I know the "how to limit" or "how to get 1st row" has been posted many times but I can't find a solution to my specific issue.
I have a inventory balance table that contains bin # with quantities
I want on my row the bin # that contains the highest quantity
The real queries are much bigger and complex than this but this example shows the issue I am facing
I first I did
select itemnumber,
(select binnumber from inventory_balance where current_balance = (select max(current_balance) from inventory_balance where inventory_balance.itemnumber = item_table.itemnumber)) as binnumber
from item_table;
This will work when there is only one "bin" with the highest quantity.
If there are 2 bins for the same item with a quantity of 10 (which is the highest quantity), the sub query will return 2 rows, triggering a oracle error
Then I tried this :
select
itemnumber,
(select binnumber from (select binnumber from inventory_balance where current_balance = (select max(current_balance) from inventory_balance where inventory_balance.itemnumber = item_table.itemnumber)) where rownum =1) as binnumber
from item_table;
Now this will not work because it seems that the references to item_table.itemnumber is invalid when inside the from (...). I get "invalid column name" error when trying to do so.
I can't use ROW_NUMBER() because the "OLAP Window functions" do not seem to be activated on the database.
Something like this:
SELECT t.itemnumber,
MIN( b.binnumber ) KEEP ( DENSE_RANK LAST ORDER BY b.current_balance ASC ) AS binnumber
FROM item_table t
LEFT OUTER JOIN inventory_balance b
ON ( t.itemnumber = b.itemnumber )
GROUP BY t.itemnumber;
Looking at the explain plan then this will only scan inventory_balance once whereas doing nested selects to get the MAX balance and then filter an outer query based on that requires two scans of inventory_balance.
Although all the required output for you minimal working example seems to be contained in the inventory_balance table so you can do (if you are not interested in the itemnumbers where there are no entries in the inventory_balance table):
SELECT itemnumber,
MIN( binnumber ) KEEP ( DENSE_RANK LAST ORDER BY current_balance ASC ) AS binnumber
FROM inventory_balance
GROUP BY itemnumber;
If you want the highest binnumber (instead of the lowest) then you can just change it to:
MAX( binnumber ) KEEP ...
Related
Output result
I want the running balance in my query. I had wrote the query.
May be i am mistaking any where please let me know.
SELECT
ACC_VMAST.VM_DATE,
ACC_VDET.CHEQUE,
ACC_VMAST.NARRATION,
ACC_VDET.DEBIT,
ACC_VDET.CREDIT,
sum(nvl(ACC_VDET.DEBIT,0) - nvl(ACC_VDET.CREDIT,0) )
over (order by ACC_VMAST.VM_DATE , ACC_VDET.DEBIT ) running_bal
FROM ACC_VMAST,
ACC_VDET,
ACC_COA
WHERE ACC_VMAST.VM_PK=ACC_VDET.VM_PK
AND ACC_COA.COA_PK=ACC_VDET.COA_PK
AND ACC_VMAST.POST_BY IS NOT NULL
AND ACC_VMAST.CANCEL_STATUS IS NULL
AND ACC_VMAST.VM_DATE BETWEEN '07/06/2021' AND '07/07/2021'
AND ACC_VDET.COA_PK= '303'
ORDER BY ACC_VMAST.VM_DATE , ACC_VDET.DEBIT;
If you have rows that have the same values for the ORDER BY clause then when you SUM the values then all the rows with the same ORDER BY value will be grouped together and totalled.
To prevent that, you can add the ROWNUM pseudo-column to the ORDER BY clause of the analytic function so that there will not be any ties:
SELECT m.VM_DATE,
d.CHEQUE,
m.NARRATION,
d.DEBIT,
d.CREDIT,
SUM( COALESCE(d.DEBIT,0) - COALESCE(d.CREDIT,0) )
OVER ( ORDER BY m.VM_DATE, d.DEBIT, ROWNUM ) AS running_bal
FROM ACC_VMAST m
INNER JOIN ACC_VDET d
ON (m.VM_PK = d.VM_PK)
INNER JOIN ACC_COA c
ON (c.COA_PK = d.COA_PK)
WHERE m.POST_BY IS NOT NULL
AND m.CANCEL_STATUS IS NULL
AND m.VM_DATE BETWEEN DATE '2021-07-06' AND DATE '2021-07-07'
AND d.COA_PK = '303'
ORDER BY
m.VM_DATE,
d.DEBIT;
You need to add a row range with "rows between unbounded preceding and current row".
