select distinct employee_id, first_name, commission_pct, department_id from
employees;
When I use the above query it results in distinct combination of all the attributes mentioned. As employee_id (being the primary key for employees) is unique, the query results in producing all the rows in the table.
I want to have a result set that has distinct combination of commission_pct and department_id. so how the query should be formed. When I tried to include the DISTINCT in the middle as
select employee_id, first_name, distinct commission_pct, department_id from
employees;
It is resulting in an error
ORA-00936-missing expression
How to form a query which results have only distinct combination of commission and department_id.The table is from HR schema of oracle.
What you request is impossible. You cannot select all the employee ids but have only distinct commission_pct and department_id.
So think it over, what you want to show:
All distinct commission_pct, department_id only?
All distinct commission_pct, department_id and the number of relevant employees?
All distinct commission_pct, department_id and the relevant employees comma separated?
All employees, but with nulls when commission_pct and department_id are the same as in the line before?
The first can be solved with DISTINCT. The second and third with GROUP BY (plus count or listagg). The last would be solved with the analytic function LAG.
You have to remove two columns before distinct
select distinct commission_pct, department_id from
employees;
Indeed, if your second query would work, what do you expect to see in the first two columns? Consider example data
| employee_id | first_name | commission_pct | department_id |
| 1 | "x" | "b" | 3 |
| 2 | "y" | "b" | 3 |
| 1 | "x" | "c" | 4 |
| 2 | "y" | "c" | 4 |
You expect to get only two row result like this
| employee_id | first_name | commission_pct | department_id |
| ? | ? | "b" | 3 |
| ? | ? | "c" | 4 |
But what do you expect in the first two column?
Can you try this one?
SELECT
NAME1,
PH
FROM
(WITH T
AS (SELECT
'mark' NAME1,
'1234567' PH
FROM
DUAL
UNION ALL
SELECT
'bailey',
'456789'
FROM
DUAL
UNION ALL
SELECT
'mark',
'987654'
FROM
DUAL)
SELECT
NAME1,
PH,
ROW_NUMBER ( ) OVER (PARTITION BY NAME1 ORDER BY NAME1) SEQ
FROM
T)
WHERE
SEQ = 1;
If you dont care on a specific row, then use aggregate functions
SELECT
NAME1,
MAX ( PH ) PH
FROM
T
GROUP BY
NAME1;
Related
I have a requirement in Oracle SQL that specific values should be repeated 5 times. So, I have written the below query and getting the result as expected.
SELECT Item_Name || RANGES AS Item_Number
FROM
(
SELECT DISTINCT 'Price Line ' || column1 || '-' AS Item_Name, level+0 RANGES
FROM
(
SELECT DISTINCT column1 from tbl where column1 in
(
'ABC',
'BCD'
)
) connect by level <= 5
) order by Item_Number
OUTPUT:
Price Line ABC-1
Price Line ABC-2
Price Line ABC-3
Price Line ABC-4
Price Line ABC-5
Price Line BCD-1
Price Line BCD-2
Price Line BCD-3
Price Line BCD-4
Price Line BCD-5
But when I add more than 10 values like 'DEF', 'EFG',.....'XYZ', the query keeps executing for hours without any result.
Any help or suggestion on this would be appreciated.
Regards,
Make sure the CONNECT BY is not operating on your table rows. For example, use a common table expression (i.e., a WITH clause) to create a row source with 5 rows using CONNECT BY and then CROSS JOIN that row source to your table. Here is an example.
