I need to convert string to decimals.
So the string value is: 89,333,22.2345
So i want to keep all decimal places and convert it to: 8933322.2345.
I tried the following query:
select to_number(replace(nvl(89,333,22.2345),0),',','') from dual;
This rounds it to 893322. But i want result with all decimals:
If i try running this query:
select to_number((replace(nvl(89,333,22.2345),0),',',''),'9999.99') from dual;
it throws error.
Try this:
select to_number('89,333,22.2345','99,999,99.9999') from dual;
I think you're passing the number as a parameter. Otherwise why would you use nvl. Then I see the query you need is going to be similar like that
select to_number(replace(nvl('89,333,22.2345','0'),',','')) from dual;
Things were wrong at your code:
since number is a varchar, it has to be placed between apostrophes
nvl takes parameters divided by a comma. And there was one closing bracket too much
nvl(89,333,22.2345),0) -> nvl('89,333,22.2345',0)
Hi I am having issue when extracting fields from CLOB data. For one record I am not getting desired output.
The record is as below:
{1:F014243107336}{2:O2021216200422XXX24563}{3:{108:O2020}{121:2c02a452-5}{433:HIT}}{4:
:4A:SEC:20200901
:4B:FC5253
:4C:20042000,
:4D:XXXXXXX
:4E:RXX
:4F:RXXXX
-}{5:{CHK:87D1003B01F7}{TNG:}}{S:{SAC:}{COP:S}}<APSECSIGN>FS3sfasdfg!==</APSECSIGN>?
I want to extract data from tag :4A: into REF_NUMBER.
I am using below SQL to get the data.
NVL(TRIM(TRANSLATE(REGEXP_REPLACE(REGEXP_SUBSTR(dbms_lob.substr(CLOB, 4000, 1 ), ':4A.?:[^:]+(:|-\})'), ':20.?:([^:]+)(:|-\})', '\1'),CHR(10)||CHR(13), ' ')),' ') AS REF_NUMBER
the output I am getting is "SEC". However I want to see output as SEC:20200901.
Can any one suggest what I am missing in my query or provide me correct query.
A general suggestion. Why don't you have your data stored as JSON ? Because, JSON related functions are very fast when compared to others. And then your problem becomes quite easy.
However to answer your question:
with inputs (str) as
(
select to_clob(q'<
{1:F014243107336}{2:O2021216200422XXX24563}{3:{108:O2020}{121:2c02a452-5}{433:HIT}}{4:
:4A:SEC:20200901
:4B:FC5253
:4C:20042000,
:4D:XXXXXXX
:4E:RXX
:4F:RXXXX
-}{5:{CHK:87D1003B01F7}{TNG:}}{S:{SAC:}{COP:S}}<APSECSIGN>FS3sfasdfg!==</APSECSIGN>?
>') from dual
)
select str, regexp_substr(str,'SEC:\d+',1,1,'n') as val
from inputs;
Output:
Updated
If you know the date is always going to be 8 digits after the :4A: tag, you can use REGEXP_SUBSTR to get the value you need. Combining it with DBMS_LOB.SUBSTR removes the tag and converts it to a string.
SELECT DBMS_LOB.SUBSTR ((REGEXP_SUBSTR (clob_val, ':4A:.*\d{8}')), 4000, 5)
FROM (SELECT EMPTY_CLOB ()
|| '{1:F014243107336}{2:O2021216200422XXX24563}{3:{108:O2020}{121:2c02a452-5}{433:HIT}}{4:
:4A:SEC:20200901
:4B:FC5253
:4C:20042000,
:4D:XXXXXXX
:4E:RXX
:4F:RXXXX
-}{5:{CHK:87D1003B01F7}{TNG:}}{S:{SAC:}{COP:S}}<APSECSIGN>FS3sfasdfg!==</APSECSIGN>?' AS clob_val
FROM DUAL);
Using Oracle SQL, there is a function, noted below, that will allow you to create a "list" of names, phone numbers, etc., without using
multiple DUAL queries and UNION/UNION ALL to get more than one record.
The query below produces a list in this case of 10 names.
SELECT COLUMN_VALUE USERNAME
FROM TABLE(SYS.DBMS_DEBUG_VC2COLL(
'WARNER,JEFF',
'MALITO,CARL',
'MOODY,JEANNE',
'PHILLIPS,HUGH & KELLY',
'PATSANTARAS,VICTORIA',
'BROWN,ROLAND',
'RADOSEVICH,MIKE',
'RIDER,JACK',
'MACLEOD,LENARD',
'SCOTT,DAN' ))
However, when trying to run this same query in Snowflake, it will not work.
I receive this error: SQL compilation error: Invalid identifier SYS.DBMS_DEBUG_VC2COLL
Is there a "Snowflake version" of this query that can be used?
Here are some options, you can see which works best for you.
