i have written this in my view page,
<a onclick="window.open('print_mine/id=<?php echo $value['id'];?>','800','400')">View</a>
it is giving me The URI you submitted has disallowed characters.
i need id in other page
i have written code in route.php as well as in controller
Look into your config/config.php and search for "disallowed" or "illegal". There you have some chars that are disallowed in CIs URIs.
Maybe you want to window.open('print_mine/<?=$value['id']?>','800','400')?
Your view:
<a onclick="window.open('print_mine/<?php echo $value['id'];?>','800','400')">View</a>
In controller:
function print_mine(){
$id = $this->uri->segment(3); #will fetch the third segment
}
Related
i have this url :
http://127.0.0.1:8000/deliverer/4
i want it like this
http://127.0.0.1:8000/deliverer/
this is my function :
public function show($id)
{
// $userhash->hashids->encode($id);
$user=User::find($id);
return view('deliverer.profile')->with('user',$user);
}
and this is my route
Route::get('deliverer/{id}', 'deliverer\DelivererController#show')->name('profile');
and this in view
<a href="http://127.0.0.1:8000/deliverer/{{ Auth::user()->id }}" >
<i class="nc-icon nc-single-02"></i>
<p>Profile</p>
</a>
Assuming, that what you're trying to accomplish is to view the current authenticated user's profile, then you should follow the steps below:
First you have to modify the route and remove the {id} from the URL, like this:
Route::get('deliverer', 'deliverer\DelivererController#show')->name('profile');
Then, inside the controller you have to remove the $id param from the show() method and change the method to get the id from the authenticated user.
public function show($id)
{
// $userhash->hashids->encode($id);
$user = \Auth::user();
return view('deliverer.profile')->with('user',$user);
}
And of course, you have to remove the Auth::user()->id() from the view route, and perhaps use the named route instead of hardcoding it, like so:
<a href="{{ route('profile') }}">
<i class="nc-icon nc-single-02"></i>
<p>Profile</p>
</a>
I'm assuming you're just trying to hide id's so users can guess the next number or try to pull up records they shouldn't.
Have you looked into UUID's? Example here: (https://dev.to/wilburpowery/easily-use-uuids-in-laravel-45be) That might be a solution.
Also, if you are worried that someone might tamper with URL to pull records, you should look into securing up your models. Do a check to see if the user should have access to that particular record. Many ways to accomplish that.
You can use token or configure a middleware, or as you did you can hash or crypt the id and make the verification after the call
The url will be like that :
http://127.0.0.1:8000/deliverer/?id=aze45a8sd54q
I got into this error:
404 Page Not Found
The page you requested was not found.
But I want to know where am I? So I can fix the URL.
If it possible how to print the actual URL out.
Update: What is the controller and function.
to debug such errors, you can do this
in application/config/routes.php at the end of the file add
$route[(:any+)] = 'process/processing/$1/$2/$3/$4';
create a file in application/controller/process.php
function processing($controller, $method, $param1, $param2){
echo "$controller <br> $method <br> $param2 <br> $param2";
}
Hope this helpyou
I have a problem when i try to add other parameter to URL.
before i use Codeigniter i add those parameters using JavaScript like this
test
but when i tried to do it with Codeigniter i don't know how.
<?php echo anchor("home/index/param1","test"); ?>
as i said i want to add this parameter for example my URL looks like this
home/index/param2
so when i click on test i want the URL to be like this
home/index/param2/param1
Take a look at CodeIgniter's URL Helper Documentation
The first parameter can contain any segments you wish appended to the URL. As with the site_url() function above, segments can be a string or an array.
