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Want a appropriate pseudocode
Write a pseudocode for any positive integer(decimal ) and display it as binary output .
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How to do 50% of 120 in scala code..need proper syntax ,& runnable code for same.
Eg :
int k = (int)(120*(50.0f/100.0f));
This is in java need scala code for same.
The answer would be:
(120*(50.0f/100.0f)).toInt
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List like this:[1,[2,3,4]]
Remove the first element of sub-list which is 2,
Result like this:[1,[3,4]]
This should get you an idea of how to do it:
rem_sublist_first([], []).
rem_sublist_first([X|Y], [X|Y2]):-
\+ X = [_|_],
rem_sublist_first(Y, Y2).
rem_sublist_first([[_|Y1]|Y2], [Y1|Y3]):-
rem_sublist_first(Y2, Y3).
test:-
rem_sublist_first([1,[2,3,4]], [1,[3,4]]),
rem_sublist_first([1,2,3,[4,5,6]], [1,2,3,[5,6]]).
I advise you to study prolog lists, they are essential for any type of prolog program so it is a worth investment if you are goind to write prolog code.
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Lets say I have the string "first=53 second=65 third=82". How do I assign each value to variables x, y, z?
Edit: The words must match as well. With the + signs and exact number of spaces.
str = "first=53 second=65 third=82"
x, y, z = str.scan(/\d+/).map(&:to_i)
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I have this array:
a= [[1,2],[3,4],[1,2],[2,3],[2,3]]
How can I make user to enter an array element ex:[1,2] and it should take that element and return the number of times it is found in the array.
You have your array a and the user input (i1 and i2), all you have to do is:
a.count([i1, i2])