I'm trying to store the output from a ps and later compare it.
I'm using the following line:
siteminder_running=`ps -ef | grep $iplanet_home | grep LLAWP | wc -l`
When I tried to compare the output I found that the variable has a tab in front of the number.
This is the output:
- 0- value
What could be the problem?
Like ruakh pointed out you can just use grep -c
siteminder_running=`ps -ef | grep $iplanet_home | grep -c LLAWP`
For fixing white space in general, I use xargs echo like this:
siteminder_running=`ps -ef | grep $iplanet_home | grep LLAWP | wc -l | xargs echo`
The wc(1) utility provided with most Unix and GNU/Linux releases prints to user terminal input filename and count (of lines/characters/what you asked it to print) separated by TAB.
In case of standard input, there is no input filename, resulting just a TAB in front of count.
There are several ways to circumvent this, for example:
ps -ef | grep $iplanet_home | grep LLAWP | wc -l | awk '{ printf "%d\n", $0 }'
printf $(ps -ef | grep $iplanet_home | grep LLAWP | wc -l)
ps -ef | grep $iplanet_home | grep LLAWP | wc -l | sed -e 's/^[ \t]*//'
As said, these are just examples, there are literally dozens ways of accomplishing this.
Related
This question already has an answer here:
Getting all files which have changed in specific time range
(1 answer)
Closed 3 years ago.
I'm trying to build a one-line command in bash which counts the number of files of type *.lu in the current directory that were modified between 15:17 and 15:47 (date does not matter here). I'm not allowed to use find (otherwise it would been easy). I'm allowed to use basic commands like ls, grep, cut, wc and so on.
What I tried to do:
ls -la *.lu | grep <MISSING> | wc -l
First of all, I'll find all files *.lu, than I need to check with grep the date (which I'm not sure how to do) and than we need to count the number of lines. I think we need to insert also cut to get to the date and check it, but how? Also if current directory does not have *.lu files it will fail rather than returning 0.
How to solve it?
ls -l *.lu | grep -E '15:[2-3][0-9]|15:1[7-9]|15:4[0-7]' | wc -l
Should do it.
With awk:
ls -al *.lu | awk 'BEGIN{count=0} {if((substr($8,0,2) == "15") && (int(substr($8,4)) >=17 && int(substr($8,4)) <= 47 )){count++}} END{print count}'
UPDATE:
Without -E
ls -l *.lu | grep '15:[2-3][0-9]\|15:1[7-9]\|15:4[0-7]' | wc -l
Redirect error in case of zeros files:
ls -l *.lu 2> /dev/null | grep '15:[2-3][0-9]\|15:1[7-9]\|15:4[0-7]' | wc -l
This is pretty ugly and can probably be done better. However, I wanted to challenge myself to do this without regexes (excepting the sed one). I don't guarantee it'll handle all of your use cases (directories might be an issue).
ls -l --time-style="+%H%M" *.lu 2>/dev/null |
sed '/total/d' |
tr -s ' ' |
cut -d ' ' -f6 |
xargs -r -n 1 -I ARG bash -c '(( 10#ARG >= 1517 && 10#ARG <= 1547)) && echo ARG' |
wc -l
There is probably a way to avoid parsing ls via stat --format=%Y.
I am using Git Bash to recursively find all of the file extensions in our legacy web site. When I pipe it to a file I would like to add line-breaks and a period in front of the file extension.
find . -type f -name "*.*" | grep -o -E "\.[^\.]+$" | grep -o -E "[[:alpha:]]{1,12}" | awk '{print tolower($0)}' | sort -u
You have different ways.
When you do not want to change your existing commands I am tempted to use
printf ".%s\n" $(find . -type f -name "*\.*" | grep -o -E "\.[^\.]+$" |
grep -o -E "[[:alpha:]]{1,12}" | awk '{print tolower($0)}' | sort -u ) # Wrong
This is incorrect. When a file extension has a space (like example.with space), it will be split into different lines.
Your command already outputs everyring into different lines, so you can just put a dot before each line with | sed 's/^/./'
You can skip commands in the pipeline. You can let awk put a dot in front of a line with
find . -type f -name "*\.*" | grep -o -E "\.[^\.]+$" | grep -o -E "[[:alpha:]]{1,12}" | awk '{print "." tolower($0)}' | sort -u
Or you can let sed ad the dot, with GNU sed also convert in lowercase.
find . -type f -name "." | sed -r 's/..([^.])$/.\L\1/' | sort -u
In the last command I skipped the grep on 12 chars, I think it works different than you like:
echo test.qqqwwweeerrrtttyyyuuuiiioooppp | grep -o -E "\.[^\.]+$" | grep -o -E "[[:alpha:]]{1,12}"
Adding a second line break for each line, can be done in different ways.