sum(nvl(ACC_VDET.DEBIT,0) - nvl(ACC_VDET.CREDIT,0) )
over (order by ACC_VMAST.VM_DATE , ACC_VDET.DEBIT rows between unbounded preceding and current row ) running_bal
I'm trying to execute a left join where multiple conditions must be met with the inclusion of pulling in the MAX sequence number that meets those conditions.
The left join is on the unique identifier in both tables. Table acaps_history has several rows for each app_id. I need to pull in only one row with the highest seq_number and activity_code of 'XU'. If the code 'XU' doesn't exist for the given app_id, then the case statement above should return 'N' for that row. The code I have currently just isn't working - returning the error "a column may not be outer-joined to a subquery":
create table orig_play3 as
(select
x.*,
case when xa.activity_code in 'XU' then 'Y' else 'N' end as cpo_flag
from
dfs_tab_orig_play_x x
left join cf.acaps_history xa on
x.APP_ID = xa.FOC_APPL_ID
and xa.activity_code in 'XU'
and xa.seq_number = (select max(seq_number) from cf.acaps_history where FOC_APPL_ID=x.app_id)
)
Given your error, it seems that the issue is the last part of your query:
and xa.seq_number = (select max(seq_number) from cf.acaps_history where FOC_APPL_ID=x.app_id)
This is still operating in the context of the ON clause, so the sub-query to find the max sequence number is the issue.
You should be able to avoid this by moving that sub-query out of the ON clause:
LEFT JOIN (
SELECT FOC_APPL_ID, activity_code, seq_number
FROM cf.acaps_history
WHERE activity_code in 'XU'
) xa
ON x.APP_ID = xa.FOC_APPL_ID
WHERE xa.seq_number = (select max(ah.seq_number) from cf.acaps_history ah where ah.FOC_APPL_ID=x.app_id and ah.activity_code in 'XU')
This may be the most inefficient way to execute this query, but it worked... It took like 3 minutes to run (table size is over 600K rows), but again, it returned the results I needed:
create table test as (
select x.*,
case when xb.activity_code in 'XU' then 'Y' else 'N' end as cpo_flag
from dfs_tab_orig_play_x x
left join
(select
xa.FOC_APPL_ID, xa.activity_code, xa.seq_number
from dfs_tab_orig_play_x x, cf.acaps_history xa
where x.app_id = xa.FOC_APPL_ID (+)
and xa.seq_number = (select max(seq_number) from cf.acaps_history where
x.app_id=FOC_APPL_ID(+) and activity_code in 'XU')) xb
on x.app_id = xb.FOC_APPL_ID (+)
)
If you are on 12c, I like OUTER APPLY for this sort of thing, because it lets you sort the rows for each app_id descending by seq_number and then just pick the highest one.
SELECT
x.*,
CASE
WHEN xa.activity_code IN 'XU' THEN 'Y'
ELSE 'N'
END
AS cpo_flag
FROM
dfs_tab_orig_play_x x
OUTER APPLY ( SELECT *
FROM cf.acaps_history xa
WHERE xa.foc_appl_id = x.app_id
AND xa.activity_code = 'XU'
ORDER BY xa.seq_number DESC
FETCH FIRST 1 ROW ONLY ) xa
Note: this logic is a little different from what you posted. In this version, it will join to the acaps_history row having the highest seq_number from among 'XU' records for the given app_id. Your version was joining to the row having the highest seq_number for the given app_id, whether that row was an 'XU' row or not. I am assuming (with little reason) that that was a bug on your part. But, if it wasn't, my version won't work as given.