CREATE TABLE ITEMS ( item_number VARCHAR2(30) );
INSERT INTO ITEMS VALUES ('ABC');
INSERT INTO ITEMS VALUES ('BCD');
INSERT INTO ITEMS VALUES ('CDE');
INSERT INTO ITEMS VALUES ('DEF');
INSERT INTO ITEMS VALUES ('EFG');
INSERT INTO ITEMS VALUES ('FGH');
INSERT INTO ITEMS VALUES ('GHI');
INSERT INTO ITEMS VALUES ('HIJ');
INSERT INTO ITEMS VALUES ('IJK');
INSERT INTO ITEMS VALUES ('JKL');
COMMIT;
WITH rowgen AS (
SELECT rownum rn FROM dual CONNECT BY rownum <= 5 )
SELECT item_number || '-' || rn
FROM items
CROSS JOIN rowgen
ORDER BY item_number, rn;
+----------------------+
| ITEM_NUMBER||'-'||RN |
+----------------------+
| ABC-1 |
| ABC-2 |
| ABC-3 |
| ABC-4 |
| ABC-5 |
| BCD-1 |
| BCD-2 |
| BCD-3 |
| BCD-4 |
| BCD-5 |
| CDE-1 |
| CDE-2 |
| CDE-3 |
| CDE-4 |
| CDE-5 |
| ... |
+----------------------+
I have an 'ITEMS' table like below:
ITEM_NO ITEM_NAME
1 Book
2 Pen
3 Sticky Notes
4 Ink
5 Corrector
6 Ruler
In another 'EMP_ITEMS' table I have the below:
EMPLOYEE ITEMS_LIST
John 1,2
Mikel 5
Sophia 2,3,6
William 3,4
Daniel null
Michael 6
The output has to be like this:
EMPLOYEE ITEMS_LIST ITEM_NAME
John 1,2 Book,Pen
Mikel 5 Corrector
Sophia 2,3,6 Pen,Sticky Notes,Ruler
William 3,4 Sticky Notes,Ink
Daniel null null
Michael 6 Ruler
I used the below query:
SELECT e.EMPLOYEE,e.ITEMS_LIST, LISTAGG(i.ITEM_NAME, ',') WITHIN GROUP (ORDER BY i.ITEM_NAME) ITEM_DESC
FROM EMP_ITEMS e
INNER JOIN ITEMS i ON i.ITEM_NO = e.ITEMS_LIST
GROUP BY e.EMPLOYEE,e.ITEMS_LIST;
But there is an error:
ORA-01722: invalid number
But there is an error: ORA-01722: invalid number
That is because your ITEMS_LIST is a string composed of numeric and comma characters and is not actually a list of numbers and you are trying to compare a single item number to a list of items.
Instead treat it as a string a look for sub-string matches. To do this you will need to surround the strings in the delimiter character and compare to see if one is the substring of the other:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE Items ( ITEM_NO, ITEM_NAME ) As
SELECT 1, 'Book' FROM DUAL UNION ALL
SELECT 2, 'Pen' FROM DUAL UNION ALL
SELECT 3, 'Sticky Notes' FROM DUAL UNION ALL
SELECT 4, 'Ink' FROM DUAL UNION ALL
SELECT 5, 'Corrector' FROM DUAL UNION ALL
SELECT 6, 'Ruler' FROM DUAL;
CREATE TABLE emp_items ( EMPLOYEE, ITEMS_LIST ) AS
SELECT 'John', '1,2' FROM DUAL UNION ALL
SELECT 'Mikel', '5' FROM DUAL UNION ALL
SELECT 'Sophia', '3,2,6' FROM DUAL UNION ALL
SELECT 'William', '3,4' FROM DUAL UNION ALL
SELECT 'Daniel', null FROM DUAL UNION ALL
SELECT 'Michael', '6' FROM DUAL;
Query 1:
SELECT e.employee,
e.items_list,
LISTAGG( i.item_name, ',' )
WITHIN GROUP (
ORDER BY INSTR( ','||e.items_list||',', ','||i.item_no||',' )
) AS item_names
FROM emp_items e
LEFT OUTER JOIN
items i
ON ( ','||e.items_list||',' LIKE '%,'||i.item_no||',%' )
GROUP BY e.employee, e.items_list
Results:
| EMPLOYEE | ITEMS_LIST | ITEM_NAMES |
|----------|------------|------------------------|
| John | 1,2 | Book,Pen |
| Mikel | 5 | Corrector |
| Daniel | (null) | (null) |
| Sophia | 3,2,6 | Sticky Notes,Pen,Ruler |
| Michael | 6 | Ruler |
| William | 3,4 | Sticky Notes,Ink |
There is a column in table 'mytable' named 'Description'.
