I'm trying to pass a parameter to a bash script:
"words.sh surf"
#!/bin/bash
#words.sh
#purpose:
#
# to return a list of words
# sorted by the length of each word
#
i=$1
cat ~/wordlist | grep $i | awk '{ print length(),$0 | "sort -n" }'
and I'm getting this message:
usage: grep [-abcDEFGHhIiJLlmnOoPqRSsUVvwxZ] [-A num] [-B num] [-C[num]].
awk: syntax error at source line 1
context is.
{ print length(), >>> -/bin/bash <<< | "sort -n" }
awk: illegal statement at source line 1
if I run the statement as a command :
cat ~/wordlist | grep surf | awk '{ print length(),$0 | "sort -n" }'
I get the correct output:
...
...
12 hypersurface
12 surfboarding
12 undersurface
12 unsurfeiting
13 subtersurface
What am I doing wrong here?
You said it's working for you, but trust me it's got issues. Re-write it as:
awk -v i="$1" '$0 ~ i{print length(), $0 }' | sort -n
Related
I am getting an issue where if I call this function below, I get the error line 89: syntax error at line 117: 'df' unexpected.
If I take the code out of the function it works fine.
Is there any reason for the error above?
This is a bash script on RHEL.
function testr{
df -H | grep -vE '^Filesystem|tmpfs|cdrom' | awk '{ print $5 " " $1 }' | while read output;
do
usep=$(echo $output | awk '{ print $1}' | cut -d'%' -f1)
partition=$(echo $output | awk '{ print $2 }')
(.. Sends alert via mail after)
done
}
Maybe a little easier to read this way?
testr_zsh () {
# This (only) works with zsh.
for usep partition in $( df -H | awk 'NR>1 && !/tmpfs|cdrom/{print $5,$1}' | sed -n '/%/s/%//p' )
do
echo "\$usep: $usep, \$partition: $partition"
done
}
testr () {
for fs in $( df -H | awk 'NR>1 && !/tmpfs|cdrom/{print $5"|"$1}' | sed -n '/%/s/%//p' )
do
usep="$(echo "${fs}" | sed 's/|.*//' )"
partition="$(echo "${fs}" | sed 's/.*|//' )"
echo "\$usep: $usep, \$partition: $partition"
done
}
On my computer not all lines that pass through the awk filter have % in them hence adding the sed filter. zsh allows two vars in the for loop which is pretty slick.
I want to get the size of the directory's content. If I use the command line I can get like this:
ls -l | head -n 1 | awk '{ print $2 }'
So the output is the size of the directory's content:
16816
But I want to do this in a bash script:
x="ls -l DBw | head -n 1 | awk '{ print $2 }'"
while sleep 1; do
y=$(eval "$x");
echo $y
done
But the output of this script is the full line:
Total 16816
Why is this happening and how can I get just the second word?
x="ls -l DBw | head -n 1 | awk '{ print $2 }'"
It's happening because $2 is inside double quotes and so it's interpreted immediately. You could escape it with \$2, but better yet:
Don't store code in variables. Use a function.
x() {
ls -l DBw | head -n 1 | awk '{ print $2 }'
}
Then you can call x many times.
while sleep 1; do
x
done
That said, it's better not to parse the output of ls in the first place. Use du to compute the size of a directory:
$ du -sh /dir
1.3M /dir
$ du -sh /dir | cut -f1
1.3M
I am trying to redirect the output of the following command to a variable $bei
awk '/Total number of/ && /multidriven/' ../reports/synthesis /hdl.check_design.rpt | grep -o '[0-9]' | awk '{s+=$1} END {print s}'
this command is working correctly if execute directly, and I am trying to redirect it into a variable to be used later.
I've tried 2 ways to do it:
bei= `awk '/Total number of/ && /multidriven/' ../reports/synthesis/hdl.check_design.rpt | grep -o '[0-9]' | awk '{s+=$1} END {print s}'`
bei= $(awk '/Total number of/ && /multidriven/' ../reports/synthesis/hdl.check_design.rpt | grep -o '[0-9]' | awk '{s+=$1} END {print s}')
But they both don't work and I receive "command not found" error. Does anyone have any idea about this and could you please help me? Thanks a lot
Reason for failure seem to be extra space between bei and $(awk.....) .
Example :
sh-4.1$ x =$(date) #With space
sh: x: command not found
sh-4.1$ x=$(date) #Without space
sh-4.1$ echo $x
Thu Sep 8 06:41:07 EDT 2016
sh-4.1$
I've been trying to get this function to work. I'm on a 17" MacBook Pro Early 2011. Setting all the variables under "else" work great if you run them separately, they also echo properly. For some reason when I put them in the function… I get a syntax error on line 12 and
battery ()
{
BATTERYISPRESENT=`ioreg -l | grep Cycle`
if [[ $BATTERYISPRESENT != *'Cycle' ]]
then
echo "No Battery Present, Probably a desktop Mac."
else
BATTERYCYCLES=`system_profiler SPPowerDataType | grep "Cycle Count" | awk '{print $3}'`
BATTCURRCAP=`pmset -g batt | sed -n '2 p' | awk '{ print $2 }' | sed 's/;//g'`
BATTERYCHARGESTATUS=`system_profiler SPPowerDataType | grep "Charging" | awk '{ print $2 }'`
BATTERYISCHARGING=`system_profiler SPPowerDataType | grep -A 4 "AC Charger Information" | grep "Connected: " | awk '{ print $2 }'`
CHARGERISCONNECTED=`system_profiler SPPowerDataType | grep -A 4 "AC Charger Information" | grep "Connected: " | awk '{ print $2 }'`
echo $BATTERYCYCLES
echo $BATTCURRCAP
echo $BATTERYISCHARGING
echo $CHARGERISCONNECTED
}
The output reads:
line 12: unexpected EOF while looking for matching ``'
line 18: syntax error: unexpected end of file
Any assistance would be greatly appreciated.
A fi upon you — you're missing the fi at the end of the else.
I have a script in bash what take from LocLog a ip from collumn 8 :
#!/bin/bash
for i in $(cat /scripts/logs/LocLog | awk '{print $8}' | sort | uniq);
do
php /scripts/a.php $i;
done
The script give an error:
bash -x log
'og: line 2: syntax error near unexpected token `
'og: line 2: `for i in $(cat /scripts/logs/LocLog | awk '{print $8}' | sort | uniq);
Any ideeas?
Get rid of the semicolon at the end of the for line.