Hello I'am very new to writing SQL and I am trying to find the appropriate way to use TOP in Oracle SQl 9:
My example:
select * from example e, test t
where e.id = t.id
and country = 'USA'
order by state ASC;
What I am trying to do is take the bottom 20 % of my query but I know you cannot use TOP. After researching I still have not found an applicable answer. I know you have to first order them but am unsure of how to then take the bottom 20%(which would be TOP since the order is ASC)
In general (like if you want the top or bottom 17.2% of the rows) you can use row_number() and count() (analytic functions) to get the result.
20% is easier - you are looking for the top (or bottom) quintile. For this, you can use the ntile() function, like so:
select [column_names]
from (
select e.*, t.*, ntile(5) over (order by state) as nt
from ..... etc
)
where nt = 1;
The subquery is your query. The column_names in the outer query are whatever you actually need; you could also use select * but that will show the ntile too (which will be 1 in all rows).
If sorting something in ASCending order gives us the top set then surely sorting in DESCending order can give us the bottom set.
This solution uses the function NTILE() to divide the records into five buckets. The first bucket is the set we want (because sorted in descending order). Sorting in ascending order and taking the fifth quintile would have the same outcome.
select * from (
select e.*
, t.*
, ntile(5) over (order by state desc) nt
from example e, test t
where e.id = t.id
and country = 'USA'
)
where nt = 1
order by state desc
/
You don't say what your sort criteria are, so I've guessed.
I'm sorry for my strange title, but I don't know what exactly I'm looking for. The task is quite simple. I have the table of competitions. Another table groups. In every group there are several contestants. In the last table are stored the results of contestants. The task is to get the first three of the contestants of every group.
So I have to loop through the groups, get the first three contestants (according to achieved points) of every group and append them into some variable.
Here is the pseudocode:
CREATE OR REPLACE PROCEDURE get_first_three_of_all(contestants OUT SOME_TYPE) AS
CURSOR groups SELECT...
BEGIN
FOR group IN groups LOOP
APPEND(contestants, get_first_three_of_one_group(group.id))
END LOOP;
END;
I have no idea, how to solve this task. I even don't know what should I look for. Would you be so kind and help me, please? Thanks.
Edited: simplified structure of my tables:
Competition: competition_id
Contestant: contestant_id
GroupContestant: contestant_group_id, competition_d, group_number, contestant_id
Result: contestant_group_id, juror, points
Select to get data of one group (group number YYY) is here:
SELECT * FROM (
SELECT res.contestant_group_id, SUM(res.points) AS points
FROM Result res
WHERE res.couple_group_id IN (SELECT couple_group_id
FROM GroupContestant
WHERE competition_id = XXX
AND group_number = YYY)
GROUP BY res.contestant_group_id
ORDER BY points DESC
)
WHERE ROWNUM <= 3;
Analytic functions to the rescue. To select top 3 results for each group, each competition:
SELECT * FROM (
SELECT grp.competition_id, grp.group_number, res.contestant_group_id, res.points,
row_number() over (partition by grp.competition_id, grp.group_number
order by res.points desc) rn
FROM (SELECT contestant_group_id, SUM(points) AS points
FROM Result
GROUP BY contestant_group_id) res
JOIN GroupContestant grp ON (grp.contestant_group_id = res.contestant_group_id)
)
WHERE rn <= 3;
Pay attention to how you resolve ties (consider using rank or dense_rank instead of row_number).
You can use RANK() analytic function to achieve the goal:
select *
from (select group_num,
points,
rank() over(partition by group_num order by points desc) rank
from results
inner join group_contestant
using (contestant_group_id))
where rank <= 3
order by group_num, points desc;
Here is SQLFiddle to play with.
How can I reference a column outside of a subquery using Oracle? I specifically need to use it in the WHERE statement of the subquery.
Basically I have this:
SELECT Item.ItemNo, Item.Group
FROM Item
LEFT OUTER JOIN (SELECT Attribute.Group, COUNT(1) CT
FROM Attribute
WHERE Attribute.ItemNo=12345) A ON A.Group = Item.Group
WHERE Item.ItemNo=12345
I'd like to change WHERE Attribute.ItemNo=12345 to WHERE Attribute.ItemNo=Item.ItemNo in the subquery, but I can't figure out if this is possible. I keep getting "ORA-00904: 'Item'.'ItemNo': Invalid Identifier"
EDIT:
Ok, this is why I need this kind of structure:
I want to be able to get a count of the "Error" records (where the item is missing a value) and the "OK" records (where the item has a value).
