Which one will workload(usage) of the CPU-Core if there is a persistent cache-miss, will be 100%? - caching

That is, if the core processor most of the time waiting for data from RAM or cache-L3 with cache-miss, but the system is a real-time (real-time thread priority), and the thread is attached (affinity) to the core and works without switching thread/context, what kind of load(usage) CPU-Core should show on modern x86_64?
That is, CPU usage is displayed as decrease only when logged in Idle?
And if anyone knows, if the behavior is different in this case for other processors: ARM, Power[PC], Sparc?
Clarification: shows CPU-usage in standard Task manager in OS-Windows

A hardware thread (logical core) that's stalled on a cache miss can't be doing anything else, so it still counts as busy for the purposes of task-managers / CPU time accounting / OS process scheduler time-slices / stuff like that.
This is true across all architectures.
Without hyperthreading, "hardware thread" / "logical core" are the same as a "physical core".
Morphcore / other on-the-fly changing between hyperthreading and a more powerful single core could make there be a difference between a thread that keeps many execution units busy, vs. a thread that is blocked on cache misses a lot of the time.

I don't get the link between the OS CPU usage statistics and the optimal use of the pipeline. I think they are uncorrelated as the OS doesn't measure the pipeline load.
I'm writing this in the hope that Peter Cordes can help me understand it better and as a continuation of the comments.
User programs relinquish control to OS very often: when they need input from user or when
they are done with the signal/message. GUI program are basically just big loops and at
each iteration control is given to the OS until the next message.
When the OS has the control it schedules others threads/tasks and if not other actions
are needed just enter the idle process (long time ago a tight loop, now a sleep state)
until the next interrupt. This is the Idle Time.
Time spent on an ISR processing user input is considered idle time by any OS.
An a cache miss there would be still considered idle time.
A heavy program takes more time to complete the work for a given message thereby returning
control to OS say 2 times in a second instead of
20.
If the OS measures that in the last second, it got control for 20ms only then the
CPU usage is (1000-20)/1000 = 98%.
This has nothing to do with the optimal use of the CPU architecture, as said stalls can
occur in the OS code and still be part of the Idle time statistic.
The CPU utilization at pipeline level is not what is measured and it is orthogonal to the
OS statistics.
CPU usage is meant to be used by sysadmin, it is a measure of the load you put on a system,
it is not the measure of how efficiently the assembly of a program was generated.
Sysadmins can't help with that, but measuring how often the OS got the control back (without
preempting) is a measure of how much load a program is putting on the system.
And sysadmins can definitively do terminate heavy programs.

Related

Flame graph(perf record) cannot display accurate CPU idle usage

When the CPU usage is 60%, the flame graphs(perf record) is used to capture the CPU usage. Why is 40% idle-related stack usage not displayed in the flame graphs? The usage of the idle stack is often less than 5%.
For flame graphs, the point is normally to measure where a process spends CPU time while it's running, not which blocking functions it calls that make it sleep, or where it gets scheduled out and sleeps when it doesn't want to.
I capture performance for one cpu processor, not one process. According to the operating system design, if there is no active task on the CPU, the CPU calls an idle waiting function. For example, Linux often calls schedule_idle until it is interrupted by a new task. Therefore, it is expected that the schedule_idle can be found in flame gragh and it consumes 40% of the cpu usage.
Perf events like cycles don't increment when the clock is halted (e.g. cycles is cpu_clk_unhalted.thread_p or similar). If you really wanted to see time spend idle, you might be able to disable idle power saving to get Linux to just spin in a loop instead of using x86 monitor/mwait or even basic hlt to put the CPU into a C-state where the clock doesn't tick.
Or run your code pinned to one logical core, and on the other logical core, pin a task that runs the pause instruction in a loop. So the physical core's clock keeps ticking for the core you're counting events for.
You should still get counts for cpu_clk_unhalted.thread_any ([Core cycles when at least one thread on the physical core is not in halt state]) when recording that event on the logical core with your task, even when that logical core is asleep.
And you can also record counts for cpu_clk_unhalted.thread to count cycles when this (hardware) thread aka logical core isn't halted, to know how much CPU time you actually used. (Or use the software event task-clock for that.)
Use perf list to see events available on your CPU, and read their descriptions carefully.

Should CPU time always be identical between executions of same code?

