how to find input ("hello world") individually in xy.txt - windows

Question

I'm trying to make a batch file which checks if the user input does exist in xy.txt well thats easy
but now if the user input is "hello world" i want to check each word individually.
i tried that..
#setlocal enableextensions enabledelayedexpansion
#echo off
:start
set /p word=" "
for /F "tokens=* delims= " %%A in ("%word%") do set A=%%A & set B=%%B
if %A%=="" goto Anovalue
if not %A%=="" goto checkforA
:Anovalue
echo first word has no value
pause
if %B%=="" goto Bnovalue
if not %A%=="" goto checkforB
:Bnovalue
echo second word has no value
pause
goto start
:checkforA
findstr /c:"%A%" xy.txt > NUL
if ERRORLEVEL 1 goto notexistA
if ERRORLEVEL 2 goto existA
:checkforB
findstr /c:"%B%" xy.txt > NUL
if ERRORLEVEL 1 goto notexistB
if ERRORLEVEL 2 goto existB
:existA
echo first word does exist in xy.txt
pause
goto checkforB
:existB
echo second word does exist in xy.txt
pause
goto start
:notexistA
echo first word does not exist in xy.txt
pause
(echo %A%) >>xy.txt
goto checkforB
:notexistB
echo second word does not exist in xy.txt
pause
(echo %B%) >>xy.txt
goto start\
Couldn't I do that in a more easier and smarter way?

Answer 1

There are a lot of ways to do what you are asking to do, many of which use a lot less code. For instance, given the following file xy.txt:
this is a test of the
system to see if it
will work the way
that i want it to
work today
This batchfile (check.bat):
#echo off
setlocal ENABLEDELAYEDEXPANSION
set words=%1
set words=!words:"=!
for %%i in (!words!) do findstr /I /C:"%%i" xy.txt > NUL && echo Found - %%i || echo Not Found - %%i
endlocal
Well return the following:
c:\>check "is test smart"
Found - is
Found - test
Not Found - smart
However, words within a word will also return true. For instance, check "day" will find day, even though it is not a separate word because it is part of today. Handling that situation would be a little more tricky. To do that, you need to encapsulate the search words with some character, and then replace all the spaces in xy.txt with the same encapsulation character. For instance, if we use a ., replace all spaces in xy.txt whwith the ., and then search for .word., we will find only whole words that match.
#echo off
setlocal ENABLEDELAYEDEXPANSION
set words=%1
set words=!words:"=!
set words=.!words: =. .!.
for /f "tokens=* delims=" %%i in (xy.txt) do (
set line=%%i
set line=.!line: =.!.
echo !line!>>xy.txt.tmp
)
for %%i in (!words!) do (
set word=%%i
set word=!word:.=!
findstr /I /C:"%%i" xy.txt.tmp > NUL && echo Found - !word! || echo Not Found - !word!
)
del xy.txt.tmp
endlocal
I chose to create an intermediary file xy.txt.tmp to house the edited file where the spaces are replaced with .. Then we can execute the following command and get the displayed results:
c:\>check "this is a test of the stem today that will work each day"
Found - this
Found - is
Found - a
Found - test
Found - of
Found - the
Not Found - stem
Found - today
Found - that
Found - will
Found - work
Not Found - each
Not Found - day
It correctly finds words at the beginning of the line, end of the line and anywhere in between. The only downside is the intermediate file that it creates and then deletes. Doing it without an intermediate file would be a bit more complex...