How to pass Json object from ajax to spring mvc controller? - ajax

Question

I am working on SpringMVC, I am passing data from ajax to controller but i got null value in my controller please check my code below
function searchText()
{
var sendData = {
"pName" : "bhanu",
"lName" :"prasad"
}
$.ajax({
type: "POST",
url: "/gDirecotry/ajax/searchUserProfiles.htm,
async: true,
data:sendData,
success :function(result)
{
}
}
MyControllerCode
RequestMapping(value="/gDirecotry/ajax/searchUserProfiles.htm",method=RequestMethod.POST)
public #ResponseBody String getSearchUserProfiles(HttpServletRequest request)
{
String pName = request.getParameter("pName");
//here I got null value
}
any one help me

Answer 1

Hey enjoy the following code.
Javascript AJAX call
function searchText() {
var search = {
"pName" : "bhanu",
"lName" :"prasad"
}
$.ajax({
type: "POST",
contentType : 'application/json; charset=utf-8',
dataType : 'json',
url: "/gDirecotry/ajax/searchUserProfiles.html",
data: JSON.stringify(search), // Note it is important
success :function(result) {
// do what ever you want with data
}
});
}
Spring controller code
RequestMapping(value="/gDirecotry/ajax/searchUserProfiles.htm",method=RequestMethod.POST)
public #ResponseBody String getSearchUserProfiles(#RequestBody Search search, HttpServletRequest request) {
String pName = search.getPName();
String lName = search.getLName();
// your logic next
}
Following Search class will be as follows
class Search {
private String pName;
private String lName;
// getter and setters for above variables
}
Advantage of this class is that, in future you can add more variables to this class if needed.
Eg. if you want to implement sort functionality.

Answer 2

Use this method if you dont want to make a class you can directly send JSON without Stringifying. Use Default Content Type.
Just Use #RequestParam instead of #RequestBody.
#RequestParam Name must be same as in json.
Ajax Call
function searchText() {
var search = {
"pName" : "bhanu",
"lName" :"prasad"
}
$.ajax({
type: "POST",
/*contentType : 'application/json; charset=utf-8',*/ //use Default contentType
dataType : 'json',
url: "/gDirecotry/ajax/searchUserProfiles.htm",
data: search, // Note it is important without stringifying
success :function(result) {
// do what ever you want with data
}
});
Spring Controller
RequestMapping(value="/gDirecotry/ajax/searchUserProfiles.htm",method=RequestMethod.POST)
public #ResponseBody String getSearchUserProfiles(#RequestParam String pName, #RequestParam String lName) {
String pNameParameter = pName;
String lNameParameter = lName;
// your logic next
}

Answer 3

I hope, You need to include the dataType option,
dataType: "JSON"
And you could get the form data in controller as below,
public #ResponseBody String getSearchUserProfiles(#RequestParam("pName") String pName ,HttpServletRequest request)
{
//here I got null value
}

Answer 4

If you can manage to pass your whole json in one query string parameter then you can use rest template on the server side to generate Object from json, but still its not the optimal approach

Answer 5

u take like this
var name=$("name").val();
var email=$("email").val();
var obj = 'name='+name+'&email'+email;
$.ajax({
url:"simple.form",
type:"GET",
data:obj,
contentType:"application/json",
success:function(response){
alert(response);
},
error:function(error){
alert(error);
}
});
spring Controller
#RequestMapping(value = "simple", method = RequestMethod.GET)
public #ResponseBody String emailcheck(#RequestParam("name") String name, #RequestParam("email") String email, HttpSession session) {
String meaaseg = "success";
return meaaseg;
}