My understanding of CPU time is that it should always be the same between every execution, on a same machine. It should require an identical amount of cpu cycles every time.
But I'm running some tests now, of executing a basic echo "Hello World", and it's giving me 0.003 to 0.005 seconds.
Is my understanding of CPU time wrong, or there's an issue in my measurement?
Your understanding is completely wrong. Real-world computers running modern OSes on modern CPUs are not simple, theoretical abstractions. There are all kinds of factors that can affect how much CPU time code requires to execute.
Consider memory bandwidth. On a typical modern machine, all the tasks running on the machine's cores are competing for access to the system memory. If the code is running at the same time code on another core is using lots of memory bandwidth, that may result in accesses to RAM taking more clock cycles.
Many other resources are shared as well, such as caches. Say the code is frequently interrupted to let other code run on the core. That will mean that the code will frequently find the cache cold and take lots of cache misses. That will also result in the code taking more clock cycles.
Let's talk about page faults as well. The code itself may be in memory or it may not be when the code starts running. Even if the code is in memory, you may or may not take soft page faults (to update the operating system's tracking of what memory is being actively used) depending on when that page last took a soft page fault or how long ago it was loaded into RAM.
And your basic hello world program is doing I/O to the terminal. The time that takes can depend on what else is interacting with the terminal at the time.
The biggest effects on modern systems include:
virtual memory lazily paging in code and data from disk if it's not hot in pagecache. (First run of a program tends to have a lot more startup overhead.)
CPU frequency isn't fixed. (idle / turbo speeds. grep MHz /proc/cpuinfo).
CPU caches can be hot or not
(for very short intervals) an interrupt randomly happening or not in your timed region.
So even if cycles were fixed (which they very much are not), you wouldn't see equal times.
Your assumption is not totally wrong, but it only applies to core clock cycles for individual loops, and only to cases that don't involve any memory access. (e.g. data already hot in L1d cache, code already hot in L1i cache inside a CPU core). And assuming no interrupt happens while the timed loop is running.
Running a whole program is a much larger scale of operation and will involve shared resources (and possible contention for them) like access to main memory. And as #David pointed out, a write system call to print a string on a terminal emulator - that communication with another process can be slow and involves waking up another process, if your program ends up waiting for it. Redirecting to /dev/null or a regular file would remove that, or just closing stdout like ./hello >&- would make your write system call return -EBADF (on Linux).
Modern CPUs are very complex beasts. You presumably have an Intel or AMD x86-64 CPU with out-of-order execution, and a dozen or so buffers for incoming / outgoing cache lines, allowing it to track about that many outstanding cache misses (memory-level parallelism). And 2 levels of private cache per core, and a shared L3 cache. Good luck predicting an exact number of clock cycles for anything but the most controlled conditions.
But yes, if you do control the condition, the same small loop will typically run at the same number of core clock cycles per iteration.
However, even that's not always the case. I've seen cases where the same loop seems to have have two stable states for how the CPU schedules instructions. Different entry condition quirks can lead to an ongoing speed difference over millions of loop iterations.
I've seen this occasionally when microbenchmarking stuff on modern Intel CPUs like Sandybridge and Skylake. It's usually not clear exactly what the two stable states are, and what exactly is causing the bottleneck, even with the help of performance counters and https://agner.org/optimize
In one case I remember, an interrupt tended to get the loop into the efficient mode of execution. #BeeOnRope was measuring slow cycles/iteration using or RDPMC for a short interval (or maybe RDTSC with core clock fixed = TSC reference clocks), while I was measuring it running faster by using a really large repeat count and just using perf stat on the whole program (which was a static executable with just that one loop written by hand in asm). And #Bee was able to repro my results by increasing the iteration count so an interrupt would happen inside the timed region, and returning from the interrupt tended to get the CPU out of that non-optimal uop-scheduling pattern, whatever it was.

Set CPU affinity for profiling

I am working on a calculation intensive C# project that implements several algorithms. The problem is that when I want to profile my application, the time it takes for a particular algorithm varies. For example sometimes running the algorithm 100 times takes about 1100 ms and another time running 100 times takes much more time like 2000 or even 3000 ms. It may vary even in the same run. So it is impossible to measure improvement when I optimize a piece of code. It's just unreliable.
Here is another run:
So basically I want to make sure one CPU is dedicated to my app. The PC has an old dual core Intel E5300 CPU running on Windows 7 32 bit. So I can't just set process affinity and forget about one core forever. It would make the computer very slow for daily tasks. I need other apps to use a specific core when I desire and the when I'm done profiling, the CPU affinities come back to normal. Having a bat file to do the task would be a fantastic solution.
My question is: Is it possible to have a bat file to set process affinity for every process on windows 7?
PS: The algorithm is correct and every time runs the same code path. I created some object pool so after first run, zero memory is allocated. I also profiled memory allocation with dottrace and it showed no allocation after first run. So I don't believe GC is triggered when the algorithm is working. Physical memory is available and system is not running low on RAM.
Result: The answer by Chris Becke does the job and sets process affinities exactly as intended. It resulted in more uniform results specially when background apps like visual studio and dottrace are running. Further investigation into the divergent execution time revealed that the root for the unpredictability is CPU overheat. The CPU overheat alarm was off while the temperature was over 100C! So after fixing the malfunctioning fan, the results became completely uniform.
You mean SetProcessAffinityMask?
I see this question, while tagged windows, is c#, so... I see the System.Diagnostics.Process object has a ThreadAffinity member that should perform the same function.
I am just not sure that this will stabilize the CPU times quite in the way you expect. A single busy task that is not doing IO should remain scheduled on the same core anyway unless another thread interrupts it, so I think your variable times are more due to other threads / processes interrupting your algorithm than the OS randomly shunting your thread to a different core - so unless you set the affinity for all other threads in the system to exclude your preferred core I can't see this helping.