When you have the awk command, swith the awk and sort and use
awk '{print "." tolower($0) "\n"}'
Or add newlines at the end of the pipeline: sed 's/$/\n/'.
I'm trying to use the /etc/passwd file to list home directories of users in the system, sorted and without repetitions, such that nonexisting directories would not be printed..
This is my command:
cut -f 6 -d ':' /etc/passwd | sort -su | ls -ld
It acts as if I just ran ls -ld with no arguments from the command pipe at all.
You can't pipe stuff into ls.. You could do something like:
ls -ld $(cut -f 6 -d ':' /etc/passwd | sort -su)
By spawning a new bash to execute the cut | sort and passing it as a ls argument
ls does not take piped output. You could, however, use forward quotes to execute it on a list of directories:
ls `cut -f 6 -d ':' /etc/passwd | sort -su `
You could use xargs
cut -f 6 -d ':' /etc/passwd | sort -su | xargs ls
You were not far away, it was enough to add a xargs before ls :
cut -f 6 -d ':' /etc/passwd | sort -u | xargs ls -ld
I've got an issue where a program suddenly doesn't want to start, no error, no nothing. To ensure the integrity of the code and its linked libraries I wanted to compare the md5sum of every (dynamically) linked library. From other posts in this forum I found it easy to list all the linked libraries show them nicely:
ldd myProgram | grep so | sed -e '/^[^\t]/ d' \
| sed -e 's/\t//' | sed -e 's/.*=..//' \
| sed -e 's/ (0.*)//'
How can I add the md5sum or sha1sum so it will add a column with the checksum next to the filename? Simply adding md5sum only produces one line and doesn't seem to do the job:
ldd myProgram | grep so | sed -e '/^[^\t]/ d' \
| sed -e 's/\t//' | sed -e 's/.*=..//' \
| sed -e 's/ (0.*)//' | md5sum
yields
3baf2fafbce4dc8a313ded067c0fccab -
leaving md5sum out produces the nice list of linked libraries:
/lib/i386-linux-gnu/i686/cmov/libpthread.so.0
/lib/i386-linux-gnu/i686/cmov/librt.so.1
/lib/i386-linux-gnu/i686/cmov/libdl.so.2
/lib/i386-linux-gnu/libz.so.1
/usr/lib/i386-linux-gnu/libodbc.so.1
/usr/lib/libcrypto++.so.9
/lib/i386-linux-gnu/libpng12.so.0
/usr/lib/i386-linux-gnu/libstdc++.so.6
/lib/i386-linux-gnu/i686/cmov/libm.so.6
/lib/i386-linux-gnu/libgcc_s.so.1
/lib/i386-linux-gnu/i686/cmov/libc.so.6
/lib/ld-linux.so.2
/usr/lib/i386-linux-gnu/libltdl.so.7
Any hint is much appreciated!
Your script is doing is piping the literal text "/lib/i386-linux-gnu/i686/cmov/libpthread.so.0..." etc. and calculating the md5sum of that...
You can use xargs to repeat any command on every line of input. The -I{} isn't strictly necessary but I'd recommend as makes your script more readable and easier to understand
For example
adam#brimstone:~$ ldd $(which bash)
| grep so | sed -e '/^[^\t]/ d'
| sed -e 's/\t//' | sed -e 's/.*=..//'
| sed -e 's/ (0.*)//'
| xargs -I{} md5sum {}
6a0cb513f136f5c40332e3882e603a02 /lib/x86_64-linux-gnu/libtinfo.so.5
c60bb4f3ae0157644b993cc3c0d2d11e /lib/x86_64-linux-gnu/libdl.so.2
365459887779aa8a0d3148714d464cc4 /lib/x86_64-linux-gnu/libc.so.6
578a20e00cb67c5041a78a5e9281b70c /lib64/ld-linux-x86-64.so.2
For loop can also be used:
for FILE in `<your command>`;do md5sum $FILE;done
For eg:
for FILE in `ldd /usr/bin/gcc | grep so | sed -e '/^[^\t]/ d' | sed -e 's/\t//' | sed -e 's/.*=..//' | sed -e 's/ (0.*)//'`;do md5sum $FILE;done
I need help doing this I tried:
#!/bin/bash
ls -l [0-9][0-9]*
I am trying to get all the entries with 2 integers in them.
says ls cannot access no such file or directory
ls -l | awk '{print $9}' | grep '[0-9][0-9]'
Or if you simply want to count them:
ls -l | awk '{print $9}' | grep '[0-9][0-9]' | wc -l