_file.txt to_file.txt
This runs this_script.rb and takes in two arguments through the command-line. The first one in our case is from_file.txt (text being copied from) and the second argument second_file.txt (text being copied to).
You can also use File.binread and File.binwrite if you wish to hold onto the file contents for a bit. (Other answers use an instant copy_stream instead.)
If the contents are other than plain text files, such as images, using basic File.read and File.write won't work.
temp_image = Tempfile.new('image.jpg')
actual_img = IO.binread('image.jpg')
IO.binwrite(temp_image, actual_img)
Source: binread,
binwrite.