If a CPU is always executing instructions how do we measure its work?

Let us say we have a fictitious single core CPU with Program Counter and basic instruction set such as Load, Store, Compare, Branch, Add, Mul and some ROM and RAM. Upon switching on it executes a program from ROM.
Would it be fair to say the work the CPU does is based on the type of instruction it's executing. For example, a MUL operating would likely involve more transistors firing up than say Branch.
However from an outside perspective if the clock speed remains constant then surely the CPU could be said to be running at 100% constantly.
How exactly do we establish a paradigm for measuring the work of the CPU? Is there some kind of standard metric perhaps based on the type of instructions executing, the power consumption of the CPU, number of clock cycles to complete or even whether it's accessing RAM or ROM.
A related second question is what does it mean for the program to "stop". Usually does it just branch in an infinite loop or does the PC halt and the CPU waits for an interupt?
First of all, that a CPU is always executing some code is just an approximation these days. Computer systems have so-called sleep states which allow for energy saving when there is not too much work to do. Modern CPUs can also throttle their speed in order to improve battery life.
Apart from that, there is a difference between the CPU executing "some work" and "useful work". The CPU by itself can't tell, but the operating system usually can. Except for some embedded software, a CPU will never be running a single job, but rather an operating system with different processes within it. If there is no useful process to run, the Operating System will schedule the "idle task" which mostly means putting the CPU to sleep for some time (see above) or jsut burning CPU cycles in a loop which does nothing useful. Calculating the ratio of time spent in idle task to time spent in regular tasks gives the CPU's business factor.
So while in the old days of DOS when the computer was running (almost) only a single task, it was true that it was always doing something. Many applications used so-called busy-waiting if they jus thad to delay their execution for some time, doing nothing useful. But today there will almost always be a smart OS in place which can run the idle process than can put the CPU to sleep, throttle down its speed etc.
Oh boy, this is a toughie. It’s a very practical question as it is a measure of performance and efficiency, and also a very subjective question as it judges what instructions are more or less “useful” toward accomplishing the purpose of an application. The purpose of an application could be just about anything, such as finding the solution to a complex matrix equation or rendering an image on a display.
In addition, modern processors do things like clock gating in power idle states. The oscillator is still producing cycles, but no instructions execute due to certain circuitry being idled due to cycles not reaching them. These are cycles that are not doing anything useful and need to be ignored.
Similarly, modern processors can execute multiple instructions simultaneously, execute them out of order, and predict and execute which instructions will be executed next before your program (i.e. the IP or Instruction Pointer) actually reaches them. You don’t want to include instructions whose execution never actually complete, such as because the processor guesses wrong and has to flush those instructions, e.g. as due to a branch mispredict. So a better metric is counting those instructions that actually complete. Instructions that complete are termed “retired”.
So we should only count those instructions that complete (i.e. retire), and cycles that are actually used to execute instructions (i.e. unhalted).)
Perhaps the most practical general metric for “work” is CPI or cycles-per-instruction: CPI = CPU_CLK_UNHALTED.CORE / INST_RETIRED.ANY. CPU_CLK_UNHALTED.CORE are cycles used to execute actual instructions (vs those “wasted” in an idle state). INST_RETIRED are those instructions that complete (vs those that don’t due to something like a branch mispredict).
Trying to get a more specific metric, such as the instructions that contribute to the solution of a matrix multiple, and excluding instructions that don’t directly contribute to computing the solution, such as control instructions, is very subjective and difficult to gather statistics on. (There are some that you can, such as VECTOR_INTENSITY = VPU_ELEMENTS_ACTIVE / VPU_INSTRUCTIONS_EXECUTED which is the number of SIMD vector operations, such as SSE or AVX, that are executed per second. These instructions are more likely to directly contribute to the solution of a mathematical solution as that is their primary purpose.)
Now that I’ve talked your ear off, check out some of the optimization resources at your local friendly Intel developer resource, software.intel.com. Particularly, check out how to effectively use VTune. I’m not suggesting you need to get VTune though you can get a free or very discounted student license (I think). But the material will tell you a lot about increasing your programs performance (i.e. optimizing), which is, if you think about it, increasing the useful work your program accomplishes.
Expanding on Michał's answer a bit:
Program written for modern multi-tasking OSes are more like a collection of event handlers: they effectively setup listeners for I/O and then yield control back to the OS. The OS wake them up each time there is something to process (e.g. user action, data from device) and they "go to sleep" by calling into the OS once they've finished processing. Most OSes will also preempt in case one process hog the CPU for too long and starve the others.
The OS can then keep tabs on how long each process are actually running (by remembering the start and end time of each run) and generate the statistics like CPU time and load (ready process queue length).
And to answer your second question:
To stop mostly means a process is no longer scheduled and all associated resource (scheduling data structures, file handles, memory space, ...) destroyed. This usually require the process to call a special OS call (syscall/interrupt) so the OS can release the resources gracefully.
If however a process run into an infinite loop and stops responding to OS events, then it can only be forcibly stopped (by simply not running it anymore).

