I am trying a code in shell script. while I am trying to convert the code from batch script to shell script I am getting an error.
BATCH FILE CODE
:: Create a file with all latest snapshots
FOR /F "tokens=5" %%a in (' ec2-describe-snapshots ^|find "SNAPSHOT" ^|sort /+64') do set "var=%%a"
set "latestdate=%var:~0,10%"
call ec2-describe-snapshots |find "SNAPSHOT"|sort /+64 |find "%latestdate%">"%EC2_HOME%\Working\SnapshotsLatest_%date-today%.txt"
CODE IN SHELL SCRIPT
#Create a file with all latest snapshots
FOR snapshot_date in $(' ec2-describe-snapshots | grep -i "SNAPSHOT" |sort /+64') do set "var=$snapshot_date"
set "latestdate=$var:~0,10"
ec2-describe-snapshots |grep -i "SNAPSHOT" |sort /+64 | grep "$latestdate">"$EC2_HOME%/SnapshotsLatest_$today_date"
I want to sort the snapshots according to dates and to save the snapshots that are created in latest date in a file.
SAMPLE OUTPUT OF ece-describe-snapshots:
SNAPSHOT snap-5e20 vol-f660 completed 2013-12-10T08:00:30+0000 100% 109030037527 10 2013-12-10: Daily Backup for i-2111 (VolID:vol-f9a0 InstID:i-2601)
It will contain records like this
I got this code :
latestdate=$(ec2-describe-snapshots | grep ^SNAPSHOT | sort -k 5 | awk '{print $5}')
ec2-describe-snapshots | grep SNAPSHOT.*$latestdate | > "$EC2_HOME/SnapshotsLatest_$today_date"
but getting this error :
grep: 2013-12-10T09:55:34+0000: No such file or directory
grep: 2013-12-11T04:16:49+0000: No such file or directory
grep: 2013-12-11T04:17:57+0000: No such file or directory
i have some snapshots made on amazon, i want to find the latest snapshots made on a date and then want to store them in a file. like date 2013-12-10 snapshots made on this date should be stored in file. Contents of snapshotslatest file should be
SNAPSHOT snap-c17f3 vol-f69a0 completed 2013-12-04T09:24:50+0000 100% 109030037527 10 2013-12-04: Daily Backup for Sanjay_Test_Machine (VolID:vol-f66409a0 InstID:i-26048111)
SNAPSHOT snap-c7d617f9 vol-3d335f6b completed 2013-12-04T09:24:54+0000 100% 109030037527 10 2013-12-04: Daily Backup for sacht_VPC (VolID:vol-3db InstID:i-ed6)
please not that if there are snapshots created on 2013-12-10, 2013-12-11, 2013-12-12. It means that the latest_date should be 2013-12-12 and all the snaphshot created on 2013-12-12 should be saved in file.
Any suggestion or lead is appreciated.
Neither the batch script nor the shell script you posted are a good starting point so let's start from scratch. Sorry, this is too big for a comment.
You want to find the latest snapshots made on a date and then want to store them in a file.
What does that mean?
Do the snapshot files have a timestamp in their name or in their content?
If not - UNIX does not store file creation timestamps so is a last-modified timestamp adequate?
Do you literally want to concatenate all of your snapshot files into one singe file or do you want to create a file that has a list of the snapshot file names?
Post some sample input (e.g. some snapshot file names and contents if that's where the timestamp is stored) and the expected output given that input.
Update your question to address all of the above, do not try to reply in a comment.
Minor issue, you don't need a pipe when re-directing output, so your line to save should be
ec2-describe-snapshots | grep SNAPSHOT.*$latestdate > "$EC2_HOME/SnapshotsLatest_$today_date"
Now the main issue here, is that the grep is messed up. I haven't worked with amazon snapshots, but judging by your example descriptions, you should be doing something like
latestdate=$(ec2-describe-snapshots | grep -oP "\d+-\d+-\d+" | sort -r | head -1)
This will get all the dates containing the form dddd-dd-dd from the file (I'm assuming the two dates in each snapshot line always match up), sort them in reverse order (latest first) and take the head which is the latest date, storing it in $latestdate.