+----+-------------------------------+
| ID | Description |
+----+-------------------------------+
| 1 | My NAME is Sajid KHAN |
| 2 | My Name is Ahmed Khan |
| 3 | MY friend name is Salman Khan |
+----+-------------------------------+
I need to write an Oracle SQL query/procedure/function to list the distinct words in the column.
The output should be:
+------------------+-------+
| Word | Count |
+------------------+-------+
| MY | 3 |
| NAME | 3 |
| IS | 3 |
| SAJID | 1 |
| KHAN | 3 |
| AHMED | 1 |
| FRIEND | 1 |
| SALMAN | 1 |
+------------------+-------+
Word matching should be case-insensitive.
I am using Oracle 12.1.
Let's suppose we would somehow manage to split every description in words.
So, instead of single row with Id = 1 and Description = 'My NAME is Sajid KHAN' we'd have 5 rows like this
ID | Description
--- | ------------
1 | My
1 | NAME
1 | is
1 | Sajid
1 | KHAN
in this form it'd be trivial, something like
select Description, count(*) from data_in_new_form group by Description
So, let's do this using recursive query.
create table mytable
as
select 1 as ID, 'My NAME is Sajid KHAN' as Description from dual
union all
select 2, 'My Name is Ahmed Khan' from dual
union all
select 3, 'MY friend name is Salman Khan' from dual
union all
select 4, 'test, punctuation! it is' from dual
;
with
rec (id, str, depth, element_value) as
(
-- Anchor member.
select id, upper(Description) as str, 1 as depth, REGEXP_SUBSTR( upper(Description), '(.*?)( |$)', 1, 1, NULL, 1 ) AS element_value
from mytable
UNION ALL
-- Recursive member.
select id, str, depth + 1, REGEXP_SUBSTR( str ,'(.*?)( |$)', 1, depth+1, NULL, 1 ) AS element_value
from rec
where depth < regexp_count(str, ' ')+1
)
, data as (
select * from rec
--order by id, depth
)
select element_value, count(*) from data
group by element_value
order by element_value
;
Please notice this version doesn't do anything about punctuation assuming words are separated with spaces.
UPDATE alternative way using hierarchic query
with rec as
(
SELECT id, LEVEL AS depth,
REGEXP_SUBSTR( upper(description) ,'(.*?)( |$)', 1, LEVEL, NULL, 1 ) AS element_value
FROM mytable
CONNECT BY LEVEL <= regexp_count(description, ' ')+1
and prior id = id
and prior SYS_GUID() is not null
)
, data as (
select * from rec
--order by id, depth
)
select element_value, count(*) from data
group by element_value
order by 2 desc
;
This query will work. The ordering of the words may be different. However, frequent words come at the beginning as you have listed.
SELECT word,
COUNT(*)
FROM
(SELECT TRIM (REGEXP_SUBSTR (Description, '[^ ]+', 1, ROWNUM) ) AS Word
FROM
(SELECT LISTAGG(UPPER(Description),' ') within GROUP(
ORDER BY ROWNUM ) AS Description
FROM mytable
)
CONNECT BY LEVEL <= REGEXP_COUNT ( Description, '[^ ]+')
)
GROUP BY WORD
ORDER BY 2 DESC;
I'm using ORACLE Database,
How to get all column with GROUP by only 1 column (EMP_ID)?
Example I have table ESD_RESULTS
FIRST_NAME | LAST_NAME | EMP_ID | WRIST_STATUS | LFOOT_STATUS | DATE
Dodo | A | 0101 | Pass | Pass | 2016-01-18 10:00
Wedi | Wil | 0105 | Pass | Pass | 2016-01-18 10:05
Dodo | A | 0101 | Pass | Fail | 2016-01-18 10:11
What I want the data display is (Get the last data by date desc if EMP_ID same):
FIRST_NAME | LAST_NAME | EMP_ID | WRIST_STATUS | LFOOT_STATUS | DATE
Dodo | A | 0101 | Pass | Fail | 2016-01-18 10:11
Wedi | Wil | 0105 | Pass | Pass | 2016-01-18 10:05
I tried to use DISTINCT and GROUP by the data still show all.
