I have this line in vb script:
fileCheck = Right(objLookFile.name, len(objLookFile.name) - len("Audit_######_"))
the Audit_######_ takes 6 digits for now. I got a situation where I have files with 7 digits and 8.
ex of file : Audit_1002611_Comnpany_MTH_11_2013.00001.txt
How I change the ###### to accept any number of digits?
dim lookFor
lookFor = fiRef(i_fi) & "_" & AIOType(i_type) & "_" & Right("00" & (month(processDate + 1)), 2) & "_" & Year(processDate + 1) & ".00001.txt"
dim minLen
minLen = len(lookFor)
dim objLookFolder, objLookFile
set objLookFolder = objFSO.GetFolder(AIODVDDir)
For each objLookFile in objLookFolder.files
if Len(objLookFile.name) >= minLen then
dim fileCheck
fileCheck = Right(objLookFile.name, len(objLookFile.name) - len("Audit_######_"))
if (Left(objLookFile.name, len("Audit_")) = "Audit_") AND (fileCheck = LookFor) then
'found the audit file
Thank you
Well, you're not doing anything with "Audit_######_" other than getting it's length. It looks like a hack-y way to just strip off the first 13 characters.
A smarter way may be to get everything after the second underscore :
fileCheck = mid(objLookFile.name, instr( instr(objLookFile.name, "_") + 1 , "_")+1)
There are several ways to handle this. Using string operations as D Stanley suggested is one way. Another is to split the file name at underscores and examine the fragments:
arr = Split(objLookFile.Name, "_", 3)
If UBound(arr) = 3 Then
If arr(0) = "Audit" And IsNumeric(arr(1)) And arr(2) = lookFor Then
...
End If
End If
Using a regular expression is probably the best approach, though:
Set re = New RegExp
re.Pattern = "Audit_\d+_" & fiRef(i_fi) & "_" & AIOType(i_type) _
& "_" & Right("00" & (month(processDate + 1)), 2) _
& "_" & Year(processDate + 1) & "\.00001\.txt"
For Each objLookFile In objFSO.GetFolder(AIODVDDir).Files
If re.Test(objLookFile.Name) Then
...
End If
Next
\d+ will match one or more digits. If you want to match a limited number of digits (e.g. at least 6 and at most 8 digits) replace that part of the pattern with \d{6,8}.
Related
hi all i have this question as bellow
how capitalize full in one vb6 Vb6 string variable
‘example
‘my fullname
Dim fullname as string
Fullname = “abdirahman abdirisaq ali”
Msgbox capitalize(fullname)
it prints abdirahmanAbdirisaq ali that means it skips the middle name space even if I add more spaces its same .
this is my own code and efforts it takes me at least 2 hours and still .
I tired it tired tired please save me thanks more.
Please check my code and help me what is type of mistakes I wrote .
This is my code
Private Function capitalize(txt As String) As String
txt = LTrim(txt)
temp_str = ""
Start_From = 1
spacing = 0
For i = 1 To Len(txt)
If i = 1 Then
temp_str = UCase(Left(txt, i))
Else
Start_From = Start_From + 1
If Mid(txt, i, 1) = " " Then
Start_From = i
spacing = spacing + 1
temp_str = temp_str & UCase(Mid(txt, Start_From + 1, 1))
Start_From = Start_From + 1
Else
temp_str = temp_str & LCase(Mid(txt, Start_From, 1))
End If
End If
Next i
checkName = temp_str
End Function
It's far simpler than that. In VB6 you should use Option Explicit to properly type your variables. That also requires you to declare them.
Option Explicit
Private Function capitalize(txt As String) As String
Dim temp_str as String
Dim Names As Variant
Dim Index As Long
'Remove leading and trailing spaces
temp_str = Trim$(txt)
'Remove any duplicate spaces just to be sure.
Do While Instr(temp_str, " ") > 0
temp_str = Replace(temp_str, " ", " ")
Loop
'Create an array of the individual names, separating them by the space delimiter
Names = Split(temp_str, " ")
'Now put them, back together with capitalisation
temp_str = vbnullstring
For Index = 0 to Ubound(Names)
temp_str = temp_str + Ucase$(Left$(Names(Index),1)) + Mid$(Names(Index),2) + " "
Next
'Remove trailing space
capitalize = Left$(temp_str, Len(temp_str) - 1)
End Function
That's the fairly easy part. If you are only going to handle people's names it still needs more work to handle names like MacFarland, O'Connor, etc.
Business names get more complicated with since they can have a name like "Village on the Lake Apartments" where some words are not capitalized. It's a legal business name so the capitalization is important.
Professional and business suffixes can also be problematic if everything is in lower case - like phd should be PhD, llc should be LLC, and iii, as in John Smith III, would come out Iii.
