I need to update value in table with (own value) - (value in other table Like) for an id
I have tried this
UPDATE FULLTABLE
SET FULLTABLE.Balance = FULLTABLE.Balance - AdvBalance.balance
WHERE FULLTABLE.id= AdvBalance.advid;
and this
update fulltable f set f.balance = ( f.balance -
select a.balance from advbalance a where a.advid=f.advertiserID)
first one is throwing error that invalid identifier. second one some other error.
I am using oracle db.
Please suggest a way to do this.
Thanks
You need a subselect to get the value from another table:
UPDATE FULLTABLE ft
SET ft.Balance = ft.Balance - (SELECT ab.balance
FROM AdvBalance ab
WHERE ft.id = ab.advid);
This will fail if it is possible that the subquery will return more than one row, but if this is the case, then you must decide how to find the right value to be subtracted.
Related
I have written a query where I want to just update some of the LINK_ID. But it is updating all the rows in that table.
Here is my query
UPDATE APP_FIBERINV.TBL_FIBER_INV_CMPAPPROVED_INFO
SET NE_LENGTH =
(select MAINT_ZONE_NE_SPAN_LENGTH from APP_FIBERINV.TBL_FIBER_INV_JOBS WHERE LINK_ID IN ('MORV_1020','ANND_1017','BBSR_1047','DLHI_5417','MYSR_0104'));
I still doubt that the update statement you have posted updates all rows in the table. It must throw an error
ORA-01427: single-row subquery returns more than one row
instead, because your subquery returns five rows where it must be one, as you must find one value for each row you want to update.
This means your subquery is wrong. It selects five rows, where it must select one. You don't want to find the five values for 'MORV_1020', 'ANND_1017', but the one value for the link ID of the row you are updating.
You also want to update certain rows (those with the five link IDs), so you must add a WHERE clause at the end of your update statement.
UPDATE app_fiberinv.tbl_fiber_inv_cmpapproved_info i
SET ne_length =
(
SELECT j.maint_zone_ne_span_length
FROM app_fiberinv.tbl_fiber_inv_jobs j
WHERE j.link_id = i.span_link_id
)
WHERE span_link_id IN ('MORV_1020', 'ANND_1017', 'BBSR_1047', 'DLHI_5417', 'MYSR_0104');
Assuming both tables share the LINK_ID as primary and foreign key, you could just use a MERGE:
MERGE INTO APP_FIBERINV.TBL_FIBER_INV_CMPAPPROVED_INFO APPR_NFO
USING (
SELECT LINK_ID, MAINT_ZONE_NE_SPAN_LENGTH
FROM APP_FIBERINV.TBL_FIBER_INV_JOBS
WHERE LINK_ID IN ('MORV_1020','ANND_1017','BBSR_1047','DLHI_5417','MYSR_0104')
) INV_JOBS
ON ( APPR_NFO.SPAN_LINK_ID = INV_JOBS.LINK_ID)
WHEN MATCHED THEN UPDATE SET APPR_NFO.NE_LENGTH = INV_JOBS.MAINT_ZONE_NE_SPAN_LENGTH;
I am not an oracle expert. I faced a very strange problem but do not know why this occur.
My query is
SELECT hc.id, hc.owner_name, hc.national_id, hc.phone_no, hc.location, hc.status, hc.expiry_status, od.office_title AS issuer, hc.create_date, hc.email, hc.LATTITUDE, hc.LONGITUDE, hc.HASAD_NO, hc.NUMBERATION, hc.BREEDING_TYPE, hc.PROGENY, hc.office_id, hc.issuer_id, hc.expiry_status, hc.status FROM health_cards hc
LEFT JOIN office_details od ON od.office_id = hc.issuer_id AND od.lang = :lang
WHERE hc.id = :search_data_num OR hc.national_id = :search_data_num or hc.phone_no = :search_data_num OR hc.owner_name LIKE :search_data ORDER BY hc.create_date DESC, hc.id desc OFFSET 0 ROWS FETCH NEXT 50 ROWS ONLY
When i m running this query i m getting following error
ORA-00918: column ambiguously defined
00918. 00000 - "column ambiguously defined"
But if i remove OFFSET 0 ROWS FETCH NEXT 50 ROWS ONLY from my query it work perfectly.
I want to know the reason why this query not working with offset statement.
You have repeated column hc.status.
`select 1 as "A" as "A" from dual` - execute OK;
`select * from (select 1 as "A"
, 2 as "A"
from dual);` - ORA-00918: column ambiguously defined
If you and offset, oracle probably does something similar.
You have the column hc.expiry_status twice in your select list.
The problem is that we allow this in a select list, but not within an inline view. When you add the row limiting clause, Oracle transforms the query and the transformation uses an inline view. There is a bug, 13687511 which is marked as fixed.
Meanwhile, the workaround is to either not select it twice, or alias the column(s).
I am creating a query in Hive to execute a R script. I am using transform function to pass the table. However when I receive the table in R it comes without the header. I know that I could create a variable and ask the user to insert the header manually but I do not wanna do it.