The way I have set it up in the fiddle returns the correct data. I think I might just end up filling in the value in each of the subqueries, since this would probably be the easiest way. Sorry if my data structures are a little convoluted. I can explain if need be.
My tables are:
create table itemcountry(
itemno number,
country nchar(3),
imgroup varchar2(10),
imtariff varchar2(20),
exgroup varchar2(10),
extariff varchar2(20) );
create table itemattribute(
attributeid varchar2(10),
tariffgroup varchar2(10),
tariffno varchar2(10) );
create table icav(
itemno number,
attributeid varchar2(10),
value varchar2(10) );
and my query so far is:
select itemno, country, imgroup, imtariff, im.error "imerror", im.ok "imok", exgroup, extariff, ex.error "exerror", ex.ok "exok"
from itemcountry
left outer join (select sum(case when icav.itemno is null then 1 else 0 end) error, sum(case when icav.itemno is not null then 1 else 0 end) ok, tariffgroup, tariffno
from itemattribute ia
left outer join icav on ia.attributeid=icav.attributeid
where (icav.itemno=12345 or icav.itemno is null)
group by tariffgroup, tariffno) im on im.tariffgroup=imgroup and imtariff=im.tariffno
left outer join (select sum(case when icav.itemno is null then 1 else 0 end) error, sum(case when icav.itemno is not null then 1 else 0 end) ok, tariffgroup, tariffno
from itemattribute ia
left outer join icav on ia.attributeid=icav.attributeid
where (icav.itemno=12345 or icav.itemno is null)
group by tariffgroup, tariffno) ex on ex.tariffgroup=exgroup and extariff=ex.tariffno
where itemno=12345;
It's also set up in a SQL Fiddle.
You can do it in a sub-query but not in a join. In your case I don't see any need to. You can put it in the join condition.
select i.itemno, i.group
from item i
left outer join ( select group, itemno
from attribute b
group by group itemno ) a
on a.group = i.group
and i.itemno = a.itemno
where i.itemno = 12345
The optimizer is built to deal with this sort of situation so utilise it!
I've changed the count(1) to a group by as you need to group by all columns that aren't aggregated.
I'm assuming that your actual query is more complicated than this as with the columns you're selecting this is probably equivilent to
select itemno, group
from item
where itemno = 12345
You could also write your sub-query with an analytic function instead. Something like count(*) over ( partition by group).
As an aside using a keyword as a column name, in this case group is A Bad Idea TM. It can cause a lot of confusion. As you can see from the code above you have a lot of groups in there.
So, based on your SQL-Fiddle, which I've added to the question I think you're looking for something like the following, which doesn't look much better. I suspect, given time, I could make it simpler. On another side note explicitly lower casing queries is never worth the hassle it causes. I've followed your naming convention though.
with sub_query as (
select count(*) - count(icav.itemno) as error
, count(icav.itemno) as ok
, min(itemno) over () as itemno
, tariffgroup
, tariffno
from itemattribute ia
left outer join icav
on ia.attributeid = icav.attributeid
group by icav.itemno
, tariffgroup
, tariffno
)
select ic.itemno, ic.country, ic.imgroup, ic.imtariff
, sum(im.error) as "imerror", sum(im.ok) as "imok"
, ic.exgroup, ic.extariff
, sum(ex.error) as "exerror", sum(ex.ok) as "exok"
from itemcountry ic
left outer join sub_query im
on ic.imgroup = im.tariffgroup
and ic.imtariff = im.tariffno
and ic.itemno = im.itemno
left outer join sub_query ex
on ic.exgroup = ex.tariffgroup
and ic.extariff = ex.tariffno
and ic.itemno = ex.itemno
where ic.itemno = 12345
group by ic.itemno, ic.country
, ic.imgroup, ic.imtariff
, ic.exgroup, ic.extariff
;
You can put WHERE attribute.itemno=item.itemno inside the subquery. You are going to filter the data anyway, filtering the data inside the subquery is usually faster too.