There is also a VB6 function that will capitalize the first letter of each word. It is StrConv(string,vbProperCase) but it also sets everything that is not the first letter to lower case. So PhD becomes Phd and III becomes Iii. Where as the above code does not change the trailing portion to lower case so if it is entered correctly it remains correct.
Try this
Option Explicit
Private Sub Form_Load()
MsgBox capitalize("abdirahman abdirisaq ali")
MsgBox capitalize("abdirahman abdirisaq ali")
End Sub
Private Function capitalize(txt As String) As String
Dim Names() As String
Dim NewNames() As String
Dim i As Integer
Dim j As Integer
Names = Split(txt, " ")
j = 0
For i = 0 To UBound(Names)
If Names(i) <> "" Then
Mid(Names(i), 1, 1) = UCase(Left(Names(i), 1))
ReDim Preserve NewNames(j)
NewNames(j) = Names(i)
j = j + 1
End If
Next
capitalize = Join(NewNames, " ")
End Function
Use the VB6 statement
Names = StrConv(Names, vbProperCase)
it's all you need (use your own variable instead of Names)
I am trying to implement search whole word only in VBScript, I tried appeding characters like space, /, ],) etc. as these characters means end of word. I need to do as many search as the number of characters I want to include using or operator. Is there any way to do it easily in VBScript.
Currently I am doing :-
w_seachString =
searchString & " " or
searchString & "/" or
searchString & "]" or
searchString & ")" or
searchString & "}" or
searchString & "," or
searchString & "."
So eventually I am comparing with lots of combination and looking for an effective way to make my variable w_seachString able to search for whole word only.
Use a regular expression with a word boundary anchor. Demo:
Option Explicit
Function qq(s) : qq = """" & s & """" : End Function
Dim r : Set r = New RegExp
r.Pattern = "\bx\b"
Dim s
For Each s In Split("axb| x |ax|x|\x/|", "|")
WScript.Echo qq(s), CStr(r.Test(s))
Next
output:
cscript 36443611.vbs
"axb" False
" x " True
"ax" False
"x" True
"\x/" True
"" False
So I've been trying for hours to figure out how to display the length of word count in vb.
For example, if I type in a sentence in a rich textbox and I click a button, I want a form to show up listing the number of one-letter words, two-letter words, three-letter words and so on within that sentence. The number of words of specific length will be outputted in labels, of course.
I found this short code online for word count:
dim wordcount as integer
dim a as string() = RichText.Text.Split(" ")
wordcount = a.length
However, I'm not sure if this code can be used to get the length of word count. Any ideas of how I can achieve outputting the number of words of a specific length in a label? Thank you.
What about something like:
Private Sub mnuCount_Click()
Const DELIMITERS As String = vbNewLine & " !"",.:;?"
Dim WordCounts(1 To 100) As Long
Dim Msg As String
Dim I As Integer
Dim WordCount As Long
With RTB
.Visible = False
.SelStart = 0
Do
.UpTo DELIMITERS, vNegate:=True
.Span DELIMITERS, vNegate:=True
If .SelLength > 0 Then
WordCounts(.SelLength) = WordCounts(.SelLength) + 1
.SelStart = .SelStart + .SelLength
Else
Exit Do
End If
Loop
.SelStart = 0
.Visible = True
End With
Msg = "Length" & vbTab & "Count"
For I = 1 To 100
If WordCounts(I) > 0 Then
Msg = Msg & vbNewLine _
& CStr(I) & vbTab & CStr(WordCounts(I))
WordCount = WordCount + WordCounts(I)
End If
Next
Msg = Msg & vbNewLine _
& "Grand total:" & vbNewLine _
& vbTab & CStr(WordCount)
MsgBox Msg
End Sub
Pradnya's code, translated to VB6:
Option Explicit
Private Sub Command1_Click()
Dim str As String
Dim splitStr() As String
Dim i As Integer
str = "ABC DEF GHIJ KLMNOPQ"
splitStr = Split(str, " ")
MsgBox "Number of words = " & UBound(splitStr) + 1 & vbCrLf & _
"Average Length = " & Len(Replace(str, " ", "")) / (UBound(splitStr) + 1)
End Sub
I made a few simplifications as well. There's no need to go through the loop to get the average. All you have to do to get the length of the whole is remove the spaces and divide by the number of elements in the array.
However, if you want to get a count of the number of words of each length, you'll have to loop through the array, getting the length of each word and storing those values one by one. Best way to do that is to set a reference to scrrun.dll (Windows Scripting Runtime) and use a Dictionary object to store the values.
I would like to extract a given string out of another one.
The sample strings shall be:
V_DDRF_2J_WTF
V_ASDF_8J_TLDR
V_LULZ_1337_3J
(Hint: The letter after the integer is ALWAYS a J.)
