I'm facing an issue loading a file with sql loader.
This is what my input file looks like:
#ID; CARD_NUMBER;USERNAME
1;86730975,86536522,86793501;JOHN SMITH
2;89734562;MICHAEL ABOT
3;87903546,87265390;JAMES ALBERT
And what I want to acheive after loading is this:
#Table data
1;86730975;JOHN SMITH
1;86536522;JOHN SMITH
1;86793501;JOHN SMITH
2;89734562;MICHAEL ABOT
3;87903546;JAMES ALBERT
3;87265390;JAMES ALBERT
I did something like this before using Sql Loader, but I can't find the source code. So if someone can help that'll be very nice for me.
I'm new to this forum and I don't know how to find all the posts related to my username, I'll appreciate if someone can help on that to.
You can go with external tables. To me personally it'll be a more convenient way to get it done:
Create a directory in Oracle that points to the exact location of the file on the server.
SQL> create or replace directory ff1 as 'c:\';
directory created
Create external table similar to this one:
SQL> create table t1(
2 t1_id number,
3 card_no varchar2(4000),
4 user_name varchar2(4000)
5 )
6 organization external(
7 type oracle_loader
8 default directory ff1
9 access parameters(
10 records delimited by newline
11 fields terminated by ';'
12 )
13 location('input.dat') --<-- file name
14 ) reject limit unlimited
15 ;
Table created.
After that, you can query that external table, and use any (there are many of them) method to split comma separated string. In this case it would be values of card_number. For example:
This is the actual data:
SQL> column card_no format a40;
SQL> column user_name format a17;
SQL> select * from t1;
T1_ID CARD_NO USER_NAME
---------- ---------------------------------------- -----------------
1 86730975,86536522,86793501 JOHN SMITH
2 89734562 MICHAEL ABOT
3 87903546,87265390 JAMES ALBERT
3 rows selected.
Transformed version of actual data:
SQL> column card_no format 9999999999;
SQL> with ocrs(ocr) as(
2 select level
3 from ( select max(regexp_count(card_no, '[^,]+')) as mx
4 from t1 ) s
5 connect by level <= s.mx
6 )
7 select *
8 from (select t.t1_id
9 , to_number(regexp_substr(t.card_no, '[^,]+',
10 1, o.ocr)) as card_no
11 , t.user_name
12 from t1 t
13 cross join ocrs o ) w
14 where w.card_no is not null
15 order by w.t1_id;
Result:
T1_ID CARD_NO USER_NAME
----------- ----------- -----------------
1 86730975 JOHN SMITH
1 86793501 JOHN SMITH
1 86536522 JOHN SMITH
2 89734562 MICHAEL ABOT
3 87265390 JAMES ALBERT
3 87903546 JAMES ALBERT
6 rows selected.
Having done that, you can use simple insert statement combined with the above query to insert new, transformed data into another table.
insert into another_table(id, card_number, user_name)
with ocrs(ocr) as(
select level
.....
/* the above query */
Related
I have a column "Names" in the "Employee" table that has following values. The values either contain only single name (first, last, username) or Multiple names separated with semicolon (;). I need to search the values from that table either by first name or last name or username.
I have created a procedure but it is fetching only 1st,4th,5th records. Please let me know how to retrieve 2nd and 3rd records as well.
Firstname and lastname can be given by user with minimum of 2 characters length.
Username is given entire.
Employee:
ID Name Title
1 Andrea Warbutton (awr01) Manager
2 Claire Taylor (cta02);Mark Kites (mak03);Anitha Rooney (anr06) HOD;Supervisor;Business
3 Dave Rites (dar12);Jessica Simpson (jesi10) Lead;Analyst
4 Nick Ken (nik56) Product (Local,Regional)
5 Claire Pilkington (cpt09) Sales Owner
Code:
Create or replace empl (pm_firstname varchar2(100),
pm_lastname varchar2(100),
pm_username varchar2(100))
BEGIN
Select * from Employee
where Upper(Name) like Upper(pm_firstname ||'%'||) -- this will fetch 1st,4th,5th record
OR Upper(SUBSTR(Name, INSTR(Name),' '+1)) like Upper(pm_lastname ||'%'||) -- this will fetch 1st,4th,5th record
OR upper(REGEXP_SUBSTR(Name,'\((.+)\)',1,1,NULL,1)) = Upper(pm_username); -- -- this will fetch 1st,4th,5th record
END;
End empl ;
Please let me know how to retrieve 2nd and 3rd records as well.