I wanna do something automatically, I am considering two options:
1) Figure out a way to pass the table with the header included when using transform function
2) Save the header in a variable and pass it in transform (I have already tried it in different ways but instead of passing the result of the query it is passing the query string - as seen below)
Here is what I have:
--Name of the origin table
set source_table = categ_table_small;
--Number of clusters
set k = "5";
--Distance to be used in the model
set distance = "euclidean";
--Folder where the results of the model will be saved
set dir_tar = "/output_r";
--Name of the model used in the naming of the files
set model_name ="testeclara_small";
--Samples: integer, number of samples to be drawn from the dataset.
set n_samples = "10";
--sampsize: integer, number of observations in each sample. This formula is suggested by the package. sampsize<-min(nrow(x), 40 + 2 * k)
set sampsize = "50";
--Creating a matrix which will store the sample number and the group of each sample according to the algorithm
CREATE TABLE IF NOT EXISTS medoids_result AS SELECT * FROM categ_table_small;
--In the normal situation you don't have the output label, it means you just have 'x' and do not have 'y', so you need to add one extra column to receive
--the group of each observation
--ALTER TABLE medoids_result ADD COLUMNS (medoid INT);
set result_matrix = medoids_result;
set headerMatrix = show columns in categ_table_small;
--Trainning query
SET mapreduce.job.name = K medoids Clara- ${hiveconf:source_table};
SET mapreduce.job.reduces=1;
INSERT OVERWRITE TABLE ${hiveconf:result_matrix}
SELECT TRANSFORM ($begin(cols="${hiveconf:source_table}" delimiter= "," excludes="y")$column$end)
USING '/usr/bin/Rscript_10gb /programs_r/du8_dev_1.R ${hiveconf:k}${hiveconf:distance}${hiveconf:dir_tar}${hiveconf:model_name}${hiveconf:n_samples}${hiveconf:sampsize}${hiveconf:headerMatrix}'
AS
(
$begin(table='${hiveconf:result_matrix}') $column$end
)
FROM
(SELECT *
FROM ${hiveconf:source_table}
DISTRIBUTE BY '1'
)t1;
You can add this line
hive -e 'set hive.cli.print.header=true;select * from tablename;'
Where tablename refers to your table name
If you want defaultly work for every table then you need to update the $HOME/.hiverc file with
hive> set hive.cli.print.header=true;
in the first line.
Can any one please help me to solve this issue
Table Name:RW_LN
LN_ID RE_LN_ID RE_PR_ID
LN001 RN001 RN002
LN002 RN002 RN003
LN003 RN003 RN001
LN004 RN001 RN002
MY Update Query is:
update table RW_LN set RE_LN_ID=(
select LN_ID
from RW_LN as n1,RW_LN as n2
where n1.RE_LN_ID = n2.RE_PR_ID)
MY Expected Result is:
LN_ID RE_LN_ID
LN001 LN003
LN002 LN004
LN003 LN002
LN004 LN003
This above query shows error as SUB QUERY RETURNS MULTIPLE ROWS.Can any one provide the solution for this, I am Beginner in Oracle 9i.So Stuck in the logic
you can try to solve this with a distinct
update table RW_LN set RE_LN_ID=(
select distinct LN_ID
from RW_LN as n1,RW_LN as n2
where n1.RE_LN_ID = n2.RE_PR_ID)
if that still returns multiple rows, it means you are missing a join somewhere along the way or potentially have a bad schema that needs to use primary keys.
If you want to take the "biggest" corresponding LN_ID, you could do
update RW_LN r1
set r1.RE_LN_ID = (select MAX(LN_ID)
FROM RW_LN r2
where r1.RE_LN_ID = r2.RE_PR_ID);
see SqlFiddle
But you should explain why you choose (as new RE_LN_ID) LN004 instead of LN001 for LN_ID LN002 (cause you could choose both)
Just guessing, but possibly this is what you want.
update
RW_LN n1
set
RE_LN_ID=(
select n2.LN_ID
from RW_LN n2
where n1.RE_LN_ID = n2.RE_PR_ID)
where exists (
select null
from RW_LN n2
where n1.RE_LN_ID = n2.RE_PR_ID and
n2.ln_id is not null)
At the moment there is no correlation between the rows you are updating and the value being returned in the subquery.
The query reads as follows:
For every row in RW_LN change the value of RE_LN_ID to be:
the value of LN_ID in a row in RW_LN for which:
the RE_PR_ID equals the original tables value of RE_LN_ID
IF there exists at least one row in RW_LN for which:
RE_PR_ID is the same as RE_LN_ID in the original table AND
LN_ID is not null
Hi Guys I have Two tables (MIGADM.CORPMISCELLANEOUSINFO and CRMUSER.PREFERENCES) and Each Has a field called PREFERENCE_ID and ORGKEY. I want to Update the Preference ID for MIGADM.CORPMISCELLANEOUSINFO with Preference_ID from CRMUSER.PREFERENCES for Each Corresponding ORGKEY. SO I wrote this Query;
update migadm.CORPMISCELLANEOUSINFO s set s.PREFERENCE_ID = (
select e.PREFERENCE_ID from crmuser.preferences e where s.ORGKEY = e.ORGKEY)
But I get:
ORA-01427: single-row subquery returns more than one row
What Should I do?
It means the columns you have selected are not unique enough to identify one row in your source table. Your first step would be to identify those columns.
To see the set of rows that have this problem, run this query.
select e.origkey,
count(*)
from crmuser.preferences e
group by e.origkey
having count(*) > 1
eg : for origkey of 2, let's say there are two rows in the preferences table.
orig_key PREFERENCE_ID
2 202
2 201
Oracle is not sure which of these should be used to update the preference_id column in CORPMISCELLANEOUSINFO
identify the row where the subquery returns more than one row (You could use REJECT ERROR clause to do it for instance) or use the condition 'where rownum = 1'.