This works if you can get your SQL to look similar:
SELECT $1::VARCHAR AS column_value
FROM (VALUES ('WARNER,JEFF'), ('MACLEOD,LENARD'), ('SCOTT,DAN'));
This also works if you can get your list to be in a single string, delimited by a pipe or similar:
SELECT value::VARCHAR AS column_value
FROM LATERAL FLATTEN(INPUT=>SPLIT('WARNER,JEFF|MACLEOD,LENARD|SCOTT,DAN', '|'));
If you have the strings in the format 'a','b' and find it painful to do one of the above, I'd do something like this:
SELECT value::VARCHAR AS column_value
FROM LATERAL FLATTEN(INPUT=>SPLIT(ARRAY_TO_STRING(ARRAY_CONSTRUCT('WARNER,JEFF', 'MALITO,CARL', 'MOODY,JEANNE'), '|'), '|'));
Similar to the above suggestions, you can try this:
SELECT VALUE::VARCHAR as column_name
FROM TABLE(FLATTEN(INPUT => ARRAY_CONSTRUCT('WARNER,JEFF', 'MALITO,CARL', 'MOODY,JEANNE'), MODE => 'array'));
I need help
i have records 123,456,789 in rows when i am execute like
this one is working
select * from table1 where num1 in('123','456')
but when i am execute
select * from table1 where num1 in(select value from table2)
no resultset found - why?
Check the DataType varchare2 or Number
try
select * from table1 where num1 in(select to_char(value) from table2)
Storing comma separated values could be the cause of problem.
You can try using regexp_substr to split comma.
First and foremost, an important thing to remember: Do not store numbers in character datatypes. Use NUMBER or INTEGER. Secondly, always prefer VARCHAR2 datatype over CHAR if you wish to store characters > 1.
You said in one of your comments that num1 column is of type char(4). The problem with CHAR datatype is that If your string is 3 characters wide, it stores the record by adding extra 1 space character to make it 4 characters. VARCHAR2 only stores as many characters as you pass while inserting/updating and are not blank padded.
To verify that you may run select length(any_char_col) from t;
Coming to your problem, the IN condition is never satisfied because what's actually being compared is
WHERE 'abc ' = 'abc' - Note the extra space in left side operator.
To fix this, one good option is to pad the right side expression with as many spaces as required to do the right comparison.The function RPAD( string1, padded_length [, pad_string] ) could be used for this purpose.So, your query should look something like this.
select * from table1 where num1 IN (select rpad(value,4) from table2);
This will likely utilise an index on the column num1 if it exists.
The other one is to use RTRIM on LHS, which is only useful if there's a function based index on RTRIM(num1)
select * from table1 where RTRIM(num1) in(select value from table2);
So, the takeaway from all these examples is always use NUMBER types to store numbers and prefer VARCHAR2 over CHAR for strings.
See Demo to fully understand what's happening.
EDIT : It seems You are storing comma separated numbers.You could do something like this.
SELECT *
FROM table1 t1
WHERE EXISTS (
SELECT 1
FROM table2 t2
WHERE ',' ||t2.value|| ',' LIKE '%,' || rtrim(t1.num1) || ',%'
);
See Demo2
Storing comma separated values are bound to cause problems, better change it.
Let me tell you first,
You have stored values in table2 which is comma seperated.
So, how could you match your data with table1 and table2.
Its not Possible.
That's why you did not get any values in result set.
I found the Solution using string array
SELECT T.* FROM TABLE1 T,
(SELECT TRIM(VALUE)AS VAL FROM TABLE2)TABLE2
WHERE
TRIM(NUM1) IN (SELECT COLUMN_VALUE FROM TABLE(FUNC_GETSTRING_ARRAY(TABLE2.VAL)))
thanks
I am developing an application in Oracle APEX. I have a string with user id's that is comma deliminated which looks like this,
45,4932,20,19
This string is stored as
:P5_USER_ID_LIST
I want a query that will find all users that are within this list my query looks like this
SELECT * FROM users u WHERE u.user_id IN (:P5_USER_ID_LIST);
I keep getting an Oracle error: Invalid number. If I however hard code the string into the query it works. Like this:
SELECT * FROM users u WHERE u.user_id IN (45,4932,20,19);
Anyone know why this might be an issue?
A bind variable binds a value, in this case the string '45,4932,20,19'. You could use dynamic SQL and concatenation as suggested by Randy, but you would need to be very careful that the user is not able to modify this value, otherwise you have a SQL Injection issue.