Desired Output:
When searched with firstname = "Andrea", the output is below
ID Name Title
1 Andrea Warbutton (awr01) Manager
When searched with firstname = "Claire", the output is below
ID Name Title
2 Claire Taylor (cta02) HOD
5 Claire Pilkington (cpt09) Sales Owner
When searched with lastname = "Simps", the output is below
ID Name Title
3 Jessica Simpson (jesi10) Analyst
When searched with username = "mak03", the output is below
ID Name Title
2 Mark Kites (mak03) Supervisor
When searched with username = "nik56", the output is below
ID Name Title
4 Nick Ken (nik56) Product (Local,Regional)
with
x as (select id, name, '"'||replace(name, ';', '","')||'"' xml from employee),
n as (select id, name, column_value as cv from x, xmltable(xml))
select id,
trim(regexp_substr(cv, '(\S*)(\s)')) fname,
trim(regexp_substr(cv, '(\S*)(\s)', 1, 2)) lname,
regexp_substr(cv, '\((.+)\)', 1, 1, NULL, 1) uname
from n
Your task would be much easier if you normalize these data. Above query outputs:
ID FNAME LNAME UNAME
1 Andrea Warbutton awr01
2 Claire Taylor cta02
2 Mark Kites mak03
2 Anitha Rooney anr06
3 Dave Rites dar12
3 Jessica Simpson jesi10
4 Nick Ken nik56
5 Claire Pilkington cpt09
demo
Now you can search first, last, usernames however you want. First expression finds first word, then second and word between brackets.
Edit:
I posted the table structure with just ID and Name columns. However, I
have Titles column also in the same format separated with (semicolon).
In this case, How can I Normalize Titles as well along with Names
This query worked for provided examples:
with
x as (select id, name, '"'||replace(name, ';', '","')||'"' xmln,
'"'||replace(title, ';', '","')||'"' xmlt
from employee),
n1 as (select id, trim(xn.column_value) nm, rownum rn from x, xmltable(xmln) xn),
n2 as (select id, trim(xt.column_value) tt, rownum rn from x, xmltable(xmlt) xt)
select id, trim(regexp_substr(nm, '(\S*)(\s)')) fname,
trim(regexp_substr(nm, '(\S*)(\s)', 1, 2)) lname,
regexp_substr(nm, '\((.+)\)', 1, 1, NULL, 1) uname,
tt title
from n1 join n2 using (id, rn)
dbfiddle demo
Be careful however, because we cannot write ideal query. If you have entries like Benicio Del Toro, Mary Jo Catlett, Jean Claude Van Damme, it's impossible to write correct regexp. Sometimes second word is part of lastname, sometimes it is firstname, middlename etc.
The proper way is to modify table structure, divide rows, check results and put correct values in correct name columns. Now you have lists which are hard to search and every method may return wrong results.
No need for PL/SQL.
SQL> with temp as
2 (select id,
3 regexp_substr(name, '[^;]+', 1, column_value) name
4 from employee cross join
5 table(cast(multiset(select level from dual
6 connect by level <= regexp_count(name, ';') + 1
7 ) as sys.odcinumberlist))
8 )
9 select id, name
10 from temp
11 where instr(name, '&search_for_name') > 0;
Enter value for search_for_name: Claire
ID NAME
---------- ------------------------------
2 Claire Taylor (cta02)
5 Claire Pilkington (cpt09)
SQL> /
Enter value for search_for_name: mak03
ID NAME
---------- ------------------------------
2 Mark Kites (mak03)
SQL>
What does it do?
temp CTE splits semi-colon separated values into rows
final query uses a simple instr function which detects whether "rows" (extracted previously) contain value you're looking for
If it must be a function, that code can be reused. As you didn't say what exactly (which datatype, I mean) you want to return, I returned a string.
