Spring 2.5 remember-me - spring

I need to create a "keep me signed-in" functionality, my application is currently using spring 2.5, I checked it on :
http://docs.spring.io/autorepo/docs/spring-security/3.0.x/reference/remember-me.html#remember-me-persistent-token
which tells about the remember-me tag which does it part, I also tried extending AbstractPreAuthenticatedProcessingFilter but I'm unable to get through.
Can someone please guide me to the solution for the requirement.
Any help would be highly appreciated.
Thanks,
Vaibhav

This can simply be accomplished using the Spring security remember me authentication mechanism. What I did was made changes in the application-context-security.xml added the tag
<remember-me services-ref="rememberMeServices" key="vaib1q2w3e4r5tazsxdc"/>
and
<beans:bean id="rememberMeProcessingFilter"
class="org.springframework.security.ui.rememberme.RememberMeProcessingFilter">
<beans:property name="rememberMeServices" ref="rememberMeServices" />
<beans:property name="authenticationManager" ref="authenticationManager" />
</beans:bean>
<beans:bean id="rememberMeServices"
class="org.springframework.security.ui.rememberme.TokenBasedRememberMeServices">
<beans:property name="userDetailsService" ref="userDetailsService" />
<beans:property name="key" value="vaib1q2w3e4r5tazsxdc" />
<beans:property name="tokenValiditySeconds" value="120"/>
<beans:property name="alwaysRemember" value="false" />
</beans:bean>
<beans:bean id="rememberMeAuthenticationProvider"
class="org.springframework.security.providers.rememberme.RememberMeAuthenticationProvider">
<custom-authentication-provider />
<beans:property name="key" value="vaib1q2w3e4r5tazsxdc" />
</beans:bean>
By adding the above a new cookie by the name 'SPRING_SECURITY_REMEMBER_ME_COOKIE' would be created and would make things work like charm.
Thanks,
-V

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Application session is shared between users while accessing from different machines

I am building an online Examination project with spring mvc and Hibernate as Frameworks and it is almost done, Now I am getting the problem with session
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<beans:property name="dataSource" ref="dataSource" />
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<beans:property name="hibernateProperties">
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<beans:prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect
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<!-- Inject the transaction manager -->
<tx:annotation-driven transaction-manager="transactionManager"/>
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and queries in dao impl are like this
#Override
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The Exam users will login to application and he have to attempt 20 questions
The application is in my local machine and which is connected with in network for testing While the Exam is started with two people I am getting the problem like below
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How to get all application's online users in Spring Security 3.0.5?

When I make an implementation for
org.springframework.security.core.userdetails.UserDetailsService
and use the statement
sessionRegistry.registerNewSession(user.getUsername(), user);
within it after successful authentication, then the
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list is not empty (but when I log out from application the session still remain within list) otherwise this list will be empty. how can I make the session registration (and also unregistration during user log out or session expiration) within sessionRegistry automatically? my spring config is as below:
<sec:http auto-config="true" use-expressions="true" access-denied-page="/accessDenied.jsf">
<sec:form-login login-page="/login.jsf" />
<sec:session-management session-authentication-strategy-ref="sas" />
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<bean id="scr"
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Most likely you have forgotten to add an HttpSessionEventPublisher to your web.xml.
Another possibility is that the principal in question has other sessions still active which haven't timed-out or been invalidated. You have a maximum session value of 10. Try setting that to "1" instead for testing.
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Exception:
Stacktrace:
....
root cause
javax.servlet.jsp.JspException: No visible WebSecurityExpressionHandler instance could be found in the application context. There must be at least one in order to support expressions in JSP 'authorize' tags.
org.springframework.security.taglibs.authz.AuthorizeTag.getExpressionHandler(AuthorizeTag.java:100)
org.springframework.security.taglibs.authz.AuthorizeTag.authorizeUsingAccessExpression(AuthorizeTag.java:58)
Here is my application-context-Security.xml:
<http auto-config='true' >
<intercept-url pattern="/user/**" access="ROLE_User" />
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<beans:bean id="daoAuthenticationProvider"
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<password-encoder hash="plaintext" />
</authentication-provider>
</authentication-manager>
I understand that I could use use-expression="true" in the http tag but that means I would have to use expression in the intercept-url tags and in the java code. Is there a workaround?
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<bean id="webexpressionHandler" class="org.springframework.security.web.access.expression.DefaultWebSecurityExpressionHandler" />
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<authentication-manager>
<authentication-provider>
...
<ldap-user-service server-ref="ldapServer"
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Detect session expired or session timeout using spring3

How to Detect session expired or session timeout using spring3.
The key is this:
<beans:bean id="concurrencyFilter"
class="org.springframework.security.web.session.ConcurrentSessionFilter">
<beans:property name="sessionRegistry" ref="sessionRegistry" />
<beans:property name="expiredUrl" value="/session-expired.htm" />
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http://static.springsource.org/spring-security/site/docs/3.0.x/reference/session-mgmt.html#concurrent-sessions

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