A safer route would be to put the IDs into an Apex collection in a PL/SQL process:
declare
array apex_application_global.vc_arr2;
begin
array := apex_util.string_to_table (:P5_USER_ID_LIST, ',');
apex_collection.create_or_truncate_collection ('P5_ID_COLL');
apex_collection.add_members ('P5_ID_COLL', array);
end;
Then change your query to:
SELECT * FROM users u WHERE u.user_id IN
(SELECT c001 FROM apex_collections
WHERE collection_name = 'P5_ID_COLL')
An easier solution is to use instr:
SELECT * FROM users u
WHERE instr(',' || :P5_USER_ID_LIST ||',' ,',' || u.user_id|| ',', 1) !=0;
tricks:
',' || :P5_USER_ID_LIST ||','
to make your string ,45,4932,20,19,
',' || u.user_id|| ','
to have i.e. ,32, and avoid to select the 32 being in ,4932,
I have faced this situation several times and here is what i've used:
SELECT *
FROM users u
WHERE ','||to_char(:P5_USER_ID_LIST)||',' like '%,'||to_char(u.user_id)||',%'
ive used the like operator but you must be a little carefull of one aspect here: your item P5_USER_ID_LIST must be ",45,4932,20,19," so that like will compare with an exact number "',45,'".
When using it like this, the select will not mistake lets say : 5 with 15, 155, 55.
Try it out and let me know how it goes;)
Cheers ,
Alex
Create a native query rather than using "createQuery/createNamedQuery"
The reason this is an issue is that you cannot just bind an in list the way you want, and just about everyone makes this mistake at least once as they are learning Oracle (and probably SQL!).
When you bind the string '32,64,128', it effectively becomes a query like:
select ...
from t
where t.c1 in ('32,64,128')
To Oracle this is totally different to:
select ...
from t
where t.c1 in (32,64,128)
The first example has a single string value in the in list and the second has a 3 numbers in the in list. The reason you get an invalid number error is because Oracle attempts to cast the string '32,64,128' into a number, which it cannot do due to the commas in the string.
A variation of this "how do I bind an in list" question has come up on here quite a few times recently.
Generically, and without resorting to any PLSQL, worrying about SQL Injection or not binding the query correctly, you can use this trick:
with bound_inlist
as
(
select
substr(txt,
instr (txt, ',', 1, level ) + 1,
instr (txt, ',', 1, level+1) - instr (txt, ',', 1, level) -1 )
as token
from (select ','||:txt||',' txt from dual)
connect by level <= length(:txt)-length(replace(:txt,',',''))+1
)
select *
from bound_inlist a, users u
where a.token = u.id;
If possible the best idea may be to not store your user ids in csv! Put them in a table or failing that an array etc. You cannot bind a csv field as a number.
Please dont use: WHERE ','||to_char(:P5_USER_ID_LIST)||',' like '%,'||to_char(u.user_id)||',%' because you'll force a full table scan although with the users table you may not have that many so the impact will be low but against other tables in an enterprise environment this is a problem.
EDIT: I have put together a script to demonstrate the differences between the regex method and the wildcard like method. Not only is regex faster but it's also a lot more robust.
-- Create table
create table CSV_TEST
(
NUM NUMBER not null,
STR VARCHAR2(20)
);
create sequence csv_test_seq;
begin
for j in 1..10 loop
for i in 1..500000 loop
insert into csv_test( num, str ) values ( csv_test_seq.nextval, to_char( csv_test_seq.nextval ));
end loop;
commit;
end loop;
end;
/
-- Create/Recreate primary, unique and foreign key constraints
alter table CSV_TEST
add constraint CSV_TEST_PK primary key (NUM)
using index ;
alter table CSV_TEST
add constraint CSV_TEST_FK unique (STR)
using index;
select sysdate from dual;
select *
from csv_test t
where t.num in ( Select Regexp_Substr('100001, 100002, 100003 , 100004, 100005','[^,]+', 1, Level) From Dual
Connect By Regexp_Substr('100001, 100002,100003, 100004, 100005', '[^,]+', 1, Level) Is Not Null);
select sysdate from dual;
select *
from csv_test t
where ('%,' || '100001,100002, 100003, 100004 ,100005' || ',%') like '%,' || num || ',%';
select sysdate from dual;
select *
from csv_test t
where t.num in ( Select Regexp_Substr('100001, 100002, 100003 , 100004, 100005','[^,]+', 1, Level) From Dual
Connect By Regexp_Substr('100001, 100002,100003, 100004, 100005', '[^,]+', 1, Level) Is Not Null);
select sysdate from dual;
select *
from csv_test t
where ('%,' || '100001,100002, 100003, 100004 ,100005' || ',%') like '%,' || num || ',%';
select sysdate from dual;
drop table csv_test;
drop sequence csv_test_seq;
Solution from Tony Andrews works for me. The process should be added to "Page processing" >> "After submit">> "Processes".
As you are Storing User Ids as String so You can Easily match String Using Like as Below
SELECT * FROM users u WHERE u.user_id LIKE '%'||(:P5_USER_ID_LIST)||'%'
For Example
:P5_USER_ID_LIST = 45,4932,20,19
Your Query Surely Will return Any of 1 User Id which Matches to Users table
This Will Surely Resolve Your Issue , Enjoy
you will need to run this as dynamic SQL.
create the entire string, then run it dynamically.