SQL> create or replace function f_search (par_what in varchar2)
2 return sys.odcivarchar2list
3 is
4 retval sys.odcivarchar2list;
5 begin
6 with temp as
7 (select id,
8 regexp_substr(name, '[^;]+', 1, column_value) name
9 from employee cross join
10 table(cast(multiset(select level from dual
11 connect by level <= regexp_count(name, ';') + 1
12 ) as sys.odcinumberlist))
13 )
14 select id ||' - '|| name
15 bulk collect into retval
16 from temp
17 where instr(name, par_what) > 0;
18
19 return retval;
20 end;
21 /
Function created.
SQL> select * from table(f_search('Andrea'));
COLUMN_VALUE
--------------------------------------------------------------------------------
1 - Andrea Warbutton (awr01)
SQL> select * from table(f_search('Claire'));
COLUMN_VALUE
--------------------------------------------------------------------------------
2 - Claire Taylor (cta02)
5 - Claire Pilkington (cpt09)
SQL>
I have afile where i recieve Birthdates and insert them into my Database.
the format is like the following
03-JUN-52
I use the following script to insert the date
update data."PersonBDates" set BIRTHDATE = to_date('13-SEP-47', 'DD-MON-YY');
and i also used
update data."PersonBDates" set BIRTHDATE = to_date('13-SEP-47', 'DD-MON-RR');
but when i check if find it 2074 not 1947.
How to insert this date into my oracle database?
Generally speaking, RR should work, but - not in all cases. You'll have to fix data first because RR will return different values:
for years from 00 to 49 you'll get this century, 20xx, while
50 to 99 will return previous century, 19xx
Here's an example:
SQL> alter session set nls_date_format = 'dd.mm.yyyy';
Session altered.
SQL> select
2 to_date('03-07-52', 'dd-mm-rr') rr1,
3 to_date('03-07-52', 'dd-mm-yy') yy1 ,
4 --
5 to_date('03-07-47', 'dd-mm-rr') rr2,
6 to_date('03-07-47', 'dd-mm-yy') yy2
7 from dual;
RR1 YY1 RR2 YY2
---------- ---------- ---------- ----------
03.07.1952 03.07.2052 03.07.2047 03.07.2047
SQL>
As you can see, both RR and YY format mask for year 47 return 2047.
What to do? Concatenate 19 to all years, e.g.
SQL> with test (col) as
2 (select '03-07-52' from dual union all
3 select '03-07-47' from dual
4 )
5 select col,
6 to_date(substr(col, 1, 6) || '19' || substr(col, -2), 'dd-mm-rrrr') result
7 ---------------- ---------------
8 -- this is "03-07-" "19" the last 2 digits
9 --
10 from test;
COL RESULT
-------- ----------
03-07-52 03.07.1952
03-07-47 03.07.1947
SQL>
[EDIT]
If your current inserting script works OK - which I doubt, regarding error code you mentioned in a comment:
ORA-01858: a non-numeric character was found where a numeric was expected
which means that not all input data have the same, expected & correct format of DD-MON-YY, then a simple way to fix birthdates might be this:
subtract 100 years from all dates whose year is larger than 2000
Here's how:
SQL> create table test (birthdate date);
Table created.
SQL> insert into test
2 select to_date('03-07-52', 'dd-mm-rr') from dual union all
3 select to_date('03-07-47', 'dd-mm-rr') from dual;
2 rows created.
SQL> select * from test;
BIRTHDATE
----------
03.07.1952
03.07.2047
SQL> update test set
2 birthdate = add_months(birthdate, -100 * 12)
3 where extract (year from birthdate) > 2000;
1 row updated.