Then to store all snapshots with the given date do something like
ec2-describe-snapshots | grep -oP "SNAPSHOT(.*?)$lastdateT(.*?)\)" > "$EC2_HOME/SnapshotsLatest_$today_date"
This will get all text starting with SNAPSHOT, containing the given date, and ending in a closing ")" and save it. Note, you may have to mess around with it a bit, if ")" can be present elsewhere.
Related
For a project I need to extract data from a lot of different blockchain GitHub profiles to a csv.
After browsing through the GitHub API I was able to achieve some of the necessary data being shown as txt/csv files using bash commands and jq.
Now doing all of this manually would probably take 7 days. I have a list of profiles i need to loop through saved as CSV.
The list looks like this --> https://docs.google.com/spreadsheets/d/1lFsewAYI7F8zSw7WPhI9E9WwR8f4G1clw1yjxY3wz_4/edit#gid=0
My approach so far to get all the repo names looks like this:
sample='[{"name":"0chain"},{"name":"0stateapp"},{"name":"0xcert"}]'
the csv belongs in here, I didn't know how to redirect it to that variable yet, but for testing purposes this was enough. If somebody knows how to, feel free to give a hint.
for row in $(echo "${sample}" | jq -r '.[] | #base64'); do
_jq()
{
echo ${row} | base64 --decode | jq -r ${1}
}
for GHUSER in $( echo $(_jq '.name')); do
curl -s https://api.github.com/users/$GHUSER/repos?per_page=100 | jq -r '.[]|.full_name'
done
done
The output looks like this:
0chain/0chain-token
0chain/client-sdk
0chain/docs
0chain/gorocksdb
0chain/hostadmin
0chain/rocksdb
0stateapp/ZSCoin
0xcert/0xcert
0xcert/conventions
0xcert/docs
0xcert/erc721-validator
0xcert/erc721-validator-api
0xcert/erc721-validator-ui
0xcert/erc721-website
0xcert/ethereum
0xcert/ethereum-crowdsale
0xcert/ethereum-dex
0xcert/ethereum-erc20
0xcert/ethereum-erc721
0xcert/ethereum-minter
0xcert/ethereum-utils
0xcert/ethereum-xcert
0xcert/ethereum-xcert-builder
0xcert/ethereum-zxc
0xcert/framework
0xcert/framework-cert-test
0xcert/nonfungiblealliance-www
0xcert/solidity-style-guide
0xcert/techpaper
0xcert/truffle
0xcert/web3.js
What I need to do is use all of the above values and generate a file that contains:
Github Profile (already stored in the attached sheet)
The Date when accessing this information
All the repositories belonging to that profile (code above but
filtered)
Now the Interesting part:
The commit history
number of commit (ID)
number of commit (ID)
Date of commit
Description of commit
person who commited
checks passed
checks failed
Almost the same needs to be done for closed and open pull requests although I think when solving the "problem" above solving the pull requests is the same strategy.
For the commits I'd do something like this:
for commits in $( $repoarray) do curl -i https://api.github.com/repos/$commits/commits | jq -r '.[]|.author.lgoin (and whatever els is needed)' done
basically this chart here needs to be filled
https://docs.google.com/spreadsheets/d/1mFXiohiWNXNP8CVztFA1PFF41jn3J9sRUhYALZShsPY/edit?usp=sharing
what I need help with:
storing my output from the first loop in a an array
loop through that array to get the number of commits
loop through that array to get the data to closed pull requests
loop through that array to get the data to open pull requests
Excuse my "noobish" question.
I'm using bash/jq and the GitHub API for the time.
I'd appreciate any kind of help.
This question already has answers here:
How to get the part of a file after the first line that matches a regular expression
(12 answers)
Closed 4 years ago.
5G_Fixed_Wireless_Dashboard_TestScedule||||||||||||||||^M
Report Run Date||08/07/2018|||||||||||||||||||||^M
Requesting User Company||NEW|||||||||||||||||||||^M
Report Criteria|||||||||||||||||||||||^M
" Service Job Updated from Date:
Service Job Updated to Date:
Service Job Created from Date: 08/06/2018
Service Job Created to Date:
Service Job Status:
Resolution Code:"|||||||||||||||||||||||^M
Created Date|Job Status|Schedule Date|Job
Number|Service Job Type|Verizon Customer Order
Number|Verizon Location Code|Service|Installation
Duration|Part Number
I want to print starting from Created Date. The result
file should be something like below.