For your example, you could try:
<?php
$base_url = 'home/index/';
$param1 = 'param1';
$param2 = 'param2';
$segments = array($base_url, $param1, $param2);
echo anchor($segments,"test");
?>
You can't do that with the form helper, you have to use your js function again :
echo anchor("home/index/param2", "test", array("onClick" => "javascript:addParam(window.location.href, 'display', 'param1');"));
It will produce :
test
But I don't see the point of dynamically change the href on the click event. Why don't you set it directly at the beginning ?
echo anchor("home/index/param2/param1", "test");
Ok i have records from database listed in view file, so u can see i wanna pass values to controler via href by update/grab function controler
echo $this->pagination->create_links();
br().br();
foreach ($query->result() as $q): ?>
<?php echo $q->info . br()?>
<?php endforeach; ?>
it works for first page in my pagination, when i am on some other page when i clicked on on record, instead passing parametars to controler when i clicked in keep adding url for example http://localhost/z/records/users/update/grab/3/update/grab/1/update/grab/1/update/grab/1/trtr
So error is when i have in url, when i am on second page in pagination
http://localhost/z/records/users/2
works only when i am on first page
http://localhost/z/records
is there a way to solve this proble. Will it works if i some how adjust routes??? Need help, please help me its very important
Try changing your link to an absolute URL:
<a href="/z/update/grab/<?php echo $q->id;?>/<?php echo $q->info; ?>">
Or adding a correct relative URL base to the header of your pages:
<base href="/z/" />
Codeigniter routes allow you to do this:
$route['post/(:any)/comment/(:any)'] = "posts/comments/$1/$2";
Then in the controller, the function inside my posts controller would work like this:
public function comments($one, $two) {
echo $one."-".$two;
}
so if you hit the url "/post/111/comment/222" the output would be
111-222
Tried URI::uri_string() but can't get it to work with the base_url.
URL: http://localhost/dropbox/derrek/shopredux/ahahaha/hihihi
Returns: dropbox/derrek/shopredux/ahahaha/hihihi
but http://localhost/dropbox/derrek/shopredux/ just returns an empty string.
I want the first call to return "ahahaha/hihihi" and the second to return "". Is there such a function?
// For current url
echo base_url(uri_string());
If url helper is loaded, use
current_url();
will be better
Try to use "uri" segments like:
$this->uri->segment(5); //To get 'ahahaha'
$this->uri->segment(6); //To get 'hihihi
form your first URL...You get '' from second URl also for segment(5),segment(6) also because they are empty.
Every segment function counts starts form localhost as '1' and symultaneous segments
For the parameter or without parameter URLs Use this :
Method 1:
$currentURL = current_url(); //for simple URL
$params = $_SERVER['QUERY_STRING']; //for parameters
$fullURL = $currentURL . '?' . $params; //full URL with parameter
Method 2:
$full_url = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on' ? "https" : "http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
Method 3:
base_url(uri_string());
I see that this post is old. But in version CI v3 here is the answer:
echo $this->uri->uri_string();
Thanks
//if you want to get parameter from url use:
parse_str($_SERVER['QUERY_STRING'], $_GET);
//then you can use:
if(isset($_GET["par"])){
echo $_GET["par"];
}
//if you want to get current page url use:
$current_url = current_url();
Running Latest Code Igniter 3.10
$this->load->helper('uri'); // or you can autoload it in config
print base_url($this->uri->uri_string());
I don't know if there is such a function, but with $this->uri->uri_to_assoc() you get an associative array from the $_GET parameters.
With this, and the controller you are in, you know how the URL looks like.
In you above URL this would mean you would be in the controller dropbox and the array would be something like this:
array("derrek" => "shopredux", "ahahaha" => "hihihi");
With this you should be able to make such a function on your own.
In CI v3, you can try:
function partial_uri($start = 0) {
return join('/',array_slice(get_instance()->uri->segment_array(), $start));
}
This will drop the number of URL segments specified by the $start argument. If your URL is http://localhost/dropbox/derrek/shopredux/ahahaha/hihihi, then:
partial_uri(3); # returns "ahahaha/hihihi"
you can use the some Codeigniter functions and some core functions and make combination to achieve your URL with query string.
I found solution of this problem.
base_url($this->uri->uri_string()).strrchr($_SERVER['REQUEST_URI'], "?");
and if you loaded URL helper so you can also do this current_url().strrchr($_SERVER['REQUEST_URI'], "?");
<?php $currentMenu = $this->uri->segment(2); ?>
<ul>
<li class="nav-item <?= ($currentMenu == 'dashboard') ? 'active' : '' ?>">
<a href="<?= site_url('/admin/dashboard'); ?>" class="nav-link"><i data-
feather="pie-chart"></i> Dashboard</a>
</li>
</ul
this is work for me