SQL> select * from test;
BIRTHDATE
----------
03.07.1952
03.07.1947
SQL>
You can modify that, of course, if there's someone who actually was born in 2000 or later.
As of error you got (ORA-01858), well, fixing it depends on how exactly you're entering those values into a table.
if it was a SQL*Loader, invalid values would be rejected and stored into the .bad file and you could fix them and reprocess them later
if it was using an external tables, you could use a where clause and omit invalid rows; for example, use regexp_like
Or, your best option is to make sure that all input values are valid dates. Then any option you choose (I mentioned previously) would work without ORA-xxxxx errors.
Alternate way of concatenating 19 to all years, as Littlefoot suggested.
to_date(regexp_replace('13-SEP-47', '([0-9]+$)', '19\1'), 'DD-MON-YYYY')
I would suggest to implement the solution where 01 is not considered as 1901 but 2001 or something similar (I assume that birthday year is not 1901 for any person in your system).
Case when substr(col, -2) < to_char(sysdate,'YY')
then to_date(col, 'DD-MON-YY')
else to_date(substr(col, 1, 6) || '19' || substr(col, -2), 'dd-mm-rrrr'
End
Cheers!!
The situation is that, when I import a file into the database, one of the first thing I usually do is to assign an unique ID for each record.
I normally do below in TSQL
ALTER TABLE MyTable
ADD ID INT IDENTITY(1,1)
I am wondering if there is something similar in PL SQL?
All my search result come back with multiple steps.
Then I'd like to know what PL SQL programmer typically do to ID records after importing a file. Do they do that?
The main purpose for me to ID these records is to trace it back after manipulation/copying.
Again, I understand there is solution there, my further question is whether PL SQL programmer actually do that, or there is other alternative which making this step not necessary in PL SQL?
OK then, as you're on Oracle 11g, there's no identity column there so - back to multiple steps. Here's an example:
I'm creating a table that simulates your imported table:
SQL> create table tab_import as
2 select ename, job, sal
3 from emp
4 where deptno = 10;
Table created.
Add the ID column:
SQL> alter table tab_import add id number;
Table altered.
Create a sequence which will be used to populate the ID column:
SQL> create sequence seq_imp;
Sequence created.
Update current rows:
SQL> update tab_import set
2 id = seq_imp.nextval;
3 rows updated.
Create a trigger which will take care about future inserts (if any):
SQL> create or replace trigger trg_bi_imp
2 before insert on tab_import
3 for each row
4 begin
5 :new.id := seq_imp.nextval;
6 end;
7 /
Trigger created.
Check what's in the table at the moment:
SQL> select * from tab_import;
ENAME JOB SAL ID
---------- --------- ---------- ----------
CLARK MANAGER 2450 1
KING PRESIDENT 5000 2
MILLER CLERK 1300 3
Let's import some more rows:
SQL> insert into tab_import (ename, job, sal)
2 select ename, job, sal
3 from emp
4 where deptno = 20;
3 rows created.
The trigger had silently populated the ID column:
SQL> select * From tab_import;
ENAME JOB SAL ID
---------- --------- ---------- ----------
CLARK MANAGER 2450 1
KING PRESIDENT 5000 2
MILLER CLERK 1300 3
SMITH CLERK 800 4
JONES MANAGER 2975 5
FORD ANALYST 3000 6
6 rows selected.
SQL>
Shortly: you need to
alter table and add the ID column
create a sequence
create a trigger
The end.
The answer given by #Littlefoot would be my recommendation too - but still I thought I could mention the following variant which will work only if you do not intend to add more rows to the table later.
ALTER TABLE MyTable add id number(38,0);
update MyTable set id = rownum;
commit;
My test:
SQL> create table tst as select * from all_tables;
Table created.
SQL> alter table tst add id number(38,0);
Table altered.
SQL> update tst set id = rownum;
3815 rows updated.
SQL> alter table tst add constraint tstPk primary key (id);
Table altered.