Created Date|Job Status|Schedule Date|Job
Number|Service Job Type|Verizon Customer Order
Number|Verizon Location Code|Service|Installation
Duration|Part Number
I have tried the following lines after you people linked me to some other questions. But my requirement is to print the result to the same file.
FILELIST=find $MFROUTDIR -maxdepth 1 -name "XXXXXX_5G_Order_*.txt"
for nextFile in $FILELIST;do
cat $nextFile | sed -n -e '/Created Date/,$p'
done
By writing above lines of code, output is printed on console. Could you please suggest some way to print it in same file.
This can be easily done with a simple awk command:
awk '/^Created Date/{p=1} p' file
Created Date|Job Status|Schedule Date|Job
Number|Service Job Type|Verizon Customer Order
Number|Verizon Location Code|Service|Installation
Duration|Part Number
We set a flag p to 1 when we encounter a line that starts with Created Date. Later we use awk default action to print each line when p==1.
References:
Effective AWK Programming
Awk Tutorial
When a disk inserted to my cluster, i wanna know that.
So i need to listen /var/adm/messages and when i catch !NEW! "online" line i must write it to a different log file.
When disk goes online I get this kind of log entries:
Dec 8 10:10:46 SMNODE01 genunix: [ID 408114 kern.info] /scsi_vhci/disk#g5000c50095f92a8f (sd69) online
Tail works without -F option. But i need -F option :/
tail messages | grep 408114 | grep '/scsi_vhci/disk#'| egrep -wi --color 'online'
I have 3 uniform words for grep.
1- The id "408114" is unique for online status.
2- /scsi_vhci/disk#
3- online
P.S: Sorry for my english :)
For grep AND use .*:
$ grep 408114.*/scsi_vhci/disk#.*online test
Dec 8 10:10:46 SMNODE01 genunix: [ID 408114 kern.info] /scsi_vhci/disk#g5000c50095f92a8f (sd69) online
Next time don't edit the question completely but ask another question.
Currently I keep 6 weeks of apache access_log. If I generate a access summary at month end:
cat /var/log/httpd/access_log* | goaccess --output-format=csv
the summary will include some access data from previous month.
How can I skip logs of previous month and summarise from first day of month?
p.s. the data-format is: %d/%b/%Y
You can trade the Useless Use of cat for a useful grep.
grep -n $(date +'[0-3][0-9]/%b/%Y') /var/log/httpd/access_log* |
goaccess --output-format=csv
If the logs are by date, it would be a lot more economical to skip the logs which you know are too old or too new, i.e. modify the wildcard argument so you only match the files you really want (or run something like find -mtime -30 to at least narrow the set to a few files).
(The cat is useless because, if goaccess is at all correctly written, it should be able to handle
goaccess --output-format=csv /var/log/httpd/access_log*
just fine.)
I have a script where I'm fetching the logs from the tomcat and sending that into the my cloud resource. Everything works well, but I have a problem when my tomcat rotates the log.
When the logs get rotated its been prefixed with date ( log gets rotated every day ). Since my script just runs every half an hour I may miss the logs when it gets rotated, because I'm fetching the logs with their static name, in the example logfile.log.
Before getting rotated the file will look like this :
logfile.log
After getting rotated, it will look like this :
logfile.log.2012-10-09
Are there any ways to get rid of this problem?
Edit:
My script :
cp /tomcat/logs/$logname $fileName
gzip $fileName
s3cmd put $fileName.gz s3://x.x.x.x.x/$folderName
Thanks in advance.
I think the best way to backup you logs is to do a check according to the mtime of the logfiles.
You can keep the log file mtime of the last backup somewhere, then check both rotated log files and current log file. If there is a rotated log file that newer then the last mtime stored, you could append the current log file to the rotated one and then backup. If only current log file is newer, then just backup it.
The mtime of the file could be retrieved by: LC_ALL=C stat logfile.log | grep '^Modify' | cut -d: -f2-, or the unix timestamp by date "+%s" --date="$(LC_ALL=C stat logfile.log | grep '^Modify' | cut -d: -f2-)"