What exactly is CPU load if instructions are executed one at a time?

I know this question has been asked many times in many different manners, but it's still not clear for me what the CPU load % means.
I'll start explaining how I perceive the concepts now (of course, I might, and sure will, be wrong):
A CPU core can only execute one instruction at a time. It will not execute the next instruction until it finishes executing the current one.
Suppose your box has one single CPU with one single core. Parallel computing is hence not possible. Your OS's scheduler will pick up a process, set the IP to the entry point, and send that instruction to the CPU. It won't move to the next instruction until the CPU finishes executing the current instruction. After a certain amount of time it will switch to another process, and so on. But it will never switch to another process if the CPU is currently executing an instruction. It will wait until the CPU becomes free to switch to another process. Since you only have one single core, you can't have two processes executing simultaneously.
I/O is expensive. Whenever a process wants to read a file from the disk, it has to wait until the disk accomplishes its task, and the current process can't execute its next instruction until then. The CPU is not doing anything while the disk is working, and so our OS will switch to another process until the disk finishes its job in order not to waste time.
Following these principles, I've come myself to the conclusion that CPU load at a given time can only be one of the following two values:
0% - Idle. CPU is doing nothing at all.
100% - Busy. CPU is currently executing an instruction.
This is obviously false as taskmgr reports %1, 12%, 15%, 50%, etc. CPU usage values.
What does it mean that a given process, at a given time, is utilizing 1% of a given CPU core (as reported by taskmgr)? While that given process is executing, what happens with the 99%?
What does it mean that the overall CPU usage is 19% (as reported by Rainmeter at the moment)?
If you look into the task manager on Windows there is Idle process, that does exactly that, it just shows amount of cycles not doing anything useful. Yes, CPU is always busy, but it might be just running in a loop waiting for useful things to come.
Since you only have one single core, you can't have two processes
executing simultaneously.
This is not really true. Yes, true parallelism is not possible with single core, but you can create illusion of one with preemptive multitasking. Yes, it is impossible to interrupt instruction, but it is not a problem because most of the instructions require tiny amount of time to finish. OS shares time with time slices, which are significantly longer than execution time of single instruction.
What does it mean that a given process, at a given time, is utilizing 1% of a given CPU core
Most of the time applications are not doing anything useful. Think of application that waits for user to click a button to start processing something. This app doesn't need CPU, so it sleeps most of the time, or every time it gets time slice it just goes into sleep (see event loop in Windows). GetMessage is blocking, so it means that thread will sleep until message arrives. So what CPU load really means? So imagine the app receives some events or data to do things, it will do operations instead of sleeping. So if it utilizes X% of CPU means that over sampling period of time that app used X% of CPU time. CPU time usage is average metric.
PS: To summarize concept of CPU load, think of speed (in terms of physics). There are instantaneous and average speeds, so speaking of CPU load, there also are instantaneous and average measurements. Instantaneous is always equal to either 0% or 100%, because at some point of time process either uses CPU or not. If process used 100% of CPU in the course of 250ms and didn't use for next 750ms then we can say that process loaded CPU for 25% with sampling period of 1 second (average measurement can only be applied with certain sampling period).
http://blog.scoutapp.com/articles/2009/07/31/understanding-load-averages
A single-core CPU is like a single lane of traffic. Imagine you are a bridge operator ... sometimes your bridge is so busy there are cars lined up to cross. You want to let folks know how traffic is moving on your bridge. A decent metric would be how many cars are waiting at a particular time. If no cars are waiting, incoming drivers know they can drive across right away. If cars are backed up, drivers know they're in for delays.
This is basically what CPU load is. "Cars" are processes using a slice of CPU time ("crossing the bridge") or queued up to use the CPU. Unix refers to this as the run-queue length: the sum of the number of processes that are currently running plus the number that are waiting (queued) to run.
Also see: http://en.wikipedia.org/wiki/Load_(computing)

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