SQL>
SQL> select id from tst where id < 15;
ID
----------
1
2
3
4
5
6
7
8
9
10
11
ID
----------
12
13
14
14 rows selected.
But as mentioned initially,- this only fixes numbering for the rows you have at the time of the update - your'e not going to get new id values for new rows anytime later - if you need that, go for the sequence solution.
You can add an id column to a table with a single statement (Oracle 11g, see dbfiddle):
alter table test_
add id raw( 16 ) default sys_guid() ;
Example:
-- create a table without an id column
create table test_ ( str )
as
select dbms_random.string( 'x', 16 )
from dual
connect by level <= 10 ;
select * from test_ ;
STR
ULWL9EXFG6CIO72Z
QOM0W1R9IJ2ZD3DW
YQWAP4HZNQ57C2UH
EETF2AXD4ZKNIBBF
W9SECJYDER793MQW
alter table test_
add id raw( 16 ) default sys_guid() ;
select * from test_ ;
STR ID
ULWL9EXFG6CIO72Z 0x782C6EBCAE2D7B9FE050A00A02005D65
QOM0W1R9IJ2ZD3DW 0x782C6EBCAE2E7B9FE050A00A02005D65
YQWAP4HZNQ57C2UH 0x782C6EBCAE2F7B9FE050A00A02005D65
EETF2AXD4ZKNIBBF 0x782C6EBCAE307B9FE050A00A02005D65
W9SECJYDER793MQW 0x782C6EBCAE317B9FE050A00A02005D65
Testing
-- Are the id values unique and not null? Yes.
alter table test_
add constraint pkey_test_ primary key ( id ) ;
-- When we insert more rows, will the id be generated? Yes.
begin
for i in 1 .. 100
loop
insert into test_ (str) values ( 'str' || to_char( i ) ) ;
end loop ;
end ;
/
select * from test_ order by id desc ;
-- last 10 rows of the result
STR ID
str100 0x782C806E16A5E998E050A00A02005D81
str99 0x782C806E16A4E998E050A00A02005D81
str98 0x782C806E16A3E998E050A00A02005D81
str97 0x782C806E16A2E998E050A00A02005D81
str96 0x782C806E16A1E998E050A00A02005D81
str95 0x782C806E16A0E998E050A00A02005D81
str94 0x782C806E169FE998E050A00A02005D81
str93 0x782C806E169EE998E050A00A02005D81
str92 0x782C806E169DE998E050A00A02005D81
str91 0x782C806E169CE998E050A00A02005D81
Regarding your other questions:
{1} Then I'd like to know what PL SQL programmer typically do to ID records after importing a file. Do they do that? The main purpose for me to ID these records is to trace it back after manipulation/copying.
-> As you know, the purpose of an id is: to identify a row. We don't "do anything to IDs". Thus, your usage of IDs seems legit.
{2} Again, I understand there is solution there, my further question is whether PL SQL programmer actually do that, or there is other alternative which making this step not necessary in PL SQL?
-> Not quite sure what you are asking here. Although there is a ROWID() pseudocolumn (see documentation), we should not use it to identify rows.
"You should not use ROWID as the primary key of a table. If you delete
and reinsert a row with the Import and Export utilities, for example,
then its rowid may change. If you delete a row, then Oracle may
reassign its rowid to a new row inserted later."
I am very new to Oracle; I have written two stored procedures where they have both different parameters. I would like to combine the queries in that two stored procedures into single query in a single stored procedure, and make sure it supports any criteria.