Now I only want to extract the integer of the bold part of the string. How do I achieve that?
xJ will only appear in the middle or the end of the string.
Use a RegExp searching for "", a (sequence of) number(s), and an optional "" - as in:
Option Explicit
Function qq(s) : qq = """" & s & """" : End Function
Dim aTests : aTests = Array( _
"V_DDRF_2J_WTF" , "_2J_" _
, "V_ASDF_8J_TLDR", "_8J_" _
, "V_LULZ_1337_3J", "_3J" _
)
Dim r : Set r = New RegExp
'r.Pattern = "_\d+J(?:_|$)"
r.Pattern = "_\d+J_?"
Dim i, s
For i = 0 To UBound(aTests) Step 2
s = r.Execute(aTests(i + 0))(0).Value
WScript.Echo qq(aTests(i + 0)) _
, qq(s) _
, CStr(aTests(i + 1) = s)
Next
output:
cscript 28561918.vbs
"V_DDRF_2J_WTF" "_2J_" True
"V_ASDF_8J_TLDR" "_8J_" True
"V_LULZ_1337_3J" "_3J" True
You may have to tinker with the pattern, depending on your input data; code to deal with non-matches should be added.
You can use regex and use this pattern \d+J or \d+\w
You can test patterns here
I Have a 2100 Rows and 6 Columns Table
Throughout the table there are only 12 Possible values, say A,B,C,D,E,F,G,H,I,J,K,L
The 12th value L is just a blank filler. It denotes blank cell.
Since there are only 11 possible values througout the table, patterns are observed.
First a Pattern Appears and it is later repeated somewhere in the table.
There can be any number of Patterns, but i have a specific format for a pattern which is to found and reported that way.
Solutions in EXCEL-VBA, PHP-MYSQL or C are welcome.
I have attached an example of what Iam looking for. Suggestions are most welcome to refine
the questions.
Information & Format : http://ge.tt/8QkQJet1/v/0 [ DOCX File 234 KB ]
Example in Excel Sheet : http://ge.tt/69htuNt1/v/0 [ XLSX File 16 KB ]
Please comment for more information or specific requirement.
Please try the code below, change the range to what you need it to be and the sheet number to the correct sheet number (I wouldn't put your full range in just yet because if you have 1000 pattern finds, you'll have to click OK on the message box 1000 times, just test with a partial range)
This will scan through the range, and find any pattern of two within a 10 row range, if you need it to find bigger patterns, youll need to add the same code again with an extra IF statement checking the next offset.
This will only find it if the same pattern exists and the same column structure is present, but its a start for you
Works fine on testing
Sub test10()
Dim rCell As Range
Dim rRng As Range
Set rRng = Sheets("Sheet1").Range("A1:I60") '-1 on column due to offset
'Scan through all cells in range and find pattern
For Each rCell In rRng.Cells
If rCell.Value = "" Then GoTo skip
For i = 1 To 10
If rCell.Value = rCell.Offset(i, 0).Value Then
If rCell.Offset(0, 1).Value = rCell.Offset(i, 1) Then
MsgBox "Match Found at: " & rCell.Address & ":" & rCell.Offset(0, 1).Address & " and " & rCell.Offset(i, 0).Address & ":" & rCell.Offset(i, 1).Address
End If
End If
Next i
skip:
Next rCell
End Sub
***UPDATE***
I have updated my code, the following now finds the pattern wherever it may appear in the next 10 rows:
Sub test10()
Dim rCell As Range
Dim rRng As Range
Dim r1 As Range
Dim r2 As Range
Set rRng = Sheets("Sheet1").Range("A1:I50") '-1 on column due to offset
i = 1 'row length
y = 0 'column length
'Scan through all cells in range and find pattern
For Each rCell In rRng.Cells
If rCell.Value = "" Then GoTo skip
i = 1
Do Until i = 10
y = 0
Do Until y = 10
xcell = rCell.Value & rCell.Offset(0, 1).Value
Set r1 = Range(rCell, rCell.Offset(0, 1))
r1.Select
ycell = rCell.Offset(i, y).Value & rCell.Offset(i, y + 1).Value
Set r2 = Range(rCell.Offset(i, y), rCell.Offset(i, y + 1))
If ycell = xcell Then
Union(r1, r2).Font.Bold = True
Union(r1, r2).Font.Italic = True
Union(r1, r2).Font.Color = &HFF&
MsgBox "Match Found at: " & rCell.Address & ":" & rCell.Offset(0, 1).Address & " and " & rCell.Offset(i, y).Address & ":" & rCell.Offset(i, y + 1).Address
Union(r1, r2).Font.Bold = False
Union(r1, r2).Font.Italic = False
Union(r1, r2).Font.Color = &H0&
End If
y = y + 1
Loop
i = i + 1
Loop
skip:
Next rCell
End Sub