One option is to use ROW_NUMBER() to identify the latest record for each employee:
SELECT t.FIRST_NAME,
t.LAST_NAME,
t.EMP_ID,
t.WRIST_STATUS,
t.LFOOT_STATUS,
t.DATE
FROM
(
SELECT FIRST_NAME, LAST_NAME, EMP_ID, WRIST_STATUS, LFOOT_STATUS, DATE,
ROW_NUMBER() OVER (PARTITION BY EMP_ID ORDER BY DATE DESC) rn
FROM ESD_RESULTS
) t
WHERE t.rn = 1
Since presumably the first name and the last name are determined by the emp_id (they don't change from one row to another), you might as well group by all three columns - resulting in less work. (On the other hand, it would make more sense to normalize your table design; one table shows the associated first name and last name for each emp_id, there is no need to repeat the first name and last name in "this" table, which you show in your post.)
Then: you can use the FIRST/LAST function, with keep (dense_rank ...), as demonstrated below, to eliminate the need for a subquery and an outer query. If there is the possibility of two rows having the exact same date and time for an emp_id, you may refine the query to accommodate "tie-breaks" of some kind. If there are no ties, then the query will work without modification.
DATE is a reserved word in Oracle, it shouldn't be used for table or column names. I changed it to DT.
with
test_data ( first_name, last_name, emp_id, wrist_status, lfoot_status, dt ) as (
select 'Dodo', 'A' , 0101, 'Pass', 'Pass', to_date('2016-01-18 10:00', 'yyyy-mm-dd hh24:mi') from dual union all
select 'Wedi', 'Wil', 0105, 'Pass', 'Pass', to_date('2016-01-18 10:05', 'yyyy-mm-dd hh24:mi') from dual union all
select 'Dodo', 'A' , 0101, 'Pass', 'Fail', to_date('2016-01-18 10:11', 'yyyy-mm-dd hh24:mi') from dual
)
-- end of test data (NOT part of the solution); SQL query begins BELOW THIS LINE
select first_name, last_name, emp_id,
min(wrist_status) keep (dense_rank last order by dt) as wrist_status,
min(lfoot_status) keep (dense_rank last order by dt) as lfoot_status,
max(dt) as dt
from test_data
group by first_name, last_name, emp_id
;
FIRST_NAME LAST_NAME EMP_ID WRIST_STATUS LFOOT_STATUS DT
---------- --------- ---------- ------------ ------------ ----------------
Dodo A 101 Pass Fail 2016-01-18 10:11
Wedi Wil 105 Pass Pass 2016-01-18 10:05
2 rows selected.
I am trying to form a query for following scenario
if my table is
signature | id | operation
abc | 1 | 1234
xyz | 1 | 1234
pqr | 2 | 1234
then my output should be
signature | id
abc | 1
xyz | 1
i.e. rows having same value in a particular column.
i have formed query like
select signature,id
from tablename
where operation = '1234'
group by signature,id
having count(*) >0;
but this is returning everything including xyz | 1 also.
Can someone suggest me correct query?
Try this:
SELECT signature,COUNT(id) FROM table_name WHERE operation = '1234' GROUP BY id;
I haven't tested this and it might be overly complicated but I THINK this will work:
SELECT Signature, ID from tablename WHERE ID in( SELECT ID FROM (SELECT ID, COUNT(*) as NumRecords from tablename GROUP BY ID HAVING NumRecords > 1)))
Try this:
We need to apply PARTITION on ID column as follows,
SELECT Result.[signature], Result.ID ,
ROW_NUMBER() over(PARTITION BY Result.ID ORDER BY Result.ID) AS [RowNum]
INTO #TempResult
FROM table_name AS Result
GROUP BY Result.[signature], Result.ID
SELECT Result.[signature], Result.ID
FROM #TempResult AS Result
where Result.[RowNum] = 1
You can use where exists for an alternative to group by
select
signature,
id
from tablename t1
where exists (
select * from tablename t2
where t1.id = t2.id
and t1.signature != t2.signature
and t1.operation = 1234
);