These are the stored procedures:
procedure usp_testsp1(RC1 OUT RCT1,
in_dep_Id IN number,
in_Org_id IN number,
in_emp_no IN number)
is
begin
select emp.Name as name,select emp.phone as phone,select emp.Race as
race
from employee emp
JOIN
Project prj ON
emp.ProjectId=prj.ProjectId
JOIN Project_Org Prorg
ON prj.ProjectId=Prorg.ProjectId
JOIN Organization Org1
ON Prorg.OrgId=Org1.OrgId
JOIN Organization Org2
ON emp.OrgId=Org2.OrgId
AND Org2.OrgType=0
WHERE (upper(emp.emp_No) in (in_emp_No ))
AND Prorg.OrgId=in_Org_id
AND Org2.OrgId=in_dep_Id
end;
procedure usp_testsp2(RC1 OUT RCT1,
in_dep_Id IN number,
in_Org_id IN number,
in_vendor_id IN raw,
in_vendor_startdate IN date,
in_vendor_enddate IN date)
is
begin
OPEN RC1 FOR
select emp.Name as name,select emp.phone as phone,select emp.Race as
race
from
from employee emp
JOIN
Project prj ON
emp.ProjectId=prj.ProjectId
JOIN Project_Org Prorg
ON prj.ProjectId=Prorg.ProjectId
JOIN Organization Org1
ON Prorg.OrgId=Org1.OrgId
JOIN Organization Org2
ON emp.OrgId=Org2.OrgId
AND Org2.OrgType=0
INNER JOIN vendor_Emp
ON emp.employeeid=vendor_emp.employeeid
INNER JOIN Vendor
ON Vendor.VendorId=Vendor_emp.VendorId
WHERE Prorg.OrgId=in_Org_id
AND Org2.OrgId=in_dep_Id
AND Vendor.VendorId=in_vendor_id
AND vendor.StartDate=in_vendor_startdate AND Vendor.EndDate=in_vendor_enddate
end;
My objective is to combine the queries within these two separate procedures into a single query such that if I combine all the parameters, I have in_emp_no, in_vendor_id, in_vendor_startdate, in_vendor_enddate apart from the common parameters any of the parameters can be null and I want to make sure that those things won't affect the rest of the query even though its not null
For ex i have only in_emp_no ='xxxx' and common inputs rest of the params like
in_vendor_id etc is null.
I would like to make my query to work even with single paramter to filter the result set
NOTEWithout using Dynamic SQL
Thanks
BJ
You can make columns in the query behave as optional, as far as your join's go, you may need to play with various combinations to make sure everything works.
Sample Table
create table sqltest (
empid number,
name varchar2(10),
orgid number,
depid number,
vendorid number);
insert into sqltest values(1,'BoB',1,1,21);
insert into sqltest values(2,'Chuck',1,1,21);
insert into sqltest values(3,'Mary',1,2,21);
insert into sqltest values(4,'Jane',1,2,22);
insert into sqltest values(5,'Rick',2,1,22);
insert into sqltest values(6,'Samir',2,6,23);
insert into sqltest values(7,'Kirk',3,6,23);
insert into sqltest values(8,'Alex',3,9,23);
commit;
Sample Proc
create or replace procedure calltest (
rc1 out SYS_REFCURSOR,
pempid number,
porgid number,
pdepid number,
pvendorid number)
is
begin
open rc1 for
select * from sqltest
where
(pempid IS NULL OR empid = pempid) and
(porgid IS NULL OR orgid = porgid) and
(pdepid IS NULL OR depid = pdepid) and
(pvendorid IS NULL OR vendorid = pvendorid);
end;
Sample Call
set autoprint on;
var vcur refcursor;
declare
begin
calltest(rc1=>:vcur,pempid=>NULL,porgid=>1,pdepid=>NULL,pvendorid=>NULL);
--calltest(rc1=>:vcur,pempid=>NULL,porgid=>1,pdepid=>2,pvendorid=>NULL);
--calltest(rc1=>:vcur,pempid=>NULL,porgid=>1,pdepid=>2,pvendorid=>22);
--calltest(rc1=>:vcur,pempid=>NULL,porgid=>NULL,pdepid=>NULL,pvendorid=>23);
end;
Sample Output 1
VCUR
------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
EMPID NAME ORGID DEPID VENDORID
--------------------------------------- ---------- --------------------------------------- --------------------------------------- ---------------------------------------
1 BoB 1 1 21
2 Chuck 1 1 21
3 Mary 1 2 21
4 Jane 1 2 22
Sample Output 2
VCUR
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
EMPID NAME ORGID DEPID VENDORID
--------------------------------------- ---------- --------------------------------------- --------------------------------------- ---------------------------------------
3 Mary 1 2 21
4 Jane 1 2 22
Sample Output 3
VCUR
------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
EMPID NAME ORGID DEPID VENDORID
--------------------------------------- ---------- --------------------------------------- --------------------------------------- ---------------------------------------
4 Jane 1 2 22
Sample Output 4
VCUR
--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
EMPID NAME ORGID DEPID VENDORID
--------------------------------------- ---------- --------------------------------------- --------------------------------------- ---------------------------------------
6 Samir 2 6 23
7 Kirk 3 6 23
8 Alex 3 9 23
This question already has answers here:
Update rows in one table with data from another table based on one column in each being equal
(5 answers)
Closed 9 years ago.
i have table called Student with columns uniquename, age,department,city,Homecountry and another table called Employee with columns uniquename, exp,qualification, Homecountry.
now i want to update Student table's department column with Employee table's qualification column values under the where condition Student.uniquename = Employee.uniquename and Student.Homecountry = Employee.Homecountry.
please help me to write the update statement.
This kind of query is called a correlated sub query. For your requirement, the query would be as below....
update students s
set s.department = (
select e.qualification
from employee e
where s.uniquename = e.uniquename
and s.Homecountry = e.Homecountry
);
updating this post based on your replies below.
Again, going forward, always post the create table and insert statements (and the expected results) to reproduce your case. If you don't see the expected results or if you see an erro when you execute the query, post the exact message instead of just saying "not working". Here is the results of my sqlplus session.
---create table and insert statements
create table student(
name varchar2(20),
age number,
department varchar2(3),
HomeCountry varchar2(10)
);
Table created.
create table employee5(
name varchar2(20),
exp number,
qualification varchar2(3),
homecountry varchar2(10)
);
Table created.
insert into student values ('Mohan',25,'EEE','India');
insert into student values ('Raja',27,'EEE','India');
insert into student values ('Ahamed',26,'ECE','UK');
insert into student values ('Gokul',25,'IT','USA');
commit;
insert into employee5 values ('Mohan',25,'ECE','India');
insert into employee5 values ('Raja',24,'IT','India');
insert into employee5 values ('Palani',26,'ECE','USA');
insert into employee5 values ('Sathesh',29,'CSE','CANADA');
insert into employee5 values ('Ahamed',28,'ECE','UK');
insert into employee5 values ('Gokul',29,'EEE','USA');
commit;
Before updating the data...
SQL> select * from student;
NAME AGE DEP HOMECOUNTR
-------------------- ---------- --- ----------
Mohan 25 EEE India
Raja 27 EEE India
Ahamed 26 ECE UK
Gokul 25 IT USA
SQL> select * from employee5;
NAME EXP QUA HOMECOUNTR
-------------------- ---------- --- ----------
Mohan 25 ECE India
Raja 24 IT India
Palani 26 ECE USA
Sathesh 29 CSE CANADA
Ahamed 28 ECE UK
Gokul 29 EEE USA
Update statement and results
1 update student s set s.age =
2 ( select e.exp
3 from employee5 e
4 where e.name = s.name
5 and e.homecountry = s.homecountry
6* )
SQL> /
4 rows updated.
SQL> select * from student;
NAME AGE DEP HOMECOUNTR
-------------------- ---------- --- ----------
Mohan 25 EEE India
Raja 24 EEE India
Ahamed 28 ECE UK
Gokul 29 IT USA
SQL> commit;
Commit complete.
update student s
set s.age = (select e.exp
from employee5 e
where e.name = s.name
and e.homecountry = s.homecountry
and rownum < 2
)
where s.age in (select age from employee5)
It wont show the message subquery returns more than one record